Title: CEM 850, Fall 2004
1CEM 850, Fall 2004
- Some notes on Thermochemistry, Bond Strengths,
and Strain energies - Ned Jackson
2Alkane ?Hf values (kcal/mol)
3Alkane ?Hf values show Systematic Patterns
- Can we estimate ?Hf by summing energy equivalents
for transferable molecular building blocks? - Bond Equivalents
- Group Equivalents
- Fragment transferability in comparisons between
compounds implies deep similarity
4Bond Equivalents
- Estimate ?Hf values from C-H, C-C bonds
- Ethane ?Hf -20.04 6 C-H, 1 C-C
- Propane ?Hf -25.02 8 C-H, 2 C-C
- \C-H -3.765 C-C 2.55
- Predict ?Hf(C5H12) 4C-C 12C-H -34.98
- N-pentane -35.08 but isopentane -40.14
- \Bond equivalents fail for branching.
5Group Equivalents
- All alkanes can be expressed in terms of four
building blocks (CH3)i(CH2)j(CH)k(C)l
(nonspecified bonds implicitly to C) - Enthalpy Equivalents
- CH3 -10.08
- CH2 -4.95
- CH -1.90
- C 0.50
6Group Equivalents (contd)
- Analogous equivalents for alkenes and aromatics
can be similarly derived, with value for CH3 held
at -10.08 kcal/mol no matter what its attached
to. - This method defines a strainless ideal for
hydrocarbons of arbitrary formula, and allows the
definition of strain.
7Strain Energies
8Thermochemistry--why care?
- Besides simple reaction ?H and ?G values,
detailed energetics define reaction direction - Combined with bond strengths and kinetics of the
reactions of interest, even imperfect energetic
ideas put limits on mechanistic possibilities - Lead in to tools for comparing reactions!
9Bond Strengths
- An X-Y bond, as defined by its atoms X and Y, is
not a uniform (thus transferable) molecule
building block - The bond equivalent approach did not lead to a
reliable method for ?Hf estimation - A group equivalent approach was required
- Some bond strengths allow development of group
equivalent ideas for reactions
10R-H BDEs worth remembering
- H-H 104.2 kcal/mol
- CH3-H 105.1
- CH3CH2-H 100.5
- (CH3)2CH-H 99.1
- (CH3)3C-H 95.2
- H2CCHCH2-H 88.1
- PhCH2-H 89.6
11An ordinary C-C s bond
- Generic C-C bond strengths in R-R
- Use group equivalents to estimate ?Hf values for
R-R, R-H, and R-H - Get ?Hf of R, R radicals from R-H, R-H via
C-H BDEs BDE(H2) 104.2 kcal/mol - Calculate R-R BDE
12Cracking of Butane 1-2 vs 2-3
- ?Hf(butane) 2(-10.08 -4.95) -30.06 est.
- ?Hf(methane) -17.9
- ?Hf(ethane) 2(-10.08) -20.16 est.
- ?Hf(propane 2(-10.08) -4.95 -25.11 est.
- ?Hf(Me) -17.9 105.1 -52.1 35.1 est.
- ?Hf(Et) -20.16 100.5 -52.1 28.2 est.
- ?Hf(Pr) -25.11 100.5 -52.1 23.3 est.
13Some Heats of Formation
14All energies in kcal/mol
15Bond Dissn Energies (BDEs)
16The strength of a p bond
- Breaking ethylenes p bond doesnt lead to two
well-defined fragments. How can we define a
separate bond strength for it? - Cis-trans isomerization of HDCCHD?
- Hydrogenation energies?
- Spectroscopic measurements?
- Others (full disassembly of molecule)?
17Ethylene isomerization
- Heat cis or trans DHCCHD and measure the rate of
isomerization as a function of T. - From kinetic analysis, obtain ?Hact for c-t
isomerization 66 kcal/mol. - Problems at high enough T, lots of other
chemistry can happen some may catalyze
isomerization, making barrier appear too low. Or,
isomerization might not go via rotation!? How to
get a check on this value?
18Hydrogenation Strategy
- H2CCH2 H2 gt H-H2C-CH2-H12.5 0 gt
-20.0 ?Hrxn -32.5 kcal/mol - Broken C-C p bond, H-H_at_104.2 kcal/mol Formed
Two ethane C-H bonds _at_100.5 kcal/mol each - BDE(p) 201. -32.5 -104.2 64.3
kcal/mol !Looks good!
19Spectroscopic approaches?
- pgtp Excited state has no p bonding, but lmax
171 nm 167 kcal/mol!? Pretty far from 66! - ?IE (ethylene - ethyl) (Electrons energy-drop
from non- to p-bonding - 10.51 - 8.12 eV 55 kcal/mol per e gt 110
kcal/mol!?
20Energetics of Full Disassembly of Ethylene
- Try to make a prediction
- C-C s BDE is 90 kcal/mol
- the p bond is 65 kcal/mol
- Predict 155 kcal/mol ?H for C2H4 gt 2CH2
- ?Hf(ethylene) 12.5 ?Hf(CH2) 92.3 184.6-12.5
172.1, almost 20 kcal/mol too large--whats
going on? - C-H bond strengths increase from C2H4 and CH2
21Cyclopropane Stereomutation
- How strong is a C-C bond in cyclopropane?
- Look at isomerization via isotopic labeling
- Directly analogous to ethylene cis-trans
isomerization - Should go via real open-chain biradical
H2C-CH2-CH2 - What about hydrogenation energies?
- Can Strain Es help?
22Thermal Stereomutation
- Measured ?Hact for c-t isomerization
- 63.7 kcal/mol (1958) 59.8 kcal/mol (1972)
- ?Hf of cyclopropane 12.7 kcal/mol
- \biradical ?Hf should be ca. 72.5 kcal/mol
- Primary C-H BDE back then was thought to be ca.
97 kcal/mol, instead of 100.5 - Propane -25 2(97-52) 65huh?
23The propanediyl disaster
- Thermochem looked like biradical must rest in a
5-9 kcal/mol well between c,t-isomers
24Why dont we expect a barrier
- General radical dimerization barrierless
- Conceptual reason theres no stabilization to
lose as bond formation begins. - Hammond postulate and/or Bell-Evans-Polanyi
principle--the more exothermic the process, the
lower its barrier will be.
25Review with current values
- We calculated the 2-3 cleavage barrier for
butane cyclopropane should have the same number,
lowered by its strain energy, which is released
upon ring opening. - So 87.2 -27.5 kcal/mol directly predicts a
barrier of 59.7, near the 1972 ?Hact value. - Just need to revise primary C-H BDE up by 3.5
kcal/mol (x2 the 7.5 kcal/mol error)
26The Methane Activation Problem
- Methane combustion is very exothermic
- CH4 2O2 --gt CO2 2H2O
- ?Hcomb -17.9 0 --gt -94.1 2(-57.8) -191.8
kcal/mol (plenty exothermic) - Its a great fuel, butit isnt liquid
- BP(CH4) -162 C 111 K
- \ Not practical for automotive use
- (similar issues surround H2)
27Partial oxidation to liquify CH4?
- Oxidation to methanol would be exothermic
- CH4 1/2O2 --gt CH3OH
- ?H -17.9 0 --gt -48.0 -30.1 kcal/mol
- Energy from CH3OH combustion?
- CH3OH O2 --gt CO2 2H2O
- ?Hcomb -48.0 --gt -209.7 -161.7 kcal/mol
28Hydrocarbon vs. Methanol FuelsEnergy Densities
- Typical hydrocarbon (CH2)n
- Mass 14 g/mol
- ?Hcomb -5 --gt -94.1(-57.8) -146.9 kcal/mol
- 10.5 kcal/molgram
- Methanol CH3OH
- Mass 30 g/mol
- ?Hcomb -161.7 kcal/mol
- 5.4 kcal/molgram
29Challenge CH4 --gt CH3OH
30Protection of Methanol?
- The C-H bond strengths in methanol are increased
from 98.1 to 110 kcal/mol by methanol
protonation, becoming stronger than those in
methane (105.1 kcal/mol). Is this enough to
control selectivity? - The key is the attacking species, presumably
either HO or CH3O radicals here.
31Radical selectivities
- Isobutane halogenation
- Bond strengths matter!
32Radical Reactions Selectivity vs. Exothermicity
- The 103.2 kcal/mol H-Cl bond means that
H-abstraction from any simple alkyl R-H is
exothermic. - H-Br bond strength is just 87.5 kcal/mol so all H
abstractions are endothermic. The relative
barriers differ by nearly the whole energy
difference between primary and tertiary radicals.
33How to obtain reaction barrier i.e. ?Hact values?
- Kineticsfor a later discussion
- Measure reaction rates as a function of T
- Extract rate constants for various T values
- Arrhenius or Eyring plots to obtain ?Eact and/or
?Hact ?Sact
34Reaction Mechanisms
- How many particles (intra- vs. intermolecular)?
- Activation energies
- What parts end up where?
- Symmetries of TSs/Intermediates
- What bonding changes happen, and when?
- Concerted or stepwise?
- Ionic or radical?
- Catalyzed or direct?
- Energy inputs (?, hn, others?)?