Car and Ramp - PowerPoint PPT Presentation

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Car and Ramp

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Title: PowerPoint Presentation Author: kat Last modified by: K Woodring Created Date: 3/8/2000 5:59:36 PM Document presentation format: On-screen Show – PowerPoint PPT presentation

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Title: Car and Ramp


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Car and Ramp
  • Part Four Graphs of Motion

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Learning Goals
  • Construct and analyze graphs of position versus
    time, and speed versus time.
  • Recognize and explain how the slope of a line
    describes the motion of an object.
  • Explain the meaning of constant speed.

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Graphs of Motion
  • Constant speed means the speed stays the same.
  • An object moving at a constant speed always
    creates a position vs. time graph that is a
    straight line.

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Slope
  • The slope of a line is the ratio of the rise
    (vertical change) to the run(horizontal change)
    of the line.

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Position-Time Graph
  • A position versus time graph can tell you whether
    an objects speed is constant or changes.
  • Remember, if the speed is constant, the graph is
    a straight line with a constant slope.
  • But if the speed is changing, the slope changes,
    so the graph curves.

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Position-Time Graph
  • Consider the speed of an accelerating ball in
    free fall.
  • As time passes, the balls speed increases.
  • Because the slope equals the speed, the slope
    must also become greater with time.

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Position-Time Graph
  • The position-time graph of an object slowing down
    is also curved.
  • A car gradually comes to a stop at a red light.
  • As time passes, the cars speed decreases.

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Speed vs. Time Graph for Constant Speed
  • The speed versus time graph has speed on the
    y-axis and time on the x-axis.
  • On this graph, a constant speed is a straight
    horizontal line.

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Calculating Distance
  • A speed versus time graph also can be used to
    find the distance the object has traveled.
  • Suppose we draw a rectangle on the speed versus
    time graph between the
  • x - axis and the line showing the speed. The area
    of the rectangle (shown below) is equal to its
    length times its height.

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