Title: Computer Architecture
1ComputerArchitecture
- EEL 4713/5764, Spring 2006
- Dr. Michael Frank
- Module 5 Computer Performance
2Part IBackground and Motivation
3I Background and Motivation
- Provide motivation, paint the big picture,
introduce tools - Review components used in building digital
circuits - Present an overview of computer technology
- Understand the meaning of computer performance
- (or why a 2 GHz processor isnt 2? as fast as
a 1 GHz model)
Topics in This Part
Chapter 1 Combinational Digital Circuits
Chapter 2 Digital Circuits with Memory
Chapter 3 Computer System Technology
Chapter 4 Computer Performance
44 Computer Performance
- Performance is key in design decisions also cost
and power - It has been a driving force for innovation
- Isnt quite the same as speed (higher clock
rate)
Topics in This Chapter
4.1 Cost, Performance, and Cost/Performance
4.2 Defining Computer Performance
4.3 Performance Enhancement and Amdahls Law
4.4 Performance Measurement vs Modeling
4.5 Reporting Computer Performance
4.6 The Quest for Higher Performance
5Course Instructional Objective 1
- As the syllabus says
- At the completion of this course, students should
be able to - CIO 1. (Metrics) Calculate and interpret
different performance and cost metrics of
computer systems. - This CIO should also support the following
Program Outcome - Students graduating from the BSEE and BSCpE
degree programs will have - PO (a). (Apply) An ability to apply knowledge of
mathematics, science and engineering - PO (e). (Solve) An ability to identify,
formulate, and solve engineering problems - PO (o). (Topics) EE A knowledge of electrical
engineering applications selected from the
digital systems areas CpE A knowledge of
computer science and computer engineering topics
including computer architecture. - Under assessment instruments, the syllabus
says - 1. Metrics. Students will solve exam problems in
which they must analyze descriptions of
hypothetical processors to determine their
performance, cost-performance, and
power-performance.
6Module Instructional Objectives
- I break down the CIO as follows
- CIO 1. Metrics (aeo). Calculate and interpret
different performance and cost metrics of
computer systems. - 1.1. Know apply (a) the definitions of clock
frequency, MIPS, execution time, performance,
throughput, cost-performance, and
power-performance. - 1.2. Explain why a given metric is or is not
appropriate to use in a given situation. - 1.3. Identify (e.i) the specific figure(s) of
merit that are most appropriate for choosing
between alternative computer designs in a given
scenario. - 1.4. Formulate (e.ii) appropriate symbolic
equations for calculating a desired figure of
merit from the provided information about an
architectural scenario. - 1.5. Solve (e.iii) problems involving the
determination of which of several computer
designs would be preferable in a given scenario. - 1.6. Apply Amdahls Law (and generalizations
thereof) in characterizing the relationship
between an improvement to a particular component
of a system and the overall improvement of the
whole system. - 1.7. Apply (a) the CPU Performance Equation that
relates performance and execution time to
instruction count, CPI, and clock frequency.
7Topic 1
- Overview of Some Important Metrics for Computer
SystemsPerformance, Cost, and Power Consumption
8Important Performance Metrics
- Some metrics that are often used, but that do not
always accurately reflect true performance - CPU clock frequency number of CPU clock cycles
per unit time - MIPS rating How many Millions of Instructions
Per Second - Benchmark ratings (e.g., SPECmarks) more on
this later - Metrics that are true measures of performance
- Total execution time of a work unit (on real
applications) - Wall-clock time from beginning to end of the
execution process - Performance 1/(execution time)
- For a single work unit
- Throughput ( work units)/(execution time)
- A generalized kind of performance
9Cost and Cost-Related Metrics
- In the real world, the performance of a system is
not the only thing that is important - For example, its cost may also matter a lot!
- E.g., the IBM Blue Gene/L has really high
performance, but youre not likely to buy it as
your next computer - We almost always have budgetary constraints.
- The usual goal Maximize the cost-performance
(i.e., cost-efficiency) of the systems that you
buy. - Cost-performance (performance) / (cost).
- In other words, you want to get the best value
for your dollar. - This strategy roughly maximizes total throughput
within a fixed budget. - Whenever you can have many systems gathered
together working in parallel.
10Throughput and Cost-Performance
- When there is a fixed budget, the maximum
throughput of a parallel system is (roughly) ?
the cost-performance of the individual serial
units.
11The Vanishing Computer Cost
12Cost/Performance
Figure 4.1 Performance improvement as a
function of cost.
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13Importance of Power Consumption
- In the real world, a computers performance and
manufacturing cost are not the only important
concerns - Operating costs, usability, and other factors may
also be important! - Today, power consumption is an increasingly
important factor that impacts all of the
following - Manufacturing cost, operating cost, performance,
and usability! - In general, higher power consumption means
- More manufacturing cost
- for more aggressive power-delivery cooling
systems - power supplies, heat sinks, fans, etc.
- Higher operating cost
- More electricity consumed, frequent
changing/recharging of batteries, inconvenience
to user - Lower performance
- Higher performance would exceed limits of cooling
system - Poor usability / poorer overall quality of
product - Annoyingly noisy cooling fans or data center A/C
units, laptops that burn up your lap - So in many design scenarios, we may wish to
maximize performance within a fixed power budget,
or minimize power consumption to reach a desired
performance.
14Throughput and Power-Performance
- When there is a fixed power budget, the maximum
throughput of a parallel system is (roughly) ?
the power-performance of the individual serial
units. - This is exactly analogous to the earlier
cost-performance analysis.
15Performance Maximizationwithin Cost and Power
Constraints
- Suppose we have both a cost budget and a power
budget, - and we want to maximize system throughput.
- With a given unit design, we must maximize the
number of units. - Then we have the following constraints on nunits
- nunits ? Cunit Cmax
- So, nunits ? Cmax/Cunit ?
- nunits ? Punit Pmax
- and nunits ? Pmax/Punit ?
- The largest value of nunits within these
constraints is - nunits min( ? Cmax/Cunit ?, ? Pmax/Punit ? )
? min( Cmax/Cunit, Pmax/Punit) ? - and so the maximum feasible throughput is
- Ttot Tunit ? nunits Tunit ?
?min(Cmax/Cunit,Pmax/Punit)?
C cost P power T throughput
16Power-Performance and Energy Efficiency
- Power-performance means performance (i.e.,
throughput) per unit of power consumption - power-performance (throughput)/(power).
- Of course, since
- throughput (work units)/(time) and
- power (energy consumed)/(time),
- The times cancel, and so power-performance is
equal to - (work units)/(energy consumed)
- In other words, system power-performance is the
same thing as the energy efficiency of the
underlying computing process. - To maximize power-performance, minimize the
amount of energy that is consumed per unit of
work that is performed.
17System Optimization Example
- Suppose you have a budget of 1M to set up a new
corporate data center that should have a total
power consumption of no more than 100kW while
serving web transactions in a simple database
application. If your goal is to maximize total
performance (in transactions/second) while
staying within your budget and meeting the power
constraint, which of the following types of
machines would be preferable as a basis for the
design? - Sun servers, each 15,000, burning 100W,
processing 100 transactions/second - Playstation 2s, each 100 from flea market, 30W,
processing 30 transactions/second - Solution
- A PS2-based design could attain 50? higher
throughput and use only 1/3 of the budget while
still meeting the power constraints!
18Topic 2
- Measuring Computer Performance
194.2 Defining Computer Performance
Figure 4.2 Pipeline analogy shows that
imbalance between processing power and I/O
capabilities leads to a performance bottleneck.
20Concepts of Performance and Speedup
- Performance 1 / Execution time
is simplified to - Performance 1 / CPU execution time
- (Performance of M1) / (Performance of M2)
Speedup of M1 over M2 - (Execution time on M2) / (Execution time
on M1) - Terminology M1 is x times as fast as M2 (e.g.,
1.5 times as fast) - M1 is 100(x 1) faster than M2 (e.g., 50
faster) - CPU time (Clock cycles executed) ? (Time per
cycle) - Instructions ? (Cycles per instruction)
? (Time per cycle) - Instructions ? CPI / (Clock frequency)
- Instruction count, CPI, and clock rate are not
completely independent, so improving one by a
given factor may not lead to overall execution
time improvement by the same factor.
CPU performance equation
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21Faster Clock ? Shorter Running Time
Figure 4.3 Faster steps do not necessarily
mean shorter travel time.
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224.3 Performance Enhancement Amdahls Law
f fraction unaffected p speedup
of the rest
Figure 4.4 Amdahls law speedup achieved if
a fraction f of a task is unaffected and the
remaining (1f) part runs p times as fast.
23Amdahls Law Used in Design
Example 4.1
- A processor spends 30 of its time on flp
addition, 25 on flp mult, - and 10 on flp division. Evaluate the following
enhancements, each - costing the same to implement
- Redesign of the flp adder to make it twice as
fast. - Redesign of the flp multiplier to make it three
times as fast. - Redesign the flp divider to make it 10 times as
fast. - Solution
- Adder redesign speedup 1 / 0.7 0.3 / 2
1.18 - Multiplier redesign speedup 1 / 0.75 0.25 /
3 1.20 - Divider redesign speedup 1 / 0.9 0.1 / 10
1.10 - What if both the adder and the multiplier are
redesigned?
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244.4 Performance Measurement vs. Modeling
Figure 4.5 Running times of six programs on
three machines.
25Performance Benchmarks
Example 4.3
- You are an engineer at Outtel, a start-up
aspiring to compete with Intel - via its new processor design that outperforms the
latest Intel processor - by a factor of 2.5 on floating-point
instructions. This level of performance - was achieved by design compromises that led to a
20 increase in the - execution time of all other instructions. You are
in charge of choosing - benchmarks that would showcase Outtels
performance edge. - What is the minimum required fraction f of time
spent on floating-point instructions in a program
on the Intel processor to show a speedup of 2 or
better for Outtel? - Solution
- We use a generalized form of Amdahls formula in
which a fraction f is speeded up by a given
factor (2.5) and the rest is slowed down by
another factor (1.2) 1 / 1.2(1 f) f /
2.5 ? 2 ? f ? 0.875
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26Performance Estimation
Average CPI ?All instruction classes (Class-i
fraction) ? (Class-i CPI) Machine cycle time
1 / Clock rate CPU execution time
Instructions ? (Average CPI) / (Clock rate)
Table 4.3 Usage frequency, in percentage, for
various instruction classes in four
representative applications.
Application ? Instrn class ? Data compression C language compiler Reactor simulation Atomic motion modeling
A Load/Store 25 37 32 37
B Integer 32 28 17 5
C Shift/Logic 16 13 2 1
D Float 0 0 34 42
E Branch 19 13 9 10
F All others 8 9 6 4
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27MIPS Rating Can Be Misleading
Example 4.5
- Two compilers produce machine code for a program
on a machine - with two classes of instructions. Here are the
number of instructions - Class CPI Compiler 1 Compiler 2
- A 1 600M 400M
- B 2 400M 400M
- What are run times of the two programs with a 1
GHz clock? - Which compiler produces faster code and by what
factor? - Which compilers output runs at a higher MIPS
rate? - Solution
- Running time 1 (2) (600M ? 1 400M ? 2) / 109
1.4 s (1.2 s) - b. Compiler 2s output runs 1.4 / 1.2 1.17
times as fast - c. MIPS rating 1, CPI 1.4 (2, CPI 1.5) 1000
/ 1.4 714 (667)
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284.5 Reporting Computer Performance
Table 4.4 Measured or estimated execution
times for three programs.
Time on machine X Time on machine Y Speedup of Y over X
Program A 20 200 0.1
Program B 1000 100 10.0
Program C 1500 150 10.0
All 3 progs 2520 450 5.6
Analogy If a car is driven to a city 100 km away
at 100 km/hr and returns at 50 km/hr, the average
speed is not (100 50) / 2 but is obtained from
the fact that it travels 200 km in 3 hours.
29Comparing the Overall Performance
Table 4.4 Measured or estimated execution
times for three programs.
Time on machine X Time on machine Y Speedup of Y over X
Program A 20 200 0.1
Program B 1000 100 10.0
Program C 1500 150 10.0
Speedup of X over Y
10 0.1 0.1
Arithmetic mean
6.7
3.4
Geometric mean
2.15
0.46
Geometric mean does not yield a measure of
overall speedup, but provides an indicator that
at least moves in the right direction
304.6 The Quest for Higher Performance
State of available computing power ca. the early
2000s Gigaflops on the desktop Teraflops in
the supercomputer center Petaflops on the
drawing board Note on terminology (see Table
3.1) Prefixes for large units Kilo 103,
Mega 106, Giga 109, Tera 1012, Peta
1015 For memory K 210 1024, M 220,
G 230, T 240, P 250 Prefixes for small
units micro 10-6, nano 10-9, pico
10-12, femto 10-15
31Supercom-puters
Figure 4.7 Exponential growth of
supercomputer performance.
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32The Most Powerful Computers
Figure 4.8 Milestones in the DOEs
Accelerated Strategic Computing Initiative (ASCI)
program with extrapolation up to the PFLOPS
level.
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33Performance is Important, But It Isnt Everything
Figure 25.1 Trend in energy consumption per
MIPS of computational power in general-purpose
processors and DSPs.
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34Computer Architecture Lecture Notes Spring
2005Dr. Michael P. Frank
- Competency Area 2
- Performance Metrics
- Lecture 1
35Performance Metrics
- Why is it necessary for us to study performance?
- Performance is usually the key to the
effectiveness of a system (hardware software). - Performance is critical to customers
(purchasers), thus, we as designers and
architects must also make it a priority. - Performance must be assessed and understood in
order for a system to communicate efficiently
with peripheral devices.
36Topic Computer Performance
- Sub-Topic Airplane Analogy
37Performance Metrics
- How can we determine performance?
Consider this example from the transportation
industry
38Performance Example
- Fuel Capacity in liters
- Range in kilometers
- Speed in kilometers/hour
- Throughput is defined as
- ( of passengers) x (cruising speed)
- Cost is given as
- (fuel capacity) / (passengers x range)
- Which mode of transportation has the best
performance?
39Performance Example
- It depends on how we define performance.
- Consider raw speed
- Getting from one place to another quickly
-
40Performance Example
- What if were interested in the rate at which
people are carried throughput -
41Performance Example
- Often times we relate performance and cost. Thus
we can consider the amount of fuel used per
passenger
42Topic Computer Performance
- Sub-Topic Basic Concepts Performance,
Throughput, and Execution Time
43Performance Metrics
- Similar measures of performance are used for
computers. - Number of computations done per unit of time
- Cost of computations
- Possibly several aspects of cost can be
considered including initial purchase price,
operating cost, cost of training users of system,
etc. - Common performance measures are
- RESPONSE TIME the amount of time it takes a
program to complete (a.k.a execution time) - THROUGHPUT the total amount of work done in a
given amount of time
44Performance Metrics
- Example
- Given the following actions
- 1. Replacing processor with a faster version
- 2. Adding additional processors to perform
separate tasks in a multiprocessor system - do they (a) increase throughput, (a) decrease
response time or (c) both?
45Defining Performance
- Our focus will be primarily on execution time.
- To maximize performance implies a minimization in
execution time - For two machines
- We say that machine Y is faster than machine X.
46Performance Metrics
(1) If X is n times faster than Y, then
- To avoid confusion, well use the following
terminology - We say We mean
- improve performance ? increase
performance - improve execution time ? decrease execution
time
47Performance Example
If machine A runs a program in 10 seconds and
machine B runs the same program in 15 seconds,
how much faster is A than B?
48Performance Example
If machine A runs a program in 10 seconds and
machine B runs the same program in 15 seconds,
how much faster is A than B?
49Topic Computer Performance
- Sub-Topic Measuring Performance
50Measuring Performance
- Quite simply, TIME is the measure of computer
performance! - The most straightforward definition of time is
wall-clock time ? elapsed time ? response time.
Total time to complete a task including system
overhead activities such as Input/Output tasks,
disk and memory accesses, etc.
51Measuring Performance
- CPU Time is the time it takes to complete a task
excluding the time it takes for I/O waits.
CPU TIME
USER CPU TIME The time CPU is busy executing the
users code.
SYSTEM CPU TIME The time CPU spends performing
operating system tasks.
Note Sometimes system and user CPU times are
difficult to distinguish since it is hard to
assign responsibility for OS activities.
52Measuring Performance
- Example,
- To understand the concept of CPUTime, consider
the UNIX command time. Once typed, it may
return a response similar to - 90.7u 12.9s 239 65
- What do these numbers mean?
53Measuring Performance
- Example,
- To understand the concept of CPUTime, consider
the UNIX command time. Once typed, it may
return a response similar to - 90.7u 12.9s 239 65
of elapsed time that is CPU time
User CPU Time
System CPU Time
Elapsed Time
54Measuring Performance
- Example,
- To understand the concept of CPUTime, consider
the UNIX command time. Once typed, it may
return a response similar to - 90.7u 12.9s 239 65
- What is the total CPUTime?
- Percentage of time spent on I/O and other
programs?
55Measuring Performance
- Example,
- To understand the concept of CPUTime, consider
the UNIX command time. Once typed, it may
return a response similar to - 90.7u 12.9s 239 65
- What is the total CPUTime?
- Percentage of time spent on I/O and other
programs?
56Measuring Performance
- Other notes
- SYSTEM PERFORMANCE reciprocal of elapsed time
on an unloaded system (e.g. no user applications) - CPU PERFORMANCE recip. of user CPU time
- CLOCK CYCLES (CC) discrete time intervals
measured by the processor clock running at a
constant rate. - CLOCK PERIOD time it takes to complete a clock
cycle - CLOCK RATE inverse of clock period
57Measuring Performance
- Consider CPU performance
-
- Also,
-
58Measuring Performance
- Since the execution time clearly depends on the
number of instructions for a program, we must
also define another performance metric - CPI average number of clock cycles
- per instruction
59Measuring Performance
- Now we have two more equations that we can define
for CPUTime
60Measuring Performance
- In summary, performance metrics include
Components of Performance Units of Measure
CPUTime Seconds for program
IC of instructions for a program
CPI Average of clock cycles per instructions
tCC Seconds per clock cycle
61Measuring Performance
- Example,
- Suppose Machine A implements the same ISA as
Machine B. Given and - for some program, and
- and for the same program, determine
which machine is faster and by how much.
62Breakdown by Instruction Category
- Recall CPI Clock cycles (CC) per instruction
- But, CPI depends on many factors, including
- Memory system behavior
- Processor structure
- Availability special processor features
- E.g., floating point, graphics, etc.
- To characterize the effect of changing specific
aspects of the architecture, we find it helpful
to break down CC into components due to different
classes (categories) of instructions - Where
- ICi instruction count for class i
- CPIi avg. cycles for insts. in class i
- n the number of instruction classes
63Example
- Suppose a processor has 3 categories of
instructions A,B,C with the following CPIs - And, suppose a compiler designer is comparing two
code sequences for a given program that have the
following instruction counts - Determine
- (i) Which code sequence executes the most
instructions? - (ii) Which will be faster?
- (iii) What is the average CPI for each code
sequence?
Instr. Class CPIi
A 1
B 2
C 3
Code Seq. Inst. counts Inst. counts Inst. counts
Code Seq. ICA ICB ICC
1 2 1 2
2 4 1 1
64Solution to Example
- Part (i)
- ICseq1 2 1 2 5 instructions
- ICseq2 4 1 1 6 instructions
- ? Code sequence 2 executes more instructions
- Part (ii)
- CCseq1 ?i(CPIixICi) 1x2 2x1 3x2 10
cycles - CCseq2 ?i(CPIixICi) 1x4 2x1 3x1 9
cycles - ? Code sequence 2 takes fewer cycles ? is faster!
- Part (iii)
- CPIseq1 CC/ICseq1 10 cyc./5 inst. 2
- CPIseq2 CC/ICseq2 9 cyc./6 inst. 1.5
- Which part should we consult to tell us which
code sequence has better performance?
65Topic Computer Performance
- Subtopic
- Benchmarks Performance Summaries
66Importance of Benchmarks
- How do we evaluate and compare the performance of
different architectures? - We use benchmarks
- Programs that are specifically chosen to measure
performance. - A workload is a set of programs.
- Benchmarks consist of workloads that (user hopes)
will predict the performance of the actual
workload - It is important that benchmarks consist of
realistic workloads - Not simple toy programs or code fragments
- Manufacturers often try to fine-tune their
machines to do well on popular benchmarks that
were too simple - This does not always mean the machine will do
well on real programs!
67SPEC benchmark
- A popular source of benchmarks is SPEC
- Standard Performance Evaluation Corporation
- General CPU benchmarks CPU2000.
- Includes programs such as
- gzip (compression), vpr (FPGA place route), gcc
(compiler), crafty (chess), vortex (database) - SPEC also offers specialized benchmarks for
- Graphics, Parallel computing, Java, mail servers,
network fileservers, web servers - They publish reports on benchmark results for
various systems. - Main metric SPECRatio Proportional to average
inverse execution time. The bigger, the better! - Reproducibility of results is very important!
68Summarizing Performance
- How do we summarize performance in a way that
accurately compares different machines? - One common approach Total Execution Time (TET)
- Based on
- Or, if the workload includes n different
programs, we can calculate the average or
Arithmetic Mean (AM) - Smaller AM ? Improved performance
- Other methods are also used
- Weighted arithmetic mean, geometric mean ratio.
69Topic Computer Performance
- Subtopic Performance Improvementand Amdahls
Law
70Performance Improvement
- Recall the formula CPUTime IC CPI / fcyc.
- Thus, CPU performance is Perf f / (ICCPI).
- Thus we can see 3 basic ways to improve CPU
performance on a given task - Increase clock frequency
- Decrease CPI
- by improved processor organization
- Decrease instruction count
- By compiler enhancement,
- change in ISA design (new instructions), or
- A more efficient application algorithm.
- However, we have to be careful!
- Sometimes, improving one of these can hurt others!
71Generalized Cost Measures
- In this course, we will often be focusing on ways
to minimize execution time of programs. - Either CPU time, or number of clock cycles.
- Execution time is one example of what we may call
a generalized cost measure (GCM). - A GCM is any property of a HW/SW design that
tells us how much of some valued resource is used
up when the system is manufactured or used. - Other examples of important GCMs include
- Energy consumed by a computation
- Silicon chip area used up by a circuit design
- Dollar cost to manufacture a computer component
- We will study some general engineering principles
that apply to the minimization of any GCM in any
system.
72Additive Cost Measures
- Let us suppose we have a GCM C for a system.
- Many times, the total cost C can be represented
as a sum of independent cost components - E.g., C C1 C2 Cn or .
- These could correspond to the resources used by
individual subsystems of the whole system. - Or, used in doing particular categories of tasks.
- For example, execution time T can be broken down
as the sum of time Tfp taken by floating-point
instructions and the time Toth for others. - That is, T Tfp Toth.
73Improving Part of a System
- Suppose a GCM is broken down as C A B.
- The total cost is the sum of two components A
B. - Now suppose you are considering making an
improvement to the system design that affects
only cost component B. - Suppose you reduce it by a factor f, to B' B/f.
- The new total cost is then C' A B'.
- The cost of component A is unaffected.
- Overall (total) cost has therefore been reduced
by the factor
74Diminishing Returns
- Suppose we continue improving (reducing) a cost
component by larger and larger factors. - Does this mean the systems total cost will be
reduced by correspondingly large factors? ? NO! - Even if we improved one cost component (B in our
example) by a factor of f 8, note that - Even here, the overall cost reduction factor
foverall would still be only the finite value
1B/A! - The system can only be improved by at most this
factor, if we improve just the one component B.
75Diminishing Returns Example
- Suppose a particular chip contains B 1 cm2 of
logic circuits, and A 2 cm2 of cache memory. - The total cost (in terms of area) is C AB 3
cm2. - Now, lets go crazy trying to simplify and shrink
the design of just the logic circuit - What is the maximum factor by whichthis tactic
can reduce the area cost of the whole design
(logicmemory)? - Obviously, this can reduce the total area from 3
(cm2) to no less than 2 (area of memory alone), - or, shrink it by a factor of foverall 3/2
1.5. - Note we could have obtained this same answer
using the equation foverall,max 1B/A as well.
Logic1 cm2
Memory2 cm2
76Graph Showing Diminishing Returns
Part/rest (initial)
(B/A)
( f )
77Important Lessons to Take from This
- Its probably not worth spending significant
design time extensively improving just a single
component of a system, - Unless that component accounts for a dominant
part of the total cost (by some measure) to begin
with.(B/A gtgt 1). - Its only worth improving a given component up to
the point where it is no longer dominant. - Reducing it further wont make a lot of
difference. - Therefore, all components with significant costs
must be improved together in order to
significantly improve an entire design. - Well-engineered systems will tend to have roughly
comparable costs in all of their major components.
78Other Ways to Calculate foverall
- Earlier, we saw this formula
- For the overall improvement factorfoverall
resulting from improvingcomponent B by the
factor f. - But, what if we dont know the values of A and B?
- What if we only know their relative sizes?
- Fortunately, it turns out that we can still
calculate foverall. - Let us define fracenh B/C B/(AB) to be the
fraction of the original total system cost that
is accounted for by the particular part B that is
going to be enhanced. - Then, the fraction of cost accounted for by A
(the rest of the system) is - Our equation for foverall can then be reexpressed
in terms of the quantities fracenh and 1-fracenh,
as follows
79Calculating foverall in terms of fracenh
- Lets re-express foverall in terms of fracenh
- We will call this form for foverall the
Generalized Amdahls Law. (Well see why in a
moment.)
80Amdahls Law Proper
- We saw that execution time is one valid cost
measure. - In such a case, note that the factor by which a
cost is reduced is the speedup, or the factor by
which performance is improved. - We thus rename the improvement factor f of B
(the enhanced part) to speedupenh, and the
overall improvement factor foverall becomes
speedupoverall, and we get - This is called Amdahls Law, and it is one of the
most widely hyped quantitative principles of
processor design. - But as we can see, it is not a special law of CPU
architecture, but just an application of the
universal engineering principle of diminishing
returns which we discussed earlier.
81Key Points from This Module
- Throughput vs. Response Time
- Performance as Inverse Execution Time
- Speedup Factors
- Averaging Benchmark Results
- CPU Performance Equation
- Execution time IC CPI tcc
- Performance fcc / (IC CPI)
- Amdahls Law
- C' A B/f
- Implies
C Execution time after improvement B Part of
execution time affected by improvement f Factor
of improvement (speedup of enhanced part) A
Part of execution time unaffected by improvement
82Example Performance Calculation
- Suppose program takes 10 secs. on computer A
- And suppose computer A has a 4 GHz clock
- Want new computer B to run prg. in 6 seconds.
- Suppose that increasing the clock speed is only
possible with a substantial processor redesign, - which will result in 1.2 as many clock cycles
being needed to execute the program. - What clock rate is needed?
- Answer 4 GHz (10/6) 1.2 8 GHz
83Another Example
- Consider two different implementations of a given
ISA, running a given benchmark - Processor A has a cycle time of 250 ps
- And a CPI of 2.0
- Processor B has a cycle time of 500 ps
- And a CPI of 1.2
- Which computer is faster on this benchmark, and
by what factor? - Processor A takes 250 ps 2.0 500 ps / instr.
- Processor B takes 500 ps 1.2 600 ps / instr.
- Thus, A is faster by a factor of 6/5 1.2.
84Another example
- Suppose some Java application takes 15 seconds on
a certain machine. - A new Java compiler is released that requires
only 0.6 as many dynamic instructions to run the
application. - Unfortunately, it also increases the CPI by 1.1
- Presumably, uses more multi-cycle instructions.
- How fast will the application run when compiled
using the new compiler? - It will take 15 0.6 1.1 9.9 seconds to run
- It will be 15/9.9 50/33 1.515 faster
- Only slightly more than 50 faster than before.
85Another Example
- Consider the following measurements of execution
time - Which of the following statements are true?
- A is faster than B for program 1.
- A is faster than B for program 2.
- A is faster than B for a workload with equal
numbers of executions of programs 1 and 2. - A is faster than B for a workload with twice as
many executions of program 1 as of program 2.
Program Computer A Computer B
1 2 sec. 4 sec.
2 5 sec. 2 sec.