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Arithmetic and Geometric Sequences

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Title: Arithmetic and Geometric Sequences


1
Arithmetic and Geometric Sequences
  • Explicit Formulas

2
  • A "sequence" (or "progression", in British
    English) is an ordered list of numbers the
    numbers in this ordered list are called
    "elements" or "terms".

3
  • A sequence may be named or referred to as "A" or
    "An". The terms of a sequence are usually named
    something like "ai" or "an", with the subscripted
    letter "i" or "n" being the "index" or counter.
    So the second term of a sequence might be named
    "a2" (pronounced "ay-sub-two"), and "a12" would
    designate the twelfth term.
  • Note Sometimes sequences start with an index of
    n 0, so the first term is actually a0. Then the
    second term would be a1. The first listed term in
    such a case would be called the "zero-eth" term.
    This method of numbering the terms is used, for
    example, in Javascript arrays. Don't assume that
    every sequence and series will start with an
    index of n 1.

4
Arithmetic Sequences
  • The two simplest sequences to work with are
    arithmetic and geometric sequences. An arithmetic
    sequence goes from one term to the next by always
    adding (or subtracting) the same value.
  • For instance, 2, 5, 8, 11, 14,... and 7, 3, 1,
    5,... are arithmetic, since you add 3 and
    subtract 4, respectively, at each step.

5
  • The number added (or subtracted) at each stage of
    an arithmetic sequence is called the "common
    difference" d, because if you subtract (find the
    difference of) successive terms, you'll always
    get this common value.

Find the common difference and the next term of
the following sequence 3, 11, 19, 27, 35,...
The difference is always 8, so d 8. Then the
next term is 35 8 43.
6
  • For arithmetic sequences, the common difference
    is d, and the first term a1 is often referred to
    simply as "a". Since you get the next term by
    adding the common difference, the value of a2 is
    just a d. The third term is a3 (a d) d
    a 2d. The fourth term is a4 (a 2d) d a
    3d.

an a1 (n  1)d
7
Examples Find a formula for an and find the
10th term
  • 2,6,10,14,18,
  • 17,10,3,-4,-11,-18,

8
Examples
  • Find the n-th term (formula) and the first three
    terms of the arithmetic sequence having a4 93
    and a8 65.

Since a4 and a8 are four places apart, then I
know from the definition of an arithmetic
sequence that a8  a4  4d.
65 93 4d 28 4d 7 d
65 a 7(7) 65 49 a 114 a
93 a 3(7) 93 21 a 114 a
OR
9
Solution
  • an114(n-1)(-7)
  • 114-7n7
  • an121-7n
  • a1114, a2107, a3100

10
Examples
  • Find the n-th term (formula) and the tenth term
    of the arithmetic sequence having a2 2 and a5
    16.
  • an-8/3(n-1)(14/3)
  • an 14/3n-22/3
  • a10118/3

11
Geometric Sequences
  • A geometric sequence goes from one term to the
    next by always multiplying (or dividing) by the
    same value.
  • So 1, 2, 4, 8, 16,... and 81, 27, 9, 3, 1,
    1/3,... are geometric, since you multiply by
    2 and divide by 3, respectively, at each step

12
  • The number multiplied (or divided) at each stage
    of a geometric sequence is called the "common
    ratio" r, because if you divide (find the ratio
    of) successive terms, you'll always get this
    common value.

Find the common ratio and the seventh term of the
following sequence 2/9, 2/3, 2, 6, 18,...
The ratio is always 3, so r 3. Then the sixth
term is (18)(3) 54 and the seventh term is
(54)(3) 162
13
  • For geometric sequences, the common ratio is r,
    and the first term a1 is often referred to simply
    as "a". Since you get the next term by
    multiplying by the common ratio, the value of
    a2 is just ar. The third term is a3 r(ar)
    ar2. The fourth term is a4 r(ar2) ar3.

an a1r(n 1)
14
Examples Find a formula for an and find the
10th term
  • 1,3,9,27,81,
  • 64,-32,16,-8,4,

15
Example
  • Find the n-th (formula) and the 26th term of the
    geometric sequence with a5 5/4 and a12 160.

These two terms are 12  5 7 places apart, so,
from the definition of a geometric sequence, I
know that a12a5r7
160 (5/4)(r7) 128 r7 2 r
5/4 a(24) 16a 5/64 a
160 a(211) 2048a 160/2048 5/64 a
OR
16
Solution
  • an5/64(2)(n-1)
  • an5/128(2)n
  • a262,621,440

17
Example
  • Find the n-th (formula) and the 11th term of the
    geometric sequence with a3 12 and a6 96.
  • an3(2)(n-1)
  • an3/2(2)n
  • a113072
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