Title: Chapter 4 Section 4'1 Inverse Functions
1Chapter 4 Section 4.1 Inverse Functions Warm-up
24.1 Inverse Functions
Chapter 4 Section 4.1 Inverse Functions
- Determine whether a function is one-to-one, and
if it is, find a formula for its inverse. - Simplify expressions of the type (f f ?1)(x)
and (f ?1 f)(x).
3Inverses
Chapter 4 Section 4.1 Inverse Functions
- When we go from an output of a function back to
its input or inputs, we get an inverse relation.
When that relation is a function, we have an
inverse function.
4Inverses
Chapter 4 Section 4.1 Inverse Functions
- Interchanging the first and second coordinates of
each ordered pair in a relation produces the
inverse relation. - Example Consider the relation g given by
- g (?2, 4), (3, ?4), (?8,
?5). - Solution The inverse of the relation is
- (4, ?2), (?4, 3), (?5,
?8).
5Inverse Relation
Chapter 4 Section 4.1 Inverse Functions
- If a relation is defined by an equation,
interchanging the variables produces an equation
of the inverse relation. -
6Inverse Relation
Chapter 4 Section 4.1 Inverse Functions
- Example Find an equation for the inverse of
the relation - y x2 ? 2x.
- Solution We interchange x and y and obtain
an equation of the inverse x y2 ? 2y. - Graphs of a relation and its inverse are always
reflections of each other across the line y x.
7Inverses of Functions
Chapter 4 Section 4.1 Inverse Functions
- If the inverse of a function f is also a
function, it is named f ?1 and read f-inverse.
The negative 1 in f ?1 is not an exponent. This
does not mean the reciprocal of f. f ?1(x) is
not equal to .
8One-to-One Functions
Chapter 4 Section 4.1 Inverse Functions
- A function f is one-to-one if different
inputs have different outputs. -
- That is,
- if a ? b
- then
- f(a) ? f(b).
9One-to-One Functions
Chapter 4 Section 4.1 Inverse Functions
- A function f is one-to-one if when the
outputs are the same, the inputs are the same. - That is,
- if f(a) f(b)
- then
- a b.
10Properties of One-to-One Functions and Inverses
Chapter 4 Section 4.1 Inverse Functions
- If a function is one-to-one, then its inverse is
a function. - The domain of a one-to-one function f is the
range of the inverse f ?1. - The range of a one-to-one function f is the
domain of the inverse f ?1. - A function that is increasing over its domain or
is decreasing over its domain is a one-to-one
function.
11Horizontal-Line Test
Chapter 4 Section 4.1 Inverse Functions
- If it is possible for a horizontal line to
intersect the graph of a function more than once,
then the function is not one-to-one and its
inverse is not a function.
12Horizontal-Line Test
Chapter 4 Section 4.1 Inverse Functions
13Horizontal-Line Test
Chapter 4 Section 4.1 Inverse Functions
- Example From the graph at the left,
determine whether the function is one-to-one and
thus has an inverse that is a function. - Solution No horizontal line intersects the
graph more than once, so the function is
one-to-one. It has an inverse that is a function.
14Horizontal-Line Test
Chapter 4 Section 4.1 Inverse Functions
15Horizontal-Line Test
Chapter 4 Section 4.1 Inverse Functions
- Example From the graph at the left,
determine whether the function is one-to-one and
thus has an inverse that is a function. - Solution There are many horizontal lines
that intersect the graph more than once. The
inputs ?1 and 1 have the same output, ?1. Thus
the function is not one-to-one. The inverse is
not a function. -
16Obtaining a Formula for an Inverse
Chapter 4 Section 4.1 Inverse Functions
- If a function f is one-to-one, a formula
for its inverse can generally be found as
follows - Replace f(x) with y.
- Interchange x and y.
- Solve for y.
- Replace y with f ?1(x).
17Example
Chapter 4 Section 4.1 Inverse Functions
- Determine whether the function f(x)
3x ? 2 is one-to-one, and if it is, find a
formula for f ?1(x).
18Example
Chapter 4 Section 4.1 Inverse Functions
- Solution The graph is that of a line and
passes the horizontal-line test. Thus it is
one-to-one and its inverse is a function. - 1. Replace f(x) with y y 3x ? 2
- 2. Interchange x and y x 3y ? 2
-
- 3. Solve for y x 2 3y
-
- 4. Replace y with f ?1(x)
- f ?1(x)
19Example
Chapter 4 Section 4.1 Inverse Functions
- Graph f(x) 3x ? 2 and
-
- f ?1(x)
-
- using the same set of axes. Then compare the
two graphs. -
20Example
Chapter 4 Section 4.1 Inverse Functions
- Solution The solutions of the inverse
function can be found from those of the original
function by interchanging the first and second
coordinates of each ordered pair. The graph f ?1
is a reflection of the graph f across the line y
x.
21Solution
Chapter 4 Section 4.1 Inverse Functions
22Inverse Functions and Composition
Chapter 4 Section 4.1 Inverse Functions
- If a function f is one-to-one, then f ?1 is
the unique function such that each of the
following holds -
- for each x in the domain of f, and for each x in
the domain of f ?1.
23Example
Chapter 4 Section 4.1 Inverse Functions
- Given that f(x) 7x ? 2, use composition of
functions to show that
f ?1(x) (x 2)/7. -
- Solution
24Example
Chapter 4 Section 4.1 Inverse Functions
25Restricting a Domain
Chapter 4 Section 4.1 Inverse Functions
- When the inverse of a function is not a function,
the domain of the function can be restricted to
allow the inverse to be a function. In such
cases, it is convenient to consider part of the
function by restricting the domain of f(x). If
the domain is restricted, then its inverse is a
function.
26Chapter 4 Section 4.1 Inverse Functions
25 / 356-357 / 1-31 Odd
274.2 Exponential Functions and Graphs
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- Graph exponential equations and functions.
- Solve applied problems involving exponential
functions and their graphs.
28Exponential Function
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- The function f(x) ax, where x is a real number,
a gt 0 and a ? 1, is called the exponential
function, base a. - The base needs to be positive in order to avoid
the complex numbers that would occur by taking
even roots of negative numbers. - Examples
29Graphing Exponential Functions
Chapter Section Exponential Functions and
Graphs
- To graph an exponential function, follow the
steps listed - 1. Compute some function values and list the
results in a table. -
- 2. Plot the points and connect them with a
smooth curve. Be sure to plot enough points to
determine how steeply the curve rises.
30Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- Graph the exponential function y f(x) 3x.
31Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- Graph the exponential function
.
32Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- Graph y 3x 2.
- The graph is the graph of y 3x shifted to left
2 units.
33Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- Graph y 4 ? 3?x
- The graph is a reflection of the graph of y 3x
across the x-axis, followed by a reflection
across the y-axis and then a shift up of 4
units.
34The Number e
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
- e ? 2.7182818284
- Find each value of ex, to four decimal places,
using the ex key on a calculator. - a) e4 b) e?0.25
- c) e2 d) e?1
35Graphs of Exponential Functions, Base e
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
36Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
37Example
Chapter 4 Section 4.2 - Exponential Functions
and Graphs
38Chapter 4 Section 4.1 Inverse Functions
26 / 370 / 2 40 Even
394.3 Logarithmic Functions and Graphs
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Graph logarithmic functions.
- Convert between exponential and logarithmic
equations. - Find common and natural logarithms with and
without using a calculator. - Change logarithm bases
40Logarithmic Functions
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- These functions are inverses of exponential
functions. - Graph x 3y.
- 1. Choose values for y.
- 2. Compute values for x.
- 3. Plot the points and connect them with a
smooth curve. -
- Note that the curve does not touch or cross
the y-axis. -
41Logarithmic Functions continued
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
Graph x 3y
42Logarithmic Function, Base a
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- We define y loga x as that number y such that x
ay, where x gt 0 and a is a positive constant
other than 1. - We read loga x as the logarithm, base a, of x.
43Finding Certain Logarithms
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Find each of the following logarithms.
- a) log2 16
- The exponent to which we raise 2 to obtain 16
is 4 thus log2 16 4. - b) log10 1000
- The exponent to which we raise 10 to
- obtain 1000 is 3 thus
log10 1000 3.
44Finding Certain Logarithms
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- c) log16 4
- The exponent we raise 16 to get 4 is ½, so
log16 4 ½. - d) log10 0.001
- We have The exponent
to - which we raise 10 to get 0.001 is ?3, so
log10 0.001 ?3.
45Logarithms
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- loga 1 0 and loga a 1, for any logarithmic
base a. -
- Convert each of the following to a logarithmic
equation. - a) 25 5x
- log5 25 x
- b) ew 30
- loge 30 w
46Example
Chapter 4 Section 4.3-Logarithmic Functions
and Graphs
- Convert each of the following to an exponential
equation. - a) log7 343 3 log7 343 3
- 73 343
-
- b) logb R 12
- logb R 12
- b12 R
47Example
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Find each of the following common logarithms on a
calculator. Round to four decimal places. - a) log 723,456
- b) log 0.0000245
- c) log (?4)
48Natural Logarithms
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Logarithms, base e, are called natural
logarithms. The abbreviation ln is generally
used for natural logarithms. Thus, - ln x means loge x.
- ln 1 0 and ln e 1, for the logarithmic base
e.
49Example
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Find each of the following natural logarithms on
a calculator. Round to four decimal places. - a) ln 723,456
- b) ln 0.0000245
- c) ln (?4)
50Changing Logarithmic Bases
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- The Change-of-Base Formula
- For any logarithmic bases a and b, and any
positive number M, -
51Example
Chapter 4 Section 4.3 Logarithmic Functions and
Graphs
- Find log6 8 using common logarithms.
-
- Solution First, we let a 10, b 6, and M
8. Then we substitute into the
change-of-base formula
52Example
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- We can also use base e for a conversion.
- Find log6 8 using natural logarithms.
-
- Solution Substituting e for a, 6 for b and 8
for M, we have
53Graphs of Logarithmic Functions
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Graph y f(x) log6 x.
- Select y.
- Compute x.
54Example
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- Graph each of the following. Describe how each
graph can be obtained from the graph of y ln
x. Give the domain and the vertical asymptote of
each function. - a) f(x) ln (x ? 2)
- b) f(x) 2 ? ln x
- c) f(x) ln (x 1)
55Graph f(x) ln (x ? 2)
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- The graph is a shift 2 units right. The domain is
the set of all real numbers greater than 2. The
line x 2 is the vertical asymptote.
56Graph f(x) 2 ? ln x
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- The graph is a vertical shrinking, followed by a
reflection across the x-axis, and then a
translation up 2 units. The domain is the set of
all positive real numbers. The y-axis is the
vertical asymptote.
57Graph f(x) ln (x 1)
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- The graph is a translation 1 unit to the left.
Then the absolute value has the effect of
reflecting negative outputs across the x-axis.
The domain is the set of all real numbers greater
than ?1. The line x ?1 is the vertical
asymptote.
58Application Walking Speed
Chapter 4 Section 4.3 Logarithmic Functions and
Graphs
- In a study by psychologists Bornstein and
Bornstein, it was found that the average
walking speed w, In feet per second, of a person
living in a city of population P, in thousands,
is given by the function - w(P) 0.37 ln P 0.05.
59Application Walking Speed continued
Chapter 4 Section 4.3- Logarithmic Functions
and Graphs
- The population of Philadelphia, Pennsylvania, is
1,517,600. Find the average walking speed of
people living in Philadelphia. -
- Since 1,517,600 1517.6 thousand, we substitute
1517.6 for P, since P is in thousands - w(1517.6) 0.37 ln 1517.6 0.05
- ? 2.8 ft/sec.
- The average walking speed of people living in
Philadelphia is about 2.8 ft/sec.
604.4 Properties of Logarithmic Functions
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Convert from logarithms of products, powers, and
quotients to expressions in terms of individual
logarithms, and conversely. - Simplify expressions of the type loga ax and
.
61Logarithms of Products
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- The Product Rule
- For any positive numbers M and N and any
logarithmic base a, - loga MN loga M loga N.
- (The logarithm of a product is the sum of the
logarithms of the factors.)
62Example
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Express as a single logarithm
. - Solution
63Logarithms of Powers
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- The Power Rule
- For any positive number M, any logarithmic base
a, and any real number p, - loga Mp p loga M.
- (The logarithm of a power of M is the exponent
times the logarithm of M.)
64Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
65Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
66Logarithms of Quotients
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- The Quotient Rule
- For any positive numbers M and N, and any
logarithmic base a, -
. - (The logarithm of a quotient is the logarithm of
the numerator minus the logarithm of the
denominator.)
67Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Express as a difference of logarithms.
68Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Express as a single logarithm.
69Applying the Properties
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Express in terms of sums and differences of
logarithms.
70Example
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Express as a single logarithm.
71Final Properties
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- The Logarithm of a Base to a Power
- For any base a and any real number x,
- loga ax x.
- (The logarithm, base a, of a to a power is the
power.) - A Base to a Logarithmic Power
- For any base a and any positive real number x,
- (The number a raised to the power loga x is x.)
72Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Simplify.
- a) loga a6
- b) ln e?8
- Solution
- a) loga a6 6
- b) ln e?8 ?8
73Examples
Chapter 4 Section 4.4- Properties of
Logarithmic Functions
- Simplify.
- a)
- b)
- Solution
-
- a)
- b)
744.5 Solving Exponential and Logarithmic Equations
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
- Solve exponential and logarithmic equations.
75Solving Exponential Equations
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
- Equations with variables in the exponents, such
as - 3x 40 and 53x 25, are called exponential
equations. - Base-Exponent Property
- For any a gt 0, a ? 1,
- ax ay ? x y.
76Example
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
- Solve .
- Write each side with the same base.
- Since the bases are the same number, 5, we can
use the base-exponent property and set the
exponents equal - Check 52x ? 3 125
- 52(3) ? 3 ? 125
- 53 ? 125
- 125 125 True
The solution is 3.
77Graphical Solution
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
- We will use the Intersect method. We graph y1
and y2 53
78Another Property
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
- Property of Logarithmic Equality
- For any M gt 0, N gt 0, a gt 0, and a ? 1,
- loga M loga N ? M N.
- Solve 2x 50
-
This is an exact answer. We cannot simplify
further, but we can approximate using a
calculator. x ? 5.6439 We can check by finding
25.6439 ? 50.
79Example
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
Negative numbers do not have real-number
logarithms. The solution is 3.
80Example
Chapter 4 Section 4.5- Solving Exponential and
Logarithmic Equations
The value 6 checks and is the solution.
814.6 Applications and Models Growth and Decay
Chapter 4 Section 4.6 Applications and Models
Growth and Decay
- Solve applied problems involving exponential
growth and decay and compound interest. - Find models involving exponential and
logarithmic functions.
82Population Growth
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- The function P(t) P0ekt, k gt 0 can model many
kinds of population growths. - In this function
- P0 population at time 0,
- P population after time,
- t amount of time,
- k exponential growth rate.
- The growth rate unit must be the same as the
time unit.
83Example
Chapter Section Applications and Models
Growth and Decay
- Population Growth of the United States. In 1990
the population in the United States was about 249
million and the exponential growth rate was 8
per decade. (Source U.S. Census Bureau) - Find the exponential growth function.
- What will the population be in 2020?
- After how long will the population be double what
it was in 1990?
84Solution
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- At t 0 (1990), the population was about 249
million. We substitute 249 for P0 and 0.08 for k
to obtain the exponential growth function. - P(t) 249e0.08t
- In 2020, 3 decades later, t 3. To find the
population in 2020 we substitute 3 for t - P(3) 249e0.08(3) 249e0.24 ? 317.
- The population will be approximately 317
million in 2020. -
-
85Solution continued
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- We are looking for the doubling time T.
- 498 249e0.08T
- 2 e0.08T
- ln 2 ln e0.08T (Taking the
natural logarithm on both sides) - ln 2 0.08T (ln ex x)
- T
- 8.7? T
- The population of the U.S. will double in about
8.7 decades or 87 years. This will be
approximately in 2077.
86Interest Compound Continuously
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- The function P(t) P0ekt can be used to
calculate interest that is compounded
continuously. - In this function
- P0 amount of money invested,
- P balance of the account,
- t years,
- k interest rate compounded continuously.
87Example
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- Suppose that 2000 is deposited into an IRA at an
interest rate k, and grows to 5889.36 after 12
years. - What is the interest rate?
- Find the exponential growth function.
- What will the balance be after the first 5 years?
- How long did it take the 2000 to double?
88Solution
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- At t 0, P(0) P0 2000. Thus the exponential
growth function is - P(t) 2000ekt. We know that
P(12) 5889.36. We then substitute and
solve for k - 5889.36
2000e12k -
-
The interest rate is about 9.
89Solution continued
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- The exponential growth function is
- P(t) 2000e0.09t.
- The balance after 5 years is
- P(5) 2000e0.09(5)
- 2000e0.45
- ? 3136.62
90Solution continued
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- To find the doubling time T, set P(T) 2 ? P0
4000 and solve for T. - 4000 2000e0.09T
- 2 e0.09T
- ln 2 ln e0.09T
- ln 2 0.09T
-
- T 7.7 ? T
- The original investment of 2000 doubled in
about 7.7 years.
91Growth Rate and Doubling Time
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- The growth rate k and the doubling time T are
related by - kT ln 2
- or
-
- or
-
- The relationship between k and T does not
depend on P0.
92Example
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- A certain towns population is doubling every
37.4 years. What is the exponential growth rate? - Solution
93Models of Limited Growth
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- In previous examples, we have modeled
population growth. However, in some populations,
there can be factors that prevent a population
from exceeding some limiting value. - One model of such growth is
-
- which is called a logistic function. This
function increases toward a limiting value a as t
approaches infinity. Thus, y a is the
horizontal asymptote of the graph.
94Exponential Decay
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- Decay, or decline, of a population is represented
by the function P(t)
P0e?kt, k gt 0. - In this function
- P0 initial amount of the substance,
- P amount of the substance left after time,
- t time,
- k decay rate.
- The half-life is the amount of time it takes for
half of an amount of substance to decay.
95Graphs
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
96Example
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- Carbon Dating. The radioactive element
carbon-14 has a half-life of 5750 years. If a
piece of charcoal that had lost 7.3 of its
original amount of carbon, was discovered from an
ancient campsite, how could the age of the
charcoal be determined? -
97Example
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
-
- Solution We know (from Example 5 in our
book), that the function for carbon dating is - P(t) P0e-0.00012t.
- If the charcoal has lost 7.3 of its
carbon-14 from its initial amount P0, then
92.7P0 is the amount present.
98Example continued
Chapter 4 Section 4.6- Applications and Models
Growth and Decay
- To find the age of the charcoal, we solve the
equation for t - The charcoal was about 632 years old.