Title: CHEMICAL REACTIONS
1CHEMICAL REACTIONS
Reactants Zn I2
Product Zn I2
2Chemical Equations
- Depict the kind of reactants and products and
their relative amounts in a reaction. - 4 Al (s) 3 O2 (g) ---gt 2 Al2O3 (s)
- The numbers in the front are called
- Stoichiometric units
- The letters (s), (g), and (l) are the physical
states of compounds.
3Introduction
- Chemical reactions occur when bonds between the
outermost parts of atoms are formed or broken - Chemical reactions involve changes in matter, the
making of new materials with new properties, and
energy changes. - Symbols represent elements, formulas describe
compounds, chemical equations describe a chemical
reaction
4- The charcoal used in a grill is basically carbon.
The carbon reacts with oxygen to yield carbon
dioxide. The chemical equation for this reaction,
C O2 ? CO2, contains the same information as
the English sentence but has quantitative meaning
as well.
5Chemical Equations
- Because of the principle of the conservation of
matter, - an equation must be balanced.
- It must have the same number of atoms of the
same kind on both sides.
6Symbols Used in Equations
- Solid ___
- Liquid (l)
- Gas ___
- Aqueous solution (aq)
- Catalyst H2SO4
- Escaping gas (?)
- Change of temperature (?)
7Balancing Equations
- When balancing a chemical reaction you may add
coefficients in front of the compounds to balance
the reaction, but you may not change the
subscripts. - Changing the subscripts changes the compound.
Subscripts are determined by the valence
electrons (charges for ionic or sharing for
covalent)
8Subscripts vs. Coefficients
- The subscripts tell you how many atoms of a
particular element are in a compound. The
coefficient tells you about the quantity, or
number, of molecules of the compound.
9Chemical Equations
- 4 Al(s) 3 O2(g) ---gt 2 Al2O3(s)
- This equation means
- 4 Al atoms 3 O2 molecules
- Produces ---gt 2 molecules of Al2O3
- AND/OR
- 4 moles of Al 3 moles of O2 ---produces ?
2 moles of Al2O3
10Steps to Balancing Equations
- There are four basic steps to balancing a
chemical equation. - Write the correct formula for the reactants and
the products. DO NOT TRY TO BALANCE IT YET! You
must write the correct formulas first. And most
importantly, once you write them correctly DO NOT
CHANGE THE FORMULAS! - Find the number of atoms for each element on the
left side. Compare those against the number of
the atoms of the same element on the right side. - Determine where to place coefficients in front of
formulas so that the left side has the same
number of atoms as the right side for EACH
element in order to balance the equation. - Check your answer to see if
- The numbers of atoms on both sides of the
equation are now balanced. - The coefficients are in the lowest possible whole
number ratios. (reduced)
11Some Suggestions to Help You
- Some of the Helpful Hints for balancing
equations - Take one element at a time, working left to right
except for H and O. Save O for next to last, and
H until last. - IF everything balances except for O, and there is
no way to balance O with a whole number, double
all the coefficients and try again. (Because O is
diatomic as an element) - (Shortcut) Polyatomic ions that appear on both
sides of the equation should be balanced as
independent units
12More Rules
- ? means yields and shows direction of action
- ? above arrow shows heat has been added
- ?? shows reaction is reversible
- MINOH try Metals first, then Ions, then
Nonmetals, and Oxygen, then Hydrogen last
13Rules
- 1. LEARN THESE DIATOMIC MOLECULES
- O2 H2 N2 F2 Cl2 Br2 I2
- 2. The same number of atoms of each element
appearing in reactants must appear in the
products. - 3. The subscripts of a formula cannot be changed
to balance the equation. Each compound must
retain its stableness via oxidation states. - 4. Choose compound with greatest number of atoms
first. - Balance by placing necessary coefficients in
front of entire molecules. -
- NO SUBSCRIPT CHANGES!
14Rules cont.
- 6. Be certain each side of equation has same
number of atoms of each type. - 7. Make sure coefficients are in lowest whole
number ratios. - 8. (aq.) stands for aqueous which is Latin for
water solution - (g) gas (l) liquid (s) solid
- (c) crystalline solid
15- Balancing chemical equations using the ones and
twos technique. - Example
- Balance the equation
- K O2 ? K2O
- Solution
- Step 1 On the left side of the equation there
are 2 oxygen atoms and on the right side of the
equation there is one oxygen atoms. Multiply K2O
by the coefficient of 2 to balance the oxygen
atoms. - K O2 ? 2K2O
- Step 2 Balance the K by placing the coefficient
of 4 in front of K - 4K O2 ? 2K2O
- Step 3 Check that all the atoms balance and make
sure that all coefficients are in the
lowest-possible ratio.
16- Balancing chemical equations using the twos and
threes technique. - Example
- Balance the equation
- Fe O2 ? Fe2O3
- Step 1 On the left side of the equation there
are 2 oxygen atoms and on the right side of the
equation there are 3 oxygen atoms. To balance the
oxygen atoms, multiply Fe2O3 by the coefficient
of 2 and the O2 by the coefficient of 3 - Fe 3O2 ? 2Fe2O3
- Step 2 Balance the Fe by placing the coefficient
of 4 in front of Fe - 4Fe 3O2 ? 2Fe2O3
- Step 3 Check that all the atoms balance and make
sure that all coefficients are in the
lowest-possible ratio.
17- Balancing chemical equations using the even
technique. - If you have an even number of a certain element
on one side of the equation and an odd number of
the same element on the other side of the
equation, multiply both sides of the equation
through by the coefficient of 2. This will give
an even number on both sides and make the
equation easier to balance. - Example
- Balance the equation
- CH3OH O2 ? H2O CO2
- Step 1 Using the CHO technique, we start with
carbon, one on each side, so carbon is balanced.
There are four H on the left and two on the
right, so we place the coefficient of 2 in front
of the H2O on the right - CH3OH O2 ? 2H2O CO2
- Step 2 When we try to balance the oxygen, we
find three on the left and four on the right. We
multiply both sides of the equation through by
two. - 2CH3OH 2O2 ? 4H2O 2CO2
- Step 3 The C and H are still balanced, and now
there are six O on the left and eight on the
right. Change the coefficient in front of the O2
to 3 to give eight O on the left. - 2CH3OH 3O2 ? 4H2O 2CO2
- Step 4 Check that all the atoms balance and make
sure that all coefficients are in the
lowest-possible ratio.
18- Balancing chemical equations using the CHO
technique. - If you are balancing equations that have carbon,
hydrogen and oxygen atoms then balance the carbon
atoms first, the hydrogen atoms second and the
oxygen atoms last. - Example
- Balance the chemical equation
- C5H12 O2 ? CO2 H2O
- Step 1 Start with C. To balance the C put the
coefficient of 5 for CO2 - C5H12 O2 ? 5CO2 H2O
- Step 2 Then, balance the H by placing the
coefficient of 6 for H2O - C5H12 O2 ? 5CO2 6H2O
- Step 3 Lastly, balance the O by placing the
coefficient of 8 for O2 - C5H12 8O2 ? 5CO2 6H2O
- Step 4 Check that all the atoms balance and make
sure that all coefficients are in the
lowest-possible ratio.
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20Balancing Equations
2
2
- ___ H2(g) ___ O2(g) ---gt ___ H2O(l)
What Happened to the Other Oxygen Atom????? This
equation is not balanced! Two hydrogen atoms from
a hydrogen molecule (H2) combines with one of the
oxygen atoms from an oxygen molecule (O2) to form
H2O. Then, the remaining oxygen atom combines
with two more hydrogen atoms (from another H2
molecule) to make a second H2O molecule.
21Balancing Equations
2
3
- ___ Al(s) ___ Br2(l) ---gt ___ Al2Br6(s)
22Balancing Equations
- ____C3H8(g) _____ O2(g)
----gt _____CO2(g) _____ H2O(g)
____B4H10(g) _____ O2(g)
----gt ___ B2O3(g) _____ H2O(g)
23Balancing Equations
- Sodium phosphate iron (III) oxide ? sodium
oxide iron (III) phosphate
Na3PO4 Fe2O3 ----gt
Na2O FePO4