Title: Linkage
1Linkage
- Genes linked on the same chromosome may segregate
together.
2Independent Assortment2 chromosomes
P AABB x aabb
A
b
a
B
Parental Gametes AB ab
F1
A
A
a
B
b
B
a
b
R
R
3MeiosisOne Chromosome No Cross Over
2n 2
A
a
Parent Cell
B
b
A
A
a
a
B
B
b
b
Daughter Cells Have Parental Chromosomes
4MeiosisOne Chromosome With Cross Over
2n 2
A
a
Parent Cell
B
b
A
A
a
a
B
b
B
b
Daughter Cells Have Recombinant Chromosomes
5Meiosis Prophase I
If genes are linked, crossing over must occur for
there to be recombination.
6Linkage?
P AABB x aabb
F1 AaBb
Test cross AaBb x aabb
1/4 AaBb
? AaBb
1/4 Aabb
? Aabb
1/4 aaBb
? aaBb
1/4 aabb
? aabb
7Recombination Frequency
- or Linkage Ratio the percentage of recombinant
types, - if 50, then the genes are not linked,
- if less than 50, then linkage is observed.
8Linkage
- Genes located on the same chromosome do not
recombine, - unless crossing over occurs,
- The recombination frequency gives an estimate of
the distance between the genes.
9Recombination Frequencies
- Genes that are adjacent have a recombination
frequency near 0, - Genes that are very far apart on a chromosome
have a linkage ratio of 50, - The relative distance between linked genes
influences the amount of recombination observed.
10a
b
a
c
11Linkage RatioP GGWW x ggwwTestcross F1 GgWw
x ggww
GW
Gw
gW
gw
- recombinant
- total progeny
Linkage Ratio
12Linkage Ratio Units
- mu (map units)
- - or -
- cm (centimorgan)
13a
b
a
c
14cis coupling
15trans repulsion
16Fly Crosses(white eyes, minature, yellow body)
Study Figs 4.2, 4.3, and 4.5
- In a white eyes x miniature cross, 900 of the
2,441 progeny were recombinant, yielding a map
distance of 36.9 mu, - In a separate white eyes x yellow body cross, 11
of 2,205 progeny were recombinant, yielding a map
distance of 0.5 mu, - When a miniature x yellow body cross was
performed, 650 of 1706 flies were recombinant,
yielding a map distance of 38 mu.
17Simple Mapping
- white eyes x miniature 36.9 mu,
- white eyes x yellow body 0.5 mu,
- miniature x yellow body 38 mu,
18Do We have to Learn More Mapping Techniques?
- Yes,
- three point mapping,
- Why,
- Certainty of Gene Order,
- Double crossovers.
19Gene Order
- It is often difficult to assign the order of
genes based on two-point crosses due to
uncertainty derived from sampling error. - A x B 37.8 mu,
- A x C 0.5 mu,
- B x C 37.6 mu,
20Double Crossovers
- More than one crossover event can occur in a
single tetrad between non-sister chromatids, - if recombination occurs between genes A and B 30
of the time, - (p 0.3),
- then the probability of the event occurring twice
is 0.3 x 0.3 0.09, or nearly 10 map units. - If there is a double cross over, does
recombination occur? - how does it affect our estimation of distance
between genes?
21Why Me? Why Map?
- Over 4000 human diseases have a genetic
component, - knowing the protein produced at specific loci
facilitates the treatment and testing, - Facilitates both classical and molecular analysis
of organisms.
22Classical Mapping
Cross an organism with a trait of interest to
homozygous mutants of known mapped genes.
- Then, determine if segregation is random in the
F2 generation, - if not, then your gene is linked (close) to the
known mapped gene.
What recombination frequency do you expect beteen
the target and HY2?
What recombination frequency do you expect beteen
the target and TT2?
23Three Point Testcross
- Triple Heterozygous
- (AaBbCc )
- x
- Triple Homozygous Recessive
- (aabbcc)
24Three Point Mapping Requirements
- The genotype of the organism producing the
gametes must be heterozygous at all three loci, - You have to be able to deduce the genotype of the
gamete by looking at the phenotype of the
offspring, - You must look at enough offspring so that all
crossover classes are represented.
25w g d
- Representing linked genes...
- W G D
- w g d
- x
- w g d
- w g d
P
WwGgDd
Testcross
wwggdd
26w g d
- Representing linked genes...
-
- w g d
- x
- w g d
- w g d
P
WwGgDd
Testcross
wwggdd
27Phenotypic Classes
W-G-D-
W-G-dd
W-
W-gg-D
W-gg-dd
wwG-D-
wwG-dd
ww
wwggD-
wwggdd
28Crossovers
W-G-D-
0
179
wwggdd
173
0
W-G-dd
1
46
wwggD-
1
52
wwG-D-
22
1
W-gg-dd
22
1
W-gg-D
2
2
wwG-dd
2
4
29W-G-D-
179
Parentals
wwggdd
173
W-G-dd
46
Recombinants 1 crossover, Region I
I
II
wwggD-
52
wwG-D-
22
Recombinants 1 crossover, Region II
W-gg-dd
22
W-gg-D
2
Recombinants, double crossover
wwG-dd
4
30I
W-G-D-
179
Parentals
wwggdd
173
W-G-dd
46
Recombinants 1 crossover, Region I
wwggD-
52
Region I
wwG-D-
22
Recombinants 1 crossover, Region II
W-gg-dd
22
46 52 2 4 500
x 100
W-gg-D
2
Recombinants, double crossover
wwG-dd
4
20.8 mu
Total 500
31II
20.8 mu
W-G-D-
179
Parentals
wwggdd
173
W-G-dd
46
Recombinants 1 crossover, Region I
wwggD-
52
Region II
wwG-D-
22
Recombinants 1 crossover, Region II
W-gg-dd
22
22 22 2 4 500
x 100
W-gg-D
2
Recombinants, double crossover
wwG-dd
4
10.0 mu
Total 500
3210.0 mu
20.8 mu
0.1 x 0.208 0.0208
NO GOOD!
6/500 0.012
33Interference
- the affect a crossing over event has on a second
crossing over event in an adjacent region of the
chromatid, - (positive) interference decreases the
probability of a second crossing over, - most common in eukaryotes,
- negative interference increases the probability
of a second crossing over.
34Gene Order in Three Point Crosses
- Find either double cross-over phenotype, based on
the recombination frequencies, - Two parental alleles, and one cross over allele
will be present, - The cross over allele fits in the middle...
-
352001
A-B-C-
1786
aabbcc
46
A-B-cc
Which one is the odd one?
52
aabbC-
990
aaB-cc
887
A-bb-C-
600
A-bb cc
589
aaB-C-
36Region I
A-B-C-
2001
aabbcc
1786
A-B-cc
46
aabbC-
52
aaB-cc
990
I
A-bb-C-
887
A-bb cc
600
aaB-C-
589
37Region II
A-B-C-
2001
aabbcc
1786
A-B-cc
46
aabbC-
52
aaB-cc
990
28.4 mu
II
A-bb-C-
887
A-bb cc
600
aaB-C-
589
38Today
- Coefficient of Confidence,
- Gene mapping in humans,
- Problems, problems, problems,
- Be sure to at least try them before Friday.