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SN1 and SN2 Reactions

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SN1 and SN2 Reactions SN1 SN2 Rate =k[RX] =k[RX][Nuc:-] Carbocation intermediate? Y N Stereochemistry mix Inversion of configuration Rearrangement ~H, ~ CH3 possible – PowerPoint PPT presentation

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Title: SN1 and SN2 Reactions


1
SN1 and SN2 Reactions
SN1 SN2
Rate kRX kRXNuc-
Carbocation intermediate? Y N
Stereochemistry mix Inversion of configuration
Rearrangement H, CH3 possible No rearrangements
2
SN1 and SN2 Reactions
SN1 SN2
Substrate 3gt2gt1 CH3Xgt1gt2
Nucleophile Unimportant, but usually weak Strong and unhindered
Leaving group Excellent Better than nucleophile
Solvent Polar and ionizing Polar aprotic
3
SN1 and SN2 Reactions
  • Do not occur with vinyl halides or aryl halides.
  • Consider the carbocation formed for SN1.
  • Consider the backside attack for SN2.

4
Elimination Reactions
  • The substitution reaction mechanisms you have
    learned are just part of the picture.
  • In the SN1 and SN2 reactions, the species that
    acts as a nucleophile may also act as a base and
    abstract a proton. This causes the elimination
    of HX and the formation of an alkene.
  • An elimination reaction can occur along with the
    substitution reaction.

5
Elimination
B- is a species acting as a base. Since HX is
lost, this particular reaction is called a
dehydrohalogenation.
6
E1 Reactions
  • E1 elimination, unimolecular
  • Rate ksubstrate (a first order process)
  • The rate-limiting step is the formation of the
    carbocation, the same as for SN1 (thats why E1
    competes).

7
E1 Reaction Mechanism
  • Step 1 The substrate forms a carbocation
    intermediate (rate-limiting step).
  • Step 2 Methanol acts as a base and removes
    H(fast step).

8
E1 Reaction Profile
rate k(CH3)3Br
-EA(step 1)/RT
k Ae
9
E1 Occurs with and Competes with SN1
  • When bromocyclohexane is heated with methanol,
    two products are possible.
  • Can you draw the mechanism that leads to each
    product?

10
SN1 E1 competing mechanisms
11
E1 Reactions
  • E1 reactions are exothermic.
  • E1 reactions occur in at least two steps and
    compete with SN1 reactions.
  • The first step is slow. It is the formation of
    the carbocation intermediate.
  • The second step is fast. It is the abstraction
    of H from the carbocation by the base.

12
Factors Affecting E1 Reactions
  • Structure of the substrate
  • Can a stable carbocation be formed?
  • Strength of the base
  • Nature of the leaving group
  • The solvent in which the reaction is run.
  • Must be able to stabilize the carbocation and the
    LG (which is usually an ion).

13
Factors Affecting E1 Reactions - Structure of the
Substrate
  • The most important factor influencing the rate of
    E1 reactions is the stability of the carbocation
    formed.
  • Stability of carbocation 3 gt 2 gt1
  • Relative rates for E1 3gt21(resonance)

14
Factors Affecting E1 Reactions - Strength of the
Base
  • The rate is not much affected by the strength of
    the base. Weak bases will work.

15
Factors Affecting E1 Reactions - the Leaving Group
  • The LG should be good.

16
Factors Affecting E1 Reactions - Solvent Effects
  • The solvent must be capable of dissolving both
    the carbocation and the leaving group.
  • E1 reactions require highly polar solvents that
    strongly solvate ions.
  • Typical solvents water, an alcohol, acetone (to
    help the alkyl halide to dissolve), or a mix.

17
Rearrangements in E1 Reactions
  • The carbocation can undergo a structural
    rearrangement to produce a more stable species.
  • hydride shift (H)
  • methyl shift (CH3)
  • If ionization would lead to a 1 carbocation,
    look for a rearrangement to occur.
  • Ionizations can be forced by the addition of
    reagents such as AgNO3. (How?)

18
A Hydride Shift Can Occur in Either SN1 or E1
Reactions
CH3OH
H
-H
SN1
  • What would the E1 products be?

19
A Methyl Shift Can Occur in Either SN1 or E1
Reactions
CH3OH
CH3
-H
SN1
  • What would the E1 product be?

20
Zaitsevs Rule
  • When two or more elimination products are
    possible, the product with the more substituted
    double bond will predominate.

21
Zaitsevs Rule
  • When two or more elimination products are
    possible, the product with the more substituted
    double bond will predominate.
  • Alkyl groups are electron-donating and contribute
    electron density to the p bond.
  • Bulky groups can be more widely separated.

22
E1 Reactions - Summary
  • The structure of the carbocation is the most
    important factor
  • Relative rates for E1 3gt2.
  • The base is typically weak or moderate in
    strength.
  • The LG should be good.
  • The solvent should be polar and protic to
    stabilize the carbocation and LG.
  • Products can exhibit rearrangements and will
    follow Zaitsevs Rule.
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