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Title: DNA: The


1
Chapter 16 The Molecular Basis of Inheritance
  • DNA The
  • Genetic Material

2
Intro to DNA Video
  • http//www.youtube.com/watch?vbVk0twJYL6Yfeature
    youtube_gdata_player

3
Just a thought
  • Make a stack of books totaling
  • about 10,000 pages.
  • That stack of books represents
  • only about one-fiftieth of the information
  • contained in the DNA of
  • every human cell.
  • Correlate this with the amount of information
  • required to code for a human being.

4
(No Transcript)
5
Quick Review1. What is the structure of a
chromosome?2. Define the term gene.3.
Identify the stage in the cell cycle in which DNA
is copied.4. What are mutations?5. Summarize
Mendels theory of heredity.
6
  • Answers
  • 1. A chromosome consists of two replicated
    strands of DNA tightly coiled around proteins.
  • The two strands, called chromatids, are attached
    at a point called a centromere.
  • 2. A gene is a segment of DNA that codes for a
    protein or RNA molecule.
  • 3. A cells DNA is copied during the synthesis
    (S) phase.
  • 4. When chromosomes break, the broken pieces can
    detach completely or can reattach in various
    ways. Therefore, the chromosome is changed, or
    mutated.

7
  • 5. (a) For each inherited trait, an individual
    has two copies of the gene, one from each parent.
  • (b) There may be alternative versions of genes.
  • (c) When two different alleles occur together,
    one of them may be completely expressed, while
    the other may have no observable effect on the
    organisms appearance.
  • (d) When gametes are formed, the alleles for each
    gene in an individual separate independently of
    one another, and when gametes unite during
    fertilization, each gamete contributes one
    allele.

8
Vocabulary
  • 1. DNA /double helix,
  • 2. Nucleosome
  • 3. Semi conservative replication,
  • 4. DNA polymerase,
  • 5. Okazaki fragment

9
Vocabulary
  1. vaccine
  2. virulent
  3. transformation
  4. bacteriophage
  5. double helix
  6. nucleotide
  7. deoxyribose
  8. base-pairing rules
  9. complementary base pair
  10. DNA replication
  11. DNA helicase
  12. replication fork
  13. DNA polymerase

10
  • 1. What are the two chemical components of
    chromosomes?

11
  • DNA and protein

12
Chapter DNA The Genetic Material
  • 1. Identifying the Genetic Material
  • A. Transformation
  • B. Viral Genes and DNA

13
2. Why did researchers originally think that
protein was the genetic material?
14
  • Until the 1940s, the case for proteins seemed
    stronger, especially since biochemists had
    identified them as a class of macromolecules with
    great heterogeneity (uniformity) and
    specificity of function, essential requirements
    for the hereditary material.
  • Also, little was known about nucleic acids, whose
    physical and chemical properties seemed far too
    uniform to account for the multitude of specific
    inherited traits exhibited by every organism.

15
Identifying the Genetic Material
  • The experiments of Griffith and of Avery yielded
    results that suggested DNA was the genetic
    material.

16
  • Frederick Griffith--Discovery of the Transforming
    Principle (Video Clip)

17
Griffiths Discovery of Transformation
18
The capsule killed, non capsule did not!
Heat-killed capsule, did not KILL! BUT A MIX OF
THE 2 DID!
19
3. Distinguish between the virulent and
non-virulent strains of Streptococcus pneumoniae
studiedby Frederick Griffith.
20
  • The virulent strains ( with capsules) are
    pathogenic (disease-causing), whereas the
    nonvirulent strains ( no capsule) are
    nonpathogenic (harmless).

21
4. What was the purpose of Griffiths studies?
22
  • Griffith was attempting to develop a vaccine
    against pneumonia.

23
What happened?5. Use this figure to summarize
the experiment in which Griffith became aware
that hereditaryinformation could be transmitted
between two organisms in an unusual manner.
24
  • information could be transmitted between two
    organisms in an unusual manner.
  • Griffith studied two strains of the bacterium
    Streptococcus pneumoniae. Bacteria of the S
    (smooth) strain can cause pneumonia in mice they
    are pathogenic because they have an outer capsule
    that protects them from an animals defense
    system. Bacteria of the R (rough) strain lack a
    capsule and are nonpathogenic.
  • To test for the trait of pathogenicity, Griffith
    injected mice with the two strains. Griffith
    concluded that the living R bacteria had been
    transformed into pathogenic S bacteria by an
    unknown, heritable substance from the dead S
    cells that allowed the R cells to make capsules.

25
Transformation
  • Something in the heat-killed bacteria that once
    were able to produce a capsule that caused them
    to kill the mice was able to transform the once
    non-virulent bacteria into capsule producing,
    virulent ones!
  • But what was that something????

26
6. Define transformation.
A change in genotype and phenotype due to the
assimilation of external DNA by a cell. When the
external DNA is from a member of a different
species, transformation results in horizontal
gene transfer.
27
Griffith 1928
  • 1. What happened to the normally non-virulent
    rough bacteria when mixed with the virulent
    smooth heat killed ones?
  • 2. Based on what happened to the bacteria, what
    was Griffiths experiment called?
  • 3. At the end of Griffiths experiment, did
    scientists know if DNA or proteins caused the
    changes?

28
Griffith 1928
  • 1. What happened to the normally non-virulent
    rough bacteria when mixed with the virulent
    smooth heat killed ones? they became virulent
  • 2. Based on what happened to the bacteria, what
    was Griffiths experiment called? the
    transforming experiment
  • 3. At the end of Griffiths experiment, did
    scientists know if DNA or proteins caused the
    changes? _no

29
Averys experiment
  • DNA destroying enzymes helped support the fact
    that it was the DNA not proteins that were the
    transforming factors!

30
  • 7. What did Oswald Avery determine to be the
    transforming factor?
  • Explain his experimental approach.

31
  • DNA !
  • Avery broke open the heat-killed pathogenic
    bacteria and extracted the cellular contents. He
    treated each of three samples with an agent that
    inactivated one type of molecule, and then tested
    the sample for its ability to transform live
    nonpathogenic bacteria.
  • Only when DNA was allowed to remain active did
    transformation occur.

32
Avery 1944
  • 4. Avery attempted to do what?
  • 5. Did people accept Averys results?



33
Avery 1944
  • 4. Avery attempted to do what? identify if the
    substance was protein or DNA
  • 5. Did people accept Averys results?


    NO

34
  • Hershey and Chase used the bacteriophage T2 and
    radioactive labels to show that viral genes are
    made of DNA, not protein.

35
  • Alfred Hershey and Martha Chase--Acceptance
    within scientific community of DNA as genetic
    material (Video Clip)

36
bacteriophage
  • 8. Sketch a T2 bacteriophage and label its head,
    tail sheath, tail fiber, and DNA.

37
  • 9. How does a bacteriophage destroy a bacterial
    cell?

38
  • The T4 phage uses its tail fibers to bind to
    specific receptor sites on the outer surface of
    an E. coli cell. The sheath of the tail
    contracts, injecting the phage DNA into the cell
    and leaving an empty capsid outside.
  • .

39
  • The cells DNA is hydrolyzed. The phage DNA
    directs production of phage proteins and copies
    of the phage genome by host and viral enzymes,
    using components within the cell.

40
  • Three separate sets of proteins self-assemble to
    form phage heads, tails, and tail fibers. The
    phage genome is packaged inside the capsid as the
    head forms. The phage directs production of an
    enzyme that damages the bacteria cell wall,
    allowing fluid to enter. The cell swells, and
    finally bursts, releasing 100 to 200 phage
    particles

41
The Hershey-Chase Experiment
42
Hershey and Chase
  • More evidence it is DNA!

43
  • Radioactive (heavy forms) were provide for the
    phages to incorporate into their structures
  • Sulfur in protein 35 S
  • Phosphorus in DNA 32 P

44
  • The radioactive sulfur remained outside with the
    protein coat of the virus.
  • The radioactive Phosphorus went inside the
    bacteria and showed that the DNA was the
    component that went inside and produced more
    viral proteins.

45
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46
  • 10. How did Hershey and Chase label viral DNA
    and viral protein so that they could be
    distinguished? Explain why they chose each
    radioactive tag in light of the chemical
    composition of DNA and protein.

47
  • Hershey and Chase used radioactive isotopes of
    sulfur to tag protein in one batch of T2 and a
    radioactive isotope of phosphorus to tag DNA in a
    second batch.
  • Because proteins, but not DNA, contain sulfur,
    radioactive sulfur atoms were incorporated only
    into the protein of the phage.

48
  • DNA stores the information that tells cells which
    proteins to make and when to make them.

49
  • 11. Describe the means by which Hershey and Chase
    established that only the DNA of a phage enters
    an E. coli cell.
  • What conclusions did these scientists draw based
    on these observations?

50
  • Separate samples of the non-radioactive E. coli
    cells were allowed to be infected by the protein
    labeled and DNA-labeled batches of T2.
  • The researchers then tested the two samples
    shortly
  • after the onset of infection to see which type of
    moleculeprotein or DNAhad entered the bacterial
    cells and would therefore be capable of
    reprogramming them.
  • Hershey and Chase found that the phage of DNA
    entered the host cells but the phage protein did
    not.
  • Hershey and Chase concluded that the DNA injected
    by the phage must be the molecule carrying the
    genetic information that makes the cells produce
    new viral DNA and proteins.

51
Hershey and Chase 1952
  • 6. What is a bacteriophage?
  • 7. Radioactive phosphorous was used to identify
    DNA because _________does not contain phosphorous
    but DNA does.
  • 8. They could then trace the path of the
    radioactive phosphorous and found that it ended
    up in the transformed______________
  • 9. Radioactively labeled Protein did not enter
    the bacteria at all but_____________________

52
Hershey and Chase 1952
  • 6. What is a bacteriophage? A virus that
    infects bacterial cells.
  • 7. Radioactive phosphorous was used to identify
    DNA because protein_does not contain phosphorous
    but DNA does.
  • 8. They could then trace the path of the
    radioactive phosphorous and found that it ended
    up in the transformed bacteriums DNA
  • 9. Radioactively labeled Protein did not enter
    the bacteria at all but remained outside the
    cell.

53
  • 10. Which experiments led to the discovery of
    DNA as the genetic material?

54
  • 10. Which experiments led to the discovery of
    DNA as the genetic material?
  • All of them, Griffiths, Avery and Hershey and
    Chases were needed to get to the idea that DNA
    and not Protein was the genetic material. It was
    ultimately Hershey and Chases experiment that
    demonstrated that it was DNA and not protein that
    transmitted the genetic material.

55
  • 1. In 1928, the experiments of Griffith
    demonstrated transformation of
  • a. R bacteria into S bacteria.
  • b. S bacteria into R bacteria.
  • c. heat-killed S bacteria into R bacteria.
  • d. S bacteria into heat-killed R bacteria.
  • 2. In 1952, Hershey and Chase used the
    bacteriophage T2 to determine that genetic
    material is made of which of the following?
  • a. protein c. DNA
  • b. RNA d. 35S
  • 3. A microorganism that is virulent is
  • a. able to cause disease. c. a bacteriophage.
  • b. transformed. d. harmless.

56
  • 4. Averys experiments showed that
  • a. DNA is responsible for transformation.
  • b. proteins are responsible for transformation.
  • c. bacteriophages are responsible for
    transformation.
  • d. virulent bacteria are responsible for
    transformation.
  • 5. Hershey and Chase injected phages with
  • a. S bacteria. c. radioactive isotopes.
  • b. R bacteria. d. vaccines.
  • 6. Hershey and Chase found that T2
    bacteriophages
  • a. inject their DNA into host cells.
  • b. cause host cells to produce viral DNA and
    proteins.
  • c. keep most of their viral proteins outside the
    host cell.
  • d. All of the above

57
  • ______ 7. radioactive sulfur and phosphorous
  • ______ 8. transformation
  • ______ 9. bacteriophage
  • ______10. vaccine
  • a. discovered by Griffith
  • b. infects bacteria
  • c. used in the Hershey and Chase experiments
  • d. helps protect the body against future
    infections by specific disease-causing agents

58
GENETIC MATERIAL answers
  • 1. a 6. d
  • 2. c 7. c
  • 3. a 8. a
  • 4. a 9. b
  • 5. c 10. d

59
2. The Structure of DNA
  • A. A Winding Staircase
  • B. Discovering DNAs Structure

60
  • Erwin Chargaff--DNA is not equal for all species
    and ratio of bases varies among species (Video
    Clip)

61
Chargaffs data
62
12. What are Chargaffs rules? How did he arrive
at them?
63
Chargaffs rules are
  • 1. The base composition varies between species.
  • 2. Within a species, the number of A and T bases
    are equal and the number of G and C bases are
  • equal.
  • Chargaff analyzed the base composition of DNA
    from a number of different organisms. He reported
    that the base composition of DNA varies from one
    species to another. He also noticed a peculiar
    regularity in the ratios of nucleotide bases. In
    the DNA of each species he studied, the number of
    adenines approximately equaled the number of
    thymines, and the number of guanines
    approximately equaled the number of cytosines

64
13. List the three components of a nucleotide.
65
  • Phosphate, Sugar (deoxyribose for DNA ribose for
    RNA), Nitrogenous base

66
nucleotide
67
  • 1. What is a nucleotide composed of?
  • 2. What scientist looked at the data that
    analyzed the amount of guanine equaled the amount
    of cytosine and the amount of thymine equaled the
    amount of adenine and what conclusion did he draw
    from this?.

68
  • 1. What is a nucleotide composed of? Sugar,
    nitrogen base and a phosphate group
  • 2. What scientist looked at the data that
    analyzed the amount of guanine equaled the amount
    of cytosine and the amount of thymine equaled the
    amount of adenine and what conclusion did he draw
    from this? Chargaff/ these nitrogen bases must
    be paired up in the structure.

69
Watson and Crick
70
  • 14. Who are the two men who built the first
    molecular model of DNA and shared the 1962 Nobel
    Prize for discovery of its structure?

71
  • James Watson and Francis Crick

72
X ray diffraction of DNAby Rosalind Franklin
73
  • 15. What was the role of Rosalind Franklin in the
    discovery of the double helix?

74
  • Rosalind Franklin, a very accomplished X-ray
    crystallographer, conducted critical experiments
    resulting in the photograph that allowed Watson
    and Crick to deduce the double-helical structure
    of DNA.

75
  • 3. X-ray diffraction was used to help determine
    what about DNA?
  • 4. Who are the 2 scientists who put all of the
    info together to describe the structure of DNA?

76
  • 3. X-ray diffraction was used to help determine
    what about DNA? the double helix shape
  • 4. Who are the 2 scientists who put all of the
    info together to describe the structure of DNA?
    Watson and Crick

77
DNA Structure
  • Chromatin--Chromosomes and DNA subunits (Video
    Clip)

78
Purines and Pyrimidinestwo types of nitrogen
bases in DNA and RNA
  • Purinesdouble rings. Adenine and Guanine
  • Pyrimidines single rings. Thymine, Cytosine and
    Uracil which replaces Thymine in RNA

79
bonding
  • G triple hydrogen bonds to C
  • A double hydrogen bonds to T
  • These un zip in DNA replication

80
  • 17. How did Watson and Cricks model explain the
    basis for Chargaffs rules?

81
  • Watson and Crick built models of a double helix
    that would matched the X-ray measurements and
    what was known about the chemistry of DNA,
    including Chargaffs rule of base equivalences.
    Through trial and error, Watson and Crick deduced
    that the nitrogenous bases of the double helix
    are paired in specific combinationsadenine (A)
    with thymine (T), and guanine (G) with cytosine
    (C)and they reflected these findings in their
    model.
  • Whenever one strand of a DNA molecule has an A,
    the partner strand has a T. And a G in one strand
    is always paired with a C in the complementary
    strand. Therefore, in the DNA of any organism,
    the amount of adenine equals the amount of
    thymine, and the amount of guanine equals the
    amount of cytosine.

82
  • 16. Distinguish between the structure of
    pyrimidines and purines.
  • Explain why adenine bonds only to thymine.

83
  • Pyrimidinescytosine (C), thymine (T), and uracil
    (U)are characterized by a six-membered ring.
  • Purinesadenine (A) and guanine (G)are
    characterized by a six-membered ring fused to a
    five-membered ring.

84
  • Always pairing a purine with a pyrimidine results
    in a uniform diameter in the double helix.

85
  • Additionally, each base has chemical side groups
    that can form hydrogen bonds with its appropriate
    partner.
  • Adenine can form two hydrogen bonds with thymine
    and only thymine. Adenine bonds only with thymine
    because adenine is a purine, and thymine is a
    pyrimidine.

86
  • 18. Given that the DNA of a certain fly species
    consists of 27.3 adenine and 22.5 guanine, use
    Chargaffs rules to deduce the percentages of
    thymine and cytosine.

87
  • 18. Given that the DNA of a certain fly species
    consists of 27.3 adenine and 22.5 guanine, use
    Chargaffs rules to deduce the percentages of
    thymine and cytosine.
  • 27.6 thymine
  • 22.5 cytosine

88
19. Name the five nitrogenous bases, and put a
checkmark in the correct column for each
base.Also indicate if the base is found in DNA
(D), RNA (R), or both (B).
89
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90
  • 20. What DNA base is complementary to adenine?
  • What DNA base is complementary to guanine?

91
  • 20. What DNA base is complementary to adenine?
    Thymine
  • What DNA base is complementary to guanine?
    Cytosine

92
  • Describe the structure of DNA relative to each of
    the following. Indicate the distance in the
    correct location on the figure as well.
  • a. distance across molecule
  • b. distance between nucleotides
  • c. distance between turns
  • d. components of the backbone
  • e. components of the rungs

93
  • a. distance across molecule 1 nm
  • b. distance between nucleotides 0.34 nm
  • c. distance between turns 3.4 nm
  • d. components of the backbone sugar-phosphate
  • e. components of the rungs A T G C
  • I will not ask these on the test!

94
5 and 3 ends
  • Organic molecules are numbered by the carbons!

95
Antiparallel
  • Go in opposite directions 5 to 3 on one side 3 to
    5 on the other!

96
  • 22. Explain what is meant by 5' and 3' ends of
    the nucleotide.

97
  • The two free ends of the polymer are distinctly
    different from each other. One end has a
    phosphate attached to a 5' carbon, and the other
    has a hydroxyl group on the 3' carbon. We refer
    to these as the 5' end and the 3' end
    respectively.

98
  • 23. What do we mean when we say the two strands
    of DNA are antiparallel?

99
  • Their subunits run in opposite directions.

100
DNA replication
101
DNA replication Video
  • http//www.youtube.com/watch?vzdDkiRw1PdUfeature
    youtube_gdata_player

102
Semi conservative
  • Half is original half is new.
  • The method of DNA replication had to be
    determined. Several tests were done to figure
    this out

103
Matthew Meselson and Franklin Stahl
  • 1958 determined that the method of DNA
    replication was semi-conservative based on
    Nitrogen that was radioactive and heavier so it
    formed bands at different heights after
    centrifugation. The multiple generations of
    replications demonstrated the method had to be
    semi-conservative due to the intermediate bands
    produced.

104
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105
  • 24. What is the semiconservative model of
    replication?

106
  • Type of DNA replication in which the replicated
    double helix consists of one old strand, derived
    from the parental molecule, and one newly made
    strand

107
  • 26. How did Meselson and Stahl create heavy DNA
    for their experiments?

108
  • Meselson and Stahl cultured E. coli for several
    generations in a medium containing nucleotide
    precursors labeled with a heavy isotope of
    nitrogen, 15N.

109
  • 27. Use Figure 16.11 to explain how Meselson and
    Stahl confirmed the semiconservative
  • mechanism of
  • DNA replication.

110
  • Meselson and Stahl transferred their heavy DNA
    to a medium with lighter isotope, 14N. A sample
    was taken after DNA replicated once another
    sample was taken after DNA replicated again. They
    extracted DNA from the bacteria in the samples
    and then centrifuged each DNA sample to separate
    DNA of different densities.
  • Meselson and Stahl compared their results to
    those predicted by each of the three models
    (conservative, semiconservative, and dispersive).

111
  • The first replication in the 14N medium produced
    a band of hybrid DNA. This result eliminated the
    conservative model.
  • The second replication produced both light and
    hybrid DNA, a result that refuted the dispersive
    model and supported the semiconservative model.
    They therefore concluded that DNA replication is
    semiconservative.

112
  • 28. Define the origins of replication.

113
  • Site where the replication of a DNA molecule
    begins, consisting of a specific sequence of
    nucleotides

114
  • 29. Distinguish between the leading and the
    lagging strands during DNA replication.

115
  • The leading strand is the new complementary DNA
    strand synthesized continuously along the
  • template strand toward the replication fork in
    the mandatory 5' to 3' direction.
  • The lagging strand is a discontinuously
    synthesized DNA strand that elongates by means of
    Okazaki fragments, each synthesized in a 5' to 3'
    direction away from the replication fork.

116
DNA is packaged into chromosomes
117
  • Histones are positively charged, and DNA is
    negatively charged.
  • Without histones the DNA could not fit into the
    nucleus!
  • Heterochromatin is highly condensed, whereas
    euchromatin is less compact.

118
The Structure of DNA
  • DNA is made of two strands of nucleotides twisted
    into the form of a double helix.

119
  • 1. Why does DNA have to replicate every time a
    cell divides?
  • 2. When does DNA replication occur in the cell
    cycle?

120
  • 1. Why does DNA have to replicate every time a
    cell divides?
  • Because every cell needs the instructions to make
    proteins that the DNA contains.
  • 2. When does DNA replication occur in the cell
    cycle?
  • S phase of interphase

121
  • Each nucleotide in DNA is made of the sugar
    deoxyribose, a
  • phosphate group, and
  • one of four nitrogen bases.
  • The four nitrogen bases found in DNA nucleotides
    are
  • adenine (A),
  • thymine (T),
  • guanine (G),
  • and
  • cytosine (C).

122
  • The two strands of DNA are complementaryeach A
    on one strand pairs with a T on the opposite
    strand, and each G on one strand pairs with a C
    on the opposite strand.

123
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124
  • 5. Describe the structure of DNA in detail, use
    a diagram to help.

125
  • 5. Describe the structure of DNA in detail, use
    a diagram to help. The sides are made up of the
    sugar deoxy ribose and the phosphate groups
    bonded covalently together the rungs are the
    nitrogen bases with cytosine and guanine bonded
    with hydrogen bonds across from each other and
    thymine and Adenine across from each other. The
    entire thing is in a double helix and runs 3 to
    5 anti parallel.

126
The Replication of DNA
  • A. The Roles of Enzymes in DNA Replication
  • Summarize the steps of DNA replication

127
Bozeman Biology video DNA replication
  • http//www.youtube.com/watch?vFBmO_rmXxIw

128
  • B. The Rate of Replication
  • To go fast, there are multiple replication forks!

129
The Replication of DNA
  • Before a cell divides, it copies its DNA by a
    process called DNA replication. ( s phase)
  • In DNA replication, enzymes work to unwind and
    separate the double helix and add complementary
    nucleotides to the exposed strands.

130
  • The result of DNA replication is two exact copies
    of the cells original DNA.
  • Each new double helix is composed of one original
    DNA strand and one new DNA strand.
  • .

131
  • DNA polymerase proofreads DNA during its
    replication so that very few errors occur

132
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133
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134
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135
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136
  • 30. What is the direction of synthesis of the new
    strand?

137
  • 5' to 3' direction

138
  • 31. What are Okazaki fragments? How are they
    welded together?

139
  • Okazaki fragments are short segments of DNA
    synthesized away from the replication fork on a
    template strand during DNA replication. Many such
    segments are joined together by the enzyme DNA
    ligase to make up the lagging strand of newly
    synthesized DNA.

140
  • topoisomerase stabilizes the intact double helix.
    It also relieves strain in the DNA ahead of the
    replication forkhelicase unwinds the double
    helix
  • A short RNA primer is added by primase in the 5'
    to 3' direction

141
  • Helicase unwinds the parental double helix.
    (Green) at the replication fork
  • 2. Molecules of single-stranded binding protein
    stabilize the unwound template strands.( grey)

142
  • 3. The leading strand is synthesized continuously
    in the 5' to 3' direction by DNA polymerase III
    after being primed by primase. ( orange)
  • 4. Primase begins synthesis of the RNA primer for
    the lagging strand. (pink)
  • 5. DNA polymerase III synthesizes discontinuously
    the lagging strand in the 5' to 3' direction.
  • 6. DNA polymerase I removes all the RNA primer
    sections and replaces them with DNA nucleotides (
    yellow)
  • 7.

143
  • 6. DNA polymerase I removes all the RNA primer
    sections and replaces them with DNA nucleotides (
    yellow)
  • 7. The replacement of the primer with DNA leaves
    the new DNA nucleotides with a free 3' end. DNA
    ligase joins the free 3' end to its adjacent 5'
    end, forming a continuous and unbroken strand of
    DNA on both the leading and lagging strands.

144
  • 33. Label the following figures. Include 3' and
    5' strands, RNA primer, primase, SSBP,
    topoisomerase, helicase, leading strand, lagging
    strand, DNA pol I, DNA pol III, DNA ligase,
    parental DNA, and new DNA On the second figure,
    also add arrows to indicate the direction of
    synthesis.

145
  • topoisomerase stabilizes the intact double
    helix.helicase unwinds the double helix
  • A short RNA primer is added by primase in the 5'
    to 3' direction

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  • 34. Put it all together! Make a detailed list of
    the steps that occur in the synthesis of a new
    strand.
  • 1. Helicase unwinds the parental double helix.
  • 2. Molecules of single-stranded binding protein
    stabilize the unwound template strands.
  • 3. The leading strand is synthesized continuously
    in the 5' ? 3' direction by DNA polymerase III
    after being primed by primase.
  • 4. Primase begins synthesis of the RNA primer for
    the lagging strand.
  • 5. DNA polymerase III synthesizes discontinuously
    the lagging strand in the 5' ? 3' direction.
  • 6. DNA polymerase I removes all the RNA primer
    sections and replaces them with DNA nucleotides.
  • 7. The replacement of the primer with DNA leaves
    the new DNA nucleotides with a free 3' end. DNA
    ligase joins the free 3' end to its adjacent 5'
    end, forming a continuous and unbroken strand of
    DNA on both the leading and lagging strands.

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Enzymes for repair and proofreading
153
  • Prokaryotes have a single circular chromosome and
    eukaryotes have DNA packaged into several
    chromosomes that are found in the nucleus.

154
  • 6. Describe how the DNA is packaged into a
    chromosome in a eukaryote and compare this to the
    prokaryotic chromosome._

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  • 6. Describe how the DNA is packaged into a
    chromosome in a eukaryote and compare this to the
    prokaryotic chromosome._ DNA is in chromosomes in
    eukaryotic cells which means it is wrapped around
    proteins called histones into units called
    nucleosomes to make chromosomes. In the
    prokaryotic cell the DNA is in a circular strand.

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  • 3. What enzyme first unwinds the DNA helix? _
  • 4. What type of bond must be broken to unzip
    the double helix ?
  • 5. Leading and lagging strands are built using
    what enzyme?
  • 6. The strands are bonded together to form 2 new
    strands each made up of one original and one new
    side. What is the name of the enzyme used to bond
    the strands together?

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  • 3. What enzyme first unwinds the DNA helix? _
  • DNA Helicase
  • 4. What type of bond must be broken to unzip
    the double helix ?
  • hydrogen_
  • 5. Leading and lagging strands are built using
    what enzyme?
  • DNA polymerase
  • 6. The strands are bonded together to form 2 new
    strands each made up of one original and one new
    side. What is the name of the enzyme used to bond
    the strands together?
  • DNA Ligase

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Replication forks
160
  • 7. How does this process make sure that the
    original information in the DNA is maintained in
    all new cells?
  • 8. Why is this process important in terms of not
    making changes in the nitrogen base order? _
  • 9. How is the process of DNA replication in
    eukaryotes different from that of prokaryotes?

161
  • 7. How does this process make sure that the
    original information in the DNA is maintained in
    all new cells?
  • The original strands are used as templates to
    make the new copies,
  • 8. Why is this process important in terms of not
    making changes in the nitrogen base order? _
  • If changes in the nitrogen bases are made the
    instructions are changes resulting in different
    proteins and this is called a mutation!__
  • 9. How is the process of DNA replication in
    eukaryotes different from that of prokaryotes?
  • In eukaryotes, the process starts in many places
    and they then connect so that large amounts of
    DNA can be copies all at once. In prokaryotes it
    is a circular process starting in 2 places and
    then connecting in the middle.

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  • 36. What is a thymine dimer? How might it occur?
    How is it repaired?

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  • A thymine dimer is the covalent linking of
    thymine bases that are adjacent on a DNA strand,
    causing the DNA to buckle and interfere with DNA
    replication. In order to repair this damage, a
    nuclease enzyme cuts the damaged DNA strand, and
    the damaged section is removed. DNA polymerase
    fills in the missing nucleotides, and DNA ligase
    seals the free end of the new DNA to the old DNA,
    making the strand complete

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Thymine Dimer
165
  • 37. Make a sketch of a chromosome and label the
    telomeres.

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telomeres
167
  • 38. Explain telomere erosion and the role of
    telomerase.

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  • Telomeres provide their protective function by
    postponing the erosion of genes located near the
    ends of DNA molecules.
  • Telomeres become shorter during every round of
    replication.

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  • Telomeric DNA tends to be shorter in dividing
    somatic cells of older individuals and in
  • cultured cells that have divided many times.
    Importantly, some cell genomes (such as germ
  • cells) must persist virtually unchanged from an
    organism to its offspring over many generations.
    In order to accomplish this, an enzyme called
    telomerase catalyzes the lengthening of telomeres
    in eukaryotic germ cells, thus restoring their
    original length and compensating for the
    shortening that occurs during DNA replication.

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  • 39. Why are cancer cells immortal even though
    most body cells have a limited life span?
  • .

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  • Researchers have found telomerase activity in
    cancerous somatic cells, suggesting that its
    ability to stabilize telomere length may allow
    these cancer cells to persist

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  • 40. On the following diagram, identify the
    following 30-nm fiber, metaphase chromosome,
    double
  • helix, histone proteins, nucleosomes, protein
    scaffold, and looped domains (300-nm fiber).
  • See pages 320-321 in your text for the labeled
    figure.

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  • 41. Distinguish between heterochromatin and
    euchromatin.

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  • Heterochromatin is eukaryotic chromatin that
    remains highly compacted during interphase and is
    generally not transcribed. Euchromatin is a less
    condensed form of eukaryotic chromatin that is
    available for transcription. Heterochromatin is
    highly condensed, whereas euchromatin is less
    compact.

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Protein production Vocabulary
  • 1. mRNA
  • 2. rRNA
  • 3. tRNA
  • 4. Transcription
  • 5. RNA polymerase
  • 6. Intron
  • 7. Exon
  • 8. Codon
  • 9. Translation
  • 10. Gene regulation
  • 11. Operon
  • 12. Mutation
  • 13. Mutagen

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links
  • A very useful game to help comprehend DNA
    replicationhttp//www.studystack.com/matching-15
    9604
  • A beneficial video about how DNA replication
    workshttp//www.youtube.com/watch?v4jtmOZaIvS0
  • A quick video on DNA damage and
    repairhttp//www.youtube.com/watch?vnPS2jBq1k48
    featurerelated
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