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Uniform Circular Motion

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Uniform Circular Motion Basic Principles & Formulas Uniform Circular Motion Principles Objects move at a constant speed (speed = scalar quantity) Objects velocity is ... – PowerPoint PPT presentation

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Title: Uniform Circular Motion


1
Uniform Circular Motion
  • Basic Principles Formulas

2
Uniform Circular Motion Principles
  • Objects move at a constant speed (speed scalar
    quantity)
  • Objects velocity is constantly changing (velocity
    vector quantity) due to a continuous change in
    direction
  • Velocity is tangent to circular motion
  • While in motion, there is a force and an
    acceleration being applied to the object

3
Uniform Circular Motion Terms Formulas
  • Period (T) time it takes to make 1 revolution
  • Period may be given, obvious or determined by
    time/revolutions ex. 25 rev. in 10 sec. T 10/25
    ? .4 sec (T 1/f)
  • Frequency (f) number of revolutions made in 1
    sec. (f 1/T) units Hz
  • (Period Frequency are Inversely Related)

4
Uniform Circular Motion Diagram
Acceleration Force Parallel to Radius /
Velocity Perpendicular to Radius
v
a
r
F
5
Uniform Circular Motion Questions
  • Q While moving in a circular path, if string
    breaks, in what direction will the object travel?
  • A In a straight line, perp. to radius
    (Law of Inertia)
  • Q In what direction is the force?
  • A Inward
  • Q In what direction is the acceleration?
  • A Inward

6
Uniform Circular Motion Terms Formulas
  • Velocity (v) 2pr
  • T
  • Acceleration (a) 4p²r
  • or v²
  • r

7
Uniform Circular Motion Terms Formulas
  • Force (F) mv²
  • r
  • or m 4p²r

8
UCM Example Problem
  • A 615 kg race car completes 1.00 lap in 14.3 sec
    around a circular track with a radius of 50.0 m.
    What is the cars T, f, v, a, F (on tires)?
  • T 14.3/1.00
  • 14.3
  • f 1.00/14.3
  • 0.0699 Hz

9
UCM Example Problem (cont.)
  • V (2)(p)(50.0)
  • 14.3
  • 22.0 m/s
  • a (22.0 m/s)²
  • 50.0
  • 9.68 m/s²

10
UCM Example Problem (cont.)
  • F (on tires) (615 kg)(22.0 m/s)²
  • 50.0 m
  • 5,950 N
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