Title: Wheatstone Bridge Equivalent Circuits
1Wheatstone Bridge / Equivalent Circuits
Homework handout Barnaal 12 (pg48) Lab2
Wheatstone Bridge/ Equiv. Circuits Read
Oscilloscope Handout Barnaal 16-20
2Wheatstone Bridge
Used to measure an unknown resistor Rx Resistor
Rk is known, and the two resistors R1 and R2 have
a known ratio R2 /R1, although their individual
values may not be known. A galvanometer (a
sensitive voltmeter) G measures the voltage
difference VAB between points A and B. Either the
known resistor Rk or the ratio R2 /R1 is adjusted
until the voltage difference VAB is zero and no
current flows through G. When VAB 0, the bridge
is said to be "balanced".
unknown
known
Since VAB 0, the voltage drop from C to A must
equal the voltage drop from C to B, VCA VCB.
Likewise, we must have VAD VBD. So we can write
3Circuit Analysis Loaded Voltage Divider (1)
R1
i1
RS
i
i1
VS
R2
i2
RLoad
Use KCL and KVL to find VLoad
?
Brute Force Analysis
4Circuit Analysis Loaded Voltage Divider (2)
Result
Reff
i
Veff
RLoad
Note A systematic application of KVL and KCL
with Ohms Law will always yield a complete
solution for the voltages and currents. In most
problems, however, one might only be interested
in the value of a single voltage or current.
There is a better way
5Thevenin method easier!
Veff open circuit potential at the divider
output
R1
i1
RS
VS
R2
i2
6Thevenin method (2)
Reff open circuit resistance with Vs replaced
by a short circuit
R1
RS
R2
7Thevenins Theorem
a
a
b
b
- Any linear network may be simplified to a
two-terminal circuit consisting of a single
voltage source, ETh , in series with a single
resistor, RTh. - ETh is the equivalent open-circuit voltage across
terminals a and b, and RTh is the equivalent
resistance seen between the same terminals. - (Note EThVeff and RThReff from previous
example) - Any mess of batteries and resistors can be
mimicked with one battery and one resistor in
series with it
8Procedure for converting any circuit to its
Thevenin equivalent
- Remove the load from the circuit.
- Set all sources in the circuit to zero by
replacing them with wires. - RTh is obtained by calculating the resistance
across the open-terminals ab. - Replace the sources removed in step 2 and obtain
Eth by calculating the open-circuit voltage
across terminals ab.
9Thevenins Theorem
a
a
R
Network A
Network B
Th
E
Th
R
L
b
b
a
a
Network A (with independent sources removed)
Network A
E
Th
R
Th
-
b
b
10Example problem (with your neighbor)
Find the Thevenin equivalent circuit! Note the
load has been already removed!
RTh?
R1
A
A
V0
ETh?
R2
B
B
R3
11Nortons Theorem
- Any linear network may be simplified to a
two-terminal circuit consisting of a single
current source, IN , and a single shunt resistor,
RN. - IN is the equivalent short-circuit current
between terminals a and b, and RN is the
equivalent resistance seen between the same
terminals.
12Procedure for converting any circuit to its
Norton equivalent
- Remove the load from the circuit.
- Set all sources in the circuit to zero.
- RN is obtained by calculating the resistance
across the open-terminals ab. (note RNRTh) - Replace the sources removed in step 2 and obtain
IN by calculating the short-circuit current
between terminals ab.
13Nortons Theorem
a
a
Network A
Network B
I
N
RN
R
L
b
b
a
a
Network A (with independent sources removed)
Network A
IN
R
N
b
b
14Example problem (with your neighbor)
Find the Norton equivalent circuit! Note the
load has been already removed!
R1
A
A
V0
IN?
R2
RN?
B
B
R3
(double-check your answer with earlier example)
15Voltage source
V0
- a perfect voltage source is a two-terminal black
box that maintains a fixed voltage drop across
its terminals, regardless of the load resistance.
This means that it must supply a current I V /
R when a resistance R is attached to its
terminals - a real voltage source can only supply a finite
maximum current, and behaves like a perfect
voltage source with a small resistance in series
16- Real voltage sources (like batteries) have
internal resistance
Rs
Vs
RL
Depends on current leaving battery!
-
-
-
Battery
Current in circuit
A voltage source likes an open-circuit load and
hates a short-circuit load
17Current source
- a perfect current source is a two-terminal black
box that maintains a constant current through the
external circuit, regardless of load resistance
or applied voltage. In order to do this it must
be capable of supplying any necessary voltage
across its terminals. - real current sources have a limit to the voltage
they can provide, they do not provide an absolute
constant output current - A current source likes short-circuit load and
hates open-circuit load
18Source Conversion
- A voltage source can be converted into a current
source - The voltage source is represented by its Thevenin
equivalent with VEth, Rs RTh - The current source is represented by its Norton
equivalent with IIN, RsRNRTh - Note INETh/RN , RNRTh
Ideal constant-current source
I
RS
I
E
RS
E IRS
I E/RS
Source conversion
19Voltage Transfer
Current Transfer
i
RS
i
iS
VS
RL
RS
V
V
RL
-
-
(current divider)
(voltage divider)
Reference Senturia
20Power Transfer
RS
i
VS
V
RL
-
Power dissipated in RL
Maximum power transfer for
(show in homework)
Then
21Maximum Power Transfer Theorem
a
b
- A load resistance will receive maximum power from
a circuit when the resistance of the load is
exactly the same as the Thevenin (or Norton)
resistance looking back at the circuit. - The maximum power delivered to the load is
22Superposition Theorem
E
E
I
I
R1
R1
R2
R1
R2
R2
- The total current through or voltage across a
resistor or branch may be determined by summing
the effects due to each independent source. - Replace all voltage sources with a short circuit
and all current sources with an open circuit,
except for the one source to be examined.
23Superposition Theorem (2)
I
KCL
KVL
(2 equations with 2 unknowns i1 i2)
brute force
Solve and find
24Superposition Theorem (3)
(same result)