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8.1 Ratio and Proportion

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Use proportions to solve real-life problems, such as computing the width of a painting. ... 2: Using Ratios ... Divide each side by 10. So, ABCD has a length of ... – PowerPoint PPT presentation

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Title: 8.1 Ratio and Proportion


1
8.1 Ratio and Proportion
  • Geometry
  • Mrs. Spitz
  • Spring 2005

2
Objectives/Assignment
  • Find and simplify the ratio of two numbers.
  • Use proportions to solve real-life problems, such
    as computing the width of a painting.
  • Chapter 8 Definitions
  • Ch.8 Postulates/
  • Theorems
  • Pp. 461-462 1-50 all
  • Quizzes after 8.3 and 8.5 and 8.7

3
Computing Ratios
  • If a and b are two quantities that are measured
    in the same units, then the ratio of a to be is
    a/b. The ratio of a to be can also be written as
    ab. Because a ratio is a quotient, its
    denominator cannot be zero. Ratios are usually
    expressed in simplified form. For instance, the
    ratio of 68 is usually simplified to 34. (You
    divided by 2)

4
Ex. 1 Simplifying Ratios
  • Simplify the ratios
  • 12 cm b. 6 ft c. 9 in.
  • 4 cm 18 ft 18 in.

5
Ex. 1 Simplifying Ratios
  • Simplify the ratios
  • 12 cm b. 6 ft
  • 4 m 18 in
  • Solution To simplify the ratios with unlike
    units, convert to like units so that the units
    divide out. Then simplify the fraction, if
    possible.

6
Ex. 1 Simplifying Ratios
  • Simplify the ratios
  • 12 cm
  • 4 m
  • 12 cm 12 cm 12 3
  • 4 m 4100cm 400 100

7
Ex. 1 Simplifying Ratios
  • Simplify the ratios
  • b. 6 ft
  • 18 in
  • 6 ft 612 in 72 in. 4 4
  • 18 in 18 in. 18 in. 1

8
Ex. 2 Using Ratios
  • The perimeter of rectangle ABCD is 60
    centimeters. The ratio of AB BC is 32. Find
    the length and the width of the rectangle

9
Ex. 2 Using Ratios
  • SOLUTION Because the ratio of ABBC is 32, you
    can represent the length of AB as 3x and the
    width of BC as 2x.

10
Solution
  • Statement
  • 2l 2w P
  • 2(3x) 2(2x) 60
  • 6x 4x 60
  • 10x 60
  • x 6
  • Reason
  • Formula for perimeter of a rectangle
  • Substitute l, w and P
  • Multiply
  • Combine like terms
  • Divide each side by 10

So, ABCD has a length of 18 centimeters and a
width of 12 cm.
11
Ex. 3 Using Extended Ratios
  • The measures of the angles in ?JKL are in the
    extended ratio 123. Find the measures of the
    angles.
  • Begin by sketching a triangle. Then use the
    extended ratio of 123 to label the measures of
    the angles as x, 2x, and 3x.

2x
3x
x
12
Solution
  • Statement
  • x 2x 3x 180
  • 6x 180
  • x 30
  • Reason
  • Triangle Sum Theorem
  • Combine like terms
  • Divide each side by 6

So, the angle measures are 30, 2(30) 60, and
3(30) 90.
13
Ex. 4 Using Ratios
  • The ratios of the side lengths of ?DEF to the
    corresponding side lengths of ?ABC are 21. Find
    the unknown lengths.

14
Ex. 4 Using Ratios
  • SOLUTION
  • DE is twice AB and DE 8, so AB ½(8) 4
  • Use the Pythagorean Theorem to determine what
    side BC is.
  • DF is twice AC and AC 3, so DF 2(3) 6
  • EF is twice BC and BC 5, so EF 2(5) or 10

4 in
a2 b2 c2 32 42 c2 9 16 c2 25 c2 5
c
15
Using Proportions
  • An equation that equates two ratios is called a
    proportion. For instance, if the ratio of a/b is
    equal to the ratio c/d then the following
    proportion can be written

Means
Extremes
? ?
The numbers a and d are the extremes of the
proportions. The numbers b and c are the means
of the proportion.
16
Properties of proportions
  • CROSS PRODUCT PROPERTY. The product of the
    extremes equals the product of the means.
  • If
  • ? ?, then ad bc

17
Properties of proportions
  • RECIPROCAL PROPERTY. If two ratios are equal,
    then their reciprocals are also equal.
  • If ? ?, then ?

b
a
To solve the proportion, you find the value of
the variable.
18
Ex. 5 Solving Proportions
4
5
Write the original proportion. Reciprocal
prop. Multiply each side by 4 Simplify.

x
7
4
x
7
4

4
5
28
x

5
19
Ex. 5 Solving Proportions
3
2
Write the original proportion. Cross Product
prop. Distributive Property Subtract 2y from each
side.

y 2
y
3y 2(y2)
3y 2y4
y
4
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