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Gauss

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Title: Gauss


1
Chapter 21
  • Gausss Law

2
Electric Field Lines
  • Electric field lines (convenient for visualizing
    electric field patterns) lines pointing in the
    direction of the field vector at any point
  • The electric field vector is tangential to the
    electric field lines at each point
  • The number of lines per unit area through a
    surface perpendicular to the lines is
    proportional to the strength of the electric
    field in a given region

3
Electric Field Line Patterns
  • For a positive point charge the lines will
    radiate outward equally in all directions
  • A positive test charge would be repelled away
    from the positive source charge
  • For a negative point charge the lines will point
    inward equally in all directions
  • A positive test charge would be attracted toward
    the negative source charge

4
Electric Field Line Patterns
  • An electric dipole consists of two equal and
    opposite point charges
  • The number of field lines leaving the positive
    charge equals the number of lines terminating on
    the negative charge
  • For two equal but like point charges, at a great
    distance from the charges, the field would be
    approximately that of a single charge of 2q
    (bulging out of the field lines between the
    charges repulsion)

5
Electric Field Line Patterns
  • For these two unequal and unlike point charges,
    at a great distance from the charges, the field
    would be approximately that of a single charge of
    q (two lines leave the 2q charge for each line
    that terminates on -q)

6
Rules for Drawing Electric Field Lines
  • For a group of charges, the lines must begin on
    positive charges and end on negative charges
  • In the case of an excess of charge, some lines
    will begin or end infinitely far away
  • The number of lines drawn leaving a positive
    charge or ending on a negative charge is
    proportional to the magnitude of the charge
  • No two field lines can cross each other

7
Electric Flux
  • Electric flux is the product of the magnitude of
    the electric field and the surface area, A,
    perpendicular to the field
  • FE EA

8
Electric Flux
  • The electric flux is proportional to the number
    of electric field lines penetrating some surface
  • The field lines may make some angle ? with the
    perpendicular to the surface
  • Then
  • The flux is a maximum (zero) when the surface is
    perpendicular (parallel) to the field

9
Electric Flux
  • If the field varies over the surface, F EA cos
    ? is valid for only a small element of the area
  • In the more general case, look at a small area
    element
  • In general, this becomes

10
Electric Flux
  • The surface integral means the integral must be
    evaluated over the surface in question
  • The value of the flux depends both on the field
    pattern and on the surface
  • SI units N.m2/C

11
Electric Flux, Closed Surface
  • For a closed surface, by convention, the A
    vectors are perpendicular to the surface at each
    point and point outward
  • (1) ? lt 90o, F gt 0
  • (2) ? 90o, F 0
  • (3) 180o gt ? gt 90o, F lt 0

12
Electric Flux, Closed Surface
  • The net flux through the surface is proportional
    to the number of lines leaving the surface minus
    the number entering the surface

13
Electric Flux, Closed Surface
  • Example flux through a cube
  • The field lines pass perpendicularly through two
    surfaces and are parallel to the other four
    surfaces
  • Side 1 F E l2
  • Side 2 F E l2
  • For the other sides, F 0
  • Therefore, Ftotal 0

14
Chapter 21Problem 23
  • The electric field on the surface of a
    10-cm-diameter sphere is perpendicular to the
    sphere and has magnitude 47 kN/C. Whats the
    electric flux through the sphere?

15
Chapter 21Problem 42
  • Whats the flux through the hemispherical open
    surface of radius
  • R in a uniform field of magnitude E shown in the
    figure?

16
Gauss Law
  • Gauss Law electric flux through any closed
    surface is proportional to the net charge Q
    inside the surface
  • eo 8.85 x 10-12 C2/Nm2 permittivity of free
    space
  • The area in F is an imaginary Gaussian surface
    (does not have to coincide with the surface of a
    physical object)

17
Gauss Law
  • A positive point charge q is located at the
    center of a sphere of radius r
  • The magnitude of the electric field everywhere on
    the surface of the sphere is E keq / r2
  • Asphere 4pr2

18
Gauss Law
  • Gaussian surfaces of various shapes can surround
    the charge (only S1 is spherical)
  • The electric flux is proportional to the number
    of electric field lines penetrating these
    surfaces, and this number is the same
  • Thus the net flux through any closed surface
    surrounding a point charge q is given by q/eo and
    is independent of the shape of the surface

19
Gauss Law
  • If the charge is outside the closed surface of an
    arbitrary shape, then any field line entering the
    surface leaves at another point
  • Thus the electric flux through a closed surface
    that surrounds no charge is zero

20
Gauss Law
  • Since the electric field due to many charges is
    the vector sum of the electric fields produced by
    the individual charges, the flux through any
    closed surface can be expressed as
  • Although Gausss law can, in theory, be solved to
    find for any charge configuration, in
    practice it is limited to symmetric situations
  • One should choose a Gaussian surface over which
    the surface integral can be simplified and the
    electric field determined

21
Field Due to a Spherically Symmetric Charge
Distribution
  • For r gt a
  • For r lt a

22
Field Due to a Spherically Symmetric Charge
Distribution
  • Inside the sphere, E varies linearly with r (E ?
    0 as r ? 0)
  • The field outside the sphere is equivalent to
    that of a point charge located at the center of
    the sphere

23
Electric Field of a Charged Thin Spherical Shell
  • The calculation of the field outside the shell is
    identical to that of a point charge
  • The electric field inside the shell is zero

24
Field Due to a Line of Charge
  • Select a cylindrical Gaussian surface (of radius
    r and length l)
  • Electric field is constant in magnitude and
    perpendicular to the surface at every point on
    the curved part of the surface
  • The end view confirms the field is perpendicular
    to the curved surface
  • The field through the ends of the cylinder is 0
    since the field is parallel to these surfaces

25
Field Due to a Line of Charge
26
Field Due to a Plane of Charge
  • The uniform field must be perpendicular to the
    sheet and directed either toward or away from the
    sheet
  • Use a cylindrical Gaussian surface
  • The flux through the ends is EA and there is no
    field through the curved part of the surface
  • Surface charge density s Q / A

27
Field Distance Dependencesfor Different Charge
Distributions
28
Chapter 21Problem 31
  • The electric field strength outside a charge
    distribution and 18 cm from its center has
    magnitude 55 kN/C. At 23 cm the field strength is
    43 kN/C. Does the distribution have spherical or
    line symmetry?

29
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 1 The electric field is zero everywhere
    inside the conducting material
  • If this were not true there were an electric
    field inside the conductor, the free charge there
    would move and there would be a flow of charge
    the conductor would not be in equilibrium

30
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 1 The electric field is zero everywhere
    inside the conducting material

31
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 1 The electric field is zero everywhere
    inside the conducting material

32
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 2 Any excess charge on an isolated
    conductor resides entirely on its surface
  • The electric field (and thus the flux) inside is
    zero whereas the Gaussian surface can be as close
    to the actual surface as desired, thus there can
    be no charge inside the surface and any net
    charge must reside on the surface

33
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 3 The electric field just outside a
    charged conductor is perpendicular to the surface
    and has a magnitude of s/eo
  • If this was not true, the component along the
    surface would cause the charge to move no
    equilibrium

34
Conductors in Electrostatic Equilibrium
  • When no net motion of charge occurs within a
    conductor, the conductor is said to be in
    electrostatic equilibrium
  • An isolated conductor has the following
    properties
  • Property 4 On an irregularly shaped conductor,
    the charge accumulates at locations where the
    radius of curvature of the surface is smallest
  • The forces from the charges at the sharp end
    produce a larger resultant force away from the
    surface.

35
Chapter 21Problem 41
  • A total charge of is applied to a thin, square
    metal plate 75 cm on a side. Find the electric
    field strength near the plates surface.

36
Answers to Even Numbered Problems Chapter 21
Problem 22 490 N m2/C
37
Answers to Even Numbered Problems Chapter 21
Problem 24 1.81 103 N m2/C
38
Answers to Even Numbered Problems Chapter 21
Problem 32 -2.0 10-4 C/m2
39
Answers to Even Numbered Problems Chapter 21
Problem 38 160 kN/C
40
Answers to Even Numbered Problems Chapter 21
Problem 56 58 nC/m2
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