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Lecture Problem 14'37

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Nylon 6,6 may be formed by means of a condensation polymerization reaction in ... For each mer unit of nylon 6,6, need one hexamethylene diamine and one adipic acid ... – PowerPoint PPT presentation

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Title: Lecture Problem 14'37


1
Lecture Problem 14.37
  • Presented by Paula Lipka

2
Problem Statement
  • Nylon 6,6 may be formed by means of a
    condensation polymerization reaction in which
    hexamethylene diamine NH2(CH2)6NH2 and adipic
    acid react with one another with the formation of
    water as a byproduct. What masses of
    hexamethylene diamine and adipic acid are
    necessary to yield 20 kg of completely linear
    nylon 6,6?

3
Adipic Acid and Hexamethylene diamine
  • Hexamethylene diamine
  • NH2(CH2)6NH2
  • MW 116.2 kg/mol
  • Adipic Acid
  • C6H8O2(OH)2
  • MW 146.2 kg/mol

4
Condensation Polymerization
  • Stepwise chemical reaction joins two units
  • Small byproduct (usually water) is released
  • Reaction time generally slower than for addition
    (free radical) polymerization
  • Products Polycarbonate, thermosetting polymers,
    phenol-formaldhyde

5
Nylon 6,6 Formation
6
Nylon 6,6 Formula and Structure
  • (NH)2(CH2)12O2

7
Solutions
  • Need 20 kg of nylon 6,6
  • How many moles of nylon are needed?
  • For each mer unit of nylon 6,6, need one
    hexamethylene diamine and one adipic acid

8
Solution Continued
  • Need 10.3 kg of hexamethylene diamine and 12.9 kg
    of adipic acid to form 20 kg of nylon 6,6
  • Where did extra 3.2 kg of material go?
  • Water!

9
Application s
  • Foundation of the synthetic fiber industry
  • Nylon Products
  • Clothing
  • Carpeting
  • Parachutes
  • Properties of Nylon
  • High Melting Point
  • Wear and UV Resistant
  • Blends easily with other fibers

10
References
  • www.pslc.ws/mactest/nylon.htm
  • www.chemheritage.org/.../NYLON/chem/make.html
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