Title: CP Projectile Test Answers
1CP Projectile Test Answers
- 1. Which of the following best represents a graph
of horizontal position as a function of time for
balls launched horizontally in the positive x
direction?
x
t
Constant forward velocity
2CP Projectile Test Answers
- 1. Which of the following best represents a graph
of horizontal position as a function of time for
balls launched horizontally in the positive x
direction?
x
t
Constant forward velocity
3CP Projectile Test Answers
- 1. Which of the following best represents a graph
of horizontal position as a function of time for
balls launched horizontally in the positive x
direction?
x
t
Constant forward velocity
4CP Projectile Test Answers
- Which of the following best represents a graph of
vertical position as a function of time for balls
launched horizontally?
y
t
Increasing downward velocity
5CP Projectile Test Answers
- Which of the following best represents a graph of
vertical position as a function of time for balls
launched horizontally?
y
t
Increasing downward velocity
6CP Projectile Test Answers
- Which of the following best represents a graph of
vertical position as a function of time for balls
launched horizontally?
y
t
Increasing downward velocity
7CP Projectile Test Answers
- 3. Which of the following graphs best
represents the horizontal velocities vs time for
balls launched horizontally?
0 m/s
Time
Constant Forward Velocity
8CP Projectile Test Answers
- 3. Which of the following graphs best
represents the horizontal velocities vs time for
balls launched horizontally?
0 m/s
Time
Constant Forward Velocity
9CP Projectile Test Answers
- 3. Which of the following graphs best
represents the horizontal velocities vs time for
balls launched horizontally?
0 m/s
Time
Constant Forward Velocity
10CP Projectile Test Answers
- 4. Which of the following graphs best
represents the vertical velocities vs time for
balls launched horizontally?
0 m/s
Time
Increasing downward velocity
11CP Projectile Test Answers
- 4. Which of the following graphs best
represents the vertical velocities vs time for
balls launched horizontally?
0 m/s
Time
Increasing downward velocity
12CP Projectile Test Answers
- 4. Which of the following graphs best
represents the vertical velocities vs time for
balls launched horizontally?
0 m/s
Time
Increasing downward velocity
13CP Projectile Test Answers
- 5. Which of the following graphs best
represents the horizontal acceleration vs time
for balls launched horizontally?
0 m/s2
Time
Constant forward Velocity
14CP Projectile Test Answers
- 5. Which of the following graphs best
represents the horizontal acceleration vs time
for balls launched horizontally?
0 m/s2
Time
Constant forward Velocity
15CP Projectile Test Answers
- 5. Which of the following graphs best
represents the horizontal acceleration vs time
for balls launched horizontally?
0 m/s2
Time
Constant forward Velocity
16CP Projectile Test Answers
- 6. Which of the following graphs best
represents the vertical acceleration vs time for
balls launched horizontally?
0 m/s2
Time
Constant downward acceleration equal to 9.8 m/s2
17CP Projectile Test Answers
- 6. Which of the following graphs best
represents the vertical acceleration vs time for
balls launched horizontally?
0 m/s2
Time
Constant downward acceleration equal to 9.8 m/s2
18CP Projectile Test Answers
- 6. Which of the following graphs best
represents the vertical acceleration vs time for
balls launched horizontally?
0 m/s2
Time
Constant downward acceleration equal to 9.8 m/s2
19CP Projectile Test Answers
- 7. An Olympic athlete throws a javelin at five
different angles above the horizontal, each with
the same speed 20o 30 o 50 o 600 70 o Which
two throws cause the javelin to land the same
distance away? - a)Â Â Â Â Â 20 o and 70 o
- b)Â Â Â Â Â 30 o and 60 o
- c)Â Â Â Â Â 20 o and 50 o
- d)Â Â Â Â Â 50 o and 70 o
- 8. Why? Projectiles fired at
complementary angles produce the same horizontal
range check - projectile lab 2 results.
20CP Projectile Test Answers
- 7. An Olympic athlete throws a javelin at five
different angles above the horizontal, each with
the same speed 20o 30 o 50 o 600 70 o Which
two throws cause the javelin to land the same
distance away? - a)Â Â Â Â Â 20 o and 70 o
- b)Â Â Â Â Â 30 o and 60 o
- c)Â Â Â Â Â 20 o and 50 o
- d)Â Â Â Â Â 50 o and 70 o
- 8. Why? Projectiles fired at
complementary angles produce the same horizontal
range check - projectile lab 2 results.
21CP Projectile Test Answers
- 7. An Olympic athlete throws a javelin at five
different angles above the horizontal, each with
the same speed 20o 30 o 50 o 600 70 o Which
two throws cause the javelin to land the same
distance away? - a)Â Â Â Â Â 20 o and 70 o
- b)Â Â Â Â Â 30 o and 60 o
- c)Â Â Â Â Â 20 o and 50 o
- d)Â Â Â Â Â 50 o and 70 o
- 8. Why? Projectiles fired at
complementary angles produce the same horizontal
range check - projectile lab 2 results.
22CP Projectile Test Answers
- 9. A projectile is fired at 30 degrees above
the horizon. Which statement is true of the - y component of its velocity
- a) it is greater than the x component of its
velocity - b) it is less than the x component of its
velocity - c) it is equal to the x component of its
velocity - d) its y component of its velocity is -9.8 m/s2
- 10. Why Any launch angle less than 45o
produces greater initial horizontal launch
velocities. - Any launch angle greater than 45o produces
greater vertical launch velocities.
23CP Projectile Test Answers
- 9. A projectile is fired at 30 degrees above
the horizon. Which statement is true of the - y component of its velocity
- a) it is greater than the x component of its
velocity - b) it is less than the x component of its
velocity - c) it is equal to the x component of its
velocity - d) its y component of its velocity is -9.8 m/s2
- 10. Why Any launch angle less than 45o
produces greater initial horizontal launch
velocities. - Any launch angle greater than 45o produces
greater vertical launch velocities.
24CP Projectile Test Answers
- 9. A projectile is fired at 30 degrees above
the horizon. Which statement is true of the - y component of its velocity
- a) it is greater than the x component of its
velocity - b) it is less than the x component of its
velocity - c) it is equal to the x component of its
velocity - d) its y component of its velocity is -9.8 m/s2
- 10. Why Any launch angle less than 45o
produces greater initial horizontal launch
velocities. - Any launch angle greater than 45o produces
greater vertical launch velocities.
25CP Projectile Test Answers
- 11. Which of the following will have the
greatest time of flight when fired from the - ground to the ground?
- a) A projectile fired at 100 m/s at 25o degrees
- b) A projectile fired at 100 m/s at 35o degrees
- c) A projectile fired at 100 m/s at 45o degrees
- d) A projectile fired at 100 m/s at 55o degrees
- 12. Why? The higher the launch angle the longer
the time of flight.The higher the launch angle
the longer it takes the projectile to achieve
zero vertical velocity at the projectiles maximum
height
26CP Projectile Test Answers
- 11. Which of the following will have the
greatest time of flight when fired from the - ground to the ground?
- a) A projectile fired at 100 m/s at 25o degrees
- b) A projectile fired at 100 m/s at 35o degrees
- c) A projectile fired at 100 m/s at 45o degrees
- d) A projectile fired at 100 m/s at 55o degrees
- 12. Why? The higher the launch angle the longer
the time of flight.The higher the launch angle
the longer it takes the projectile to achieve
zero vertical velocity at the projectiles maximum
height
27CP Projectile Test Answers
- 13. Which of the following will travel the
greatest horizontal distance when fired from the - ground to the ground?
- a) A projectile fired at 100 m/s at 10o degrees
- b) A projectile fired at 100 m/s at 20o degrees
- c) A projectile fired at 100 m/s at 50o degrees
- d) A projectile fired at 100 m/s at 70o degrees
- e) A projectile fired at 100 m/s at 80o degrees
- 14. Why? A 45 degree launch angle results in the
greatest horizontal distance. A 500 launch angle
is the closest to 450 of the choices listed.
28CP Projectile Test Answers
- 13. Which of the following will travel the
greatest horizontal distance when fired from the - ground to the ground?
- a) A projectile fired at 100 m/s at 10o degrees
- b) A projectile fired at 100 m/s at 20o degrees
- c) A projectile fired at 100 m/s at 50o degrees
- d) A projectile fired at 100 m/s at 70o degrees
- e) A projectile fired at 100 m/s at 80o degrees
- 14. Why? A 45 degree launch angle results in the
greatest horizontal distance. A 500 launch angle
is the closest to 450 of the choices listed.
29CP Projectile Test Answers
- 13. Which of the following will travel the
greatest horizontal distance when fired from the - ground to the ground?
- a) A projectile fired at 100 m/s at 10o degrees
- b) A projectile fired at 100 m/s at 20o degrees
- c) A projectile fired at 100 m/s at 50o degrees
- d) A projectile fired at 100 m/s at 70o degrees
- e) A projectile fired at 100 m/s at 80o degrees
- 14. Why? A 45 degree launch angle results in the
greatest horizontal distance. A 500 launch angle
is the closest to 450 of the choices listed.
30CP Projectile Test Answers
- 15. A projectile is fired at 45 degrees above
the horizon. Which statement is true of the y
component of its acceleration - the y component of its acceleration at its
maximum height is 0 m/s2 - b) the y component of its acceleration
initially is 9.8 m/s2 sin 450 - the y component of its acceleration initially
is -9.8 m/s2 sin 450 - d) the y component of its acceleration at
its maximum height is -9.8 m/s2 - 16. Why? The y component of the acceleration
due to gravity is a constant -9.8m/s2 regardless
of the y position of the projectile. It is
-9.8m/s2 on a projectiles way up, at itsmaximum
height and on its way down.
31CP Projectile Test Answers
- 15. A projectile is fired at 45 degrees above
the horizon. Which statement is true of the y
component of its acceleration - the y component of its acceleration at its
maximum height is 0 m/s2 - b) the y component of its acceleration
initially is 9.8 m/s2 sin 450 - the y component of its acceleration initially
is -9.8 m/s2 sin 450 - d) the y component of its acceleration at
its maximum height is -9.8 m/s2 - 16. Why? The y component of the acceleration
due to gravity is a constant -9.8m/s2 regardless
of the y position of the projectile. It is
-9.8m/s2 on a projectiles way up, at itsmaximum
height and on its way down.
32CP Projectile Test Answers
- 15. A projectile is fired at 45 degrees above
the horizon. Which statement is true of the y
component of its acceleration - the y component of its acceleration at its
maximum height is 0 m/s2 - b) the y component of its acceleration
initially is 9.8 m/s2 sin 450 - the y component of its acceleration initially
is -9.8 m/s2 sin 450 - d) the y component of its acceleration at
its maximum height is -9.8 m/s2 - 16. Why? The y component of the acceleration
due to gravity is a constant -9.8m/s2 regardless
of the y position of the projectile. It is
-9.8m/s2 on a projectiles way up, at itsmaximum
height and on its way down.
33CP Projectile Test Answers
- 17 . You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity - it had on your first throw, its time of
flight will be - 1.4 times as much.
- half as much.
- twice as much. vfyviy gt tvfy-viy
t related to vi -
g - d) Four times as much
- e. the same
34CP Projectile Test Answers
- 17 . You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity - it had on your first throw, its time of
flight will be - 1.4 times as much.
- half as much.
- twice as much. vfyviy gt tvfy-viy
t related to vi -
g - d) Four times as much
- e. the same
35CP Projectile Test Answers
- 17 . You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity - it had on your first throw, its time of
flight will be - 1.4 times as much.
- half as much.
- twice as much. vfyviy gt tvfy-viy
t related to vi -
g - d) Four times as much
- e. the same
36CP Projectile Test Answers
- 17 . You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity - it had on your first throw, its time of
flight will be - 1.4 times as much.
- half as much.
- twice as much. vfyviy gt tvfy-viy
t related to vi -
g - d) Four times as much
- e. the same
37CP Projectile Test Answers
- 17 . You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity - it had on your first throw, its time of
flight will be - 1.4 times as much.
- half as much.
- twice as much. vfyviy gt tvfy-viy
t related to vi -
g - d) Four times as much
- e. the same
38CP Projectile Test Answers
- 18. You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity it had on your first throw, the
maximum height it will achieve is - a. 1.4 times as much.
- b. half as much.
- c. twice as much.
- d. four times as much The ball will be in the
air for twice as long and it will travel twice as
fast initially. twice the time at twice the
speed. - e. the same
39CP Projectile Test Answers
- 18. You are throwing a ball for the second
time. If the ball leaves your hand with twice
the velocity it had on your first throw, the
maximum height it will achieve is - a. 1.4 times as much.
- b. half as much.
- c. twice as much.
- d. four times as much The ball will be in the
air for twice as long and it will travel twice as
fast initially. twice the time at twice the
speed. - e. the same
40CP Projectile Test Answers
- 19. You are throwing a ball for the second time.
If the ball leaves your hand with twice the
velocity - it had on your first throw, the vertical velocity
at the maximum height will be - a. 1.4 times as much.
- b. half as much.
- c. twice as much.
- d. four times as much
- e. the same All projectiles at their maximum
height will have a vertical velocity of 0 m/s
41CP Projectile Test Answers
- 19. You are throwing a ball for the second time.
If the ball leaves your hand with twice the
velocity - it had on your first throw, the vertical velocity
at the maximum height will be - a. 1.4 times as much.
- b. half as much.
- c. twice as much.
- d. four times as much
- e. the same All projectiles at their maximum
height will have a vertical velocity of 0 m/s
42CP Projectile Test Answers
- 19. You are throwing a ball for the second time.
If the ball leaves your hand with twice the
velocity - it had on your first throw, the vertical velocity
at the maximum height will be - a. 1.4 times as much.
- b. half as much.
- c. twice as much.
- d. four times as much
- e. the same All projectiles at their maximum
height will have a vertical velocity of 0 m/s
43CP Projectile Test Answers
- 20. Projectiles that are fired down at 10
degrees below the horizon will have - a higher y velocity when they hit the ground when
compared to projectile fired up at 10 degrees
above the horizon at the same speed - a lower y velocity when they hit the ground when
compared to a projectile fired up at 10 degrees
above the horizon at the same speed - c) the same y velocity when they hit the
ground when compared to a projectile fired up at
10 degrees above the horizon at the same speed. - d) have a velocity that could be higher or
lower when compared to a projectile fired up at
10 degrees above the horizon depending on the
whether the initial velocities are above 10 m/s
or below 10 m/s.
44CP Projectile Test Answers
- 20. Projectiles that are fired down at 10
degrees below the horizon will have - a higher y velocity when they hit the ground when
compared to projectile fired up at 10 degrees
above the horizon at the same speed - a lower y velocity when they hit the ground when
compared to a projectile fired up at 10 degrees
above the horizon at the same speed - c) the same y velocity when they hit the
ground when compared to a projectile fired up at
10 degrees above the horizon at the same speed. - d) have a velocity that could be higher or
lower when compared to a projectile fired up at
10 degrees above the horizon depending on the
whether the initial velocities are above 10 m/s
or below 10 m/s.
45CP Projectile Test Answers
- The projectile fired up at 10 m/s 10o above the
horizon will eventually become a 10 m/s
projectile fired down
Fired up becomes Fired down.
Fired down
46CP Projectile Test Answers
- The projectile fired up at 10 m/s 10o above the
horizon will eventually become a 10 m/s
projectile fired down
Fired up becomes Fired down.
Fired down
47CP Projectile Test Answers
- The projectile fired up at 10 m/s 10o above the
horizon will eventually become a 10 m/s
projectile fired down
Fired up becomes Fired down.
Fired down
48Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
49Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
50Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
51Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
52Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
53Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
54Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
55Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
56Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
57Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
58Projectile Test-time of flight for yi1.20m and
yf0m a) What is the time of flight of the
dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) -
t .49s
59Projectile Test-a) What is the time of flight of
the dropped ball?
- Given Find FRS
- g - 9.8 m/s2 t?s yf yi
viyt ½ gt2 - viy0m/s yf yi ½ gt2
- yi1.20 m yf - yi ½ gt2
- yf0m yf - yi t2
- ½ g
-
yf - yi t 0m-1.20m - ½ g ½
(-9.8m/s2) - a)
t .49s
60Projectile Test-time of flight for yi1.20m and
yf0m
- b) What is the time of flight for the ball fired
at 10 m/s horizontally? - The time of flight for the horizonatally
fired ball is also 0.49s. The time of flight is
independent of the horizontal velocity.
61Projectile Test-time of flight for yi1.20m and
yf0m
- b) What is the time of flight for the ball fired
at 10 m/s horizontally? - The time of flight for the horizonatally
fired ball is also 0.49s. The time of flight is
independent of the horizontal velocity.
62Projectile Test-time of flight for yi1.20m and
yf0m
- b) What is the time of flight for the ball fired
at 10 m/s horizontally? - The time of flight for the horizonatally
fired ball is also 0.49s. The time of flight is
independent of the horizontal velocity.
63Projectile Test-time of flight for yi1.20m and
yf0m
- c) What is the horizontal distance of the ball
fired at 10m/s? - c) vixvx Dx t vx Dx .49 s (10
m/s) 4.9 m - t
64Projectile Test-time of flight for yi1.20m and
yf0m
- c) What is the horizontal distance of the ball
fired at 10m/s? - c) vixvx Dx t vx Dx .49 s (10
m/s) 4.9 m - t
65Projectile Test-time of flight for yi1.20m and
yf0m
- c) What is the horizontal distance of the ball
fired at 10m/s? - c) vixvx Dx t vx Dx .49 s (10
m/s) 4.9 m - t
66Projectile Test-time of flight for yi1.20m and
yf0m
- c) What is the horizontal distance of the ball
fired at 10m/s? - c) vixvx Dx t vx Dx .49 s (10
m/s) 4.9 m - t
67Projectile Test-time of flight for yi1.20m and
yf0m
- c) What is the horizontal distance of the ball
fired at 10m/s? - c) vixvx Dx t vx Dx .49 s (10
m/s) 4.9 m - t
68Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2 yf 1.20
m 0 m/s (.25s) ½ (-9.8m/s2)(.25s)2 .31 m
69Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2 yf 1.20
m 0 m/s (.25s) ½ (-9.8m/s2)(.25s)2 .31 m
70Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2 yf 1.20
m 0 m/s (.25s) ½ (-9.8m/s2)(.25s)2 .31 m
71Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2 yf 1.20
m 0 m/s (.25s) ½ (-9.8m/s2)(.25s)2 .31 m
72Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2 yf 1.20
m 0 m/s (.25s) ½ (-9.8m/s2)(.25s)2 .31 m
73Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2
- yf 1.20 m 0 m/s (.25s) ½
(-9.8m/s2)(.25s)2 .31 m
74Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2
- yf 1.20 m 0 m/s (.25s) ½
(-9.8m/s2)(.25s)2 .31 m
75Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2
- yf 1.20 m 0 m/s (.25s) ½
(-9.8m/s2)(.25s)2 .31 m
76Projectile Test-time of flight for yi1.20m and
yf0m
- d) What is the horizontal and vertical positions
of the ball fired 10 m/s horizontally .25 seconds
into its flight? - vixvx Dx t vx Dx .25 s (10 m/s)
2.5 m - t
- yf yi viyt ½ gt2
- yf 1.20 m 0 m/s (.25s) ½
(-9.8m/s2)(.25s)2 .31 m
77Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
78Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
79Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
80Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
81Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
82Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
83Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
84Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
85Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
86Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
87Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
88Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
89Projectile Test Answers
- Givens
- yo .25 m
- y.98m
- vo 10.0 m/s f 650
- g - 9.8 m/s2
- vfy0m/s
- a) vox vocos f 10.0 m/s cos 65o 4.23 m/s
- b) voy vosin f 10.0 m/s sin 65o 9.06 m/s
90Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
91Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
92Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
93Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
94Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
95Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
96Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
97Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
98Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
99Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
100Projectile Test Answers
- c) Given
- yo .25 m
- y.98m
- vo 10.0 m/s
- f 650
- g - 9.8 m/s2
- vfy0m/s
- vfyviy gt tvfy-viy 0 m/s 9.06
m/s .92seconds - g 9.8m/s2
101Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
102Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
103Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
104Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
105Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
106Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
107Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
108Projectile Test Answers
- Determine the maximum height achieved by the
ball. - d) yf yi viyt ½ gt2
- yf .25m 10 m/s (.92s) ½ (-9.8m/s2)(.92s)2
5.25m -
- Determine the horizontal position of the ball at
the maximum height. - e) vixvx Dx t vx Dx .92 s (10
m/s) 9.2 m - t
109Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
110Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
111Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
112Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
113Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
114Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
115Projectile Test Answers
- f) Determine the total time of flight from the
.25 m vertical launch position to the .98 m
vertical landing position. - y yo vosin f t ½ g t2
- .98 .25m 10m/s sin(650) t ½ (-9.8 m/s2)
(t)2 - Â
- 0 -.73 m 9.06 m/s ( t ) ½ (-9.8 m/s2) (t)2
- Â
- A -4.9 B 9.06 C -.73 m
- Â
- Using the quadratic equation t .0844s (way up
) and 1.76s (way down)
116Projectile Test Answers
- g) Determine the horizontal landing position of
the ball. - vox Dx
- t
- Â
- t vox Dx 1.76s (4.23 m/s ) 7.44m
117Projectile Test Answers
- g) Determine the horizontal landing position of
the ball. - vix Dx
- t
- Â
- t vox Dx 1.76s (4.23 m/s ) 7.44m
118Projectile Test Answers
- g) Determine the horizontal landing position of
the ball. - vix Dx
- t
- Â
- t vox Dx 1.76s (4.23 m/s ) 7.44m
119Projectile Test Answers
- g) Determine the horizontal landing position of
the ball. - vix Dx
- t
- Â
- t vox Dx 1.76s (4.23 m/s ) 7.44m
120Projectile Test Answers
- g) Determine the horizontal landing position of
the ball. - vix Dx
- t
- Â
- t vox Dx 1.76s (4.23 m/s ) 7.44m
121Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
122Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
123Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
124Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
125Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
126Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0
127Projectile Test Answers
- Determine the angle of the ball as it lands in
the can. (extra credit) - vfyviy gt
- vfy 9.06 m/s (-9.8m/s2) (1.76s)
- vfy-8.19 m/s
- vx4.23 m/s
- Inv tan ( vfy/vx) angle with respect to the
horizon - Inv tan ( -8.19 m/s / 4.23 m/s ) 62.7 0