Title: phy201_11
1Physics 211
12 Oscillatory Motion
- Simple Harmonic Motion
- Energy of a Simple Harmonic Oscillator
- The Pendulum
- Comparing Simple Harmonic Motion and Uniform
Circular Motion - Damped Oscillations
- Forced Oscillations
2Simple Harmonic Motion
Hookes Law F -kx F restoring force x
displacement from equilibrium position
3x0
x-A
XA
42
d
x
(
)
(
)
(
)
F
t
-
kx
t
ma
t
m
dt
2
2
d
x
k
Û
-
x
dt
m
2
Differential Equation,
need to find solution
so that left hand side
right hand side
From looking at graph of position versus time
(
)
Guess
x
t
A
cos(
w
t
)
A
and
w
constants
.
5(No Transcript)
6What is the meaning of the constant A
at time
t
0
(
)
(
)
x
0
A
cos
0
A
which is the displacement from equilibrium at
time
t
0
p
at time
t
w
p
p
æ
æ
ö
ö
(
)
x
A
cos
w
A
cos
p
-
A
è
ø
è
ø
w
w
The max and min values of
x
are
A
Û
A
is the amplitude of the motion
the maximum displacement from equilibrium
position
7cos(x)
1
?
??
cos(2n?) 1
-1
cos(2n1?) -1
8Meaning of
w
2
n
p
for
t
Þ
x
A
w
(
)
2
n
1
p
for
t
Þ
x
-
A
w
motion repeats between
A
Harmonic Motion
If it repeats itself exactly
Simple Harmonic Motion
(SHM)
(
)
(
)
2
n
2
p
2
n
p
2
p
Time between repeats
-
(
angle changes
2
p
)
w
w
w
This is called the Period of the Oscillation,
T
Angular Frequency
Rate of change of angle with time
2
p
w
T
9The number of times motion repeats in
1 second
1
w
is the frequency
f
T
2
p
rad
f
Hz
º
cps
w
º
s
-
1
s
2
p
m
T
2
p
w
k
When is the velocity the greatest/least When is
the acceleration the greatest/least
10(
)
2
n
p
2
n
1
p
x
A
Û
t
t
w
w
(
)
(
)
at these times the velocity v
t
-
A
w
sin
w
t
Þ
2
n
p
2
n
p
æ
æ
ö
ö
(
)
v
-
A
sin
w
-
A
sin
2
n
p
0
è
ø
è
ø
w
w
(
)
(
)
2
n
1
p
æ
2
n
1
p
æ
ö
ö
(
)
(
)
v
-
A
sin
w
-
A
sin
2
n
1
p
0
è
ø
è
ø
w
w
so velocity is zero at maximum displacement
the acceleration on the other hand is a maximum
(
)
2
n
p
2
n
1
p
æ
æ
ö
ö
a
-
w
A
a
w
A
2
2
è
ø
è
ø
w
w
The acceleration is zero when
x
0
The velocity is the greatest when
x
0
v
A
w
max
11Energy of a Simple Harmonic Oscillator
Mass experiences spring force,
thus its P
.
E is
1
U
(
x
)
kx
2
2
The spring force is a conservative force
The total energy of the mass is
1
1
1
1
(
)
2
(
)
2
E
K
U
m
v
kx
m
v
t
kx
t
constant
2
2
2
2
2
2
tot
\
The total energy when v
0
is equal to
1
E
kA
2
2
tot
which must be its value at ALL
TIMES
!
1
1
1
(
)
Þ
E
t
m
v
kx
kA
2
2
2
2
2
2
tot
1
1
k
Þ
when
x
0
,
K
m
v
kA
Þ
v
A
2
2
max
max
2
2
m
12The Pendulum
?
l
T
s
mg cos?
mg sin?
Wmg
13Restoring Force
-mg
when
q
F
-
mg
sin
q
q
is small
s
mg
\
F
-
mg
q
-
mg
-
s
l
l
º
Hookes Law for the Pendulum
2
d
s
,
This force provides the tangential acceleration
2
dt
and we obtain a similar differential equation to
before
.
Comparing to before we see
mg
k
x
s
l
(
)
(
)
s
t
A
cos
w
t
m
ml
l
T
2
p
2
p
2
p
k
mg
g
14The Physical Pendulum
d
????d x W
?
Wmg
Note that the pivot point could be inside the
boundaries of the object
15We formulate this for an object suspended so that
its center of gravity is at a distance d from the
pivot point, by using angular quantities
The restoring torque
due to gravity
t
-
mgd
sin
q
-
mgd
q
(small angle approx
.
)
using
t
I
a
2
d
q
mgd
mgd
2
Þ
a
-
q
-
w
q
,
where
w
2
dt
I
I
(
)
(
)
Þ
q
t
A
cos
w
t
I
Þ
T
2
p
mgd
16The Torsion Pendulum
By suspending a mass at the end of a wire
supported tightly at the other end,
we make
a torsion pendulum.
By twisting the object
through a small angle we produce a restoring
torque
d
q
2
t
-
kq
I
a
I
dt
2
2
d
q
k
Þ
-
q
dt
I
2
I
T
2
p
k
17Comparing Simple Harmonic Motion and Uniform
Circular Motion
(
)
(
)
x
t
A
cos
w
t
is precisely the time variation
of the x coordinate of a particle performing
uniform circular motion about a fixed point
at a fixed distance
A
.
p
æ
ö
(
)
(
)
y
t
A
sin
w
t
A
cos
w
t
-
is the time variation
è
ø
2
of the y coordinate,
which is a SHM variation
.
p
Here though we have a phase shift of
j
-
2
p
The argument
w
t
-
is called the phase of the motion
.
2
18Damped Oscillations
If there are frictional forces present
D
E
W
lt
0
tot
nc
Thus the total energy decreases
and becomes
a non constant function of time,
E
(
t
)
¹
constant.
1
(
)
2
Þ
E
(
t
)
kA
t
2
(
)
Þ
A
t
decreases with time
The differential equation describing the position
of a particle undergoing damped SHM is of the
form
d
x
dx
2
m
-
kx
-
b
dt
dt
2
19Forced Oscillations
If there is another external oscillating force
acting on the object
(in the direction of motion
)
one says that the motion of the oscillator is
forced by this external force.
The differential
equation describing such motion is
d
x
dx
2
(
)
m
-
kx
-
b
F
cos
w
t
dt
dt
0
2
20solutions to this equation give amplitudes of the
form
F
0
m
A
(
t
)
(
)
(
)
b
w
2
2
w
-
w
2
2
m
0
w
is the frequency of the SHM
(i
.
e
.
no friction
0
and forcing oscillation
)
If b
(friction
) is small,
then if
w
w
the amplitude
0
becomes larger and larger
º
RESONANCE