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Problem 12

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If the diffusion coefficient in the Fick's law is uniform in ... Explain this trend in physical terms (from a particle or fluid ... frequency wc is defined ... – PowerPoint PPT presentation

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Title: Problem 12


1
Problem 12
  • Explain under what conditions a diffusion
    equation can be derived from the continuity
    equation plus a Ficks law

2
Solution Problem 12
  • The Ficks law states (for a generic species)
  • The continuity equation is

and by using Ficks law becomes
3
Solution Problem 12 (II)
  • If the diffusion coefficient in the Ficks law is
    uniform in space it can be taken outside the
    divergence operator and a diffusion equation can
    be written as

4
Problem 13
  • Determine the dimension (in MKSA) of the electron
    mobility
  • Find a relationship between the electron mobility
    and the plasma conductivity (reciprocal of the
    resistivity) for the case in which the plasma
    current is carried only by the electrons and the
    density is uniform

5
Solution Problem 13
  • The electron mobility, for a given collision
    frequency, is defined as
  • The plasma conductivity is defined as s1/h while
    the resistivity appears in the Ohms law as
  • The electron mobility was introduced from the
    fluid equation of motion as

6
Solution Problem 13 (II)
  • For a uniform density the gradient is zero and
    the mobility for the electrons will satisfy
  • While for the conductivity, considering the
    definition of current density, it can be written
  • Then

7
Problem 14
  • Write the MHD momentum equation for steady state
    and no gravitational effect.
  • A cylindrical plasma with uniform axial magnetic
    field is confined in these conditions
  • Intense heating is applied in the plasma core
    region (the inner, centered section of the plasma
    along the axis)
  • Is it possible to maintain the initial steady
    state conditions while the heating takes place?
    Explain why yes or why not (assume plasmaideal
    gas)
  • What happens to the current density j in the MHD
    momentum equation when the plasma is heated?

8
Solution Problem 14
  • The MHD momentum equation for steady state and no
    gravitational effect is
  • If the plasma temperature is being raised around
    the axis the pressure gradient will increase (the
    temperature is non uniform and will have a
    gradient)
  • To maintain the steady state the force balance
    will require to increase the magnetic field
    (improving the confinement)

9
Solution Problem 14 (II)
  • The current density (diamagnetic current) is the
    result of the BXgrad p force and will increase
    self-consistently to maintain the force balance

10
Problem 15
  • For the case of a diffusion across a magnetic
    field what happens to the perpendicular diffusion
    coefficient when the magnetic field is increased?
  • Explain this trend in physical terms (from a
    particle or fluid point of view)

11
Solution Problem 15
  • The perpendicular diffusion coefficient for a
    magnetized plasma is
  • The Larmor frequency wc is defined as

then an increase in the magnetic field reduces
the diffusion coefficient
12
Solution Problem 15 (II)
  • From the Ficks law, in general,
  • it is clear that a smaller diffusion coefficient
    reduces the flux. Therefore an increased magnetic
    field also reduces the flux across the field
    itself
  • This is equivalent to say that the increase in
    the magnetic field improves the plasma confinement

13
Problem 16
  • An electrostatic perturbation in a non-magnetized
    plasma is detected propagating at a frequency of
    10GHz. The plasma has a density of 1018 m-3 and a
    temperature of 3 eV
  • Find the wavelength associated to the perturbation

14
Solution Problem 16
  • The frequency of the oscillations is given by the
    dispersion relation

where
  • The detected frequency corresponds to an angular
    frequency

15
Solution Problem 16 (II)
  • The plasma frequency is given by

where
  • The wavenumber is found inverting the dispersion
    relation

16
Solution Problem 16 (III)
  • The wavelength is finally found from
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