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Gravitational Dynamics

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Title: Gravitational Dynamics


1
Gravitational Dynamics
2
Gravitational Dynamics can be applied to
  • Two body systemsbinary stars
  • Planetary Systems
  • Stellar Clustersopen globular
  • Galactic Structurenuclei/bulge/disk/halo
  • Clusters of Galaxies
  • The universelarge scale structure

3
Syllabus
  • Phase Space Fluid f(x,v)
  • Eqn of motion
  • Poissons equation
  • Stellar Orbits
  • Integrals of motion (E,J)
  • Jeans Theorem
  • Spherical Equilibrium
  • Virial Theorem
  • Jeans Equation
  • Interacting Systems
  • Tides?Satellites?Streams
  • Relaxation?collisions

4
How to model motions of 1010stars in a galaxy?
  • Direct N-body approach (as in simulations)
  • At time t particles have (mi,xi,yi,zi,vxi,vyi,vzi)
    , i1,2,...,N (feasible for Nltlt106).
  • Statistical or fluid approach (N very large)
  • At time t particles have a spatial density
    distribution n(x,y,z)m, e.g., uniform,
  • at each point have a velocity distribution
    G(vx,vy,vz), e.g., a 3D Gaussian.

5
N-body Potential and Force
  • In N-body system with mass m1mN, the
    gravitational acceleration g(r) and potential
    f(r) at position r is given by

r12
r
mi
Ri
6
Eq. of Motion in N-body
  • Newtons law a point mass m at position r moving
    with a velocity dr/dt with Potential energy F(r)
    mf(r) experiences a Force Fmg , accelerates
    with following Eq. of Motion

7
Orbits defined by EoM Gravity
  • Solve for a complete prescription of history of a
    particle r(t)
  • E.g., if G0 ? F0, F(r)cst, ? dxi/dt vxici
    ? xi(t) ci t x0, likewise for yi,zi(t)
  • E.g., relativistic neutrinos in universe go
    straight lines
  • Repeat for all N particles.
  • ? N-body system fully described

8
Example 5-body rectangle problem
  • Four point masses m3,4,5 at rest of three
    vertices of a P-triangle, integrate with time
    step1 and ½ find the positions at time t1.

9
Star clusters differ from air
  • Size doesnt matter
  • size of starsltltdistance between them
  • ?stars collide far less frequently than molecules
    in air.
  • Inhomogeneous
  • In a Gravitational Potential f(r)
  • Spectacularly rich in structure because f(r) is
    non-linear function of r

10
Why Potential f(r) ?
  • More convenient to work with force, potential per
    unit mass. e.g. KE?½v2
  • Potential f(r) is scaler, function of r only,
  • Easier to work with than force (vector, 3
    components)
  • Simply relates to orbital energy E f(r) ½v2

11
Example energy per unit mass
  • The orbital energy of a star is given by

0 since and
0 for static potential.
So orbital Energy is Conserved in a static
potential.
12
Example Force field of two-body system in
Cartesian coordinates
13
Example Energy is conserved
  • The orbital energy of a star is given by

0 since and
0 for static potential.
So orbital Energy is Conserved in a static
potential.
14
A fluid element Potential Gravity
  • For large N or a continuous fluid, the gravity dg
    and potential df due to a small mass element dM
    is calculated by replacing mi with dM

r12
dM
r
d3R
R
15
Potential in a galaxy
  • Replace a summation over all N-body particles
    with the integration
  • Remember dM?(R)d3R for average density ?(R) in
    small volume d3R
  • So the equation for the gravitational force
    becomes

R?Ri
16
Poissons Equation
  • Relates potential with density
  • Proof hints

17
Gausss Theorem
  • Gausss theorem is obtained by integrating
    poissons equation
  • i.e. the integral ,over any closed surface, of
    the normal component of the gradient of the
    potential is equal to 4?G times the Mass enclosed
    within that surface.

18
Poissons Equation
  • Poissons equation relates the potential to the
    density of matter generating the potential.
  • It is given by

19
Laplacian in various coordinates
20
Poissons eq. in Spherical systems
  • Poissons eq. in a spherical potential with no ?
    or F dependence is

21
Proof of Poissons Equation
  • Consider a uniform distribution of mass of
    density ?.

g
r
22
  • Take d/dr and multiply r2 ?
  • Take d/dr and divide r2?

23
From Density to Mass
M(rdr)
M(r)
24
  • From Gravitational Force to Potential

From Potential to Density
Use Poissons Equation
The integrated form of Poissons equation is
given by
25
More on Spherical Systems
  • Newton proved 2 results which enable us to
    calculate the potential of any spherical system
    very easily.
  • NEWTONS 1st THEOREMA body that is inside a
    spherical shell of matter experiences no net
    gravitational force from that shell
  • NEWTONS 2nd THEOREMThe gravitational force on a
    body that lies outside a closed spherical shell
    of matter is the same as it would be if all the
    matter were concentrated at its centre.

26
Circular Velocity
  • CIRCULAR VELOCITY the speed of a test particle
    in a circular orbit at radius r.

For a point mass
For a homogeneous sphere
27
Escape Velocity
  • ESCAPE VELOCITY velocity required in order for
    an object to escape from a gravitational
    potential well and arrive at ? with zero KE.
  • It is the velocity for which the kinetic energy
    balances potential.

-ve
28
ExampleSingle Isothermal Sphere Model
  • For a SINGLE ISOTHERMAL SPHERE (SIS) the line of
    sight velocity dispersion is constant. This also
    results in the circular velocity being constant
    (proof later).
  • The potential and density are given by

29
Proof Density
Log(?)
??r-2 n-2
Log(r)
30
Proof Potential
  • We redefine the zero of potential?
  • If the SIS extends to a radius ro then the
    mass and density distribution look like this

M
?
r
r
ro
ro
31
  • Beyond ro
  • We choose the constant so that the potential is
    continuous at rro.

r
? r-1
logarithmic
?
32
So
33
Plummer Model
  • PLUMMER MODELthe special case of the
    gravitational potential of a galaxy. This is a
    spherically symmetric potential of the form
  • Corresponding to a density

which can be proved using poissons equation.
34
  • The potential of the plummer model looks like
    this

?
r
?
35
  • Since, the potential is spherically symmetric g
    is also given by
  • ?
  • The density can then be obtained from
  • dM is found from the equation for M above and
    dV4?r2dr.
  • This gives

(as before from Poissons)
36
Isochrone Potential
  • We might expect that a spherical galaxy has
    roughly constant ? near its centre and it falls
    to 0 at sufficiently large radii.
  • i.e.
  • A potential of this form is the ISOCHRONE
    POTENTIAL.

37
Orbits in Spherical Potentials
  • The motion of a star in a centrally directed
    field of force is greatly simplified by the
    familiar law of conservation of angular momentum.

Keplers 3rd law
pericentre
apocentre
38
?eff
39
  • at the PERICENTRE and APOCENTRE
  • There are two roots for
  • One of them is the pericentre and the other is
    the apocentre.
  • The RADIAL PERIOD Tr is the time required for the
    star to travel from apocentre to pericentre and
    back.
  • To determine Tr we use

40
  • The two possible signs arise because the star
    moves alternately in and out.
  • In travelling from apocentre to pericentre and
    back, the azimuthal angle ? increases by an
    amount

41
  • The AZIMUTHAL PERIOD is
  • In general will not be a rational number.
    Hence the orbit will not be closed.
  • A typical orbit resembles a rosette and
    eventually passes through every point in the
    annulus between the circle of radius rp and ra.
  • Orbits will only be closed if is an integer.

42
?????????????Graphs
  • The velocity of the star is slower at apocentre
    due to the conservation of angular momentum.
  • ??????????????????????????

43
Fluid approachPhase Space Density
  • PHASE SPACE DENSITYNumber of stars per unit
    volume per unit velocity volume f(x,v) (all
    called Distribution Function DF).
  • The total number of particles per unit volume
    is given by

44
  • E.g., air particles with Gaussian velocity (rms
    velocity s in x,y,z directions)
  • The distribution function is defined by
  • mdNf(x,v)d3xd3v
  • where dN is the number of particles per unit
    volume with a given range of velocities.
  • The mass distribution function is given by
    f(x,v).

45
  • The total mass is then given by the integral of
    the mass distribution function over space and
    velocity volume
  • Notein spherical coordinates d3x4pr2dr
  • The total momentum is given by

46
  • The mean velocity is given by

47
  • Examplemolecules in a room
  • These are gamma functions

48
  • Gamma Functions

49
Liouvilles Theorem
  • We previously introduced the concept of phase
    space density. The concept of phase space
    density is useful because it has the nice
    property that it is incompessible for
    collisionless systems.
  • A COLLISIONLESS SYSTEM is one where there
    are no collisions. All the constituent particles
    move under the influence of the mean potential
    generated by all the other particles.
  • INCOMPRESSIBLE means that the phase-space
    density doesnt change with time.

50
  • Consider Nstar identical particles moving in
    a small bundle through spacetime on neighbouring
    paths. If you measure the bundles volume in
    phase space (Vol?x ? p) as a function of a
    parameter ? (e.g., time t) along the central path
    of the bundle. It can be shown that
  • It can be seen that the region of phase space
    occupied by the particle deforms but maintains
    its area. The same is true for y-py and z-pz.
    This is equivalent to saying that the phase space
    density fNstars/Vol is constant.? df/dt0!

px
px
x
x
51
DF Integrals of motion
  • If some quantity I(x,v) is conserved i.e.
  • We know that the phase space density is conserved
    i.e
  • Therefore it is likely that f(x,v) depends on
    (x,v) through the function I(x,v), so ff(I(x,v)).

52
Jeans theorem
  • For most stellar systems the DF depends on (x,v)
    through generally three integrals of motion
    (conserved quantities), Ii(x,v),i1..3 ? f(x,v)
    f(I1(x,v), I2(x,v), I3(x,v))
  • E.g., in Spherical Equilibrium, f is a function
    of energy E(x,v) and ang. mom. vector L(x,v).s
    amplitude and z-component

53
EoM?Jeans eq.
54
Spherical Equilibrium System
  • Described by potential f(r)
  • SPHERICAL density ?(r) depends on modulus of r.
  • EQUILIBRIUMProperties do not evolve with time.

55
Anisotropic DF f(E,L,Lz).
  • Energy is conserved as
  • Angular Momentum Vector is conserved as
  • DF depends on Velocity Direction through Lr X v

56
Proof Angular Momentum is Conserved
  • ?

Since
then the force is in the r direction.
?both cross products on the RHS 0.
So Angular Momentum L is Conserved in Spherical
Isotropic Self Gravitating Equilibrium Systems.
Alternatively ?rF F only has components in
the r direction??0 so
57
Proof Energy is conserved
  • The total energy of an orbit is given by

0 since and
0 for equilibrium systems.
So Energy is Conserved.
58
Linear Momentum
  • The change in linear momentum with time is given
    by
  • Since P is not conserved.
  • However, when you sum up over all stars, linear
    momentum is conserved.

59
Spherical Isotropic Self Gravitating Equilibrium
Systems
  • ISOTROPICThe distribution function only depends
    on the modulus of the velocity rather than the
    direction.

Notethe tangential direction has ? and ?
components
60
Isotropic DF f(E)
  • In a static potential the energy of an particle
    is conserved.
  • So,if we write f as a function of E then it will
    agree with the statement

NoteEenergy per unit mass
For incompressible fluids
61
  • So
  • Ecst since
  • For a bound equilibrium system f(E) is positive
    everywhere (can be zero) and is monotonically
    decreasing.

62
  • SELF GRAVITATINGThe masses are kept together by
    their mutual gravity. In non self gravitating
    systems the density that creates the potential is
    not equal to the density of stars. e.g a black
    hole with stars orbiting about it is not self
    gravitating.

63
Eddington Formulae
  • EDDINGTON FORMULAEThese can be used to get the
    density as a function of r from the energy
    density distribution function f(E).

64
Proof of the 1st Eddington Formula
65
So, from a given distribution function we can
compute the spherical density.
66
Relation Between Pressure Gradient and
Gravitational Force
  • Pressure is given by

67
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68
  • So, this gives
  • This relates the pressure gradient to the
    gravitational force. This is the JEANS EQUATION.

Note ??2P
Note-ve sign has gone since we reversed the
limits.
69
So, gravity, potential, density and Mass are all
related and can be calculated from each other by
several different methods.
g
M
??2
vesc
?(E)
?(r)
?(r)
70
Proof Situation where Vc2const is a Singular
Isothermal Sphere
  • From Previously
  • Conservation of momentum gives

71
  • ?

?
72
  • ?
  • Since the circular velocity is independent of
    radius then so is the velocity dispersion?Isotherm
    al.

73
Finding the normalising constant for the phase
space density
  • If we assume the phase space density is given by
  • ?

74
  • We can then find the normalizing constant so that
    ??(r) is reproduced.
  • Note you want to integrate f(E) over all
    energies that the star can have I.e. only
    energies above the potential?
  • We are integrating over stars of different
    velocities ranging from 0 to ?.

75
  • One way is to stick the velocity into the
    distribution function
  • Using the substitution gives

76
  • Now ? can also be found from poissons equation.
    Substituting in ? from before gives
  • Equating the r terms gives

as before.
77
Flattened Disks
  • Here the potential is of the form ?(R,z).
  • No longer spherically symmetric.
  • Now it is Axisymmetric

78
Orbits in Axisymmetric Potentials
  • We employ a cylindrical coordinate system (R,?,z)
    centred on the galactic nucleus and align the z
    axis with the galaxies axis of symmetry.
  • Stars confined to the equatorial plane have no
    way of perceiving that the potential is not
    spherically symmetric.
  • ?Their orbits will be identical to those in
    spherical potentials.
  • R of a star on such an orbit oscillates around
    some mean value as the star revolves around the
    centre forming a rosette figure.

79
Reducing the Study of Orbits to a 2D Problem
  • This is done by exploiting the conservation of
    the z component of angular momentum.
  • Let the potential which we assume to be symmetric
    about the plane z0, be ?(R,z).
  • The general equation of motion of the star is
    then
  • The acceleration in cylindrical coordinates is

Motion in the meridional plane
80
  • The component of angular momentum about the
    z-axis is conserved.
  • If ? has no dependence on ? then the azimuthal
    angular momentum is conserved (r?F0).
  • Eliminating in the energy equation using
    conservation of angular momentum gives

Specific energy density in 3D
?eff
81
  • Thus, the 3D motion of a star in an axisymmetric
    potential ?(R,z) can be reduced to the motion of
    a star in a plane.
  • This (non uniformly) rotating plane with
    cartesian coordinates (R,z) is often called the
    MERIDIONAL PLANE.
  • ?eff(R,z) is called the EFFECTIVE POTENTIAL.

82
Minimum in ?eff
  • The minimum in ?eff has a simple physical
    significance. It occurs where
  • (2) is satisfied anywhere in the equatorial plane
    z0.
  • (1) is satisfied at radius Rg where
  • This is the condition for a circular orbit of
    angular speed

83
  • So the minimum in ?eff occurs at the radius at
    which a circular orbit has angular momentum Lz.
  • The value of ?eff at the minimum is the energy of
    this circular orbit.

?eff
R
E
?
Rcir
84
  • The angular momentum barrier for an orbit of
    energy E is given by
  • The effective potential cannot be greater than
    the energy of the orbit.
  • The equations of motion in the 2D meridional
    plane then become .

85
  • The effective potential is the sum of the
    gravitational potential energy of the orbiting
    star and the kinetic energy associated with its
    motion in the ? direction.
  • Any difference between ?eff and E is simply
    kinetic energy of the motion in the (R,z) plane.
  • Since the kinetic energy is non negative, the
    orbit is restricted to the area of the meridional
    plane satisfying .
  • The curve bounding this area is called the ZERO
    VELOCITY CURVE since the orbit can only reach
    this curve if its velocity is instantaneously
    zero.

86
  • When the star is close to z0 the effective
    potential can be expanded to give

Can generally be ignored since the gravitational
force is only in the z direction close to the
equatorial plane.
?2
So, the orbit is oscillating in the z direction.
87
  • The orbits are bound between two radii (where the
    effective potential equals the total energy) and
    oscillates in the z direction.
  • ????????graph of z vs R??????????

88
  • If the energy of the orbit is reduced the two
    points between which the orbit is bound
    eventually become one.
  • You then get no radial oscillation.
  • You have circular orbits in the plane of the
    galaxy.
  • This is one of the closed orbits in an
    axisymmetric potential and has the property that.

(Minimum in effective potential.)
Centrifugal Force
Gravitational force in radial direction
89
  • The following figure shows the total angular
    momentum along the orbit.
  • ??????????????????????????
  • Angular momentum is not quite conserved but
    almost.
  • This is because the star picks up angular
    momentum as it goes towards the plane and vice
    versa.
  • These orbits can be thought of as being planar
    with more or less fixed eccentricity.
  • The approximate orbital planes have a fixed
    inclination to the z axis but they precess about
    this axis.

90
Orbits in Planar Non-Axisymmetrical Potentials
  • Here the angular momentum is not exactly
    conserved.
  • There are two main types of orbit
  • BOX ORBITS
  • LOOP ORBITS

91
LOOP ORBITS
  • Star rotates in a fixed sense about the centre of
    the potential while oscillating in radius
  • Star orbits between allowed radii given by its
    energy.
  • There are two periods associated with the orbit
  • Period of the radial oscillation
  • Period of the star going around 2?
  • The energy is generally conserved and determines
    the outer radius of the orbit.
  • The inner radius is determined by the angular
    momentum.

apocentre
pericentre
92
Box Orbits
  • Have no particular sense of circulation about the
    centre.
  • They are the sum of independent harmonic motions
    parallel to the x and y axes.
  • In a logarithmic potential of the form
  • box orbits will occur when RltltRc and loop
    orbits will occur when RgtgtRc.

93
JEANS EQUATION
  • The jeans equation for oblate rotator
  • a steady-state axisymmetrical system in which ?2
    is isotropic and the only streaming motion is
    azimuthal rotation

94
  • The velocity dispersions in this case are given
    by
  • If we know the forms of ?(R,z) and ?(R,z) then at
    any radius R we may integrate the Jeans equation
    in the z direction to obtain ?2.

95
Obtaining ?2
  • Inserting this into the jeans equation in the
    R
  • direction gives

96
  • Example suppose

97
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98
Tidal Stripping
  • TIDAL RADIUSRadius within which a particle is
    bound to the satellite rather than the host
    system.
  • Consider a satellite of mass profile ms(R) moving
    in a spherical potential ?(r) made from a mass
    profile M(r).

R
r
V(r)
99
  • The condition for a particle to be bound to the
    satellite rather than the host system is

Differential (tidal) force on the particle due to
the host galaxy
Force on particle due to satellite
100
  • So,
  • Therefore the formula for Tidal Radius is
  • The tidal radius is smallest at pericentre where
    r is smallest.
  • The inequality can be written in terms of the
    mean densities.
  • The satellite mass is not constant as the tidal
    radius changes.

101
Lagrange Points
  • There is a point between two bodies where a
    particle can belong to either one of them.
  • This point is known as the LAGRANGE POINT.
  • A small body orbiting at this point would remain
    in the orbital plane of the two massive bodies.
  • The Lagrange points mark positions where the
    gravitational pull of the two large masses
    precisely cancels the centripetal acceleration
    required to rotate with them.
  • At the lagrange points

102
Effective Force of Gravity
  • A particle will experience gravity due to the
    galaxy and the satellite along with a centrifugal
    force and a coriolis term.
  • The effective force of gravity is given by
  • The acceleration of the particle is given by

Coriolis term
Centrifugal term
103
Jakobis Energy
  • The JAKOBIS ENERGY is given by
  • Jakobis energy is conserved because

104
  • For an orbit in the plane (r perpendicular to ?)

105
  • EJ is also known as the Jakobi Integral.
  • Since v2 is always positive a star whose Jakobi
    integral takes the value EJ will never tresspass
    into a region where ?eff(x)gtEJ.
  • Consequently the surface ?eff(x)gtEJ, which we
    call the zero velocity surface for stars of
    Jakobi Integral EJ, forms an impenetrable wall
    for such stars.

106
  • By taking a Taylor Expansion rrs, you end up
    with
  • Where we call the radius rJ the JAKOBI LIMIT of
    the mass m.
  • This provides a crude estimate of the tidal
    radius rt.

107
Dynamical Friction
  • DYNAMICAL FRICTION slows a satellite on its orbit
    causing it to spiral towards the centre of the
    parent galaxy.
  • As the satellite moves through a sea of stars
    I.e. the individual stars in the parent galaxy
    the satellites gravity alters the trajectory of
    the stars, building up a slight density
    enhancement of stars behind the satellite
  • The gravity from the wake pulls backwards on the
    satellites motion, slowing it down a little

108
  • The satellite loses angular momentum and slowly
    spirals inwards.
  • This effect is referred to as dynamical
    friction because it acts like a frictional or
    viscous force, but its pure gravity.

109
  • More massive satellites feel a greater friction
    since they can alter trajectories more and build
    up a more massive wake behind them.
  • Dynamical friction is stronger in higher density
    regions since there are more stars to contribute
    to the wake so the wake is more massive.
  • For low v the dynamical friction increases as v
    increases since the build up of a wake depends on
    the speed of the satellite being large enough so
    that it can scatter stars preferentially behind
    it (if its not moving, it scatters as many stars
    in front as it does behind).
  • However, at high speeds the frictional force
    ?v-2, since the ability to scatter drops as the
    velocity increases.
  • Note both stars and dark matter contribute to
    dynamical friction

110
  • The dynamical friction acting on a satellite of
    mass ms moving at vs kms-1 in a sea of particles
    with gaussian velocity distribution
  • is

111
  • For an isotropic distribution of stellar
    velocities this is
  • i.e. only stars moving slower than M contribute
    to the force. This is usually called the
    Chandrasekhar Dynamical Friction Formula.
  • For sufficiently small vM we may replace f(vM) by
    f(0) to give
  • For a sufficiently large vM, the integral
    converges to a definite limit and the frictional
    force therefore falls like
  • vM-2.

112
  • When there is dynamical friction there is a drag
    force which dissipates angular momentum. The
    decay is faster at pericentre resulting in the
    staircase like appearance.
  • ??????????????????????????????????

113
  • As the satellite moves inward the tidal force
    becomes greater so the tidal radius decreases and
    the mass will decay.
  • ???????????????????????????????????????

114
Scalar Virial Theorem
  • The Scalar Virial Theorem states that the kinetic
    energy of a system with mass M is just
  • where ltv2gt is the mean-squared speed of the
    systems stars.
  • Hence the virial theorem states that

Virial
115
  • Equation of motion

This is Tensor Virial Theorem
116
  • E.g.
  • So the time averaged value of v2 is equal to the
    time averaged value of the circular velocity
    squared.

117
  • In a spherical potential

So ltxygt0 since the average value of xy will be
zero. ?ltvxvygt0
118
Adiabatic Invariance
  • Suppose we have a sequence of potentials ?p(r)
    that depends continuously on the parameter P(t).
  • P(t) varies slowly with time.
  • For each fixed P we would assume that the orbits
    supported by ?p(r) are regular and thus phase
    space is filled by arrays of nested tori on which
    phase points of individual stars move.
  • Suppose

119
  • The orbit energy of a test particle will change.
  • Suppose
  • The angular momentum J is still conserved because
    r?F0.
  • E.g. circular orbit in a flat potential

Initial Final
Let P(t)Vcir
?
120
  • So, if Vcir increases by a factor of 2 then the
    radius of the orbit would decrease by a factor of
    2 and the period would decrease by a factor of 4.
  • E.g. in a potential
  • In general the orbital eccentricity is conserved
    e.g. a circular orbit will stay circular.

121
  • In general, two stellar phase points that started
    out on the same torus will move onto two
    different tori.
  • However, if P is changed very slowly compared to
    all characteristic times associated with the
    motion on each torus, all phase points that are
    initially on a given torus will be equally
    affected by the variation in P
  • Any two stars that are on a common orbit will
    still be on a common orbit after the variation in
    P is complete. This is ADIABATIC INVARIANCE.
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