Determining%20the%20Form%20of%20the%20Rate%20Law - PowerPoint PPT Presentation

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Determining%20the%20Form%20of%20the%20Rate%20Law

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... k using values from any of the experiments given Units will be different for k depending on order of reactants Example BrO3- : Exp 1 & 2 Exp 1: 8.0x10-4 = k ... – PowerPoint PPT presentation

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Title: Determining%20the%20Form%20of%20the%20Rate%20Law


1
  • Determining the Form of the Rate Law

2
Rate Law
  • The mathematical expression that allows
    calculations of reaction rate as a function of
    reactant concentration.
  • Must be determined experimentally by altering the
    initial concentrations of all reactants and
    observing the effect on initial rate.

3
How Data is created
4
Rate Law Equation
  • Since the concentrations within a reaction change
    the instant the reaction starts, chemists look at
    the effect of the initial concentrations.
  • For any general reaction
  • aA bB ? products
  • The rate law equation may be expressed as the
    product of the initial concentrations raised to
    some exponential value.
  • Rate kAmBn
  • k, m and n must be experimentally determined

5
Method of Initial Rates
  • Used to find the form of the rate law
  • Choose one reactant to start with
  • Find two experiments where the concentration of
    that reactant changes but all other reactants
    stay the same
  • Write the rate laws for both experiments
  • Divide the two rate laws
  • Solve for the order
  • Follow the same technique for other reactants

6
Example
  • Choose one reactant to start with
  • NH4
  • Find two experiments where the concentration of
    that reactant changes but all other reactants
    stay the same
  • Exp 2 3

7
  • Write the rate laws for both experiments
  • Exp 2 2.70x10-7 k(0.100)x(0.010)y
  • Exp 3 5.40x10-7 k(0.200)x(0.010)y
  • Divide the two rate laws
  • 0.50 0.50x
  • Use log rules to solve for the order
  • x 1 so the order for NH4 is one

8
  • Follow the same technique for other reactants
  • NO2- Exp 1 2
  • Exp 1 1.35x10-7 k(0.100)1(0.0050)y
  • Exp 2 2.70x10-7 k(0.100)1(0.010)y
  • 0.5 0.5y
  • y 1
  • So Rate kNH41NO2-1
  • Overall Reaction Order
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