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PROBLEM 7

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Assume activity equals molality. We need to use the KSP for calcite to solve this problem. ... of carbon dioxide in water at 25 C. If the dissolved CO2 concentration ... – PowerPoint PPT presentation

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Title: PROBLEM 7


1
PROBLEM 7
  • If a water is in equilibrium with calcite at 25
    C, what is the calcium concentration in mg L-1
    if the CO32- is 5 mg L-1? Assume activity equals
    molality.
  • We need to use the KSP for calcite to solve this
    problem.

2
  • We also need to convert mg L-1 CO32- to mol L-1.
  • (1 g/1000 mg)(5 mg L-1)/(60.01 g mol-1)
    8.33?10-5
  • aCa2 5.13?10-5 mol L-1
  • (5.13?10-5 mol L-1)(40.078 g mol-1)(1000 mg/1 g)
    2.05 mg L-1

3
Problem 8
  • Calculate the solubility product for the
    dissolution of carbon dioxide in water at 25 C.
    If the dissolved CO2 concentration in a lake at
    the same temperature is 2.2 mg L-1, is the lake
    in equilibrium with atmospheric CO2 (partial
    pressure 10-3.5)? If not, it the gas
    volatilizing from the lake or dissolving into it?

4
  • The reaction of interest is as follows
  • CO2(g) H2O(l) ? H2CO30
  • Here we must realize that CO2(aq) and H2CO30 are
    essentially the same species.
  • ?rG? ?fG?(H2CO30) - ?fG?(CO2) - ?fG?(H2O)
  • ?rG? -623.2 (-394.4) (-237.1) 8.3 kJ mol-1

5
  • Assuming that aH2O ? 1, activity coefficients are
    equal to unity, and for CO2(g), aCO2 ? PCO2, we
    write
  • Now we must convert mg L-1 CO2(aq) to mol L-1.
  • (2.2 mg L-1 CO2)(1 g/1000 mg)/(44.01 g mol-1)
    5.0?10-5 mol L-1

6
  • PCO2 1.41?10-3 atm 10-2.85
  • No the lake water is not in equilibrium with
    atmospheric CO2. The partial pressure of CO2 in
    the lake is greater than that in the atmosphere,
    so CO2 will bubble out of the lake.
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