Quadrature Amplitude Modulation (QAM) Transmitter - PowerPoint PPT Presentation

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Quadrature Amplitude Modulation (QAM) Transmitter

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Example: y(t) = f(t) cos(wc t) Assume f(t) is an ideal lowpass signal with bandwidth w1. Assume w1 wc. Y(w) is real-valued if F(w) is real-valued ... – PowerPoint PPT presentation

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Title: Quadrature Amplitude Modulation (QAM) Transmitter


1
Quadrature Amplitude Modulation (QAM) Transmitter
  • Prof. Brian L. Evans
  • Dept. of Electrical and Computer Engineering
  • The University of Texas at Austin

2
Introduction
  • Digital Pulse Amplitude Modulation (PAM)
    modulates digital information onto amplitude of
    pulse and may be later modulated by sinusoid
  • Digital Quadrature Amplitude Modulation (QAM) is
    two-dimensional extension of digital PAM that
    requires sinusoidal modulation
  • Digital QAM modulates digital information onto
    pulses that are modulated onto
  • Amplitudes of a sine and a cosine, or
    equivalently
  • Amplitude and phase of single sinusoid

3
Amplitude Modulation by Cosine
Review
  • Example y(t) f(t) cos(wc t)
  • Assume f(t) is an ideal lowpass signal with
    bandwidth w1
  • Assume w1 lt wc
  • Y(w) is real-valued if F(w) is real-valued
  • Demodulation modulation then lowpass filtering
  • Similar derivation for modulation with sin(w0 t)

4
Amplitude Modulation by Sine
Review
  • Example y(t) f(t) sin(wc t)
  • Assume f(t) is an ideal lowpass signal with
    bandwidth w1
  • Assume w1 lt wc
  • Y(w) is imaginary-valued if F(w) is real-valued
  • Demodulation modulation then lowpass filtering

5
Digital QAM Modulator
6
Phase Shift by 90 Degrees
  • 90o phase shift performed by Hilbert transformer
  • cosine gt sine
  • sine gt cosine
  • Frequency response of idealHilbert transformer

7
Hilbert Transformer
  • Magnitude response
  • All pass except at origin
  • For fc gt 0
  • Phase response
  • Piecewise constant
  • For fc lt 0

90o
f
-90o
8
Hilbert Transformer
  • Continuous-time ideal Hilbert transformer
  • Discrete-time ideal Hilbert transformer

Even-indexed samples are zero
9
Discrete-Time Hilbert Transformer
  • Approximate by odd-length linear phase FIR filter
  • Truncate response to 2 L 1 samples L samples
    left of origin, L samples right of origin, and
    origin
  • Shift truncated impulse response by L samples to
    right to make it causal
  • L is odd because every other sample of impulse
    response is 0
  • Linear phase FIR filter of length N has same
    phase response as a delay of length (N-1)/2
  • (N-1)/2 is an integer when N is odd (here N 2 L
    1)
  • How would you make sure that delay from local
    oscillator to sine modulator is equal to delay
    from local oscillator to cosine modulator?

10
Performance Analysis of PAM
  • If we sample matched filter output at correct
    time instances, nTsym, without any ISI, received
    signal
  • where the signal component is
  • v(t) output of matched filter Gr(?) for input
    ofchannel additive white Gaussian noise N(0 ?2)
  • Gr(?) passes frequencies from -?sym/2 to ?sym/2
    ,where ?sym 2 ? fsym 2? / Tsym
  • Matched filter has impulse response gr(t)

v(nT) N(0 ?2/Tsym)
3 d
for i -M/21, , M/2
d
-d
-3 d
4-PAM
11
Performance Analysis of PAM
Filtered noise
T Tsym
Noise power
s2 d(t1t2)
12
Performance Analysis of PAM
  • Decision errorfor inner points
  • Decision errorfor outer points
  • Symbol error probability

8-PAM Constellation
13
Performance Analysis of QAM
  • Received QAM signal
  • Information signal s(nT)
  • where i,k ? -1, 0, 1, 2 for 16-QAM
  • Noise, vI(nT) and vQ(nT) are independent Gaussian
    random variables N(0 ?2/T)

14
Performance Analysis of QAM
  • Type 1 correct detection

15
Performance Analysis of QAM
  • Type 2 correct detection
  • Type 3 correct detection

16
Performance Analysis of QAM
  • Probability of correct detection
  • Symbol error probability

17
Average Power Analysis
  • PAM and QAM signals are deterministic
  • For a deterministic signal p(t), instantaneous
    power is p(t)2
  • 4-PAM constellation points -3 d, -d, d, 3 d
  • Total power 9 d2 d2 d2 9 d2 20 d2
  • Average power per symbol 5 d2
  • 4-QAM constellation points d j d, -d j
    d,d j d, -d j d
  • Total power 2 d2 2 d2 2 d2 2 d2 8 d2
  • Average power per symbol 2 d2
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