Title: Structural Analysis I
1Structural Analysis I
- Structural Analysis
- Trigonometry Concepts
- Vectors
- Equilibrium
- Reactions
- Static Determinancy and Stability
- Free Body Diagrams
- Calculating Bridge Member Forces
2Learning Objectives
- Define structural analysis
- Calculate using the Pythagoreon Theorem, sin, and
cos - Calculate the components of a force vector
- Add two force vectors together
- Understand the concept of equilibrium
- Calculate reactions
- Determine if a truss is stable
3Structural Analysis
- Structural analysis is a mathematical examination
of a complex structure - Analysis breaks a complex system down to
individual component parts - Uses geometry, trigonometry, algebra, and basic
physics
4How Much Weight Can This Truss Bridge Support?
5Pythagorean Theorem
- In a right triangle, the length of the sides are
related by the equation - a2 b2 c2
6Sine (sin) of an Angle
- In a right triangle, the angles are related to
the lengths of the sides by the equations - sin?1
Opposite b Hypotenuse c
sin?2
7Cosine (cos) of an Angle
- In a right triangle, the angles are related to
the lengths of the sides by the equations - cos?1
Adjacent a Hypotenuse c
cos?2
8This Truss Bridge is Built from Right Triangles
9Trigonometry Tips for Structural Analysis
- A truss bridge is constructed from members
arranged in right triangles - Sin and cos relate both lengths AND magnitude of
internal forces - Sin and cos are ratios
10Vectors
- Mathematical quantity that has both magnitude and
direction - Represented by an arrow at an angle ?
- Establish Cartesian Coordinate axis system with
horizontal x-axis and vertical y-axis.
11Vector Example
- Suppose you hit a billiard ball with a force of 5
newtons at a 40o angle - This is represented by a force vector
12Vector Components
- Every vector can be broken into two parts, one
vector with magnitude in the x-direction and one
with magnitude in the y-direction. - Determine these two components for structural
analysis.
13Vector Component Example
- The billiard ball hit of 5N/40o can be
represented by two vector components, Fx and Fy
14Fy Component Example
- To calculate Fy, sin?
- sin40o
-
- 5N 0.64 Fy
- 3.20N Fy
15Fx Component Example
- To calculate Fx, cos?
- cos40o
-
- 5N 0.77 Fx
- 3.85N Fx
16What does this Mean?
Your 5N/40o hit is represented by this vector
The exact same force and direction could be
achieved if two simultaneous forces are applied
directly along the x and y axis
17Vector Component Summary
Force Name 5N at 40
Free Body Diagram
x-component 5N cos 40
y-component 5N sin 40
18How do I use these?
She pulls with 100 pound force
- Calculate net forces on an object
- Example Two people each pull a rope connected
to a boat. What is the net force on the boat?
He pulls with 150 pound force
19Boat Pull Solution
y
- Represent the boat as a point at the (0,0)
location - Represent the pulling forces with vectors
Fm 150 lb
Ff 100 lb
Tm 50o
Tf 70o
x
20Boat Pull Solution (cont)
Separate force Ff into x and y components
- First analyse the force Ff
- x-component -100 lb cos70
- x-component -34.2 lb
- y-component 100 lb sin70
- y-component 93.9 lb
21Boat Pull Solution (cont)
Separate force Fm into x and y components
- Next analyse the force Fm
- x-component 150 lb cos50
- x-component 96.4 lb
- y-component 150 lb sin50
- y-component 114.9 lb
22Boat Pull Solution (cont)
Force Name Ff Fm Resultant (Sum)
Vector Diagram (See next slide)
x- component -100lbcos70 -34.2 lb 150lbcos50 96.4 lb 62.2 lb
y-component 100lbsin70 93.9 lb 150lbsin50 114.9 lb 208.8 lb
23Boat Pull Solution (end)
y
- White represents forces applied directly to the
boat - Gray represents the sum of the x and y components
of Ff and Fm - Yellow represents the resultant vector
FTotalY
Fm
Ff
-x
x
FTotalX
24Equilibrium
- Total forces acting on an object is 0
- Important concept for bridges they shouldnt
move! - S Fx 0 means The sum of the forces in the x
direction is 0 - S Fy 0 means The sum of the forces in the y
direction is 0
25Reactions
- Forces developed at structure supports to
maintain equilibrium. - Ex If a 3kg jug of water rests on the ground,
there is a 3kg reaction (Ra) keeping the bottle
from going to the center of the earth.
3kg
Ra 3kg
26Reactions
- A bridge across a river has a 200 lb man in the
center. What are the reactions at each end,
assuming the bridge has no weight?
27Determinancy and Stability
- Statically determinant trusses can be analyzed by
the Method of Joints - Statically indeterminant bridges require more
complex analysis techniques - Unstable truss does not have enough members to
form a rigid structure
28Determinancy and Stability
- Statically determinate truss 2j m 3
- Statically indeterminate truss 2j lt m 3
- Unstable truss 2j gt m 3
29Acknowledgements
- This presentation is based on Learning Activity
3, Analyze and Evaluate a Truss from the book by
Colonel Stephen J. Ressler, P.E., Ph.D.,
Designing and Building File-Folder Bridges