Path kernels and partitions - PowerPoint PPT Presentation

About This Presentation
Title:

Path kernels and partitions

Description:

Relationship among path kernels, semikernels and partitions ... Conjuncture about kernels is true for every n 9 a is false for every n 360 ... – PowerPoint PPT presentation

Number of Views:24
Avg rating:3.0/5.0
Slides: 19
Provided by: Katr2
Category:

less

Transcript and Presenter's Notes

Title: Path kernels and partitions


1
Path kernels and partitions
  • Peter Katrenic
  • Institute of Mathematics
  • Faculty of Science
  • P. J. Å afárik University, KoÅ¡ice

2
Coloring
  • G(V,E)

?(G)kl
?V1,V2 V1?V2? V1?V2 V ?(GV1)k ?(GV2)l
V1
V2
k2l2
3
Graph decomposition with bounded maximal degree
  • G(V,E)

?(G)kl
?V1,V2 V1?V2? V1?V2 V ?(GV1)k ?
(GV2)l
V1
V2
k2l3
4
Path partition conjecture
  • G(V,E)

?(G)kl
?V1,V2 V1?V2? V1?V2 V ? (GV1)k ?
(GV2)l
V1
V2
k3l5
5
Pn-kernel and Pn-semikernel
  • A subset K of V(G) is called Pn-kernel of G
    if
  • ?(GK) n-1
  • every vertex v ?V(G-K) is adjacent to a
    Pn-1-terminal vertex of GK.
  • A subset S of V(G) is called a Pn-semikernel of G
    if
  • ?(GS) n-1
  • every vertex in N(S)-S is adjacent to a
    Pn-1-terminal vertex of GS.

6
Difference between kernel and semikernel
x6
x7
x4
x2
x1
x3
x8
x5
Mx2,x3,x4,x5
No
-is M P5-kernel in G?
Yes
-is M P5-semikernel in G?
7
Conjecture about kernels
G(V,E)
For every n2 exists K?V, that K is Pn-kernel
in G.
n4
8
Conjecture about semikernels
G(V,E)
For every n2 exists S?V, thatS is
Pn-semikernel in G.
n4
9
Conjectures
Every graphis ?-partitionable
Every graph has Pn-kernelfor every n2
Every graph has Pn-semikernel for every n2
10
Relationship among path kernels, semikernels and
partitions
  • Let P be a hereditary class of graphs. If every
    graph in P has Pn-semikernel, then every graph in
    P has Pn-kernel.
  • Let G be a graph with ?(G)ab, ab. If G has
    Pb1-semikernel, then G is (a,b)-partitionable.

11
The existence of Pn-kernels for small values of n
  • Dunbar,Frick
  • Every graph has P7-kernel
  • Melnikov,Petrenko
  • Every graph has P8-kernel
  • P.K.(2005)
  • Every graph has P9-kernel

12
Graphs that have Pn-kernels for all n
  • If every block of graph G is either a complete
    graph or a cycle, then G has Pn-kernel for all
    n2.
  • Let G be a complete multipartite graph. The G has
    Pn-kernel for all n2.

13
Cycle lengths and path kernels
  • If G is graph with g(G)n-2, then G has Pn-kernel
  • Let G be a graph with ?(G)ab, ab. If g(G)a-1,
    then G is (a,b)-partitionable
  • Let G be a graph with ?(G)ab, ab. If c(G)a1,
    then G is (a,b)-partitionable

14
Absent of Pn-kernels for big values of n
  • Thomassen
  • Exists graph, that dont have a P364-kernel
  • P.K.(2005)
  • For every n364 exists graph, that dont have
    a Pn-kernel

15
Algorithm to find Pn-semikernel for small values
of n
  • Let SHi, where i is smallest integer such that
    Hi is a subgraph of G.
  • Algorithm
  • Initially we let BV(G)-S and A?.
  • Identify all P8 terminal vertices of S and move
    all their B-neighbours to A. If N(S) n B is
    empty, then stop, else 2.
  • If two vertices x and y in S have a common
    B-neighbour, then move one common B-neighbour of
    x and y to S and return to 1.
  • If some P7-terminal vertex x of S has a
    B-neighbour, then move one B-neighbour of x to S
    and return to 1, else 4.
  • 5 6
  • If some P3-terminal vertex x of S has a
    B-neighbour, then move one B-neighbour of x to S
    and return to 1, else 2.

16
Sequence of graphs Hi for n7
H1
H2
H3
H4
H5
Príklad
H6
H7
H8
H9
17
Summary of conjecture status
  • Conjuncture about kernels is true for every n 9
    a is false for every n 360
  • If G is graph with ?(G)17, then G is
  • ?-partitionable

18
  • Thanks for your attention.
Write a Comment
User Comments (0)
About PowerShow.com