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Gauss Theorem

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Title: Gauss Theorem


1
Gauss Theorem
  • Using the notation of the figure below, recall
    that Gauss theorem is stated as follows
  • For an arbitrary continuous fixed volume V and
    associated closed surface area dA with a unit
    vector pointing outward normal to the
    surface, the following equation holds

2
Mass conservation
  • Conservation of mass is the concept that matter
    can neither be created nor destroyed in a system.
    In application to an arbitrary fixed volume this
    means that any changes in mass over time must be
    due to the mass flow or flux into or out of the
    volume. For a fluid of density, r, with mass,
    this concept is quantitatively
    expressed as
  • For density field, r(x,y,z,t), the fact that the
    volume integral is over the entire spatial domain
    leads to the equality

3
Mass conservation
  • Apply Gauss theorem on the flux term
  • This leads to the following integral form of
    conservation of mass

4
Mass conservation
  • There are two ways that the above integral is
    equal to 0.
  • I) The first is that the boundary of the surface
  • contains a unique symmetry such that the above
  • integral is zero. As an example of this,
    consider
  • the following 1-D integral
  • This possibility is too restrictive as we wish
    our results to be
  • applicable to any arbitrary shape.

5
Mass conservation
  • II) The other possibility is that the integrand
    itself is equal
  • zero throughout the integral domain. This leads
    to the result
  • Although this possibility might seem trivial this
    is the exact
  • result we are looking for.

6
Mass conservation
  • Use of the material derivative of the density
    field
  • conservation of mass can also be expressed in
    terms of the fractional rate of change of density
    as
  • This form shows us that fractional rate of change
    of the density (or volume) of a fluid element
    fluid is related to the divergence of the flow
    field

7
Incompressibility
  • If variations in density are small compared to a
    background density then the conservation of mass
    expression reduces to the simple form
  • The question arises when is it appropriate to use
    this simple form of mass conservation for steady
    flows?
  • If flows were unsteady and density was assumed
    to be strictly constant in the fluid medium then
    propagating waves would have infinite energy (See
    Waves and Tides). Also, one additional
    requirement is that we dont consider vertical
    lengths scales so large that hydrostatic pressure
    causes large density variations.

8
Example - 1
  • Find a value of a(x,y) to make the following flow
    field incompressible?

9
Example -2
  • A well mixed ocean layer extends from the surface
    to 80m deep with a measured average horizontal
    divergence at the surface of
  • The time averaged vertical flow at the surface is
    zero
  • Find the vertical flow at a depth of 60m (z-60m)
  • You can assume the flow is incompressible.
  • Draw a simple diagram depicting your result.

10
Incompressibility Conditions of applicability
  • One easy way to determine the conditions under
    which the incompressible equation holds is to
    perform dimensional scaling analysis. For a flow
    field with characteristic density, r, speed, U,
    and length scale, L, we wish for the fractional
    rate of change of density to be much less than
    the characteristic dimensions of the divergence
    field.
  • Notice we are examining characteristic scales
    and not actual derivatives in the above
    expression

11
Incompressibility Conditions of applicability
  • It is shown without proof that the restriction
  • Leads to the result that
  • So we can approximate a fluid as incompressible
    provided the square of the Mach number, M, is
    small.
  • Details of the above limit will be provided in SO
    414
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