Title: Organic%20Mechanisms
1Organic Mechanisms
2Free Radical Substitution
- CH4 Cl2 ? CH3Cl HCl
- An example of a substitution reaction is the
- chlorination of methane.
- A chlorine atom replaces an atom of Hydrogen
- in a molecule of methane.
3Free radical Substitution
- The mechanism involved in the chlorination of
Methane is believed to consist of the following
steps.
4Initiation
- uv light
- Cl2 Cl Cl
- The reaction mechanism begins with the homolytic
fission of the chlorine molecule by UV light. - Two atoms of chlorine with unpaired electrons are
formed. These are very reactive and, as stated
above, are called free radicals.
5Propagation
- CH4 Cl CH3
HCl - CH3 Cl2 CH3CL Cl
- A chlorine atom attacks the methane molecule to
form Hydrogen chloride and a methyl free radical.
The methy free radical attacks a chlorine
molecule and gives us one of the desired
products, CH3Cl. In so doing it yields another
chlorine free radical. If this follows the same
pathway it will yield more products and more free
radicals. - We now have a chain reaction initiated by
chlorine radicals and ending with new chlorine
radicals. This also explains why a large number
of chloromethane molecules are produced for every
photon absorbed.
6Termination
- As the number of free radicals is increasing and
the concentrations - of methane and chlorine are falling. A single
free radical has - caused many thousands of methane and chlorine
molecules to be - broken down.
- Eventually, the probability of one of these
reactions occurring increases. - 2Cl .... Cl2
- CH3 Cl .... CH3Cl
- CH3 CH3 .... CH3CH3
7Evidence
- Tetramethyl-lead greatly speeds up the
reaction. - Molecular oxygen slows down the reaction.
- Studies have shown that tetramethyl-lead,
Pb(CH3)4, decomposes to give lead, Pb, and four
CH3 radicals. This would greatly increase the
concentration of methyl radicals, thus increasing
the reaction rate, i.e it serves as an
accelerator. - On the other hand oxygen, O2, combines with
methyl radicals, CH3, to form the less reactive
peroxymethyl radical, CH3OO. This slows down the
reaction as a single oxygen molecule prevents
thousands of CH3Cl molecules being formed. Oxygen
is an inhibitor and the slowing down of a
reaction by small amounts of a substance is a
sure indication that a chain reaction is involved.
8Evidence for free radical substitution
- Free Radical Substitution Mechanism
- Halogenation reactions with alkanes involve
replacement of one or all of the hydrogens in the
alkane. These reactions may produce many products
due to the high reactivity of the free radical
species. The substitution reaction needs energy
to be supplied before the reaction can proceed.
Heating or shining ultraviolet light on the
reaction mixture may supply this energy. - (a) Chlorination of Methane
- Evidence for the mechanism occurs at all steps
- For the initiation step
- 1. The reaction will not occur in the dark at
room temperature. It will occur at room
temperature if ultraviolet light is shone on the
reactants.
9- 2. The energy supplied is not sufficient to break
a C-H bond. Sufficient energy isupplied to break
a Cl-Cl bond however. The energy of the radiation
needs to - be at least that required to homolytically spilt
the chlorine molecule. - 3. No molecular hydrogen produced hence no
hydrogen free radicals have been formed. - For the propagation steps
- 1. Thousands of chloromethane molecules are
produced for every one photon of light used. This
suggests a chain reaction consistent with
theproposed mechanism. - 2. No molecular hydrogen produced hence no
hydrogen free radicals have been formed. - For the termination steps
- 1. Ethane is produced in small amounts. Its
occurrence can only be explained by - CH3 CH3 CH3CH3
- If the reaction is left run with excess chlorine
and uv light di- tri- and tetra-chloro methane
are produced as are minute amounts of a range of
chloroethanes. - 2. The presence of tetramethyl-lead greatly
speeds up the reaction as it a source of methyl
free radicals
10Ionic Addition
- An addition reaction is one in which 2 substances
react together to form a single substance. - The mechanism involved is different from that
between methane and chlorine
11ELECTROPHILIC ADDITION OF BROMINE
C
Reagent Bromine. (Neat liquid or
dissolved in tetrachloromethane, CCl4
) Conditions Room temperature. No catalyst
or UV light required! Equation C2H4(g)
Br2(l) gt CH2BrCH2Br(l) 1,2 -
dibromoethane Mechanism It is surprising
that bromine should act as an
electrophile as it is non-polar.
CONVERSIONS
12Ionic Mechanism of Bromination of Ethene
- Step 1
- The first stage in the mechanism involves a
bromine molecule becoming momentarily polarised
on approach to the region of high electron
density of the double bond. The bromine molecule
undergoes heterolytic fission (unequal
splitting), forming a bromonium ion (Br) and a
bromide ion(Br),
13Step 2
- The Br, in order to gain the 2 electrons it
needs, attacks the C2H4 molecule. - The Br forms a covalent bond with one of the
carbon atoms. - The other carbon atom is left with a positive
charge since it lost one of its outer electrons.
This positively charged atom is called a
carbonium ion.
Carbonium ion
14Step3
- The carbonium ion is then attacked by the Br-
ion. This results in the formation of
1,2-dibromoethane.
15Evidence of ionic addition
- Evidence addition using bromine water gives
2-bromoethanol - (CH2BrCH2OH)
- OR
- addition with bromine water containing a chloride
(sodium chloride) - gives 1-bromo-2-chloroethane (Allow
1-chloro-2-bromoethane) - (CH2BrCH2Cl)
- OR
- Another specified anion / chlorine water / HCl in
water (HCl(aq), hydrochloric acid) - Product where that anion has added in place of
the chlorine (e.g. 2-chloroethanol for chlorine
water, and ethanol for HCl(aq))
16ELECTROPHILIC ADDITION OF HCl
B
Reagent Hydrogen Chloride... it is
electrophilic as the H is slightly
positive Condition Room temperature. Equation
C2H4(g) HCl(g) gt C2H5Cl(l)
chloroethane Mechanism Step 1 As the HCl
nears the alkene, one of the carbon-carbon bonds
breaks The pair of electrons attaches to the
slightly positive H end of H-Cl. The HCl bond
breaks to form a chloride ion. A carbocation
(positively charged carbon species) is
formed. Step 2 The chloride ion behaves as a
nucleophile and attacks the carbocation. Overall
there has been addition of HCl across the double
bond.
CONVERSIONS
17Esterification-Formation of an Ester
- An Ester is formed when an alcohol and a
carboxylic acid react together. This is called a
condensation reaction. -
- Alcohol Carboxylic Acid ? Ester
Water - The reverse reaction is called a Hydrolysis.
- Esters may be Hydrolysed easily in the presence
of a Base like NaOH or KOH. - Ethyl Ethanoate Sodium Hydroxide ? Sodium
Ethanoate Ethanol - CH3COOC2H5 NaOH ?
CH3COONa C2H5OH
18Soap formation
- Soaps are salts of fatty acids (long chain
carboxylic acids). Fats are esters formed by the
condensation of fatty acids and glycerol
(propane-1,2,3-triol). - Soaps are manufactured by the base hydrolysis of
these fats (esters). In this experiment the fat
is hydrolysed using sodium hydroxide in ethanol
solution. The ethanol is then removed by
distillation. - Soaps are formed by the hydrolysis of fatty acid
esters to produce salts of the fatty acids.
19How Soap Works
The hydrocarbon end of the molecule is
hydrophobic (water repelling) and the carboxylate
end is hydrophilic (water attracting). The
hydrophobic end dissolves in grease and the
hydrophilic end dissolves in the water.
20Soap
Soaps are formed by the hydrolysis of fatty acid
esters to produce salts of the fatty acids.
- Glycerine TriSterate NaOH ? Sodium
Sterate Glycerol - 3C17H35COOCH2 3NaOH 3C17H35COONa
21Preparation of Soap
The ethanol solvent is removed by distillation
Reflux apparatus used in the preparation of Soap
22Polymerisation reactions
- Polymers are long chain molecules made by joining
together many small molecules called monomers. - The polymers that we study are Addition polymers
because their manufacture involves addition
reactions.
23POLYMERISATION OF ALKENES
ADDITION POLYMERISATION
Process during polymerisation, an alkene
undergoes an addition reaction with itself
all the atoms in the original alkenes are used to
form the polymer long hydrocarbon chains are
formed
the equation shows the original monomer and
the repeating unit in the polymer
ethene poly(ethene)
MONOMER POLYMER
n represents a large number
24POLYMERISATION OF ALKENES
EXAMPLES OF ADDITION POLYMERISATION
ETHENE
POLY(ETHENE)
PROPENE
POLY(PROPENE)
CHLOROETHENE
POLY(CHLOROETHENE) POLYVINYLCHLORIDE PVC
POLY(TETRAFLUOROETHENE) PTFE Teflon
TETRAFLUOROETHENE
25ELIMINATION OF WATER (DEHYDRATION)
L
An elimination reaction is one in which a small
molecule is removed from a larger molecule to
leave a double bond in the larger
molecule. Example. The removal of water from an
alcohol is an example of an elimination
reaction Product alkene Equation e.g.
C2H5OH(l) gt CH2 CH2(g) H2O(l)
CONVERSIONS
26Redox reactions
- When a primary alcohol reacts with an oxidising
agent the primary alcohol is converted to an
aldehyde. - When a secondary alcohol reacts with an oxidising
agent the secondary alcohol is converted to a
ketone.
27OXIDATION OF PRIMARY ALCOHOLS
N
Primary alcohols are easily oxidised to
aldehydes e.g. CH3CH2OH(l)
O gt CH3CHO(l) H2O(l)
it is essential to distil off the aldehyde before
it gets oxidised to the acid
CH3CHO(l) O gt CH3COOH(l)
OXIDATION TO ALDEHYDES DISTILLATION
OXIDATION TO CARBOXYLIC ACIDS REFLUX
Aldehyde has a lower boiling point so distils off
before being oxidised further
Aldehyde condenses back into the mixture and gets
oxidised to the acid
CONVERSIONS
28OXIDATION OF ALDEHYDES
O
- Aldehydes are easily oxidised to carboxylic acids
- e.g. CH3CHO(l) O
gt CH3COOH(l) - one way to tell an aldehyde from a ketone is to
see how it reacts to mild oxidation - ALDEHYES are EASILY OXIDISED
- KETONES are RESISTANT TO MILD OXIDATION
- reagents include TOLLENS REAGENT and
FEHLINGS SOLUTION - TOLLENS REAGENT
- Reagent ammoniacal silver nitrate solution
- Observation a silver mirror is formed on the
inside of the test tube - Products silver carboxylic acid
- Equation Ag e- gt Ag
- FEHLINGS SOLUTION
- Reagent a solution of a copper(II) complex
- Observation a red precipitate forms in the blue
solution - Products copper(I) oxide carboxylic acid
CONVERSIONS
29OXIDATION OF SECONDARY ALCOHOLS
Secondary alcohols are easily oxidised to
ketones e.g. CH3CHOHCH3(l)
O gt CH3COCH3(l) H2O(l)
Propan-2-ol is
oxidised to propanone
CONVERSIONS
30REDUCTION OF ALDEHYDES
R
Reagent H2 / Nickel catalyst
Conditions Product primary alcohol Equation
e.g. CH3CHO(l) 2H gt
C2H5OH(l)
Ethanal is reduced to Ethanol
CONVERSIONS
31REDUCTION OF CARBOXYLIC ACIDS
Q
Reagent/catalyst H2 Nickel catalyst
Conditions reflux in ethoxyethane Product aldehy
de Equation e.g. CH3COOH(l)
2H gt CH3CHO(l) H2O(l)
CONVERSIONS
32REDUCTION OF KETONES
S
Reagent H2 / Nickel catalyst
Conditions warm in water or ethanol Product seco
ndary alcohol Equation e.g.
CH3COCH3(l) 2H gt
CH3CH(OH)CH3(l)
Propanone is reduced to Propan-2-ol
CONVERSIONS
33ESTERS
Structure Substitute an organic group for the H
in carboxylic acids Nomenclature first part from
alcohol, second part from acid e.g. methyl
ethanoate CH3COOCH3
ETHYL METHANOATE
METHYL ETHANOATE
34ESTERS
Structure Substitute an organic group for the H
in carboxylic acids Nomenclature first part from
alcohol, second part from acid e.g. methyl
ethanoate CH3COOCH3 Preparation From
carboxylic acids or acyl chlorides Reactivity Unr
eactive compared with acids and acyl chlorides
ETHYL METHANOATE
METHYL ETHANOATE
35ESTERS
Structure Substitute an organic group for the H
in carboxylic acids Nomenclature first part from
alcohol, second part from acid e.g. methyl
ethanoate CH3COOCH3 Preparation From
carboxylic acids or acyl chlorides Reactivity Unr
eactive compared with acids and acyl
chlorides Isomerism Esters are structural
isomers of carboxylic acids
ETHYL METHANOATE
METHYL ETHANOATE
36STRUCTURAL ISOMERISM FUNCTIONAL GROUP
Classification CARBOXYLIC ACID
ESTER Functional Group R-COOH
R-COOR Name PROPANOIC ACID
METHYL ETHANOATE Physical properties O-H bond
gives rise No hydrogen bonding to
hydrogen bonding insoluble in water get
higher boiling point and solubility in
water Chemical properties acidic
fairly unreactive reacts with alcohols
hydrolysed to acids
37PREPARATION OF ESTERS - 1
Reagent(s) alcohol carboxylic
acid Conditions reflux with a strong acid
catalyst (e.g. conc. H2SO4 ) Equation
e.g. CH3CH2OH(l) CH3COOH(l)
CH3COOC2H5(l) H2O(l) ethanol
ethanoic acid ethyl ethanoate Notes Conc.
H2SO4 is a dehydrating agent - it removes
water causing the equilibrium to move to the
right and thus increases the yield of the
ester For more details see under
Reactions of carboxylic acids
38HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL
HCOOH C2H5OH METHANOIC
ETHANOL ACID
ETHYL METHANOATE
39HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL
HCOOH C2H5OH METHANOIC
ETHANOL ACID
ETHYL METHANOATE
METHYL ETHANOATE
40HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL
HCOOH C2H5OH METHANOIC
ETHANOL ACID
ETHYL METHANOATE
CH3COOH CH3OH ETHANOIC METHANOL
ACID
METHYL ETHANOATE
41HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL The products of hydrolysis depend on the
conditions used... acidic CH3COOCH3
H2O CH3COOH CH3OH alkaline
CH3COOCH3 NaOH gt CH3COO Na
CH3OH
42HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL The products of hydrolysis depend on the
conditions used... acidic CH3COOCH3
H2O CH3COOH CH3OH alkaline
CH3COOCH3 NaOH gt CH3COO Na
CH3OH If the hydrolysis takes place
under alkaline conditions, the organic
product is a water soluble ionic salt
43HYDROLYSIS OF ESTERS
Hydrolysis is the opposite of esterification
ESTER WATER CARBOXYLIC ACID
ALCOHOL The products of hydrolysis depend on the
conditions used... acidic CH3COOCH3
H2O CH3COOH CH3OH alkaline
CH3COOCH3 NaOH gt CH3COO Na
CH3OH If the hydrolysis takes place
under alkaline conditions, the organic
product is a water soluble ionic salt
The carboxylic acid can be made by treating the
salt with HCl CH3COO Na HCl
gt CH3COOH NaCl
44NATURALLY OCCURING ESTERS - TRIGLYCERIDES
triglycerides are the most common component of
edible fats and oils they are esters of the
alcohol glycerol (propane-1,2,3-triol) S
aponification alkaline hydrolysis of
triglycerol esters produces soaps a simple
soap is the salt of a fatty acid as most oils
contain a mixture of triglycerols, soaps are not
pure the quality of a soap depends on the oils
from which it is made
45Hydrolysis of Esters to produce soap
- Soaps
- Soaps are formed by the hydrolysis of fatty acid
- esters to produce salts of the fatty acids. The
- hydrocarbon end of the molecule is hydrophobic
- (water repelling) and the carboxylate end is
- hydrophilic (water attracting). The hydrophobic
end - dissolves in grease and the hydrophilic end
- dissolves in the water.