Title: AP Physics B Giancoli 11
1AP Physics BGiancoli 11 12
2Assignments
- Reading 11.1-4,7-9,11-13 and 12.1,2,4-7
- Problems Waves 11.42,43,55,56
- Sound 12.4,5,10,11
- Strings/AirColumns12.29,30,35
- Interference 12.42,43
- Doppler 12.51,52
- SHM 11.4,5,20, 25
- Pendulum 11.31,32
3Preview
- What are the two categories of waves with regard
to mode of travel? - Mechanical
- Electromagnetic
- Which type of wave requires a medium?
- Mechanical
- An example of a mechanical wave?
- Sound
4Velocity of a Wave
- The speed of a wave is the distance traveled by a
given point on the wave (such as a crest) in a
given internal of time. - v d/t
- d distance (m)
- t time (s)
- v f l
- v speed (m/s)
- l wavelength (m)
- f frequency (s-1, Hz)
5Period of a Wave
- T 1/f
- T Period (s)
- F frequency (s-1, Hz)
6Problem Sound travels at approximately 340 m/s,
and light travels at 3.0 x 108 m/s. How far away
is a lightning strike if the sound of the thunder
arrives at a location 5.0 seconds after the
lightning is seen?
Light travels almost instantaneously from strike
location to the observer. The sound travels much
more slowly d vs t (340 m/s)(5.0 s) 170m
7Problem The frequency of a C key on the piano
is 262 Hz. What is the period of this note? What
is the wavelength? Assume speed of sound in air
to be 340 m/s at 20 oC. T 1/f 1/262 s-1
0.00382 s V f l l v/f l 340 m/s / 262
/s 1.30 m
8Problem
- A sound wave traveling through water has a
frequency of 500 Hz and a wavelength of 3 m. How
fast does sound travel through water? - v l f 3m (500 Hz) 1500 m/s
9Wave on a Wire
- v FT
- m / L
- v, velocity, m/s
- FT, tension on a wire, N
- m/L mass/unit length, kg/m
- m/L may be shown as m
10Problem Ex. 11-11
- A wave whose wavelength is 0.30 m is traveling
down a 300 m long wire whose total mass is 15 kg.
If the tension of the wire is 1000N, what are the
speed and frequency of the wave? - Using equation on prior slide
- v v( 1000N) / (15kg)(300m)
- 140m/s
- f v / l 140 m/s / 0.30 m 470 Hz
-
11Types of Waves
- A transverse wave is a wave in which particles of
the medium move in a direction perpendicular to
the direction which the wave moves. - Example Waves on a guitar string
- A longitudinal wave is a wave in which particles
of the medium move in a direction parallel to the
direction which the wave moves. These are also
called compression waves. - Example Sound
- http//einstein.byu.edu/masong/HTMstuff/WaveTrans
.html
12What are two types of wave shapes?
13- http//www.school-for-champions.com/science/sound.
htm
14Transverse Wave Type
15Longitudinal Wave Type
16Longitudinal vs Transverse
17Other Waves Types Occurring in Nature
- Light electromagnetic
- Ocean waves surface
- Earthquakes combination
- Wave demos
- http//www.kettering.edu/drussell/Demos/waves/wav
emotion.html - http//www.kettering.edu/drussell/Demos/doppler/m
ach1.html
18Properties of Waves
- Reflection occurs when a wave strikes a medium
boundary and bounces back into the original
medium. - Those waves completely reflected have the same
energy and speed as the original wave.
19Types of Reflection
- Fixed-end Reflection-
- The wave reflects with
- inverted phase.
- Open-end Reflection-
- The wave reflects with
- The same phase.
- www.iop.org/activity/education/Teaching_Resources
20Refraction of Waves
- Wave is transmitted
- from one medium to
- another.
- Refracted waves may
- change speed and
- Wavelength
- Almost always is accompanied
- by some reflection.
- Refracted waves do not
- change frequency.
21Sound - a longitudinal wave
- Sound travels through air about 340 m/s.
- Sound travels through other media as well, often
much faster than 340 m/s. - Sound waves are started by vibration of some
other material, which starts the air vibrating. - www.silcom.com/aludwig/musicand.htm
22Hearing Sounds
- We hear a sound as high or low pitch
depending on the frequency or wavelength.
High-pitched sounds have short wavelengths and
high frequencies. Low-pitched sounds have long
wavelengths and low frequencies. Humans hear
from about 20 Hz to about 20,000 Hz. - The amplitude of a sounds vibration is
interpreted as its loudness. We measure loudness
(also known as
sound intensity)
on the decibel scale, which is
logarithmic.
http//www.allegropianoworks.com/assets/rare_compr
ess.jpg
23Doppler Effect
- The Doppler Effect is the apparent change in
pitch of a sound as a result of the relative
motion of an observer and the source of a sound.
Coming toward you a car horn appears higher
pitched because the wavelength has been
effectively decreased by the motion of the car
relative to you. The opposite occurs when you are
behind the car.
http//people.finearts.uvic.ca/aschloss/course_ma
t/MU207/images/Image2.gif
24Pure Sound
- Sounds are longitudinal waves, but they can be
shown to look like transverse waves. - When air motion is graphed in a pure sound tone
versus position, we get what looks like a sine or
cosine function. - A tuning fork produces a relatively pure tone as
does a human whistle.
25Graphing a Sound Wave
26Complex Sounds
- Because of superposition and interference, real
world waveforms may not appear to be pure sine or
cosine functions. - This is because most real world sounds are
composed of multiple frequencies. - The human voice and most musical instruments are
examples.
27The Oscilloscope
- With an Oscilloscope we can view waveforms. Pure
tones will resemble sine or cosine functions, and
complex tones will show other repeating patterns
that are formed from multiple sine and cosine
functions added together. (Amplitude vs time.)
28The Fourier Transform
- The Fourier transform has long been used for
characterizing linear systems and for identifying
the frequency components making up a continuous
waveform. This mathematical technique separates a
complex waveform into its component frequencies. - The Fourier Transforms ability to represent
time-domain data in the frequency domain and
vice-versa has many applications. One of the most
frequent applications is analysing the spectral
(frequency) energy contained in data that has
been sampled at evenly-spaced time intervals.
Other applications include fast computation of
convolution (linear systems responses, digital
filtering, correlation (time-delay estimation,
similarity measurements) and time-frequency
analysis.
29Fourier Transform - showing time domain and
frequency domain.
30Superposition Principle
- When two or more waves pass a particular point in
a medium simultaneously, the resulting
displacement of the medium at that point is the
sum of the displacements due to each individual
wave. - The waves are said to interfere with each other.
31Superposition of Waves
- When two or more waves meet, the displacement at
any point of the medium is equal to the algebraic
sum of the displacements due to the individual
waves.
32Types of Interference
- If the waves are in phase, when crests and
troughs are aligned, the amplitude in increased
and this is called constructive interference. - If the waves are out of phase, when crests and
troughs are completely misaligned, the amplitude
is decreased and can even be zero. This is called
destructive interference.
33Constructive Interference
- Crests are
- Aligned ?
- the waves are
- in phase
34Destructive Interference
Crests are aligned with troughs ? Waves are out
of phase
35Constructive Destructive Interference
36Interference Problem Draw the waveform from the
two components shown below.
37Standing Waves
- A standing wave is one which is reflected back
and forth between fixes ends of a string or pipe. - Reflection may be fixed or open-ended.
- Superposition of the wave upon itself results in
a pattern of constructive and destructive
interference and an enhanced wave. Lets see a
simulation - http//www.5min.com/Video/The-Rubens-Tube-Frequenc
y-of-Fire-1858291
38Fixed-end standing waves - guitar or violin string
- Fundamental
- 1st harmonic
- l 2L
- First overtone
- 2nd harmonic
- l L
- Second Overtone
- 3rd harmonic
- l 2L/3
http//id.mind.net/zona/mstm/physics/waves/standi
ngWaves/standingWaves1/StandingWaves1.html
39Problem
- A string of length 12 m thats fixed at both ends
supports a standing wave with a total of 5 nodes.
What are the harmonic number and wavelength of
this standing wave? - L 4(1/2 l ) ? l 2L/4 4th harmonic since
it matches ln 2L/n for n 4 - wavelength l4 2(12m) / 4 6 m
40Open-ended standing waves - flute clarinet
l 2L l L l (2/3)L
41physics.indiana.edu/p105_f02/standing_waves_...
42http//upload.wikimedia.org/wikibooks/en/3/32/Fhss
t_waves40.png
- open ends one end both ends
- closed closed
43Sample Problem
- 12-30. a) Determine the length of an organ pipe
that emits middle C (262Hz). The air temp. is
21oC. - A) v 331m/s 0.6 m/soC(21oC) 344m/s
- A) l 2L v fl 2lf L v/2f
344m/s/2(262/s) - L 0.656m
- B) What are the wavelength and frequency of the
1st harmonic? - Frequency is 262 Hz
- Wavelength is twice the length of the pipe, 1.31
m. - C) What is the wavelength and frequency in the
traveling sound wave produced in the outside air? - They are the same because it is air that is
resonating in the organ pipe 262Hz and 1.31 m
44Superposition of 2 sound waves http//www.ece.utex
as.edu/nodog/me379m/superposition.html
45Resonance and Beats
- Resonance occurs when a vibration from one
oscillator occurs at a natural frequency for
another oscillator. - The first oscillator will cause the second to
vibrate. - See next slide.
46Resonance
- http//www.isd-dc.org/ISD-Wash/GIFS20Pictures20
20Whatnots/tuningforkresonance.jpg
47Beats
- The word physicists use to describe the
characteristic loud/soft pattern that
characterizes two nearly matched frequencies. - Musicians call this being out of tune.
48Beats
- When two sound waves whose frequencies are close
but not exactly the same, the resulting sound
modulates in amplitude changing from loud to soft
to loud. This is called beat frequency and is
shown by - fbeat f 1 - f 2
49Diffraction
- Bending of a wave around a barrier
- Diffraction of waves combined with interference
of the diffracte waves causes diffraction
patterns. - Here is an example using a ripple tank.
- http//www.falstad.com/ripple/
50Double-slit or multi-slit diffraction
- micro.magnet.fsu.edu/.../doubleslit/
- Remove frame
51(No Transcript)
52Single Slit Diffraction
- n l s sin q
- n -- dark band number
- l -- wavelength (m)
- s -- slit width (m)
- q -- angle defined by central band, slit, and
dark bank
53Sample Problem
- Light of wavelength 360 nm is passed through a
diffraction grating that has 10,000 slits per cm.
If the screen is 2.0 m from the grating, how far
from the central bright band is the first order
bright band?
54Sample Problem
- Light of wavelength 560 nm is passed through two
slits. It is found that, on a screen 1.0 m from
the slits, a bright spot is formed at x 0, and
another is formed at x 0.03m. What is the
spacing between the slits?
55Sample Problem
- Light is passed through a single slit of width
2.1 x 10-6 m. How far from the central bright
band do the 1st and 2nd order dark bands appear
if the screen is 3.0 m away from the slit?
56Mathematical Description of a Traveling Wave
- Y A sin (v t k x )
- Y dependent of x and t y(x,t) or y of x t
- If the - sign is used, wave is traveling in x
direction ? - A is amplitude of the wave
- m (omega) is angular frequency (m 2pf)
- k angular wave (k 2 pk, k 1/l)
57Other forms
- Important features of the wave amplitude,
frequency f (through v), period T (which is 1/f
2p/v), wavelength (l 2p/k) and wave speed v
(which is lf v/k) - y Asin2pft (1/l)x or
- y Asin(2p/l)(vt x)
58Sample Problem The vertical position y of any
point on a rope that supports a transverse wave
traveling horizontally is given by the
equation y 0.1 sin (6 p t 8 p x)
Find amplitude 0.1 angular frequency v
6 p s -1 frequency f v / (2 p) (6 p s -1 )/
(2 p ) 3 Hz angular wave number k k / (2 p )
8 p m -1) / ((2 p) 4 m-1 wavelength l 1/ k
1/ (4 m-1) 0.25 m period T 1/f 1 / 3 Hz
0.33s wave speed v f l 0.25m (3 Hz)
0.75 m/s
59Assignment
60Sound Level
- Intensity Rate at which sound waves transmit
energy is measured in energy per unit area
watt/m2 or watt/cm 2 - Intensity level or loudness level, B
- B 10log I/Io where Io 1x10-12 w/m2
-
or 1x10-16 w/cm2
61More math
- b 10 log I
- Io 10-16 w/cm 2
- Intensity level 10 log Intensity / threshhold
of hearing - We all dont hear the same, so this is a
comparative measurement in decibels
62Flow chart for b problem
- If I 4.7 x 10-10 w/cm2
- 10xlog(4.7 2nd EE -10 / 1 2nd EE -16) 66.7
dB - If I 2.9 x 10-3 w/cm2
- 10xlog(2.9 2nd EE -3 / 1 2nd EE -16) 135
dB
63Problem
- Now we are going backwards from intensity level
(dB) to intensity (w/cm2) - If the intensity level is 83 dB, convert that to
intensity in w/cm2. - B 10 log I / Io get to a working eqtn
- B /10 log I / Io
- Log-1(B/10) Log-1(log I/Io)
- Log-1(B/10) I/Io
64- Lets say that the intensity level of a sound is
25.3 dB. What is the intensity of the sound in
w/cm2? - B 10 log I / Io
- 25.3 dB 10 log (I/10-16 w/cm2)
- 2.53 log I log 10-16
- 2.50 log 10-16 log I
- 2.50 16 log I
65- 25.3 dB 10 log (I/10-16 w/cm2)
- 2.53 log I log 10-16
- 2.50 log 10-16 log I ? what power do you
raise 10 to, to get 10-16? - 2.50 16 log I
- Adding on the left ? -13.5 log I
- Raise 10 to the -13.5 power by this sequence
- 2nd 10x (-13.5) ? 3.16 x 10-14 w/cm2 I
66Doppler Effect
- Doppler Effect is the apparent change in
frequency as a result of relative motion between
the source of a sound and an observer. -
- f frequency heard by observer
- f frequency of source
- v velocity of sound in air
- vd velocity of detector
- vs velocity of source
67Sample Problem
- A source of 4 kHz sound waves travel at 1/9 the
speed of sound toward a detector thats moving at
1/9 the speed of sound, toward the source. - a. what is the frequency of the waves as theyre
received by the detector? - b. how does the wavelength of the detected waves
compare to the wavelength of the emitted waves?
68- v 1/9 v x f 5/4 f 5/4 (4 kHz) 5 kHz
- v - 1/9 v
- sign on top as detector moves toward source
- sign on bottom as source moves toward det.
- Frequency is shifted up by a factor of 5/4, the l
will shift down by the same factor. - ld ls / 5/4 4/5 l s
69Sample
- A person yells, emitting a constant frequency of
200 Hz, as he runs at 5m/s toward a stationary
brick wall. When the reflected waves reach the
person, how many beats per second will he hear?
(Use 343 m/s for the speed of sound.)
70Determine what f will be reflected and heard by
the runner. person is source and wall is
detector fwall v f
v - vrunner Reflected sound wave
(no change in f) wall is the source and runner
is the detector. frunner v v
runner f
v Combine these two formulae frunner v
vrunner f v - vrunner
f (3435)m/s (200Hz) 206 Hz
(343-5)m/s Beat frequency is fbeat 206Hz - 200
Hz 6 Hz. p. 343 Princeton
71Doppler Effect for Light
- wps.prenhall.com/.../ch25_SWA/images/8.gif
- c 3 x 10 8 m/s
- u speed of the source and the detector.
72www.sv.vt.edu/.../class95/physics/doppler.gif
73Periodic Motion
- Motion that repeats itself over a fixed and
reproducible period of time - An example is a planet moving about its sun.
This is called the period (T) or year of the
planet - Mechanical devices on earth that have periodic
motion are useful timers and are called
oscillators.
74Simple Harmonic Motion
- Attach a weight to a spring, stretch the spring
past its equilibrium point and release. The
weight bobs up and down with a reproducible
period, T - Plot position vs time to get a graph that
resembles a sine or cosine function. The graph is
sinusoidal, so the motion is referred to as
simple harmonic motion. - Springs and pendulums undergo simple harmonic
motion and are referred to as simple harmonic
oscillators.
75Graph Analysis
76Graph Analysis
77Oscillator Definitions
- Amplitude
- Maximum displacement from equilibrium
- Related to energy
- Period
- Length of time required for one oscillation
- Frequency
- How fast the oscillator is oscillating
- f 1/T in Hz or s-1
78Problem 11-5
- An elastic cord vibrates with a frequency of 3.0
Hz when a mass of 0.60 kg is hung from it. What
is its frequency if only 0.38 kg hangs from it?
79Springs
- Springs are a common type of simple harmonic
oscillator. - Our springs are ideal springs, which means
- They are massless
- They are both compressible and extensible.
- They will follow Hookes Law.
- F -kx
80Hookes Law Review
The force constant of a spring can be determined
by attaching a weight and seeing how far it
stretches.
81Period of a Spring
T period (s) m mass (kg) k force constant
(N/m)
82Sample Problem
- Calculate the period of a 350 g mass attached to
an ideal spr5ing with a force constant of 35 N/m.
83Sample Problem
- A 300 g mass attached to a spring undergoes
simple harmonic motion with a frequency of 25 Hz.
What is the force constant of the spring?
84Sample Problem
- An 80 g mass attached to a spring hung vertically
causes it to stretch 30 cm from its unstretched
position. If the mass is set into oscillation on
the end of the spring, what is its period?
85Combinations of Springs
- In parallel, springs work together
- In series, springs work independently
86What do you think?
Does this combination of springs act as parallel
or series? Answer parallel !
87Problem
- If you want to double the force constant of a
spring, you - A. double its length by connecting it to another
one just like it. - B. cut it in half.
- C. add twice as much mass.
- D. take half of the mass off.
- Answer B
88Conservation of Energy
- Springs and pendulums obey conservation of energy
- The equilibrium position has high kinetic energy
and low potential energy. - The positions of maximum displacement have high
potential energy and low kinetic energy. - Total energy of the oscillating system is
constant.
89Problem 11-20
- A block of mass m is supported
- by 2 identical parallel vertical
- springs, each with spring stiffness
- constant k. What will be the
- frequency of vibration?
General form of a restoring force producing SHM
with spring constant of 2k
90Sample Problem
91Spring Problem
92Another spring problem
93Pendulums
- Pendulums can be thought of as simple harmonic
oscillators. - The displacement needs to be small for it to work
properly.
94Conservation of Energy
- Pendulums also obey conservation of energy.
- The equilibrium position has high kinetic energy
and low potential energy. - The positions of maximum displacement have high
potential energy and low kinetic energy. - Total energy of the oscillating system is
constant.
95Pendulum Forces
2005 Pearson Prentice Hall Fig 11-12
96Period of a Pendulum
T -- period (s) l -- length of string (m) g --
gravitational acceleration (m/s2)
97Problem
- Predict the period of a pendulum consisting of a
500 g mass attached to a 2.5 m long string.
98Problem
- Suppose you notice that a 5 kg weight fixed to a
string swings back and forth 5 times in 20
seconds. How long is the string?
99Last problem!
- The period of a pendulum is observed to be T.
Suppose you want to make the period 2T. What do
you do to the pendulum?