Title: Absorption
1Absorption
2Absorption
- Light passing through a material medium will
- a) travel at a slower v c/n where n(f)
dispersion - b) have some absorption depending on the
electric dipole moment and orientation of the
incident light E - c) the absorbed energy become the heat or light.
3Absorption
- Gross description
- where cconcentration, ? extinction coeff.
- Integrates to (Beer-Lambert Law)
4Â Â Â Â
5Optical Density
- In terms of A ecl absorbance, we have
- ln(Io/I) A or log10(Io/I) A/2.303 O.D.
- OD 1 means 1/10 is transmitted
- OD 2 means 1/100 is transmitted
- OD 1, followed by OD 2 results in OD 3
- Transmittance T I/Io e-A
- Transmittance (I/Io) x 100
6Absorption
- In simpler molecules there will be a number of
discrete absorption lines - In macromolecules there are so many lines that a
broad absorption band forms - The type of incident light used (uv, IR, etc.)
determines the type of absorption that is probed
uv probes electronic ir probes vibrational,
etc. - How are the measurements made?
7Spectrophotometer
- Used to measure OD vs l
- Simplest l varies with dial setting (rotation
of prism or grating photocell detector
single beam compare sample to blank of buffer - If e known you can determine concentration
- Fancier double-beam instruments with
monochromator and recorder coupled to grating
read OD vs l directly with a constant comparison
to blank
8Details I
- Animation
- Light source incandescent tungsten for near IR
to vis Hg arc lamp for 250 350 nm Xe lamp for
lt250 nm
9DNA hypochromism
- More order means less absorption perfect
crystals are clear (diamonds) - So, ss DNA absorbs more than ds DNA at same
concentration more base stacking means less
absorption- so can monitor DNA melting by
absorption
10Applications II
- Monitor denaturation/renaturation e.g.
helix-coil in ds transition of DNA
11Maxwell ??
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26Scattering
27Scattering of Light
Scattering of light is what we call the
phenomenon in which light waves interact with
particles (molecules) and are removed from an
incident light beam. For an example, put a
few drops of milk into a container of water.
Shine a flashlight through the water. The
transmitted light looks orange or red (looking
back into the flashlight), while the light
scattered out the sides is blue or gray.
28Scattering of Light
Question if the amount of scattering depends on
the number of scatterers, why do we not see much
scattering when a laser passes through glass?
Answer We return to the idea of
interference. For a relatively dense medium,
there is a good chance that for each molecule
scattering light, another one is one-half
wavelength away.
29Scattering of Light
For light scattered sideways from a beam, this
results in destructive interference.
In the forward direction, the interference is
constructive, so the result is that the beam
continues to propagate.
30Scattering
Why is the sky black when seen from outer
space? There are no particles to speak of, so
there is no scattered light we thus see a
black sky.
31Scattering
- First quantitative experiments in 1869 by Tyndall
(scattering of small particles in the air
Tyndall effect) - 1871 Lord Rayleigh started a quantitative study
and theory - Basic idea incident monochromatic linearly
polarized light beam incident on a sample.
Assume - No absorption
- Randomly oriented and positioned scatterers
- Isotropic scatterers
- Independently scattering particles (dilute)
- Particles small compared to wavelength of light
32Classical Wave description
- The incident electric field is
- E Eocos(2px/l 2pt/T)
- Interaction with molecules drives their electrons
at the same f to induce an oscillating dipole - pinduced a Eocos(2px/l 2pt/T)
- This dipole will radiate producing a scattered
E field from the single molecule
dipole
Obs. Pt.
r
f
33Rayleigh scattering
- E1/r. So I1/r2.- necessary since I
energy/time/area and A r2 - E1/l2. So I1/l4 blue skies and red sunsets
(rises) - Elastic scattering same f
- sinf dependence when f 0 or p at poles of
dipole no scattering max in horizontal plane
34Polarizability and index of refraction
- a related to n , but how?
- Note that if n 1
- where c is the weight concentration
- Then
- where N number concentration
35Polarizability and index of refraction
- So,
- For a particle in a solvent with nsolv, we have
n2 n2solv 4pNa. We get
36Scattered Intensity
- Detect intensity, not E, where
- Substituting for ?, we have
37Scattered Intensity
- If there are N scatterers/unit volume and all are
independent with N NAc/M, then - We define the Rayleigh ratio Rq
38Basic Measurement
- If the intensity ratio Iq/Io, nsolv, dn/dc, l, c,
f, and r are all known, you can find M. - Usually write Kc/Rq 1/M
- Measurements are usually made as a function of
concentration c and scattering angle q - The concentration dependence is given by
- Where B is called the thermodynamic virial
39Polydispersity
- If the solution is polydisperse has a mixture
of different scatterers with different Ms - then
we measure an average M but which average? - So the weight-averaged M is measured!
40Angle Dependence
- If the scatterers are small (d lt l/20), they are
called Rayleigh scatterers and the above is
correct the scattering intensity is independent
of scattering angle - If not, then there is interference from the light
scattered from different parts of the single
scatterer - Derivation of Particle Scattering Factor P(q)
41Particle Scattering Factor
- Different shapes give different P(q)
42Rayleigh Scattering
Scattering of white light from very small objects
depends strongly on the wavelength of the light -
short wavelengths are scattered most easily
smaller than the wavelength
43Rayleigh Scattering
Scattering of white light from very small
objects depends strongly on the wavelength of the
light - short wavelengths are scattered most
easily
Light passing through more of the atmosphere is
scattered more.
The sun at noon appears pale yellow, and at
sunset it is red.
44Rayleigh Scattering
The sky appears blue, for the same reason as
we look up in the sky, we see light that has been
scattered by molecules. More blue light is
scattered than green or red, although some of
these colors are present as well. The result
we see unsaturated blue.
Red light keeps going over our heads and out
the other side of the atmosphere.
45Mie Scattering - Large Particles
Now consider the cigarette smoke that is exhaled.
Does it look blue?
Exhaled smoke tends to look pretty much white (or
gray).
Water condenses on the particles making them much
larger - scattering is independent of the
wavelength.
46Mie Scattering
Why are clouds white (cumulus clouds)?
Lots of large water droplets scatter light of
all wavelengths equally. Light is scattered
multiple time in traversing the cloud.
47Mie Scattering
- When the particles are larger than about
one-tenth of a wavelength. - The light scattered from one point of the
particle may well be out of phase with light
scattered from another point. The two beams then
interfere and the scattered-light intensity is no
longer symmetrical as in Rayleigh case.
48Mie Scattering
- Mies theory takes into account the size of
the particles, their refractive index, the
refractive index of the surrounding of the
particles, as well as the shape, dielectric
constant, and absorptivity of the particles,
leading to a series (in theory an infinite
number) of partial waves. In Rayleigh scattering,
only the first few terms need to be consider. Mie
scattering includes Rayleigh scattering as a
special case.
49Mie Scattering
- The ratio i/I0 in Mie scattering is
determined by Mie extinction coefficient, µ,
which gives
K, extinction factor, is the ratio of cross
section of the light affected by a particle to
the cross section of the particle. It is
generally larger than unity because of the
refractive index difference between particles and
the medium between them.
50Polarization
x
An x-polarized field
z
y
(Side view of wave)
51Polarization
y
y
y
x
x
x
Head-on view of polarization
52Polarization by Scattering
Rayleigh scattering in addition to
being wavelength dependent is also polarization
dependent (leads to polarized light).
53Polarization by Scattering
y
x
Scattering molecule
z
Electric field causes charge to oscillate
54Polarization by Scattering
55Raman Scattering
- High energy photon (with E hf, much greater
than DE hf vibrational energy transition)
scatters from a sample and gives rise to 2
shifted frequency components in the scattered
light one at ff and one at f-f. - Its as if part of the photon were absorbed
Efinal h(f-f)or the transition energy added
to the photon that leaves Efinal h(ff)
56Non-linear Stuff
- Suppose the incident E field is E Eocos(2pft)
and it interacts with the polarizability of the
molecule to produce an induced dipole - p(t) a(t) Eocos(2pft)
- But a(t) ao(t) a(t)cos(2pft) since the
vibrations of the molecule lead to a time varying
polarizability at natural frequency f - Therefore p(t) Eoao(t) a(t)cos(2pft)cos(2p
ft) Eoa(t)cos(2pft) Eoa(t)cos(2pft)cos(2pft
) - The first term oscillates in phase with the
incident light elastic (Rayleigh) scattering
well see later and represents the bulk of the
light the second term is the Raman scattering
term
57Raman term
- Using cosA cosB ½ cos(AB)cos(A-B)
- The Raman term can be re-written as
- ½ Eoa(t)cos2p(ff)t cos2p(f-f)t
Anti-Stokes
Stokes
58Raman Experiment
Very low scattered intensity need high
concentration, good collection optics, long cell,
cooled photomultiplier tube, long
experiments Calculate Df from laser line (laser
f not important) same info as IR absorption,
even using visible light and water as solvent
59Example Data
acetaminophen
Plotted Intensity vs 1/l wavenumber (cm-1)
60Raman Scattering
- Cascaded Raman Scattering, Stimulated Raman
Scattering. - Application
- Raman Scattering, nonlinear interaction between
incident light and lattice of solid state media
(Optical Branch), 10cm-1 to 103cm-1
61Brillouin Scattering
- Similar as Raman Scattering, nonlinear
interaction between incident light and lattice of
solid state media (Phonon Branch), lt10cm-1.
62Holography
63History of Holography
- Invented in 1948 by Dennis Gabor for use in
electron microscopy, before the invention of the
laser - Leith and Upatnieks (1962) applied laser light to
holography and introduced an important off-axis
technique
British physicist Dennis Gabor won the Nobel
Prize in physics in 1971.
64Conventional photography
- Conventional
- 2-d version of a 3-d scene
- Photograph lacks depth perception or parallax
- Film sensitive only to radiant energy
- Phase relation (i.e. interference) are lost
65Holographic photography
- Hologram
- Interfere wavefront of light from a scene with a
reference wave - Converts phase information into amplitude
information - Freezes and reconstruct the intricate wavefront
of light that carries all the original
information of the scene - holos Greek for whole message
- graphein Greek for write
66In-line (Gabor) Hologram
Recording
x
z
z0
Coherent source
Photographic plate
object
lens
- Object a small scattering objects on a
transparent background - transmitted wave - relatively strong uniform
plane wave
- complex amplitude R (a real constant)
(reference wave)
- scattered wave - a weak wave due to
transmittance variations - in the object
(object wave)
- complex amplitude O(x,y)-
67Recording
- Reference wave
- Object wave
- Intensity distribution on plate
68Linear development
- When developed the photographic plate will have a
transmittance which depends on the intensity
distribution in the recorded plate - tb background transmittance due to R2
term - B parameter which is a function of the
recording an developing process
69Hologram reconstruction
- When illuminated by a coherent wave, A(x,y),
known as the reconstruction wave, the optical
field emerging from the transparency is, - i.e. a superposition of 4 waves
- If A(x,y)R(x,y), i.e. reconstruction and
reference waves are identical,
70Hologram reconstruction
- Three terms in the reconstructed wave
Direct wave identical to reference wave except
for an overall change in amplitude
Object wave identical to object wave except for
a change in intensity
Conjugate wave complex conjugate of object wave
displaced by a phase angle 2 ?
71Hologram reconstruction
- Three terms in the reconstructed wave of the
point hologram
Direct wave identical to reference wave
(propagates along z) except for an overall change
in amplitude
- Conjugate wave spherical wave collapsing to a
point at a distance z to the right of the
hologram - a real image
- displaced by a phase angle 2kz
Object wave Spherical wave except for a change
in intensity Br2 i.e. reconstructed wavefront
72Direct, object and conjugate waves
Object wave
Reference wave
Real image
Virtual image
Direct wave
Conjugate wave
-z
z
z0
73Direct, object and conjugate waves
- Direct wave corresponds to zeroth order grating
diffraction pattern - Object wave gives virtual image of the object
(reconstructs object wavefront) first order
diffraction - Conjugate wave conjugate point, real image (not
useful since image is inside-out due to negative
phase angle) first order diffraction - In general, we wish to view only the object wave
the other waves just confuse the issue
74Off-axis (Leith-Upatnieks) Hologram
Leith Upatnieks (1962-64)
Recordings
x
z
q
Photographic plate
object
75Off-axis (Leith-Upatnieks) Hologram
Interference pattern on the photographic plate
With linear development, the photo plate has
transmittance
76Reconstruction of off-axis hologram
Directly transmitted wave
Halo
Original object wave(virtual image)
Conjugate real image
z
halo
Object wave is separable from the other waves.
Itovercome the major drawback of Gabors in-line
hologram
x
Hologram
Transmitted wave
Virtual image
Real image
77Fourier Hologram (Vander Lugt, 1964)
x
x
Recordings
Object O(x,y)
Photographic plate
reference
f
f
d(xb,y)
Complex amplitude of object wave at photographic
plate
O(x,y) complex amplitude of object leaving the
object plane F Fourier transform
78Record and Reconstruction
Reference wave at photographic plate
Intensity interference pattern at photographic
plate
Reconstructions
x
z
Fourier hologram
f
f
x
79Reconstruction
Complex amplitude in the back focal plane of the
lens
focus on the axis
halo around a focus
original object wave shifted downwards by a
distance b
conjugate of original object wave inverted and
shifted upwards by a distance b
where the symbol ? denotes the correlation
operation.
b
b
O(-xb,-y) conjugate inverted
O(x-b,y) original object
Direct halo
80Image Hologram
A hologram made by placing a photographic plate
near the location of the real image formed by a
lens.
d2
f
Image
object
photographic plate
d1
Gauss imaging condition (lens law)
The position of the reconstructed image is on the
hologram itself. Therefore, the distance from the
hologram to the image is very short consequently
image hologram is insensitive to the coherency of
the reconstructed beam. Application
White-light hologram
81Fraunhofer Hologram
x
x
z
object
photographic plate
z0
Object is small enough for its far-field
diffraction pattern (Fraunhofer diffraction)to be
formed at the photographic plate.
82Making a hologram
83Hologram Reflection vs. Transmission
- Transmission hologram reference and object waves
traverse the film from the same side - Reflection hologram reference and object waves
traverse the emulsion from opposite sides
View in Transmission
View in reflection
84Phase hologram
Amplitude(absorption) hologram
Phase modulations due to variation of refractive
index or thickness.
Amplitude modulations due to absorption changes
of photographic materials, Da(x) regime
Thin(or plane) hologram Raman-Nath diffraction
Thick (or volume) hologram Bragg diffraction
The thickness of the recording material is small
compared with the interference fringe spacing.
(L grating period)
L
L
d
cf. Q-parameter
Qlt1 thin hologram Qgt1 volume hologram
851-3. Thin Hologram
Thin phase hologram Thin amplitude hologram
- Complex amplitude transmittance
(a) Thin amplitude hologram
saptially varying
Recording
x
O(x,z)
L
q
z
q
R (x,z)
d
86where
grating wavevector (or grating period)
interference fringe spacing
where t0 average amplitude transmittance of
the grating t1 amplitude of spatial
variation
87Reconstructions
transmitted beam
incident
diffracted beam
(reference beam)
Diffraction efficiency h
Maximum diffracted amplitude is obtained when
t0t11/2 , i.e.
88Diffracted amplitudes
0th diffraction beam (directly transmitted)
-1st-order diffraction beam
1st-order diffraction beam
-1st-order diffraction beam
0th diffraction beam (directly transmitted)
1st-order diffraction beam
hmax for amplitude grating
89(b) Thin phase hologram
For phase grating (no loss),
- complex amplitude transmittance
- Complex amplitude transmittance of the grating
where Jn Bessel function of the first kind of
order n
A thin phase grating diffracts a wave incident on
hologram into a large number of orders.
q
Raman-Nath diffraction
q
Recording
Reconstruction
90- nth-order diffraction efficienty
- Only first-order diffracted wave contributes to
the desired image.
911-4. Volume Hologram
Typically,
Volume hologram
3-D system of layers
Reflection hologram
recording medium (bulk) ex) crystal
thick film
q10o
The diffracted amplitude is a maximum only when
the Bragg condition is satisfied.
Reflection hologram
reconstruction
recording
O
R
92(A) Coupled Wave Theory (A. Kogelnik, 1969)
Ref.gt Bell System Technical Journal, 48,
2909-2947 (1969) Coupled wave theory
for thick hologram gratings
Recordings
x
x
S(l0)
q0
z
q0
z
q0
q0
R(l0)
R(l0)
S(l0)
(a) Transmission volume grating
(b) Reflection volume grating
93Reconstructions
b
z
z
q
q
R(l)
S(l)
Vector diagram for Bragg incidence
(a) Volume transmission grating
x
S(l)
b
q
z
z
q
R(l)
(b) Volume reflection grating
94Assumed equations for gratings
- refractive index changes (phase hologram)
- absorption index changes (amplitude hologram)
where n0 and a0 average values of refractive
and absorption constant, respectively.
grating vector
where E total electric field k
spatially varying propagation constant in grating
95The propagation constant can be written a
where
coupling constant
Interaction between reference wave R and signal
wave S.
For k0, no modulation of phase or absorption
gratings and hence, no diffraction.
- Total electric-field E in the grating
where
propagation vectors for two waves with
Derivation of coupled wave equations
Substituting total E-field into wave equation and
comparing the terms involving and
96We get
terms
terms
where (prime) denote differentiation w, r, f, z
Note that term is
introduced for non-Bragg condition.
- Define dephasing measure as
for transmission grating
for reflection grating
where
and
recording(writing) wavelength
reading wavelength
It is useful parameter for evaluating the effects
of deviations from the Bragg condition.
97- Slowly-varying Amplitude Approximation(SVAA)
and
(i.e. energy interchange between R and S is
small.)
Coupled wave equations
where obliquity factors
for transmission hologram
for reflection hologram
Coupled wave equations can be solved for the
appropriate boundary conditions.
- Transmission hologram R(0)1, S(0)0
- Reflection hologram R(0)1, S(d)0
Trial solution
98(B) (volume) Transmission Holograms
(i) Pure Phase Holograms
For pure phase hologram, a0a10
where
For incidence at Bragg condition, x0
- Diffraction efficiency at Bragg condition
99- When the angle of incidence or the wavelength of
the incident beam deviates from the values of
Bragg condition, the diffraction efficiency is
given by
where or
100(ii) Pure phase hologram with loss
For a lossy phase grating ( ),
101(iii) Amplitude Hologram
For a pure amplitude hologram,
where
Diffraction efficiency
0.04
a0a1
For incidence at Bragg angle, x0, the
diffraction efficiency is
1.0 2.0 3.0
where a0a1
102(iv) Mixed Holograms
103(C) (volume) Reflection Holograms
(i) Pure Phase Hologram
For non-Bragg incidence, diffraction amplitude
where
1
For Bragg incidence,
1.0 2.0 3.0
104(ii) Amplitude Holograms
where
For Bragg incidence
For the special case of a0a1,
105Theoretical Maximum Diffraction Efficiency
Hologram Type
Thin Transmission
Volume Transmission
Volume Reflection
Modulation
Amplitude
Phase
Amplitude
Phase
Amplitude
Phase
h()
6.25
33.9
3.7
100
7.2
100
106Volume Holography
- In volume holography, we apply an object beam and
a reference beam simultaneously on a
photosensitive material that records the
interference pattern. - Applying one of these beams to the resultant
recording recreates the other.
107Bragg Selectivity
- The hologram is sensitive to the exact recreation
of the reference beam. A change in angle,
position, or wavelength of the beam will lead to
a failure to reconstruct the image. - The sensitivity increases with thickness of the
holographic material.
108Multiplexing
- This can be used to our advantage. We record one
object image with our hologram. - We then change the beam angle, wavelength, or
position, until the image disappears, and record
another image in the holographic material. - By this method, multiple object images may be
stored in a single piece of holographic material.
109Storing Data
- We can convert binary data to an array of
black-and-white pixels with a spatial light
modulator (SLM). - We can store multiple pages of data in our
holographic crystal. - We can then read back out our pages via the
reference beam.
110Multiplexing Methods
- Angle one changes the angle of the reference
beam. - Wavelength one changes the wavelength of the
reference beam. - Shift one changes the position of the
holographic material relative to the beams. - Coherence one changes the position of the
material and the coherence function of the
reference beam.
111? ? ? ?
1121. Optical source and laser
2. Physical Process in lasing medium
3. Population Inversion
4. Components of laser
113Sources of Radiation
- In order to be suitable for spectroscopic
studies, a source must generate a beam of
radiation with sufficient power for easy
detection and measurement and its output power
should be stable for reasonable periods. Sources
are of two types. - 1. Continuum sources
- 2. Line Sources
114(No Transcript)
115- Continuum Sources
- Continuum sources emit radiation that changes in
intensity slowly with wavelength. It is widely
used in absorption and fluorescence spectroscopy.
For the ultraviolet region, the most common
source is the deuterium lamp. High pressure gas
filled arc lamps that contain argon, xenon, or
mercury serve when a particular intense source is
required. For the visible region of the spectrum,
the tungsten filament lamp is used universally.
The common infrared sources are inert solids
heated to 1500 to 2000 K.
116- Line Sources
- Sources that emit a few discrete lines find wide
use in atomic absorption spectroscopy, atomic and
molecular fluorescence spectroscopy, and Raman
spectroscopy. Mercury and sodium vapor lamps
provide a relatively few sharp lines in the
ultraviolet and visible regions and are used in
several spectroscopic instruments. Hollow cathode
lamps and electrodeless discharge lamps are the
most important line sources for atomic absorption
and fluorescence methods.
117Laser Sources
- The term LASER is an acronym for Light
Amplification by Stimulated Emission of
Radiation. Laser are highly useful because of
their very high intensities, narrow bandwidths,
single wavelength, and coherent radiation. Laser
are widely used in high-resolution spectroscopy.
118Characteristics of Laser
(a) ????
?????????????????604.7nm, ??????0.00047nm,
He-Ne??
(b) ???????
??P100????? W 100??, t1?.
? t10-11?, ?P1015??. ? t10-15sec, then
119(c) ?????,????
????,???360?, ??????1/10?.
(d) ???
??????????????,??????????????????????10??.
(e) ????
??????????, ???????????.???????????????????.
120- Laser Examples
- Solid state
- NdYAG1064 nm IR 523 nm green, cw/pulsed
- Gas
- He-Ne 632.8 nm red, cw
- Ar 488 nm (blue) or 514.5 nm (green) also UV
lines, cw (4-level system - Dye
- Organic dye solutions ? tunable outputs (various
distinct ?s), pulsed (4-level system)
121- Laser Examples
- Semiconductor laser
- Free electrons laser
Application of Laser
????,????,???,????, ????????.????.????, ????,
????.
????, ????,????.
???????,?????.
?????.????.???.
122- Four processes in Lasing Mechanism
- 1. Pumping
- 2. Spontaneous emission (fluorescence)
- 3. Stimulated emission
- 4. Absorption
123- Pumping
- Molecules of the active medium are excited to
higher energy levels - Energy for excitation ? electrical, light, or
chemical reaction
124(No Transcript)
125- 2. Spontaneous Emission
- A molecule in an excited state can lose excess
energy by emitting a photon (this is
fluorescence) - E h? hc/? E Ey Ex
- E (fluorescence) lt E (absorption) ?
- ? (fluorescence) gt ? (absorption) fluorescent
light is at longer wavelength than excitation
light
126(No Transcript)
127- 3. Stimulated Emission
- Must have stimulated emission to have lasing
- Excited molecules interact with photons produced
by emission - Collision causes excited molecules to relax and
emit a photon (i. e., emission) - Photon energy of this emission photon energy of
collision photon ? now there are 2 photons with
same energy (in same phase and same direction)
128(No Transcript)
129- 4. Absorption
- Competes with stimulated emission
- A molecule in the ground state absorbs photons
and is promoted to the excited state - Same energy level as pumping, but now the photons
that were produced for lasing are gone
130(No Transcript)
131- Population Inversion
- Must have population inversion to sustain lasing.
- Population of molecules is inverted (relative to
how the population normally exists). - Normally there are more molecules in the ground
state than in the excited state (need gt 50 ). - Population inversion More molecules in the
excited state than in the ground state.
132- Why is it important?
- More molecules in the ground state ? more
molecules that can absorb photons - Remember absorption competes with stimulated
emission - Light is attenuated rather than amplified
- More molecules in the excited state ? net gain in
photons produced
133(No Transcript)
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??????????T,???En??????Nn, ?
K???????,?????????????????, g n??????n ??? (???E
n)???.
(????????????????.)
N1?????E1????,
N2?????E2????,
E2gtE1,?1???,2???????
135?
????,?????????????????? ????.?
???????????
136?????
E2????????dt????????E1????????-dN2 ,?
A21??????E2???E1???????.??
?????,?
137?
??
????????, ????????E2??????????,??????????????,
????(?????),??????????????
???????????????,??????????10-8,???10-31??????,
????.
??????????????,?????????????(10-8)??????.
138??????
?dN21?dt????E2?????E1???????,?
??????????????,?????????????????????????????.??
??????.
139???????, ?????,????????????????????????????.??
?
??
????????
140??????
????????,?
?????????h?/kT?????,????????.
141?
???????????????,?????????????,????????????.
B12 ????????E1?????E2??????,
B21 ????????E2?????E1??????.
142?????????
???????,????????,??????????,????????????.
??????????,????. ?????????????????????????????
,?????????,??,?????.
dt ?????????
dt ???????????
143????
?
????.
?????,???????,??
???????????.
??????????,????????,??????????????,?????????.
144- How to achieve population inversion?
- Laser systems 3-level or 4-Level
- 4-level is better ? easier to sustain population
inversion - 3-level system lasing transition is between Ey
(excited state) and the ground state - 4-level system lasing transition is between two
energy levels (neither of which is ground state) - All you need is to have more molecules in Ey than
Ex for population inversion (4-level system) ?
easier to achieve than more molecules in Ey than
ground state (3-level system)
145(No Transcript)
146????????????
(a) ?????
?????? ?694.3nm
?????
147 ????????, ??????????????????E3,?????????E3????
????10-1110-8,???????????E2????
E2????, ????10-31??E2??????????,
???????????????????
???????.
E1?E2??????????????.
???????????.??????.
148 (b)????? He-Ne??????
149 He?????????,3s?1s?????????????????,???3s?1s???
????.
Ne???2s?3s???He???3s?1s????,??,?????????He??????
????Ne?????,?????????????.?????,??3s?3p,
2s?2p????????,??3p?2p????????,??,??3s?2s??????,???
???.
150Components of Lasers
(1) ????(?????).
(2) ????.
(3) ?????.
151- Component of Lasers
- The important components of laser source are
lasing medium, pumping source, and mirrors. The
heart of the device is the lasing medium. It may
be a solid crystal such as ruby, a semiconductor
such as gallium arsenide, a solution of an
organic dye or a gas such as argon or krypton.
152(No Transcript)
153??????
(1)???????
????????????????
???????????,
154(2) ????????
??
????????.
????,??????????.
????????
??????
????
????
155(3) ??????????????
?????
156?????????
????G??????????????????.
X
??????????
N2gtN1?,G?? N2ltN1?,G??
157????
????????,????????
? ?????????,?????
? ??????, ?????,??????.
??,?????,???????????????????,????????????????.
158gt1,???
lt1,???
1,??????
GM??????????.?GgtGM?,??????????,??????,??????.
?????,????????????????????,???????????,G??,?G?GM?,
??????.