John A. Schreifels - PowerPoint PPT Presentation

About This Presentation
Title:

John A. Schreifels

Description:

Work = force acting over some distance: w = d x F (referenced to the system) ... John A. Schreifels. Chemistry 212. Chapter 19-6. 8 6 ... – PowerPoint PPT presentation

Number of Views:15
Avg rating:3.0/5.0
Slides: 18
Provided by: maso85
Learn more at: http://mason.gmu.edu
Category:
Tags: john | schreifels

less

Transcript and Presenter's Notes

Title: John A. Schreifels


1
Chapter 19
  • Thermodynamics and Equilibrium

2
Overview
  • First Law of Thermodynamics
  • Spontaneous Processes and Entropy
  • Entropy and the Second Law of Thermodynamics
  • Standard Entropies and the Third Law of
    Thermodynamics
  • Free Energy Concept
  • Free Energy and Spontaneity
  • Interpretation of Free Energy
  • Free Energy and Equilibrium Constants
  • Relating DG to the Equilibrium Constant
  • Change of Free Energy with Temperature

3
First Law of Thermodynamics
  • First law can be written as
  • DE q w
  • where q heat involved in the process and w
    work done by or to the system.
  • Work can be electrical or pressure volume
  • Work force acting over some distance w ? d x
    F (referenced to the system).
  • During reactions often there is an expansion of
    gases against some pressure where pressure is
    equal to the force per unit area
  • or .
  • Work is obtained by substitution
  • w ? d x F ? d x (PxA) or
  • w ? P?V.
  • The first law can be restated as E q ? P?V.

4
Energy and Enthalpy
  • From the first law q ?E P?V.
  • With no change in volume the equation simplifies
    to qV ?E.
  • At constant pressure qP ?E P?V.
  • There are times when both volume and pressure can
    change the heat involved in the reaction is then
    a more complicated function of ?E.
  • Enthalpy the heat output at constant pressure.
    H E PV.
  • In general, ?H ?E P?V V?P.
  • At constant pressure, a change in enthalpy is
    given by
  • ?H ?E P?V qP.
  • Normally, ?H and ?E are fairly close to each
    other in magnitude. In the combustion of propane
    (see book), ?E ?2043 kJ, ?H ?2041 kJ and w
    ?P?V ?2kJ.

5
Spontaneous Processes
  • Spontaneous process one that occurs without any
    continuous external influence it may not occur
    rapidly.
  • E.g. combustion of hydrogen with oxygen
    spontaneous decomposition of water never occurs
    spontaneously.
  • H2(g) O2(g) ? ½H2O(l)
  • E.g.2 Weak acid
  • HF(aq) H2O(aq)? F?(aq) H3O(aq) Ka
    3.52x10?4
  • E.g. 3 Solubility of solids.
  • AgCl(s) ? Ag(aq) Cl?(aq) Ksp 1.8x10?10
  • Moves to equilibrium amounts of reactants and
    product.
  • Rate of spontaneous change related to ratio of
    rate constants for forward and reverse reactions.
  • Extent of reaction related to energy difference
    between forward and reverse reactions (?H).
  • Goal Determine criteria necessary to predict
    spontaneity.

6
Enthalpy, Entropy, and Spontaneous Processes
Review.
  • Negative value for enthalpy thought to be
    criterion for spontaneity since most reactions
    with negative ?H are spontaneous, but exceptions
    exist
  • The reverse of the spontaneous reaction in not
    spontaneous. Reactions can only be spontaneous
    in one direction.
  • Qc compared to Kc indicates the direction of the
    reaction (will be related to the thermodynamic
    quantity soon).
  • E.g. determine the direction of reaction when
    0.100M acetic acid (Ka 1.75x10?5), 0.100 M
    sodium acetate, and 0.100 M HCl are mixed
    together.
  • Solution LeChateliers principle says reaction
    shifted to the left. What about when the
    reaction is reversed?

7
ENTROPY
  • Entropy thermodynamic quantity that is measure
    of randomness of system.
  • All changes tend to increase in randomness
    (second law of thermodynamics).
  • ?Stotal Sfinal ? Sinitial
  • ?Stotal ?Ssys ?Ssurr ? 0.
  • ?Ssys is sometimes negative, but is more than
    offset by ?Ssurr.
  • ?S is positive for a transition from ordered to
    less ordered system (such as with melting and
    vaporization) and negative for the reverse.
  • E.g. determine the sign of ?S for the following
    changes (what about the reverse of these?)
  • N2(g) 3H2(g) ? 2NH3(g)
  • CaCO3(s) ? Ca(s) CO2(g)
  • H2(g) O2(g) ? H2O(l)
  • H2O(l) ? H2O(s)

8
Entropy and the Second Law
  • Second Law all systems tend towards an increase
    in the randomness of the system. In terms of
    entropy, the total entropy of the universe always
    increases.
  • ?Stotal ?Ssys ?Ssurr ? 0.
  • ?Srev ??Sfwd.
  • ?S of phase change determined from heat of phase
    change. ?S ?H/T.
  • E.g. Determine ?S of melting and vaporization
    for water. ?Hfus 6.0kJ/mol and ?Hvap 40.8
    kJ/mol.
  • Generally, ?Sfus lt ?Svap. Entropy of s lt l lt g.
  • Since ?S ?H/T, we can determine temperature of
    phase change (mp or bp) if ?H and ?S of phase
    change are known.
  • E.g. Determine boiling point of chlorine if
    ?Hvap 6.41kJ/mol ?Svap 37.3 J/K?mol.

9
Entropy and Probability
  • Randomness is related to the probability of
    finding a molecule in a particular microstate
  • E.g. determine the probability of having
    perfectly order system (HH) when
  • Two microstates (heads, H, and tails,T) of same
    exact energy (same likelihood of existing).
  • Two particles. Then the possible states are HH,
    TT, TH, HT. Probability, P, of perfectly order
    system 25 (PHH 2-2100).
  • E.g.2 determine PHHH for 3 particles.
  • Possible states HHH, TTT, HHT, HTH, THH,
    HTT,THT, TTH. (PHHH 2-3100).
  • Ludwig Boltzmann statistical approach to
    entropy, S, given by S k?lnW where k
    Boltzmann's const. R/N 1.38x10?23J/K.
  • W total of ways that all atoms in a sample
    can be arranged and still have same energy.
  • E.g. Determine molar entropy of CO (2 states)
    and HCl (1 state) molecules in a crystal.

10
Entropy and Probability
  • Third Law perfectly ordered crystal has zero
    entropy.
  • entropy change when molecules filling a container
    after expansion is related probability of this
    expansion and is given by the relationship
    (constant T and n)
  • E.g. determine the entropy change that occurs
    when a gas expands to twice its initial volume.
  • E.g.2 twice its initial pressure.

11
Entropy and Temperature
  • At absolute zero there is no molecular motion and
    the S of a perfectly order system is zero.
  • Entropy expressed in absolute quantities.
  • Entropy increases with temperature.
  • Entropy increases dramatically as the melting and
    boiling points.
  • Standard Molar Entropies, So, ?So.
  • Standard molar entropy, So entropy of 1 mol of a
    compound at 1 atm and 25C.
  • Entropy of a compound is the total entropy. Not
    relative to the reference state.
  • As with ?Ho it is convenient to present all
    entropies at reference set of conditions.
  • As with ?Ho, ?So of the reaction can be
    determined. For general reaction
  • aA bB cC ... ? mM nN oO ...
  • ?So (mSM nSN ...) ? (aSA bSB ...).
  • E.g. determine ?So of the reaction using data in
    the table from the text.
  • NH3(g) ? 3/2 H2(g) ½ N2(g)

12
GIBB'S FREE ENERGY
  • Spontaneity can also be expressed without ?Ssurr.
  • Recall ?Stotal ?Ssys ?Ssurr ? 0 and
  • ?Ssurr ??H/T.
  • Combining ?Stotal ?Ssys ? ?H/T ? 0 or
  • ?T?Stotal ?G ?H ? T?Ssys ? 0
  • Gibb's Free Energy, ?G and in general terms is G
    H ? TS. Criterion for spontaneity is ?G ? 0.
    Always found to be true.
  • If ?H and ?S are known, spontaneity of reaction
    can be determined.
  • Possible signs of enthalpy and entropy
  • E.g. determine ?Go for the melting of water.
    ?Ho 6.03 kJ/mol ?So 22.1 J/K at ?10C.

13
?G Temperature Dependence
  • Spontaneity Reaction becomes spontaneous when ?G
    goes from to ?. We use ?G 0 to tell us when
    reaction just becomes spontaneous or 0 ?H ? T?S
    or T ?H/?S.
  • E.g. determine the temperature at which the
    synthesis of HI(g) becomes spontaneous.
  • ?Ho 52.96 kJ and ?So 166.4 J/mol
  • H2(g) I2(g) ? 2HI(g)

14
Standard Free Energy Changes for Reactions
  • Free Energy is a state function and an extensive
    property so that its value is dictated by the
    number of moles appearing in the equation.
  • ½ N2(g) 3/2 H2(g) ? NH3(g) ?Go ?16.5 kJ
  • N2(g) 3 H2(g) ? 2 NH3(g) ?Go ?33.0 kJ

15
Standard free energies of formation, DGfO.
  • ?Go 0 for elements in most stable form (as with
    enthalpy).
  • Free Energies are listed in tables and can be
    used to determine ?G of reaction and spontaneity.
  • For general reaction aA bB cC ... ? mM nN
    oO ...
  • E.g. Determine ?G for
  • 4NH3(g) 5O2(g)? 4NO(g) 6H2O(g).
  • As with enthalpy reactions can be coupled to
    determine ?G for unknown reaction.
  • Determine ?G Fe2O3(s) 3/2C(g) ? 3/2CO2
    2Fe(s).
  • Given
  • Fe2O3(s) ? 2Fe(s) 3/2O2(g) ?Go 742 kJ
  • 3/2 C(gr) 3/2O2(g) ? 3/2CO2(g) ?Go ?592 kJ.

16
EQUILIBRIUM CONSTANTS AND ?G
  • Equilibrium constant for a reaction aA bB ...
    ? mM nN ... is defined as
  • Tells how far to right reaction proceeds.
  • Large value ? mostly products.
  • Small value ? mostly reactants.
  • At equilibrium this equation must always be
    obeyed no matter what relative amount of reactant
    and was started with.
  • Reaction quotient, Q, defined in same way as K
    but refers to some initial condition that might
    not be at equilibrium.
  • These two are related to ?G by the equation
  • ?G RTln(Q/K).
  • When Q K equilibrium exists and ?G 0.

17
EQUILIBRIUM CONSTANTS AND DG
  • K and Q often separated by rewriting
  • ?G ?Go RTlnQ and ?Go ?RTlnK.
  • From initial conditions and ?Go, the free energy
    of the reaction can be determined.
  • E.g. determine ?G at 25C for the reaction
  • H2O(l) ? H (aq) OH?(aq) if the concentration
    of H 1.00x10?5 M OH? 1.00x10?5 M
  • K can be determined under standard conditions if
    ?G is known.
  • E.g. Determine K for 3NO(g) ? N2O(g) NO2(g)
  • E.g.2 Determine K for NH4NO3(s) ? N2O(g)
    2H2O(g).
  • ?Go can be determined if K is known.
  • E.g. determine ?Go for the solubility of AgCl(s)
    if its Ksp 1.8x10?10
  • E.g. 2 determine ?Go for ionization of HF in
    water. Ka 3.5x10?4.
Write a Comment
User Comments (0)
About PowerShow.com