3.7 Perpendicular Lines in the Coordinate Plane

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3.7 Perpendicular Lines in the Coordinate Plane

• Geometry
• Mrs. Spitz
• Fall 2005

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Standard/Objectives

• Standard 3 Students will learn and apply
  geometric concepts.
• Objectives
• Use slope to identify perpendicular lines in a
  coordinate plane
• Write equations of perpendicular lines.

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Assignment

• Pp. 175-177 7-45 and 47-50

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Postulate 18 Slopes of Perpendicular Lines

• In a coordinate plane, two non-vertical lines are
  perpendicular if and only if the product of their
  slopes is -1.
• Vertical and horizontal lines are perpendicular

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Ex. 1 Deciding whether lines are perpendicular

• Find each slope.
• Slope of j1
• 3-1 - 2
• 1-3 3
• Slope of j2
• 3-(-3) 6 3
• 0-(-4) 4 2
• Multiply the two slopes. The product of
• -2 3 -1, so j1 ? j2
• 3 2

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Ex.2 Deciding whether lines are perpendicular

• Decide whether AC and DB are perpendicular.
• Solution
• Slope of AC
• 2-(-4) 6 2
• 4 1 3
• Slope of DB
• 2-(-1) 3 1
• -1 5 -6 -2

The product of 2(-1/2) -1 so AC?DB
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Ex.3 Deciding whether lines are perpendicular

• Line h y ¾ x 2
• The slope of line h is ¾.
• Line j y-4/3 x 3
• The slope of line j is -4/3.
• The product of ¾ and -4/3 is -1, so the lines are
  perpendicular.

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Ex.4 Deciding whether lines are perpendicular

• Line r 4x5y2
• 4x 5y 2
• 5y -4x 2
• y -4/5 x 2/5
• Slope of line r is -4/5

• Line s 5x 4y 3
• 5x 4y 3
• 4y -5x 3
• y -5/4 x 3/5
• Slope of line s is -4/5

The product of the slopes is NOT -1 so r and s
are NOT perpendicular.
-4 -5 1 5 4
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Ex. 5 Writing the equation of a perpendicular
line.

• Line l1 has an equation of y -2x 1. Find the
  equation of a line l2 that passes through P(4, 0)
  and is perpendicular to l1. First you must find
  the slope, m2.

• m1 m2 -1
• -2 m2 -1
• m2 ½
• Then use m ½ and (x, y) (4, 0) to find b.
• y mx b
• 0 ½(4) b
• 0 2 b
• -2 b
• So, an equation of l2 is
• y ½ x - 2

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Ex. 6 Writing the equation of a perpendicular
line

• The equation y 3/2 x 3 represents a mirror.
  A ray of light hits the mirror at (-2, 0). What
  is the equation of the line p that is
  perpendicular to the mirror at this point?

• The mirrors slope is 3/2, so the slope of p is
  -2/3. Use m
• -2/3 and (x, y) (-2, 0) to find b.
• 0 -2/3(-2) b
• 0 4/3 b
• -4/3 b
• So, an equation for p is
• y -2/3 x 4/3

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Coming Attractions

• Chapter 3 Review pp.180-182 1-24.
• Chapter 3 Exam
• Chapter 4 Vocabulary
• Chapter 4 Postulates/ Theorems