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Quiz 22 OCT 08

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... 4000g of U represents 4000/238 = 16.8067 moles/t. Since 96% of U is solubilized, we will have 0.96*16.8067 = 16.13 moles/t of U solubilized. – PowerPoint PPT presentation

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Title: Quiz 22 OCT 08


1
Quiz 22 OCT 08
2
  • A process developed to treat minerals containing
    4000 ppm of tetravalent uranium (UO2) is based on
    the following conditions
  • Consumption of H2SO4 25 kg/t
  • Consumption of NaClO3 2 kg/t
  • Volume of attacking solution/ mineral mass 1
    m3/t
  • This treatment is used to solubilize 96 of
    uranium content.

3
  • You are asked to
  • Write the oxidation equation of U(IV) by ClO3-
    ions
  • Determine the efficiency of the oxidizing
    treatment
  • Determine the composition in uranium and H2SO4,
    of the solutions after attack (by making the
    following hypothesis that the variation of H
    is negligible during the reaction period)

4
  • The purification of uranium is performed by
    chromatography on anion exchange resins columns (
    with an exchange capacity for one monovalent ion
    3 eq/kg)
  • Determine, by using Figure 1, the distribution
    coefficient of U(VI) between the attacking
    solution and the resin ( consider that an excess
    of resin is used per unitary volume of solution)
  • Determine the volume of uraniferous solution that
    you can transfer on a column composed of 100 kg
    of resins where we want to saturate to 70
    maximum the exchange sites, knowing that the
    extraction reaction is
  • The extraction of 1 U(VI) is saturating 4 sites
    of the resin

5
Distribution Ration KD
Concentration (NH4)2SO4 or H2SO4 in Mol/L
6
CORRECTION
  • Write the oxidation equation of U(IV) by ClO3-
    ions

OXIDATION
REDUCTION
7
Determine the efficiency of the oxidizing
treatment (1)
  • Number of moles of U solubilized
  • 4000 ppm of U is equal to 4000 g/t of U
  • Knowing that the molar mass M of U is 238 g /
    mole, 4000g of U represents 4000/238 16.8067
    moles/t. Since 96 of U is solubilized, we will
    have 0.9616.8067 16.13 moles/t of U
    solubilized.
  • Number of moles of NaClO3 used
  • M of NaClO3 is 106.5 g/mole
  • Consumption is 2 kg/t, 2000g/t 2000/106.5
    18.78 moles/t

8
Determine the efficiency of the oxidizing
treatment (2)
  • Number of moles of NaClO3 necessary to the
    process
  • After Eq 1, 1 mole of NaClO3 reacts with 3 moles
    of UO2
  • If we have 16.13 moles of U, we need 16.13/3
    5.37 moles of NaClO3
  • The efficiency will be 5.37/ 18.78 0.286

9
Composition Solution
  • Uranium
  • Mass of U solubilized
  • 4000 g 96 3840g/t or 3.840g/L, knowing that
    the volume is 1 m3 1000L.
  • U is 3.840/238 0.016M/L
  • H2SO4
  • 25kg/t 25000g/t or 25 g/L, knowing that the
    volume is 1 m3 1000L.
  • M 98g/mole
  • H2SO4 25/98 0.255moles/L

10
Distribution Coefficient
H2SO4 0.25M Kd U(VI) 200
11
Volume of the uraniferous solution
  • Exchange capacity of the resin
  • 3 eq/kg 100 kg of resin 300 eq/kg in
    monovalent ion
  • In uranium we will have 300/4 75 moles of
    U/column
  • The saturation is 70 so 7570 52.5 moles of U
  • The total volume of the uraniferous solution is
  • 52.5 moles/0.016 3254.8 liters
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