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Computer System Security CSE 5339/7339

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Computer System Security CSE 5339/7339 Lecture 4 August 31, 2004 Contents Encryption Substitution and Transposition Ciphers Symmetric and Asymmetric Enciption Merkle ... – PowerPoint PPT presentation

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Title: Computer System Security CSE 5339/7339


1
Computer System SecurityCSE 5339/7339
Lecture 4 August 31, 2004
2
Contents
  • Encryption
  • Substitution and Transposition Ciphers
  • Symmetric and Asymmetric Enciption
  • Merkle-Hellman Knapsacks
  • Murtazas Presentation

3
Exercise (Group work)
Decrypt the following encrypted
quotation fqjcb rwjwj vnjax bnkhj whxcq
nawjv nfxdu mbvnu ujbbf nnc
4
Non-Repeating Series of Numbers
Non-repeating series of numbers
Encryption
Decryption
ciphertext
plaintext
Original plaintext
5
One-Time Pads
  • Name ? set of sheets of paper with keys, glued
    into a pad
  • The sender would tear off enough number of pages
  • The receiver needs a pad identical to the one
    used by the sender

6
One-Time Pads (cont.)
  • The sender would write the keys one at a time
    above the letters of the plaintext.
  • K1 k2 k3 k4 ... Kn
  • p1 p2 p3 p4 ... pn
  • The plaintext is enciphered using a pre-arranged
    chart (Vignere Tableau) all 26 letters in each
    column in some scrambled order
  • select the substitution in row pi, column Ki
  • Problems
  • Unlimited number of keys Absolute
    synchronization between sender and receiver

7
Vernam Cipher
  • Plaintext
  • V E R N A M C I P H E R
  • 21 4 17 13 0 12 2 8 15 7 4 17
  • Random numbers
  • 76 48 16 82 44 3 58 11 60 5 48 88
  • Sum
  • 97 52 33 95 44 15 60 19 75 12 52 105
  • Sum mod 26
  • 19 0 7 17 18 15 8 19 23 12 0 1
  • Ciphertext
  • t a h r s p i t x m a b

8
Book Ciphers
  • Both sender and receiver need access to identical
    objects
  • Example telephone book xxx-xxx-xxxx (use xx
    mod 26 as a key)
  • Problem High frequency letters
  • A, E, O, T ? 40 of all letters used in Standard
    English text
  • A, E, O, T, N, I ? 50 of all letters used in
    Standard English text
  • The probability that the key letter and plain
    text letter is in these 6 letters is
  • 0.25

9
Transposition (Diffusion)
  • The letters of the message are rearranged
  • Columnar transposition
  • Example
  • THIS IS A MESSAGE TO SHOW HOW A COLMUNAR
    TRANSPOSITION WORKS

10
  • T H I S I
  • S A M E S
  • S A G E T
  • O S H O W
  • H O W A C
  • O L M U N
  • A R T R A
  • N S P O S
  • I T I O N
  • W O R K S
  • tssoh oaniw haaso lrsto imghw utpir seeoa mrook
    istwc nasna

11
Stream and Block Ciphers
  • Stream ? converts one symbol of plaintext into a
    symbol of ciphertex
  • Block ? encrypts a group of plaintext symbols as
    one block.

12
Symmetric Encryption Systems (Secret Key)
  • Both sender and receiver share one key
  • Encryption and decryptions algorithms are closely
    related
  • N (N-1) /2 keys are needed for N users to
    communicate in pairs
  • Key must be kept secret

13
Asymmetric Encryption Systems (public Key)
  • One key must be kept secret, the other can be
    freely exposed private key and public key
  • Only the corresponding private key can decrypt
    what has been encrypted using the private key

14
Merkle-Hellman Knapsacks (Chapter 10)
  • Algorithms is based on the knapsack problem
  • What is the knapsack problem?
  • General Knapsacks
  • Superincreasing knapsacks

15
General Knapsacks (Hard)
Given a sequence of integers a1, a2, , an and a
target sum T, the problem is to find a vector of
0s and 1s such that the sum of the integers
associated with 1s equals T S 17, 38, 73, 4,
11, 1 T 53 Solution (0,1,0,1,1,0)
16
Superincreasing Knapsacks (Easy)
We place an additional restriction on the
problem The integers of S must form an
superincresaing Sequence. (I.e. each integer is
greater than the sum of all preceding
integers) S 1, 4, 11, 17, 38, 73 Algorithm?
(Students participation)
17
Group Work
S 1, 4, 11, 17, 38, 73 Algorithm? Try it
with T 96 T 95
18
Knapsack Problem as a Public Key Algorithm
Public Key Set of integers of a knapsack
problem Private Key Corresponding
superincreasing knapsack
19
Math Background
Identity i is identity for op if i op x x op i
x Inverse b is inverse of a if a op b b op a
i Prime Number Any number greater than 1 that
is divisible only by itself and 1 2 divides
10 10 is divisible by 2 Composite vs. prime
20
Math Background (cont.)
Greatest Common Divisor gcd(a,b) The largest
integer that divides both a and b gcd(15,10)
5 If p is a prime number gcd(p.q) 1 for any q
lt p If x divides a and b ? x also divides a
(kb)
21
Modular Arithmetic
  • Reminder after division
  • a mod n b ? a cn b (11 mod 3 2, 5 mod 3
    2)
  • Confine results to a particular range 0 n-1
  • Operations , -, can be applied before or after
    mod is taken
  • x and y are equivalent under mod n iff x mod n
    y mod n
  • x and y are equivalent under mod n iff x y
    kn

22
Modular Arithmetic (cont)
  • Multiplicative inverse of a ? a-1

0 1 2 3 4
0 0 0 0 0 0
1 0 1 2 3 4
2 0 2 4 1 3
3 0 3 1 4 2
4 0 4 3 2 1
Product mod 5 a 2, a-1 3
23
Fermats Theorem
For any prime p and any element a lt p ap mod p
a Or ap-1 mod p 1 The inverse of a is x
such that ax mod p 1 ap-1 mod p x ap-2
mod p
24
Example
Compute the inverse of 3 mod 5 x 35-2 mod 5 x
27 mod 5 2
25
Merkle- Hellman Knapsack (again)
Idea ? is to encode a binary message as a
solution to a knapsack problem, reducing the
ciphertext to the target sum obtained by adding
terms corresponding to 1s in the plain
text. Public Key Set of integers of a knapsack
problem Private Key Corresponding
superincreasing knapsack Technique for
converting a superincreasing knapsack into
regular one!
26
Merkle- Hellman Knapsack (cont)
  • Normal arithmetic ? or preserve
    superincreasing sets
  • Modular arithmetic ? may destroy superincreasing
    sets
  • Modular arithmetic ? sensitive to common factors
  • Consider w x mod n
  • If w and n share common factors ? not all values
    0-n-1
  • Otherwise (relatively prime) ? all values
  • (If w and n are relatively prime, w has
    multiplicative inverse mod n)

27
Example
x 3 x mod 5 3 x mod 6
1 3 3
2 1 0
3 4 3
4 2 0
5 0 3
28
Breaking the superincreasing nature of integer
  • Multiple by w and take mod n
  • n and w are relatively prime.
  • Select S
  • Select w and n, n gt summation of si
  • Obtain H (hi w si mod n)

29
Example (Encryption)
  • S 1, 2, 4, 9
  • w 15, n 17
  • H 15, 13, 9, 16
  • P ? 0100 1011 1010 0101
  • C ? 13 40 24 29
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