Title: 5-1 HOMOGENEOUS PRODUCTION FUNCTION
15-1 HOMOGENEOUS PRODUCTION FUNCTION
- For homogeneous production return to scale could
easily be defined. - f(tx1,tx2)tkf(x1,x2 )
- kgt1 , increasing return to sacle for small
range. - k1 , constant return to scale
- klt1 , decreasing return to scale
- just like the utility function , the homogeneous
production function contain linear expansion path
which means RTSx1x2f(x2/x1). - the homothetic production function is a
increasing transformation function of a linear
homogeneous production function. As it is proved
for the homothetic production utility
function, for the homothetic production function
the average cost function is independent from the
level of production, and it is only a function
the ratio of input price levels. This can be
easily shown for the Cobb-Douglas production
function.
q
x
x2
Expansion path
x1
25-1 HOMOGENEOUS PRODUCTION FUNCTION
- qf(x1,x2)
- If f(tx1,tx2) tkf(x1,x2) , then x1f1 x2f2
kf(x1 , x2) - If k1 , then x1f1 x2f2 q f(x1 , x2)
- (x1f1)/q (x2f2)/q 1
- (?q/ ?x1)(x1/q) (?q/ ?x2)(x2/q) 1
- ?x1,q ?x2,q 1 exhaustion theorem , or
- x1f1 x2f2 q marginal productivity theory
of distribution - two steps 1 each factor should receive its
marginal productivity - 2 all output should be
exhausted. - for k1, long run profit equals to zero.
- ?pq r1x1 r2x2 pq pf1x1 pf2x2 pq
p(f1x1 f2x2)pq pq 0 - ?(t)pf(tx1,tx2) r1t x1 r2t x2 t pf(x1,x2)
tr1x1 tr2x2 t? - profit function is homogenous of degree one with
respect to scale of
production. - If each factor is paid according to its value of
marginal product , profit will be zero regardless
of its scale of production.
35-1 HOMOGENEOUS PRODUCTION FUNCTION
- So when production function is homogeneous of
degree one, the scale of production is not
defined - If ?gt0 , t (scale of production) can be
increased forever. - If ?lt0 the firm will go out of business.
- If ?0 scale can not be defined.
- Solution
- In order to use the exhaustion theorem results,
considering the above difficulties - 1 Production function defined not as homogeneous
of degree one. - 2- First and second order condition for profit
maximization should exist. - 3- maximum profit should equal to zero .
- ?pq r1x1 r2x2 0 , r1pf1 , r2pf2 ,
- ?pq pf1x1pf2x2 0 , qf1x1f2x2
(exhaustion theorem) - undefined scale of production, actually means
non existence of the second order condition for
profit maximization.
45-1 HOMOGENEOUS PRODUCTION FUNCTION
- x1f1 x2f2 q
- (f1x1f11x2f21)dx1 (f2 x1f12 x2f22 )dx2
dq - dq/dx1(dx20)f1f11x1 x2f21f1 , f11
(-x2/x1)f21 - dq/dx2(dx10)f2f22x2 x1f12f2 , f22
(-x1/x2)f12 - f11f22f122 f122 - f122 0(straight line.It
should be greater than zero). - However, constant return to scale assumption
is needed in many cases what should be done we
assume that - 1-, the whole industry has a constant return to
scale production function but the individual firm
does not. - 2-Scale of production is finite, in such a way
that equates demand with supply in the whole
industry . - The long run cost function will have a special
shape when production function is homogeneous .
Suppose that x10 and x20 , relates to the one
unit of the production level - f (tx10,t x20)tk f(x10,x20) tk , so
q tk - c r1x10 r2x20 a ? cost of producing
one unit -
55-1 HOMOGENEOUS PRODUCTION FUNCTION
- Cat total cost of producing q units.
- qtk production function ,
- Caq1/k total cost function , AC TC/q
aq(1-k)/k , MC(a/k)q(1-k)/k - 5-2 C.E.S. PRODUCTION FUNCTION
- An special form of homogeneous production
function is the one which has Constant Elasticity
of Substitution. - qAax1-? (1-a)x2 -? -1/ ?
homogeneous of degree one. - MPx1(?q/?x1) a/(A-?)(q/x1) ?1
homogeneous of degree zero - MPx2(?q/?x2) (1-a)/(A-?)(q/x2) ?1
homogeneous of degree zero - RTSx1 x2 ( MPx1)/( MPx2)a/(A-?)(q/x1)
?1/(1-a)/(A-?)(q/x2) ?1 - RTSx1 x2a/(1-a)(x2/x1) ?1 , if x1
increases then RTS wil decrease - s(f1f2)/(f12q) , f12(?1) a (1-a)q2?1/A2?
, - s1/(?1) , ?(1- s)/ s
- since sgt0 , then ?gt-1 for concavity
condition to prevail.
65-2 C.E.S. PRODUCTION FUNCTION
- 1 if s 0 then ? 8 ,
- RTS a/(1-a)(x2/x1) ?1
- when ? 8 , if x2gtx1 , RTS 8
, - if x1gtx2 ,
RTS 0 - 2 0lt slt1 , ? gt 0
- qAax1-? (1-a)x2 -? -1/ ?
- If qq0 , then , ax1-? (1-a)x2 -?
q0/A K - If x10 , x2 is not defined, if x1 8,
ax1-? 0 , x2K/(1- a)-1/? - If x20 , x1 is not defined, if x2 8,
(1-a)x2 -? 0 , x1(K/a)-1/? -
x2
RTS 8
RTS0
x1
x2
K/(1- a)-1/?x2
x1
75-2 C.E.S. PRODUCTION FUNCTION
- 3 if s 1, ?0, q is not
defined, using hopital rule we get
Cobb-Douglass production function - 4 if sgt1, , -1lt ? lt0 , ax1-? (1-a)x2
-? q0/A K - if x10 , then , x2K/(1- a)-?
- if x20 , then , x1(K/a)-?
- 5 s 8 , then ? -1 , ax1 (1-a)x2
q0/A K - if x10 , then , x2K/(1- a)
- if x20 , then , x1(K/a)
-
x2K/(1- a)-?
x1(K/a)-?
x2K/(1- a)
x1(K/a)
85-2 C.E.S. PRODUCTION FUNCTION
- Estimation of C E S
- RTSx1 x2a/(1-a)(x2/x1) ?1 (r1/r2)
- (x2/x1) a(r1/r2) s s 1/(1 ?)
a(1-a)/ a s - log(x2/x1)log a s log (r1/r2)
95-3 KHUN-TUCKER CONDITIONS
- First application
- qf(x1,x2)
- x1x11x12
- x12 x1 bought in the market with the market
price equal to r1 - x11x1 produced by the firm with a production
function x11g(x3) - x3 input bought for the production of x1
with a price equal to r3 - Max ? pq - TC pq (r1x12 r2x2
r3x3) - S.T. X11 g(x3)
- Max ? pf(x11x12, x2) r1x12 r2x2 r3x3
?g(x3) x11 - ??/?x11 ?x11 pf1 - ?0 ,
x11 ?x110 - ??/?x12 ?x12 pf1 r1 0 ,
x12 ?x120 - ??/?x2 ?x2 pf2 r2 0 ,
x2 ?x20 - ??/?x3 ?x3 ? g(x3) r3 0 , x3
?x30 - ??/?? ??g(x3) x11 0 ,
? ??0 - Three cases could be mentioned
105-3 KHUN-TUCKER CONDITIONS
- 1- x1 is totally bought from the market
x110 , x1x12 - x11 0 , ?x11 lt 0 , pf1 ?lt0 ,
pf1 lt ? - x12 ? 0 , ?x12 0 , pf1 r1 0 ,
pf1 r1 - x30 , ?x3 lt 0 , ? g(x3) r3 lt0
, ? lt r3 / g(x3) MCx1 - Pf1 r1 lt ? lt MCx1 , r1 lt MCx1
- 2 x1 is totally produced , nothing will be
bought from the market. - x11 ? 0 , ?x11 0 , pf1 ?0 ,
pf1 ? - x12 0 , ?x12 lt 0 , pf1 r1 lt 0 ,
pf1 lt r1 - x3 ? 0 , ?x3 0 , ? g(x3) r3 0
, ? r3 / g(x3) MCx1 - Pf1 ? MCx1 , pf1 lt r1 , ,
r1gt MCx1 - 3- x1 is both produced and bought from the market
- x11 ? 0 , ?x11 0 , pf1 ?0 ,
pf1 ? - x12 ? 0 , ?x12 0 , pf1 r1 0 ,
pf1 r1 - x3 ? 0 , ?x3 0 , ? g(x3) r3 0
, ? r3 / g(x3) MCx1 - Pf1 ? MCx1 , pf1 r1 , ,
r1 MCx1
115-3 KHUN-TUCKER CONDITIONS
- Second application
- qf(L, K) LL1 L2 L3 wage
discrimination. - If L1 L0 , wagew
- If L2 0.2 L0 , wage1.5w
- If L3 0.2 L0 , wage2w
- Max ?0 pf(L1L2L3,K) - wL1 - 1.5wL2 - 2wL3
rk µ1(L0-L1) µ2(0.2L0-L2) µ3(0.2L0-L3) - ??0/?L1 ?0L1 pfL w - µ1 0 ,
L1 ?0L10 - ??0/?L2 ?0L2 pfL 1.5w µ2 0 , L2
?0L20 - ??0/?L3 ?0L3 pfL 2w µ3 0 ,
L3 ?0L30 - ??0/?k ?0k pfk r 0 ,
k ?0k0 - ??0/? µ1 ?0µ1 L0 L1 0 ,
µ1 ?0µ10 - ??0/? µ2 ?0µ2 0.2L0 L2 0 ,
µ2 ?0µ20 - ??0/? µ3 ?0µ3 0.2 L0 L3 0 ,
µ3 ?0µ30 - Seven situations is possible
125-3 KHUN-TUCKER CONDITIONS
- 1- L1 L2 L3 0
- L1 0 , ?0L1lt0 , pfL- w - µ1 lt0 ,
- L0 L1 gt0 , µ10
, pfL lt w - 2- 0lt L1lt L0 , L2 L3 0 ,
- L1gt 0 , ?0L1 0 , pfL- w - µ1 0 ,
- L0 L1 gt0 , µ10
, pfL w - 3- L1L0 , L2 L3 0 ,
- L1gt 0 , ?0L1 0 , pfL- w - µ1 0 ,
- L0 L1 0 , µ1 gt 0
, pfL gt w - L2 0 , ?0L2 lt0 , pfL- 1.5 w µ2 lt0 ,
- 0.2 L0 L2 gt0 , µ2
0 pfL lt1.5 w - 4 - L1L0 , 0ltL2lt0.2 L0 , L30
- L1gt 0 , ?0L1 0 , pfL- w - µ1 0 ,
- L0 L1 0 , µ1 gt 0
- L2gt 0 , ?0L2 0 , pfL- 1.5 w µ2 0 ,
- 0.2 L0 L2 gt0 , µ2
0 pfL 1.5 w -
135-3 KHUN-TUCKER CONDITIONS
-
- 5 - L1L0 , L2 0.2 L0 , L30
- L1gt 0 , ?0L1 0 , pfL- w - µ1 0 ,
- L0 L1 0 , µ1 gt 0
- L2gt 0 , ?0L2 0 , pfL- 1.5 w µ2 0
, - 0.2 L0 L2 0 , µ2
gt0 1.5 wlt pfLlt2w - 6 - L1L0 , L2 0.2 L0 , 0lt L3lt
0.2 L0 pfL 2w - 7 - L1L0 , L2 0.2 L0
L3 0.2 L0 pfL gt 2w
145-4 Duality in production
- Max qf(x1,x2) cost function
could be found from - S.T. Cr1x1r2x2 production
function - Min Cr1x1r2x2
production function could be found - S.T. q0 f(x1,x2) from cost
function (duality ) - xixi(r1,r2, q0) , or xixi(r1/r2 , q0)
- Cr1x1r2x2
- r1? f1 , r2? f2
- ( ?C/?r1)(?r1/?r1)x1 ( ?x1/?r1)r1 ( ?r2/?r1)x2
( ?x2/?r1)r2 - x1 ? f1 ( ?x1/?r1) ? f2 (
?x2/?r1) - x1 ? f1 ( ?x1/?r1) f2 (
?x2/?r1)x1 ??q0/?r1x1 - ?C(q,r1,r2)/?r1 x1(q , r1, r2)
- ?C(q,r1,r2)/?r2 x2(q , r1, r2)
- From the above equations we could find q in
terms of x1 and x2 -
-
155-4 Duality in production
- Example
- CA(r1ar2b)1/(ab)q1/(ab)
- A(ab)(aabb)-1/(ab)
- ?C/?r1 a/(ab)Aq1/(ab)(r2/r1)b/(ab) x1
- ?C/?r2 b/(ab)Aq1/(ab)(r2/r1)-a/(ab) x2
- x1ax2b q a/(ab)ab/(ab)b A(ab)
- q x1ax2b 1/a/(ab)ab/(ab)b A(ab)
B x1ax2b -
165-5 PRODUCTION UNDER UNCERTAINTY
- Basic idea
- Under certainty people know exactly what they are
getting and how much utility they will yield.
There are three types of uncertainty - 1- some goods by their nature are games . like
horse riding bets or insurance or stock market
transaction. In these cases purchase does not
guarantee a particular outcome. - 2- Dealing with others, or uncertainty about the
action of individuals. - 3- Lack of understanding of information. Like
information about weather condition . For this
reason people are willing to pay for these kind
of information. - We only concentrate on the first type of
uncertainty. - Game x prizes of x1 , x2 , x3 , ..xn
- probability v1 , v2 , v3 ,
..vn -
175-5 PRODUCTION UNDER UNCERTAINTY
- Game Flipping a coin x1 win 1( Head) ,
x2loose 1(Tail) - E(x) v1x1 v2x2 (1/2)(1) (1/2)( -1) 0
- If the player plays the game many times (n
8) he will neither loose nor win.
- Game Flipping a coin x1 win 4( Head) ,
x2loose 3(Tail) - E(x) v1x1 v2x2 (1/2)(4) (1/2)( -3) 1/2
- If the player plays the game many times (n
8) he will win 1/2. - FAIR GAMES
- If cost of entry is equal to the expected value
of the game, the game is called fair game. We
expect that people accept the fair games. But ,
the Petersburg paradox showed that this is not
the case. - .
185-5 PRODUCTION UNDER UNCERTAINTY
- Petersburg paradox
- Game Flipping a coin till head appears
- Xi represent the prize awarded when the head
appears . The game could be played infinitely. - amount of win probability of win
- x12 v11/2
- x222 v2
(1/22) - x323
v3(1/23) - .. .
- xn2n vn(1/2n) n
8 - E(x)S vi xi ( 111..1) 8
- Is there any one who is willing to pay infinite
amount of money for this game? - Bernolli tried to solve the puzzle, by
introducing the concept of - Utility . He said that the utility of the win is
important for decision making rather the the
amount of the win by itself.
195-5 PRODUCTION UNDER UNCERTAINTY
- U(x)alog(xi)utility of the amount of win (x)
probability of win - u(x1)alog2
v11/2 - u(x2)alog22
v2 (1/22) - u( x3)alog23
v3(1/23) - ..
. - u(xn)alog2n
vn(1/2n) -
n 8 - Eu(x)Sviu(xi)(1/2)alog2(1/22) alog22 ..
(1/2n) alog2n - alog2S(i/2i )2alog2
- As it is seen the expected utility of x is
defined , but there is no upper bond on u(x). a
could be very large, and the expected utility
could be defined very large and unreasonable. - Another attempt is made by J.V. Neuman, and O.
Morgenstern by introducing the concept of
decision theory under the uncertain situations,
an attempt by these two to generalize some of the
foundations of the theory of individual choice to
cover uncertain situation.
205-5 PRODUCTION UNDER UNCERTAINTY
- Utility index
- The first attempt to in explaining the theory is
to assign indices to utility under uncertain
situations. - Prizes x1, x2, x3 , .xn xn is
the most preferred - Prob. v1 , v2 , .vn U(x1) 0
U(xn ) 1 - J.V. Neuman, and O. Morgenstern showed that there
is a reasonable way to assign specific utility
numbers to the different prizes available. What
they proved is that a probability like ?i exist
which makes the following relation holds - U(xi) ?i u(xn)(1- ?i) u(x1)
- What this relation means is that, that there
exist a probability such as ?i which makes the
individual indifferent between the following two
alternatives,(or both alternatives have the same
satisfaction for the individual) - 1- having xi with certainty,(with a satisfaction
of u(xi)) and - 2-a game winning xn with probability ?i and
winning x1 with probability (1- ?i), with a
satisfaction of ?i u(xn)(1- ?i) u(x1)
215-5 PRODUCTION UNDER UNCERTAINTY
- Suppose that we assign two numbers to u(xn) and
u(x1) - U(xn) 1 , and U(x1) 0
- U(xi) ?i u(xn)(1- ?i) u(x1) ?i
- for each i 1,2,.n , there exist a probability
like ?i which is equal to the utility of having
xi with certainty . So these probabilities could
be considered as utility indices. - Expected utility maximization
- Using the utility index it is possible to prove
that a rational individual will choose among the
uncertain situations based upon their expected
value of utility to him.The one with the highest
expected utility will be chosen. - Suppose that individual faces two games
- Game 1 winning x2 with probability (q) ,
- winning x3 with probability (1-q),
- Game 2 winning x5 with probability (t),
- winning x6 with probability (1-t)
225-5 PRODUCTION UNDER UNCERTAINTY
- Eu(1)q u(x2)(1-q) u(x3)q ?2(1-q) ?3
- Eu(1)q?2 u(xn)(1- ?2) u(x1)(1-q) ?3
u(xn)(1- ?3) u(x1) - Eu(1)q ?2(1-q) ?3 u(xn)q (1- ?2) (1-q)
(1- ?3) u(x1) - If ?aq ?2(1-q) ?3, then q (1- ?2) (1-q)
(1- ?3)(1- ?a) - Eu(1) ?au(xn) (1- ?a)u(x1) ?a
- Eu(2)t u(x5)(1-t) u(x6)t ?5(1-t) ?6
- Eu(2)t ?5 u(xn)(1- ?5) u(x1)(1-t) ?6
u(xn)(1- ?6) u(x1) - Eu(2)t?5(1-t) ?6 u(xn)t (1- ?5) (1-t)
(1- ?6) u(x1) - If ?b t ?5 (1-t) ?6, then t (1- ?5)
(1-t) (1- ?6)(1- ?b) - Eu(2) ?b u(xn) (1- ?b )u(x1) ?b
- If Eu(1)gt Eu(2) , then ?agt?b
- Game one will be chosen because it yields a
higher utility.
235-5 PRODUCTION UNDER UNCERTAINTY
- Risk Aversion
- Those games which has higher expected utility are
less risky. - Game 1 winning b with probability of 1/2
- winning -b (loosing b) with
probability of 1/2 - Game 2 winning 2b with probability of 1/2
- winning -2b (loosing 2b) with
probability of 1/2
U(x)
U(x)
U(w2b)
U(wb)
U(w)
U(w-b)
Eu(1)1/2u(wb)1/2 u(w-b)
Eu(2)1/2u(w2b)1/2 u(w-2b)
U(w - 2b)
x
W
Wb
W2b
W-b
W-2b
245-5 PRODUCTION UNDER UNCERTAINTY
- An individual who always rejects fair bets is
said to be risk-averse . His marginal utility of
income(wealth) is decreasing. He will always
willing to pay a premium to insure himself
against the risk. Change uncertain position to
certain one. - Production behavior
- There are two source of uncertainty for a
producer - price and quantity. At the first stage, suppose
that price is not certain p1 , p2 , p3
,..pn price level - v1 , v2 , v3 ,..vn
probability - ?ipiq c(q) profit level when price pi
- u(?i) utility obtained from the
profit level when price is pi - Eu(?)Sin vi u(?i) expected utility of
profit derived in the uncertain situation . - In the uncertain situations the producer should
maximize the expected utility of profit, rather
than maximizing the expected level of profits. - d Sin vi u(?i)/dq 0 , Sin
vi u(?i)(pi c(q))0 -
-
255-5 PRODUCTION UNDER UNCERTAINTY
- There could be three situations
- 1- individual is risk netural. He is indifferent
between risky and non risky situations. - d u(?i)/d?i 0 , u(?i)A is constant,
u(?i)0 - v1A(p1 c(q)) v2A(p2 c(q)). vn A(pn
c(q)0 , qq0 - 2- individual is risk averse. He prefers non
risky situation to risky situation. - d u(?i)/d?i lt 0 , u(?i)is decreasing ,
u(?i) lt 0 - v1 u(?1)(p1c(q)) v2 u(?2)( (p2c(q)). vn
u(?n)(pnc(q))0,, qq1 - and u(?1)gt u(?2)gt. u(?n), q1ltq0
- 3- individual is risk taker. He is prefers risky
situation to non risky situation. - d u(?i)/d?i gt 0 , u(?i)is increasing ,
u(?i) gt 0 - v1 u(?1)(p1c(q)) v2 u(?2)( (p2c(q)). vn
u(?n)(pnc(q))0 qq2 - , and u(?1)lt u(?2)lt. u(?n), q2gtq0
265-5 PRODUCTION UNDER UNCERTAINTY
- 2- suppose that price is known but quantity is
not known. (future market in the agricultural
products). - quantity q1 , q2 , q3 ,.qn target
q0, qifiq0 - fi percent of q0 which depends on climate.
- probability v1 , v2 , v3 , .vn
- ?ipfiq0 c(q0)
- Producer decision is to find the target
production level - d Sin vi u(?i)/dq 0 , Sin vi u(?i)(p fi
c(q))0 - the same result will be obtained.
275-6 LINEAR PRODUCTION
x2
Expansion path
- 1-Fixed proportion input combination
- 2-constant return to scale.
- 1- one output q
- m inputs xi , I1,2,3,4.n
- one activity (production technique) j1
- xiaiq total input of xi necessary to
produce total q - aiinput of xi necessary to produce one unit
of q - qmin(xi/ai)
- suppose that a1 2 , and a2 5 ,
- q x1a1q x2a2q
- 1 2 5
- 2 4 10
- ..
- n 2n 5n
- Qmin(x1/2 , x2/5)min(8/2 , 10/5)2
q3
3
q2
2
q1
1
x1
1
2
3
Expansion path
x2
q2
10
q1
5
x1
2
4
8
285-6 LINEAR PRODUCTION
- 2- one output q
- m input xi i 1, 2, . m
- n activity j1, 2, .n
- q S1n qj
- xi Sj1n aij qj
- aij xi necessary to produce one unit of q
in the jth activity. - input of xi necessary to produce one unit of
q Ai - Ai (xi/q)Sj1n aij (qj/q) Sj1n aij ?j
?j qj/q - qmin(xi/Ai)
- Suppose that there are three activities and
two inputs -
-
j1 J2 J3
X1 a111 a 12 2 a134
X2 a218 a225 a233
activity
input
295-6 LINEAR PRODUCTION
x2
J2
J1
- Not even it is possible to
- produce one unit of output
- with any of these activities,
- but also it is possible to
- produce one unit of q
- with the combination
- of these activities
- (xi/q) Sj1n aij ?j ,
- ?j qj/q , j1,2
- Suppose ?1 ?21/2 , q1
- X1qa11 ?1a12 ?2
- 1(1)(1/2)(2)(1/2)1.5
- X2qa21 ?1a22 ?2
- (1)(8)(1/2)(5)(1/2)6.5
16
Q2
E
J3
F
Q2
7.33
10
A
6.5
8
Q1
G
Q2
B
Q1
5
C
Q1
6.66
x1
1.5
2
4
6
8
10
1
305-6 LINEAR PRODUCTION
- Suppose ?21/3 ?32/3 , q2
- X1qa12 ?2a13 ?3
- 2(2)(1/3)(4)(2/3)6.66
- X2qa22 ?2 a23 ?3
- (2)(5)(1/3)(3)(2/3)7.33
- Only points on ABC line or EFG line are
efficient. Any other point is not efficient.
Efficient point ,(comparing to any other point),
is the one that can produce the same level of
output with minimum amount of inputs. In the same
manner ith activity is not efficient if another
activity like j, could be found which produce the
same output with less output (either x1 or x2 or
both should be lower). - 3- s outputs qh h1,2,3,4..s
- m inputs xi i 1,2,3,4.
- one activity
- xi Sh1s aihqh
- aih input xi necessary to produce one unit of
output h.
315-6 LINEAR PRODUCTION
- 4- h outputs qh h1,2,3,4,..s
- m inputs xi i 1,2,3.m
- n activity j1,2,3. N
- qh Sj1n ahj zj
- xi Sj1n bij zj
- ahjamount of output h in one unit of
composite commodity basket in activity j . - composite commodity basket basket of
commodities contains from h outputs. - Zj units of composite commodities produced in
activity j - bij input i used for the production of one
unit of composite commodity in activity j .
32 5-6 LINEAR PRODUCTION
- Application of linear programming for linear
activities - Max TRp1q1 p2q2 pnqn original
- S.T. ai1q1 ai2q2 ..ainqn xi0 i
1,2,3 ,.m - L p1q1 p2q2 . ?1 x10 (a11q1a12q2a1nqn
) - ?2 x20
(a21q1a22q2a2nqn) -
- ?m xm0
(am1q1am2q2amnqn) - (?L/?q1)Lq1 p1 - ?1a11 ?2a21 - - ?mam1 0 ,
q1 Lq10 - (?L/?q2)Lq2 p2 - ?1a12 ?2a22 - - ?mam2 0
, q2 Lq20 - ..
- (?L/?qn)Lqn pn - ?1a1n ?2a2n - . ?mamn 0
, qn Lqn0 - (?L/??1) L?1 x10 a11q1 a12q2-- a1nqn
0 , ?1 L?1 0 - (?L/??2) L?2 x20 a21q1 a22q2-- a2nqn
0 , ?2 L?2 0 -
- (?L/??m) L?m xm0 am1q1 am2q2-- amnqn 0
, ?m L?m 0 - mn equations, mn unkowns (?1. ?m, q1,qn)
- Max TR Sj1n pjqj
335-6 LINEAR PRODUCTION
- Min TCr1x1r2x2..rmxm
dual - S.T. a1jr1a2jr2..amjrm pj j1,2,3.n.
- aijr1a2jr2..amjrm average cost of qj
- In the long run equilibrium in perfect
competition , average cost could not be lower
than price. If Acqj is lower than price, the
optimum solution (minimum cost) for ri will be ri
0 . - Lr1x1r2x2rmxm µ1p10 (a11r1a21r2.
am1rm) -
. - µnpn0 (a1n
r1a2n r2. amn rm) - (?L/?r1)Lr1x1 - µ1a11 - . - µna1n 0 ,
r1Lr10 - (?L/?r2)Lr2x2 - µ1a21 - . - µna2n 0 ,
r2Lr20 - ..
- (?L/?rm)Lrmxm- µ1am1 - . - µnamn 0 ,
rmLrm0 - (?L/?µ1)Lµ1p1 - a11r1 - . - am1 rm 0 ,
µ1Lµ10 - (?L/?µ1)Lµ2p2 - a12r1 - . - am2 rm 0 ,
µnLµn0 -
- (?L/?µn)Lµnpn - a1n r1 - . -amn rm 0 ,
µnLµn0 - mn equations, mn unknown , (r1 rm ,
µ1µn)
345-6 LINEAR PRODUCTION
- Comparing original and dual F.O.C.
- Original parameterdual constraint pj
- Original constraint dual parameterxi
- ri ?i shadow price of xi
TCSimrixiSjn pjqjTR - qjµj shadow quantity for qj
TCSimrixiSjn pjqjTR - Example production of Car and Truck,
- price of car5000 , price of truck4000
- Resource Total required to
produce required to produce - available one unit Truck
one unit of Car - Labor 720 L.H. 1 L.H.
2 L.H. - Machine 900 M.H. 3 M.H.
1 M.H. - Steel 1800 T 5 Ton
4 Ton - Max TR4000T 5000C
- S.T. T 2C 720
C300 , T 120 - 3 T C 900 max
TR1980000 - 5 T 4C 1800
355-6 LINEAR PRODUCTION
Min 720pL900pk1800ps s.t. pL3pk5 ps 4000
2pLpk4 ps 5000 As it is clear , machine
constraint is not binding so Price of machine
is zero pk0 pL 5ps 4000
pL1500 2pL 4ps 5000 ps500
min
TC1980000
min TC maxTR
profit 0
Car
900
Machine
800
700
600
steel
500
400
TR4000T5000C
300
200
labor
100
Truck
100
200
300
400
500
600
700
36H Q , CH 5 , PROBLEMS
- Q5-1 Each of the following production
functions is homogeneous of degree one. In each
case, derive the marginal products for x1 and x2
and demonstrate that they are homogenous of
degree zero (a) q(ax1x2 bx12 -
cx22 )/(ax1bx2) - (b) qAx1ax21-a bx1 cx2
- solution
- a (dq/dx1) (ax1-2bx1)(ax1bx2)-a(ax1x2
bx12 - cx22 )/(ax1bx2)2 - MPx1(mx1,mx2)
- m2 (ax1-2bx1)(ax1bx2)-a(ax1x2 bx12 -
cx22)/m2(ax1bx2)2 MPx1(x1,x2) - (dq/dx2) (ax2 2cx2)(ax1bx2)-a(ax1x2
bx12 - cx22 )/(ax1bx2)2 - MPx2(mx1,mx2)
- m2 (ax2-2cx2)(ax1bx2)-a(ax1x2 bx12 - cx22
/m2(ax1bx2)2 MPx1(x1,x2) - B (dq/dx1)aAx1a-1x21-a baA(x1/x2)a-1,
MP(mx1,mx2)MP(x1,x2) - (dq/dx2)aAx1ax2-a baA(x1/x2)a,
MP(mx1,mx2)MP(x1,x2)
37H Q , CH 5 , PROBLEMS
- Q5-2 An entrepreneur uses two distinct
production processes to produce two distinct
goods, Q1 and Q2. The production function for
each good is CES, and the entrepreneur obeys the
equilibrium condition for each. Assume that Q1
has a higher elasticity of substitution and a
lower value for the parameter than Q2 .
Determine the input price ratio at which the
input use ratio would be the same for both goods.
Which good would have the higher input use ratio
if the input price ratio were lower? Which would
have the higher use ratio if the price ratio were
higher? - Solution the equilibrium conditions are as
follows - k1a1rs1 k2a2rs2 kiinput use
ratio for i (x1/x2)i - by assumption s1gt s2 and a1gt a2
. - if k1k2 , then a1rs1 a2rs2 , so r
(a2/a1) r - by assumption (s1 - s2)gt0 ,
- if rr , then k1k2 , and if rgt r , then
k1gtk2 and vice versa
38 H Q , CH 5 , PROBLEMS
- Q5-3 An entrepreneur has the production function
of the form - qAx1ax21-a . She buys input and sells output
at fixed prices, but is subject to a quota which
allows her to purchase not more than x10 units of
x1. She would have purchased more in the absence
of quota. Use the Kuhn-Tucker analysis to
determine the entrepreneurs conditions for
profit maximization. What is the optimal relation
between the value of the marginal product of each
input and its price. What is the optimal relation
between the RTS and the input price ratio. - Solution
- Max ? pq r1x1 r2x2 ?(x10-x1)
- (??/?x1) pMPx1 r1 - ? 0 ,
(??/?x1)x1 0 - (??/?x2) pMPx2 r2 0 ,
(??/?x2)x2 0 - (??/? ?) (x10-x1) 0 ,
?(x10-x1) 0 - if x10, pMPx1lt r1 ? and if
x1gt0, pMPx1 r1 ? - if x20, pMPx2lt r2 and if
x2gt0, pMPx2 r2 - r2pMPx2p(1-a)A(x1/x2)a
- r1pMPx1paA(x1/x2)a-1 - ?
- RTS (MPx1/MPx2)(r1 ?)/r2 gt r1 /r2
-
39 H Q , CH 5 , PROBLEMS
- Q5-4 Use Shepherd's lemma to find the
production function that corresponds to the cost
function C(r12(r1r2)1/2 r2)q and demonstrate
that it is CES. - Solution
- (?C/?r1)(1r2(r1r2)-1/2 )q
- (?C/?r2)(1r1(r1r2)-1/2 )q if r(r1/r2)
- (?C/?r1)(1r2(r1r2)-1/2 )q(1 r1/2)q
- (?C/?r2)(1r1(r1r2)-1/2 )q(1 r1/2)q
- (1 r1/2)q x1
- (1 r1/2) q x2 qx1x2/ (x1x2)
½(1/2)x1-1 (1/2)x2 1-1 - Q5-5 A farmer who sells at a fix price of 5
dollars per unit and has the cost function
C3.50.5 q2 , plans to maximizes profit under
certainty. After planning she discovers that she
can have a fertilizer applied that will increase
her yield 40 percent with a probability of 0.25
percent, 60 percent with a probability of 0.5 ,
and 88 percent with a probability of 0.25 . Her
utility function is U(?)1/2 . Determine the
maximum amount that she is willing to pay for the
fertilizer application. Contrast this amount with
the expected value of the increase in her profit
as a result of fertilizer application.
40H Q , CH 5 , PROBLEMS
- Solution
- qtarget , P5 , C(q)3.5 0.5 q2 , U?
1/2 , U(1/2) ?-1/2 - (v11/4 , d11.4) , (v21/2 , d21.6) ,
(v31/4 , d31.88) - EU(?)Si3 vi u( ?i ) Si3 vi u pdiq
C(q) , ?i pdiq C(q) - dEU(?)/dq Si3 vi u (?i) pdi C (q) 0
- qq0 , EU(?) Si3 vi u pdiq0 C(q0) U0
- no fertilizer situation
- pmc , q5 , ? pq TC 25 (3.5
(0.5)(25) ) 9 - u (?)1/2 3
- U0 should be greater than 3 for the farmer to
use fertilizer . The difference between these
two (U0 3) is the farmers gain in - terms of utility and maximum amount that he
is willing to pay for fertilizer. - d( E(?))/dq dv1 ?1 v2 ?2 v3
?31/4(5)(1.4q) - 3.5 0.5q2 - 1/2(5)(1.6q) - 3.5 0.5q2 1/4(5)(1.88q)
- 3.5 0.5q2 /dq 0 - qA , ? E(?) ? , U U(?) , U can be
compared with U0
41H Q , CH 5 , PROBLEMS
- Q5-6 a linear production function contains
four activities for the production of one output
using two inputs. The input requirements per unit
output are - a111 a122 a133 a145
- a216 a225 a233 a242
- are any activities inefficient in the sense that
there is no input price at which they would be
used.
x2
J1
J2
Solution Comparing to point e point b is
not efficient. Since with the same amount of x1 ,
it uses less x 2 . In order to find the x1 and
x2 related to point e x1
q?a11(1-?)a13 , x2 q?a21(1-?)a23 x12
, q1 , a111 , a133 , ?1/2 x21(1/2)(6)
(1/2)(3)4.5
J3
a
b
6
e
5
4.5
J4
4
c
3
2
d
1
x1
1
2
3
4
5
6
42H Q , CH 5 , PROBLEMS
- Q5-7 Each of the linear activities yields s
outputs and uses m inputs as described by - h outputs qh h1,2,3,4,..s
- m inputs xi i 1,2,3.m
- n activity j1,2,3. N
- qh Sj1n ahj zj xi Sj1n
bij zj - ahj the amount of output h in one unit of
composite commodity in activity j . - composite commodity basket of commodities
contains from h outputs. - Zj units of composite commodities produced in
activity j - bij input i used for the production of one
unit of composite commodity in activity j . - An entrepreneur possesses fixed quantities of
each of the inputs. She desires to maximizes her
total revenue from the sale of outputs at
constant market prices. Formulate her
optimization problem as a linear-programming
system, and derive the dual programming system.
43H Q , CH 5 , PROBLEMS
- Solution
- If ph is the price of qh , total income is equal
to Y - ahjamount of output h in one unit of composite
commodity in activity j . - composite commodity basket of commodities
contains from h outputs. - Zj units of composite commodities produced in
activity j - bij input i used for the production of one
unit of composite commodity in activity j - Y Shs ph qh Shs ph Sj1n ahj zj , so
maximization problem is - max Y Shs ph Sj1n ahj zj total revenue
- S.T. xi Sj1n bij zj input constraint
(decision variable Zj). - the dual formulation is
- Min CSim ri xi total cost
- S.T. Sim bij ri yj (yj Shs ph ahj revenue
from one level of Zj , Zj 1 ) - Sim bij ricost of producing one level of Zj
(decision variableri) - Sim bij ri cost of production of one unit of
composite commodity in activity j. - yj ph Sj1n ahj Sj1n ph ahj income
received from the sale of one unit of composite
commodity in activity j .