Welcome to Physics I !!! - PowerPoint PPT Presentation

About This Presentation
Title:

Welcome to Physics I !!!

Description:

Physics I 95.141 LECTURE 17 11/8/10 ... Center of Mass (2D, 2 particles) For two particles lying in the x-y plane, we can find the center of mass ... – PowerPoint PPT presentation

Number of Views:143
Avg rating:3.0/5.0
Slides: 38
Provided by: Facult134
Learn more at: https://faculty.uml.edu
Category:
Tags: center | mass | physics | welcome

less

Transcript and Presenter's Notes

Title: Welcome to Physics I !!!


1
Physics I95.141LECTURE 1711/8/10
2
Outline/Administrative Notes
  • Notes
  • HW Review Session on 11/17 shifted to 11/18.
  • Last day to withdraw with a W is 11/12 (Friday)
  • Outline
  • Ballistic Pendulums
  • 2D, 3D Collisions
  • Center of Mass and translational motion

3
Ballistic Pendulum
  • A device used to measure the speed of a
    projectile.

m
h
M
Mm
vo
v1
4
Ballistic Pendulum
m
Mm
M
vo
v1
5
Ballistic Pendulum
Mm
h
Mm
v1
6
Exam Prep Problem
  • You construct a ballistic pendulum out of a
    rubber block (M5kg) attached to a horizontal
    spring (k300N/m). You wish to determine the
    muzzle velocity of a gun shooting a mass (m30g).
    After the bullet is shot into the block, the
    spring is observed to have a maximum compression
    of 12cm. Assume the spring slides on a
    frictionless surface.
  • A) (10pts) What is the velocity of the block
    bullet immediately after the bullet is embedded
    in the block?
  • B) (10pts) What is the velocity of the bullet
    right before it collides with the block?
  • C) (5pts) If you shoot a 15g mass with the same
    gun (same velocity), how far do you expect the
    spring to compress?

7
Exam Prep Problem
  • k300N/m, m30g, M5kg, ?xmax12cm
  • A) (10pts) What is the velocity of the block
    bullet immediately after the bullet is embedded
    in the block?

8
Exam Prep Problem
  • k300N/m, m30g, M5kg, ?xmax12cm
  • B) (10pts) What is the velocity of the bullet
    right before it collides with the block?

9
Exam Prep Problem
  • k300N/m, m30g, M5kg, ?xmax12cm
  • C) (5pts) If you shoot a 15g mass with the same
    gun (same velocity), how far do you expect the
    spring to compress?

10
Collisions
  • In the previous lecture we discussed collisions
    in 1D, and the role of Energy in collisions.
  • Momentum always conserved!
  • If Kinetic Energy is conserved in a collision,
    then we call this an elastic collision, and we
    can write
  • Which simplifies to
  • If Kinetic Energy is not conserved, the collision
    is referred to as an inelastic collision.
  • If the two objects travel together after a
    collision, this is known as a perfectly inelastic
    collision.

11
Collision Review
  • Imagine I shoot a 10g projectile at 450m/s
    towards a 10kg target at rest.
  • If the target is stainless steel, and the
    collision is elastic, what are the final speeds
    of the projectile and target?

12
Collision Review
  • Imagine I shoot a 10g projectile at 450m/s
    towards a 10kg target at rest.
  • If the target is wood, and projectile embeds
    itself in the target, what are the final speeds
    of the projectile and target?

13
Additional Dimensions
  • Up until this point, we have only considered
    collisions in one dimension.
  • In the real world, objects tend to exist (and
    move) in more than one dimension!
  • Conservation of momentum holds for collisions in
    1, 2 and 3 dimensions!

14
2D Momentum Conservation
  • Imagine a projectile (mA) incident, along the
    x-axis, upon a target (mB) at rest. After the
    collision, the two objects go off at different
    angles
  • Momentum is a vector, in order for momentum to be
    conserved, all components (x,y,z) must be
    conserved.

15
2D Momentum Conservation
  • Imagine a projectile (mA) incident, along the
    x-axis, upon a target (mB) at rest. After the
    collision, the two objects go off at different
    angles

16
Conservation of Momentum (2D)
  • Solving for conservation of momentum gives us 2
    equations (one for x-momentum, one for
    y-momentum).
  • We can solve these if we have two unknowns
  • If the collision is elastic, then we can add a
    third equation (conservation of kinetic energy),
    and solve for 3 unknowns.

17
Example problem
  • A cue ball travelling at 4m/s strikes a billiard
    ball at rest (of equal mass). After the
    collision the cue ball travels forward at an
    angle of 45º, and the billiard ball forward at
    -45º. What are the final speeds of the two balls?

18
Example Problem II
  • Now imagine a collision between two masses
    (mA1kg and mB2kg) travelling at vA2m/s and vB
    -2m/s along the x-axis. If mA bounces back at an
    angle of -30º, what are the final velocities of
    each ball?

19
Example Problem II
  • Now imagine a collision between two masses
    (mA1kg and mB2kg) travelling at vA2m/s and vB
    -2m/s on the x-axis. If mA bounces back at an
    angle of -30º, what are the final velocities of
    each ball, assuming the collision is elastic?

20
Simplification of Elastic Collisions
  • In 1D, we showed that the conservation of Kinetic
    Energy can be written as
  • This does not hold for more than one dimension!!

21
Problem Solving Collisions
  1. Choose your system. If complicated (ballistic
    pendulum, for example), divide into parts
  2. Consider external forces. Choose a time interval
    where they are minimal!
  3. Draw a diagram of pre- and post- collision
    situations
  4. Choose a coordinate system
  5. Apply momentum conservation (divide into
    component form).
  6. Consider energy. If elastic, write conservation
    of energy equations.
  7. Solve for unknowns.
  8. Check solutions.

22
Center of Mass
  • Conservation of momentum is powerful for
    collisions and analyzing translational motion of
    an object.
  • Up until this point in the course, we have chosen
    objects which can be approximated as a point
    particle of a certain mass undergoing
    translational motion.
  • But we know that real objects dont just move
    translationally, they can rotate or vibrate
    (general motion) ? not all points on the object
    follow the same path.
  • Point masses dont rotate or vibrate!

23
Center of Mass
  • We need to find an addition way to describe
    motion of non-point mass objects.
  • It turns out that on every object, there is one
    point which moves in the same path a particle
    would move if subjected to the same net Force.
  • This point is known as the center of mass (CM).
  • The net motion of an object can then be described
    by the translational motion of the CM, plus the
    rotational, vibrational, and other types of
    motion around the CM.

24
Example
F
F
F
F
25
Center of Mass
  • If you apply a force to an non-point object, its
    center of mass will move as if the Force was
    applied to a point mass at the center of mass!!
  • This doesnt tell us about the vibrational or
    rotation motion of the rest of the object.

26
Center of Mass (2 particles, 1D)
  • How do we find the center of mass?
  • First consider a system made up of two point
    masses, both on the x-axis.

xB
mA
xA
x0
xB
x-axis
27
Center of Mass (n particles, 1D)
  • If, instead of two, we have n particles on the
    x-axis, then we can apply a similar formula to
    find the xCM.

28
Center of Mass (2D, 2 particles)
  • For two particles lying in the x-y plane, we can
    find the center of mass (now a point in the xy
    plane) by individually solving for the xCM and
    yCM.

29
Center of Mass (3D, n particles)
  • We can extend the previous CM calculations to
    n-particles lying anywhere in 3 dimensions.

30
Example
  • Suppose we have 3 point masses (mA1kg, mB3kg
    and mC2kg), at three different points
    A(0,0,0), B(2,4,-6) and C(3,-3,6).

31
Solid Objects
  • We can easily find the CM for a collection of
    point masses, but most everyday items arent made
    up of 2 or 3 point masses. What about solid
    objects?
  • Imagine a solid object made out of an infinite
    number of point masses. The easiest trick we can
    use is that of symmetry!

32
CM and Translational Motion
  • The translational motion of the CM of an object
    is directly related to the net Force acting on
    the object.
  • The sum of all the Forces acting on the system is
    equal to the total mass of the system times the
    acceleration of its center of mass.
  • The center of mass of a system of particles (or
    objects) with total mass M moves like a single
    particle of mass M acted upon by the same net
    external force.

33
Example
  • A 60kg person stands on the right most edge of a
    uniform board of mass 30kg and length 6m, lying
    on a frictionless surface. She then walks to the
    other end of the board. How far does the board
    move?

34
Solid Objects (General)
  • If symmetry doesnt work, we can solve for CM
    mathematically.
  • Divide mass into smaller sections dm.

35
Solid Objects (General)
  • If symmetry doesnt work, we can solve for CM
    mathematically.
  • Divide mass into smaller sections dm.

36
Example Rod of varying density
  • Imagine we have a circular rod (r0.1m) with a
    mass density given by ?2x kg/m3.

x
L2m
37
Example Rod of varying density
  • Imagine we have a circular rod (r0.1m) with a
    mass density given by ?2x kg/m3.

x
L2m
Write a Comment
User Comments (0)
About PowerShow.com