Title: Gravitational Dynamics
1Gravitational Dynamics
2Gravitational Dynamics can be applied to
- Two body systemsbinary stars
- Planetary Systems
- Stellar Clustersopen globular
- Galactic Structurenuclei/bulge/disk/halo
- Clusters of Galaxies
- The universelarge scale structure
3Syllabus
- Phase Space Fluid f(x,v)
- Eqn of motion
- Poissons equation
- Stellar Orbits
- Integrals of motion (E,J)
- Jeans Theorem
- Spherical Equilibrium
- Virial Theorem
- Jeans Equation
- Interacting Systems
- Tides?Satellites?Streams
- Relaxation?collisions
4How to model motions of 1010stars in a galaxy?
- Direct N-body approach (as in simulations)
- At time t particles have (mi,xi,yi,zi,vxi,vyi,vzi)
, i1,2,...,N (feasible for Nltlt106). - Statistical or fluid approach (N very large)
- At time t particles have a spatial density
distribution n(x,y,z)m, e.g., uniform, - at each point have a velocity distribution
G(vx,vy,vz), e.g., a 3D Gaussian.
5N-body Potential and Force
- In N-body system with mass m1mN, the
gravitational acceleration g(r) and potential
f(r) at position r is given by
r12
r
mi
Ri
6Eq. of Motion in N-body
- Newtons law a point mass m at position r moving
with a velocity dr/dt with Potential energy F(r)
mf(r) experiences a Force Fmg , accelerates
with following Eq. of Motion
7Orbits defined by EoM Gravity
- Solve for a complete prescription of history of a
particle r(t) - E.g., if G0 ? F0, F(r)cst, ? dxi/dt vxici
? xi(t) ci t x0, likewise for yi,zi(t) - E.g., relativistic neutrinos in universe go
straight lines - Repeat for all N particles.
- ? N-body system fully described
8Example 5-body rectangle problem
- Four point masses m3,4,5 at rest of three
vertices of a P-triangle, integrate with time
step1 and ½ find the positions at time t1.
9Star clusters differ from air
- Size doesnt matter
- size of starsltltdistance between them
- ?stars collide far less frequently than molecules
in air. - Inhomogeneous
- In a Gravitational Potential f(r)
- Spectacularly rich in structure because f(r) is
non-linear function of r
10Why Potential f(r) ?
- More convenient to work with force, potential per
unit mass. e.g. KE?½v2 - Potential f(r) is scaler, function of r only,
- Easier to work with than force (vector, 3
components) - Simply relates to orbital energy E f(r) ½v2
11Example energy per unit mass
- The orbital energy of a star is given by
0 since and
0 for static potential.
So orbital Energy is Conserved in a static
potential.
12Example Force field of two-body system in
Cartesian coordinates
13Example Energy is conserved
- The orbital energy of a star is given by
0 since and
0 for static potential.
So orbital Energy is Conserved in a static
potential.
14A fluid element Potential Gravity
- For large N or a continuous fluid, the gravity dg
and potential df due to a small mass element dM
is calculated by replacing mi with dM
r12
dM
r
d3R
R
15Potential in a galaxy
- Replace a summation over all N-body particles
with the integration - Remember dM?(R)d3R for average density ?(R) in
small volume d3R - So the equation for the gravitational force
becomes
R?Ri
16Poissons Equation
- Relates potential with density
- Proof hints
17Gausss Theorem
- Gausss theorem is obtained by integrating
poissons equation - i.e. the integral ,over any closed surface, of
the normal component of the gradient of the
potential is equal to 4?G times the Mass enclosed
within that surface.
18Poissons Equation
- Poissons equation relates the potential to the
density of matter generating the potential. - It is given by
19Laplacian in various coordinates
20Poissons eq. in Spherical systems
- Poissons eq. in a spherical potential with no ?
or F dependence is
21Proof of Poissons Equation
- Consider a uniform distribution of mass of
density ?.
g
r
22- Take d/dr and multiply r2 ?
- Take d/dr and divide r2?
23From Density to Mass
M(rdr)
M(r)
24- From Gravitational Force to Potential
From Potential to Density
Use Poissons Equation
The integrated form of Poissons equation is
given by
25More on Spherical Systems
- Newton proved 2 results which enable us to
calculate the potential of any spherical system
very easily. - NEWTONS 1st THEOREMA body that is inside a
spherical shell of matter experiences no net
gravitational force from that shell - NEWTONS 2nd THEOREMThe gravitational force on a
body that lies outside a closed spherical shell
of matter is the same as it would be if all the
matter were concentrated at its centre.
26Circular Velocity
- CIRCULAR VELOCITY the speed of a test particle
in a circular orbit at radius r.
For a point mass
For a homogeneous sphere
27Escape Velocity
- ESCAPE VELOCITY velocity required in order for
an object to escape from a gravitational
potential well and arrive at ? with zero KE. - It is the velocity for which the kinetic energy
balances potential.
-ve
28ExampleSingle Isothermal Sphere Model
- For a SINGLE ISOTHERMAL SPHERE (SIS) the line of
sight velocity dispersion is constant. This also
results in the circular velocity being constant
(proof later). - The potential and density are given by
29Proof Density
Log(?)
??r-2 n-2
Log(r)
30Proof Potential
- We redefine the zero of potential?
- If the SIS extends to a radius ro then the
mass and density distribution look like this
M
?
r
r
ro
ro
31- Beyond ro
- We choose the constant so that the potential is
continuous at rro.
r
? r-1
logarithmic
?
32So
33Plummer Model
- PLUMMER MODELthe special case of the
gravitational potential of a galaxy. This is a
spherically symmetric potential of the form - Corresponding to a density
which can be proved using poissons equation.
34- The potential of the plummer model looks like
this
?
r
?
35- Since, the potential is spherically symmetric g
is also given by - ?
- The density can then be obtained from
- dM is found from the equation for M above and
dV4?r2dr. - This gives
(as before from Poissons)
36Isochrone Potential
- We might expect that a spherical galaxy has
roughly constant ? near its centre and it falls
to 0 at sufficiently large radii. - i.e.
- A potential of this form is the ISOCHRONE
POTENTIAL.
37Orbits in Spherical Potentials
- The motion of a star in a centrally directed
field of force is greatly simplified by the
familiar law of conservation of angular momentum.
Keplers 3rd law
pericentre
apocentre
38?eff
39- at the PERICENTRE and APOCENTRE
- There are two roots for
- One of them is the pericentre and the other is
the apocentre. - The RADIAL PERIOD Tr is the time required for the
star to travel from apocentre to pericentre and
back. - To determine Tr we use
40- The two possible signs arise because the star
moves alternately in and out. - In travelling from apocentre to pericentre and
back, the azimuthal angle ? increases by an
amount
41- The AZIMUTHAL PERIOD is
- In general will not be a rational number.
Hence the orbit will not be closed. - A typical orbit resembles a rosette and
eventually passes through every point in the
annulus between the circle of radius rp and ra. - Orbits will only be closed if is an integer.
42?????????????Graphs
- The velocity of the star is slower at apocentre
due to the conservation of angular momentum. - ??????????????????????????
43Fluid approachPhase Space Density
- PHASE SPACE DENSITYNumber of stars per unit
volume per unit velocity volume f(x,v) (all
called Distribution Function DF). -
- The total number of particles per unit volume
is given by
44- E.g., air particles with Gaussian velocity (rms
velocity s in x,y,z directions) - The distribution function is defined by
- mdNf(x,v)d3xd3v
- where dN is the number of particles per unit
volume with a given range of velocities. - The mass distribution function is given by
f(x,v).
45- The total mass is then given by the integral of
the mass distribution function over space and
velocity volume - Notein spherical coordinates d3x4pr2dr
- The total momentum is given by
46- The mean velocity is given by
47- Examplemolecules in a room
- These are gamma functions
48 49Liouvilles Theorem
- We previously introduced the concept of phase
space density. The concept of phase space
density is useful because it has the nice
property that it is incompessible for
collisionless systems. - A COLLISIONLESS SYSTEM is one where there
are no collisions. All the constituent particles
move under the influence of the mean potential
generated by all the other particles. - INCOMPRESSIBLE means that the phase-space
density doesnt change with time.
50- Consider Nstar identical particles moving in
a small bundle through spacetime on neighbouring
paths. If you measure the bundles volume in
phase space (Vol?x ? p) as a function of a
parameter ? (e.g., time t) along the central path
of the bundle. It can be shown that -
- It can be seen that the region of phase space
occupied by the particle deforms but maintains
its area. The same is true for y-py and z-pz.
This is equivalent to saying that the phase space
density fNstars/Vol is constant.? df/dt0!
px
px
x
x
51DF Integrals of motion
- If some quantity I(x,v) is conserved i.e.
- We know that the phase space density is conserved
i.e - Therefore it is likely that f(x,v) depends on
(x,v) through the function I(x,v), so ff(I(x,v)).
52Jeans theorem
- For most stellar systems the DF depends on (x,v)
through generally three integrals of motion
(conserved quantities), Ii(x,v),i1..3 ? f(x,v)
f(I1(x,v), I2(x,v), I3(x,v)) - E.g., in Spherical Equilibrium, f is a function
of energy E(x,v) and ang. mom. vector L(x,v).s
amplitude and z-component
53EoM?Jeans eq.
54Spherical Equilibrium System
- Described by potential f(r)
- SPHERICAL density ?(r) depends on modulus of r.
- EQUILIBRIUMProperties do not evolve with time.
-
55Anisotropic DF f(E,L,Lz).
- Energy is conserved as
- Angular Momentum Vector is conserved as
- DF depends on Velocity Direction through Lr X v
56Proof Angular Momentum is Conserved
Since
then the force is in the r direction.
?both cross products on the RHS 0.
So Angular Momentum L is Conserved in Spherical
Isotropic Self Gravitating Equilibrium Systems.
Alternatively ?rF F only has components in
the r direction??0 so
57Proof Energy is conserved
- The total energy of an orbit is given by
0 since and
0 for equilibrium systems.
So Energy is Conserved.
58Linear Momentum
- The change in linear momentum with time is given
by - Since P is not conserved.
- However, when you sum up over all stars, linear
momentum is conserved.
59Spherical Isotropic Self Gravitating Equilibrium
Systems
- ISOTROPICThe distribution function only depends
on the modulus of the velocity rather than the
direction.
Notethe tangential direction has ? and ?
components
60Isotropic DF f(E)
- In a static potential the energy of an particle
is conserved. - So,if we write f as a function of E then it will
agree with the statement
NoteEenergy per unit mass
For incompressible fluids
61- So
- Ecst since
- For a bound equilibrium system f(E) is positive
everywhere (can be zero) and is monotonically
decreasing.
62- SELF GRAVITATINGThe masses are kept together by
their mutual gravity. In non self gravitating
systems the density that creates the potential is
not equal to the density of stars. e.g a black
hole with stars orbiting about it is not self
gravitating.
63Eddington Formulae
- EDDINGTON FORMULAEThese can be used to get the
density as a function of r from the energy
density distribution function f(E).
64Proof of the 1st Eddington Formula
65So, from a given distribution function we can
compute the spherical density.
66Relation Between Pressure Gradient and
Gravitational Force
67(No Transcript)
68- So, this gives
- This relates the pressure gradient to the
gravitational force. This is the JEANS EQUATION.
Note ??2P
Note-ve sign has gone since we reversed the
limits.
69So, gravity, potential, density and Mass are all
related and can be calculated from each other by
several different methods.
g
M
??2
vesc
?(E)
?(r)
?(r)
70Proof Situation where Vc2const is a Singular
Isothermal Sphere
- From Previously
- Conservation of momentum gives
71?
72- ?
- Since the circular velocity is independent of
radius then so is the velocity dispersion?Isotherm
al.
73Finding the normalising constant for the phase
space density
- If we assume the phase space density is given by
- ?
74- We can then find the normalizing constant so that
??(r) is reproduced. - Note you want to integrate f(E) over all
energies that the star can have I.e. only
energies above the potential? - We are integrating over stars of different
velocities ranging from 0 to ?.
75- One way is to stick the velocity into the
distribution function - Using the substitution gives
76- Now ? can also be found from poissons equation.
Substituting in ? from before gives - Equating the r terms gives
as before.
77Flattened Disks
- Here the potential is of the form ?(R,z).
- No longer spherically symmetric.
- Now it is Axisymmetric
78Orbits in Axisymmetric Potentials
- We employ a cylindrical coordinate system (R,?,z)
centred on the galactic nucleus and align the z
axis with the galaxies axis of symmetry. - Stars confined to the equatorial plane have no
way of perceiving that the potential is not
spherically symmetric. - ?Their orbits will be identical to those in
spherical potentials. - R of a star on such an orbit oscillates around
some mean value as the star revolves around the
centre forming a rosette figure.
79Reducing the Study of Orbits to a 2D Problem
- This is done by exploiting the conservation of
the z component of angular momentum. - Let the potential which we assume to be symmetric
about the plane z0, be ?(R,z). - The general equation of motion of the star is
then - The acceleration in cylindrical coordinates is
-
Motion in the meridional plane
80- The component of angular momentum about the
z-axis is conserved. - If ? has no dependence on ? then the azimuthal
angular momentum is conserved (r?F0). - Eliminating in the energy equation using
conservation of angular momentum gives
Specific energy density in 3D
?eff
81- Thus, the 3D motion of a star in an axisymmetric
potential ?(R,z) can be reduced to the motion of
a star in a plane. - This (non uniformly) rotating plane with
cartesian coordinates (R,z) is often called the
MERIDIONAL PLANE. - ?eff(R,z) is called the EFFECTIVE POTENTIAL.
82Minimum in ?eff
- The minimum in ?eff has a simple physical
significance. It occurs where - (2) is satisfied anywhere in the equatorial plane
z0. - (1) is satisfied at radius Rg where
- This is the condition for a circular orbit of
angular speed
83- So the minimum in ?eff occurs at the radius at
which a circular orbit has angular momentum Lz. - The value of ?eff at the minimum is the energy of
this circular orbit.
?eff
R
E
?
Rcir
84- The angular momentum barrier for an orbit of
energy E is given by - The effective potential cannot be greater than
the energy of the orbit. - The equations of motion in the 2D meridional
plane then become .
85- The effective potential is the sum of the
gravitational potential energy of the orbiting
star and the kinetic energy associated with its
motion in the ? direction. - Any difference between ?eff and E is simply
kinetic energy of the motion in the (R,z) plane. - Since the kinetic energy is non negative, the
orbit is restricted to the area of the meridional
plane satisfying . - The curve bounding this area is called the ZERO
VELOCITY CURVE since the orbit can only reach
this curve if its velocity is instantaneously
zero.
86- When the star is close to z0 the effective
potential can be expanded to give
Can generally be ignored since the gravitational
force is only in the z direction close to the
equatorial plane.
?2
So, the orbit is oscillating in the z direction.
87- The orbits are bound between two radii (where the
effective potential equals the total energy) and
oscillates in the z direction. - ????????graph of z vs R??????????
88- If the energy of the orbit is reduced the two
points between which the orbit is bound
eventually become one. - You then get no radial oscillation.
- You have circular orbits in the plane of the
galaxy. - This is one of the closed orbits in an
axisymmetric potential and has the property that.
(Minimum in effective potential.)
Centrifugal Force
Gravitational force in radial direction
89- The following figure shows the total angular
momentum along the orbit. - ??????????????????????????
- Angular momentum is not quite conserved but
almost. - This is because the star picks up angular
momentum as it goes towards the plane and vice
versa. - These orbits can be thought of as being planar
with more or less fixed eccentricity. - The approximate orbital planes have a fixed
inclination to the z axis but they precess about
this axis.
90Orbits in Planar Non-Axisymmetrical Potentials
- Here the angular momentum is not exactly
conserved. - There are two main types of orbit
- BOX ORBITS
- LOOP ORBITS
91LOOP ORBITS
- Star rotates in a fixed sense about the centre of
the potential while oscillating in radius - Star orbits between allowed radii given by its
energy. - There are two periods associated with the orbit
- Period of the radial oscillation
- Period of the star going around 2?
- The energy is generally conserved and determines
the outer radius of the orbit. - The inner radius is determined by the angular
momentum.
apocentre
pericentre
92Box Orbits
- Have no particular sense of circulation about the
centre. - They are the sum of independent harmonic motions
parallel to the x and y axes. - In a logarithmic potential of the form
- box orbits will occur when RltltRc and loop
orbits will occur when RgtgtRc.
93JEANS EQUATION
- The jeans equation for oblate rotator
- a steady-state axisymmetrical system in which ?2
is isotropic and the only streaming motion is
azimuthal rotation
94- The velocity dispersions in this case are given
by - If we know the forms of ?(R,z) and ?(R,z) then at
any radius R we may integrate the Jeans equation
in the z direction to obtain ?2.
95Obtaining ?2
- Inserting this into the jeans equation in the
R - direction gives
96 97(No Transcript)
98Tidal Stripping
- TIDAL RADIUSRadius within which a particle is
bound to the satellite rather than the host
system. - Consider a satellite of mass profile ms(R) moving
in a spherical potential ?(r) made from a mass
profile M(r).
R
r
V(r)
99- The condition for a particle to be bound to the
satellite rather than the host system is -
Differential (tidal) force on the particle due to
the host galaxy
Force on particle due to satellite
100- So,
- Therefore the formula for Tidal Radius is
- The tidal radius is smallest at pericentre where
r is smallest. - The inequality can be written in terms of the
mean densities. - The satellite mass is not constant as the tidal
radius changes.
101Lagrange Points
- There is a point between two bodies where a
particle can belong to either one of them. - This point is known as the LAGRANGE POINT.
- A small body orbiting at this point would remain
in the orbital plane of the two massive bodies. - The Lagrange points mark positions where the
gravitational pull of the two large masses
precisely cancels the centripetal acceleration
required to rotate with them. - At the lagrange points
102Effective Force of Gravity
- A particle will experience gravity due to the
galaxy and the satellite along with a centrifugal
force and a coriolis term. - The effective force of gravity is given by
- The acceleration of the particle is given by
Coriolis term
Centrifugal term
103Jakobis Energy
- The JAKOBIS ENERGY is given by
- Jakobis energy is conserved because
104- For an orbit in the plane (r perpendicular to ?)
105- EJ is also known as the Jakobi Integral.
- Since v2 is always positive a star whose Jakobi
integral takes the value EJ will never tresspass
into a region where ?eff(x)gtEJ. - Consequently the surface ?eff(x)gtEJ, which we
call the zero velocity surface for stars of
Jakobi Integral EJ, forms an impenetrable wall
for such stars.
106- By taking a Taylor Expansion rrs, you end up
with - Where we call the radius rJ the JAKOBI LIMIT of
the mass m. - This provides a crude estimate of the tidal
radius rt.
107Dynamical Friction
- DYNAMICAL FRICTION slows a satellite on its orbit
causing it to spiral towards the centre of the
parent galaxy. - As the satellite moves through a sea of stars
I.e. the individual stars in the parent galaxy
the satellites gravity alters the trajectory of
the stars, building up a slight density
enhancement of stars behind the satellite - The gravity from the wake pulls backwards on the
satellites motion, slowing it down a little
108- The satellite loses angular momentum and slowly
spirals inwards. - This effect is referred to as dynamical
friction because it acts like a frictional or
viscous force, but its pure gravity.
109- More massive satellites feel a greater friction
since they can alter trajectories more and build
up a more massive wake behind them. - Dynamical friction is stronger in higher density
regions since there are more stars to contribute
to the wake so the wake is more massive. - For low v the dynamical friction increases as v
increases since the build up of a wake depends on
the speed of the satellite being large enough so
that it can scatter stars preferentially behind
it (if its not moving, it scatters as many stars
in front as it does behind). - However, at high speeds the frictional force
?v-2, since the ability to scatter drops as the
velocity increases. - Note both stars and dark matter contribute to
dynamical friction
110- The dynamical friction acting on a satellite of
mass ms moving at vs kms-1 in a sea of particles
with gaussian velocity distribution - is
111- For an isotropic distribution of stellar
velocities this is - i.e. only stars moving slower than M contribute
to the force. This is usually called the
Chandrasekhar Dynamical Friction Formula. - For sufficiently small vM we may replace f(vM) by
f(0) to give - For a sufficiently large vM, the integral
converges to a definite limit and the frictional
force therefore falls like - vM-2.
112- When there is dynamical friction there is a drag
force which dissipates angular momentum. The
decay is faster at pericentre resulting in the
staircase like appearance. - ??????????????????????????????????
113- As the satellite moves inward the tidal force
becomes greater so the tidal radius decreases and
the mass will decay. - ???????????????????????????????????????
114Scalar Virial Theorem
- The Scalar Virial Theorem states that the kinetic
energy of a system with mass M is just - where ltv2gt is the mean-squared speed of the
systems stars. - Hence the virial theorem states that
Virial
115This is Tensor Virial Theorem
116- E.g.
- So the time averaged value of v2 is equal to the
time averaged value of the circular velocity
squared.
117So ltxygt0 since the average value of xy will be
zero. ?ltvxvygt0
118Adiabatic Invariance
- Suppose we have a sequence of potentials ?p(r)
that depends continuously on the parameter P(t). - P(t) varies slowly with time.
- For each fixed P we would assume that the orbits
supported by ?p(r) are regular and thus phase
space is filled by arrays of nested tori on which
phase points of individual stars move. - Suppose
119- The orbit energy of a test particle will change.
- Suppose
- The angular momentum J is still conserved because
r?F0. - E.g. circular orbit in a flat potential
Initial Final
Let P(t)Vcir
?
120- So, if Vcir increases by a factor of 2 then the
radius of the orbit would decrease by a factor of
2 and the period would decrease by a factor of 4. - E.g. in a potential
- In general the orbital eccentricity is conserved
e.g. a circular orbit will stay circular.
121- In general, two stellar phase points that started
out on the same torus will move onto two
different tori. - However, if P is changed very slowly compared to
all characteristic times associated with the
motion on each torus, all phase points that are
initially on a given torus will be equally
affected by the variation in P - Any two stars that are on a common orbit will
still be on a common orbit after the variation in
P is complete. This is ADIABATIC INVARIANCE.