CHAPTER 6 Sampling Distributions - PowerPoint PPT Presentation

1 / 23
About This Presentation
Title:

CHAPTER 6 Sampling Distributions

Description:

The 'unknown' numerical values that is used to describe the properties of a ... for the top five players of Orlando Magic is presented in the following table. ... – PowerPoint PPT presentation

Number of Views:10
Avg rating:3.0/5.0
Slides: 24
Provided by: morgan89
Category:

less

Transcript and Presenter's Notes

Title: CHAPTER 6 Sampling Distributions


1
  • CHAPTER 6 Sampling Distributions
  • Homework 1abcd,3acd,9,15,19,25,29,33,43
  • Sec 6.0 Introduction
  • Parameter
  • The "unknown" numerical values that is used to
    describe the properties of a population.
  • Sample Statistics
  • The computed numerical values from the
  • measurements in a sample.

2
  • Sec 6.1 What is a Sampling Distribution?
  • Sampling Error
  • The error results from using a sample instead
    of censusing the population to estimate a
    population quantity.
  • Sampling Distributions
  • The sample statistics vary from one sample to
    another. Therefore, there is a distribution
    function associated with each sampling statistic.
    This is called the sampling distribution.

3
  • Example 6.1
  • The three most popular numbers which were
    picked up by a group of students are 7, 17, and
    24. Assume that the population mean and standard
    deviation are 16 and 8, respectively.
  • (a). List all the possible samples of two
    numbers that can be obtained from this three
    numbers.
  • (b). Find the sample mean for each sample.
  • (c). Compute the sample error for each sample.
  • (Solutions in the note page)

4
  • Example 6.2 (Basic)
  • The population of average points per game (ppg)
    for the top five players of Orlando Magic is
    presented in the following table. (First eight
    games in 1996 playoff)
  • Player ppg
  • O'Neal(O) 25.3
  • Anderson(A) 16.4
  • Grant(G) 16.9
  • Hardaway(H) 22.3
  • Scott(S) 13.4
  • (a) Find the sampling distribution of the mean of
    the
  • "ppg" of three players from the population of
    five
  • players. (Part (a) solution is in note page)

5
  • Example 6.2 Continue
  • (b) Compute the mean and standard deviation of
    the sample mean.
  • ltSolution to part (b)gt
  • Note If you forget how to do it, you need to
    review Chapter 4.

6
  • Example 6.2 Continue
  • (c) Find the sampling distribution of the sample
    median of the "ppg" of three players from the
    population of five players. (solution in note
    page)
  • (d) Compute the mean and mean square error of the
    sample median.
  • ltSolution to part (d)gt

7
  • Sec 6.2 Some Criterions for choosing a
  • Statistics
  • Point Estimator
  • A point estimator of a population parameter is
    a rule that tell us how to obtain a single number
    based on the sample data. The resulting number
    is called a point estimator of this unknown
    population parameter.

8
  • Unbiasedness
  • The mean of the sampling distribution of a
  • statistic is called the expectation of this
    statistic. If the expectation of a statistics is
    equal to the population parameter this statistics
    is intended to estimate, then the statistics is
    called an unbiased estimator of this population
    parameter. If the expectation of a statistics is
    not equal to the population parameter, the
    statistics is a biased estimator.

9
  • NOTES
  • (1). If the population is normally distributed
    and the sample are randomly selected from this
    population, the sample mean is the best unbiased
    estimator of the population mean.
  • (2). If the population has an extremely skewed
    distribution and the sample size of the random
    sample is small, the sample mean may not be best
    estimator of the population mean.

10
  • Example 6.3
  • Consider the probability distribution shown
    here.
  • x p(x)
  • 2 1/3
  • 4 1/3
  • 9 1/3
  • (a) Find m.
  • ltSolution to (a)gt

11
  • Example 6.3 Continue
  • (b) List all possible samples of three
    observations.
  • ltsolution for part (b)gt
  • (2,2,2)
  • (2,,2,4) (2,4,2) (4,2,2)
  • (2,4,4) (4,2,4) (4,4,2)
  • (4,4,4)
  • (2,2,9) (2,9,2) (9,2,2)
  • (2,4,9) (2,9,4) (4,2,9) (4,9,2) (9,2,4) (9,4,2)
  • (4,4,9) (4,9,4) (9,4,4)
  • (2,9,9) (9,2,9) (9,9,2)
  • (4,9,9) (9,4,9) (9,9,4)
  • (9,9,9)

12
  • Example 6.3 Continue
  • (c) For a sample of 3 observations, find the
    sampling distribution of the sample mean and its
    mean value
  • ltSolution to part (c)gt
  • mean P(mean)
  • 2 1/27
  • 8/3 3/27
  • 10/3 3/27
  • 4 1/27
  • 13/3 3/27
  • 5 6/27
  • 17/3 3/27
  • 20/3 3/27
  • 22/3 3/27
  • 9 1/27

13
  • Example 6.3 Continue
  • (d) For a sample of 3 observations, find the
    sampling distribution of the sample median and
    E(median).
  • ltSolution to part (d)gt
  • median P(median)
  • 2 7/27
  • 4 13/27
  • 9 7/27
  • E(median) Smedian P(median)
  • 2 7/27 413/27 97/27 14.33

14
  • Sec 6.3 Central Limit Theorem
  • Some properties of the sample mean
  • (1). The expectation of the sampling distribution
    of is equal to
    the population mean m, i.e.
  • (2). The sampling distribution of sample mean is
    approximately normal for sufficiently large
    sample size even if the sampled population is not
    normally distributed.
  • (3). The sampling distribution of sample mean is
    exactly normal if the sampled population is
    normally distributed no matter how small the
    sample size is.

15
  • Central Limiting Theorem
  • Suppose a random sample of size n is drawn from
    a population. If the sample size n is
    sufficiently large, then the sample mean has at
    least approximately a normal distribution.
  • The mean value of the sample mean is always
    equal to the population mean, and the standard
    error of the sample mean is always equal to
  • where s is the population standard deviation.

16
  • Note Each of the following figure shows the
    population distribution (n1) and three sampling
    distributions of the sample mean for different
    populations. We can see that the sampling
    distribution of the sample mean is approximately
    normal distributed when the sample size getting
    larger.

17
Figure 6.1 Normal Population
2.0
2.0
f(x)
f(x)
1.0
1.0
0.0
0.0
-4
-2
0
2
4
-4
-2
0
2
4
n 1
n 2
2.0
2.0
f(x)
f(x)
1.0
1.0
0.0
0.0
-4
-2
0
2
4
-4
-2
0
2
4
n 4
n 30
18
Figure 6.2 Chi-Square Population
2.0
2.0
f(x)
f(x)
1.0
1.0
0.0
0.0
0.0
0.5
1.0
1.5
2.0
2.5
3.0
0.0
0.5
1.0
1.5
2.0
2.5
3.0
n 1
n 2
2.0
2.0
f(x)
f(x)
1.0
1.0
0.0
0.0
0.0
0.5
1.0
1.5
2.0
2.5
3.0
0.0
0.5
1.0
1.5
2.0
2.5
3.0
n 4
n 30
19
Figure 6.1 Uniform Population
8
8
6
6
f(x)
4
f(x)
4
2
2
0
0
0.0
0.2
0.4
0.6
0.8
1.0
0.0
0.2
0.4
0.6
0.8
1.0
n 1
n 2
8
8
6
6
f(x)
4
f(x)
4
2
2
0
0
0.0
0.2
0.4
0.6
0.8
1.0
0.0
0.2
0.4
0.6
0.8
1.0
n 4
n 30
20
  • Example 6.4
  • Suppose that you selected a random sample of
    size 4 from a normal population with mean 8 and
    standard deviation 2.
  • (a) Is the sample mean normally distributed?
  • Explain.
  • (b) Find P( gt 10).
  • (c) Find P( lt 7).

21
  • ltSolutions to EX 6.4gt
  • (a) Yes. The sampling distribution of sample mean
    is exactly normal if the sampled population is
    normally distributed no matter how small the
    sample size is.
  • standard error
  • (b) P(x gt 10)
  • P(z gt 2) 0.0228
  • (c) P(x lt 7)
  • P(z lt -1) 0.1587.

22
  • Example 6.5
  • As reported in the National Center for Health
    Statistics, males who are six feet tall and
    between 18 and 24 years old have a mean weight of
    175 pounds with a 14 pound standard deviation.
  • (a). Find the probability that a random sample
    of 196 males who are six feet tall and between 18
    and 24 years of age has a mean weight greater
    than 176 pounds.
  • (b). Find the probability that a random sample
    of 4 males who are six feet tall and between 18
    and 24 years of age has a mean weight greater
    than 168 pounds. State the necessary
    assumptions.

23
  • ltSolutions to EX 6.5gt
  • (a) standard error
  • P( x gt 176)
  • P( z gt 1) 0.1587
  • (b) standard error
  • P( x gt 168)
  • P( z gt -1) 0.8413.
  • The population needs to have normal distribution.
Write a Comment
User Comments (0)
About PowerShow.com