Solutions: 2001 D

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Solutions2001 D

• By
• I Schnizzle

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2001 D Part A

• .1M Pb(NO3)2 /.1M NaCl /.1M KMnO4 /.1M C2H5OH /
  .1M KC2H3O2
• A.) Which solution has the highest boiling point?
  Explain
• The answer to this question can be found by
  referring back to the bond strengths within each
  of these solutions.
• The bond strength of any of these solutions
  determines how high or low the boiling point will
  be.

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2001 D Part A Cont

• Since bonds within ionic compounds are stronger
  than those within covalent compounds the .1M of
  C2H5OH is out.
• Than looking at your other four solutions which
  are ionic Pb(NO3)2 has the most ions of the
  remaining four solutions there for it will have
  the highest boiling point.

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2001 D Part B

• .1M Pb(NO3)2 /.1M NaCl /.1M KMnO4 /.1M C2H5OH /
  .1M KC2H3O2
• B.) Which solution has the highest pH? Explain
• The pH level of any solution is determined by how
  basic or acidic the solution is.
• If a solution has a weak acid and a salt it will
  form a more basic solution. This goes for a salt
  and weak base as well except the solution would
  be more acidic

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2001 D Part B Cont

• KC2H3O2 is the solution that will have the
  highest pH based on the weak acid and salt it
  has.
• When KC2H3O2 is added to H2O the compound will
  dissociate and the weak acid and salt, K in this
  case will form new compounds.
• With the new compound formed from the weak acid
  the new solution will be more basic, and in turn
  have higher pH.

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2001 D Part C

• .1M Pb(NO3)2 /.1M NaCl /.1M KMnO4 /.1M C2H5OH /
  .1M KC2H3O2
• C.) Identify a pair of solutions that would
  produce a precipitate when mixed together. Write
  the formula of the precipitate.
• In order to complete this question you must first
  have a general understanding of your solubility
  rules.

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2001 D Part C Cont

• After looking over your solubility rules you will
  find that Pb2 does not tend to dissolve with
  most salts.
• Therefore the solutions of Pb(NO3)2 and NaCl are
  good solutions that will form a precipitate since
  the ions will form new compounds one of which is
  PbCl2 which is insoluble.

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2001 D Part C Cont

• The equation for this new precipitate formed
  would be as follows.
• Pb(NO3)2 NaCl yields NaNO3 PbCl2
• After balancing this equation the final balanced
  equation would be Pb(NO3)2 2NaCl yields 2NaNO3
  PbCl2
• Where the PbCl2 is the precipitate formed and is
  also the formula of the precipitate.

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2001 D Part D

• .1M Pb(NO3)2 /.1M NaCl /.1M KMnO4 /.1M C2H5OH /
  .1M KC2H3O2
• Which solution could be used to oxidize the
  Cl-(aq) ion? Identify the product of the
  oxidation.
• In order to oxidize something the charge on the
  ion becomes more positive so the goal is to find
  a solution that allows for Cl-s charge to become
  more positive.

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2001 D Part D Cont

• KMnO4 is a perfect solution for this oxidation to
  occur because once the ions of the KMnO4 are
  broken down they will oxidize the Cl- the most.
• This oxidation occurs and forms the product of
  ClO3- which gives the Cl- a more positive charge
  of 5

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2001D Part E

• .1M Pb(NO3)2 /.1M NaCl /.1M KMnO4 /.1M C2H5OH /
  .1M KC2H3O2
• E.) Which solution would be the least effective
  conductor of electricity? Explain.
• First of all good conductors of electricity are
  compounds that have ionic bonds within them as
  opposed to covalent bonds.
• So we are looking for a covalent bonded compound
  since that would be the least effective solution
  to conduct electricity.

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2001D Part E Cont

• C2H5OH is the only compound that has covalent
  bonds and therefore does not form any ions in
  H2O.
• Since H2O is also covalently bonded the solution
  would be the least likely to be a good conductor
  of electricity.

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BAM!

• The End