Title: Geometrical optics
1Geometrical optics
Physics 135 General Physics II 25/28 February
2005
2Law of reflection
q angle of incidence
q angle of reflection
Planar reflecting surface (mirror)
3Objects and images
Object
Image
Reflected rays appear to come from a point
Rays from point on object reflect from mirror
4Law of refraction
q1 angle of incidence
n1
q2 angle of refraction
n2
( n2 gt n1 in diagram )
5Two simple effects
Total internal reflection
Object underwater appears to be at a shallower
depth
6Thin lenses
7Objects and images
x
y
Three easy rays for ray-tracing
Thin lens equation
magnification
8Reading the signs
- In this diagram
- The object is upstream of the lens.
- The lens is a converging lens.
- The image is a real image through which light
rays actually pass, and it is downstream of the
lens.
i, f and o are all positive
9A negative lens
o 50 cm
f -30 cm
i -18.75 cm
m 0.375
Upright, virtual image 37.5 as large as object
10A compound lens system
50 cm
50 cm
150 cm
f 30 cm
f -30 cm
Total magnification
M m m (-1.5) (6.0) - 9.0
11What is going on
Light rays diverge from object.
First lens causes rays to converge.
12What is going on
Light rays diverge from object.
Diverging lens moves image to here.
First lens causes rays to converge.
13Curved mirrors
1. Assume that mirror is a section of a sphere
of radius r
2. Assume that mirrors curve is shallow -- it
is essentially in one plane
14Spherical mirrors
15Spherical mirrors
16x
y
17o
r
x
r - i
y
o - r
i
18(a little algebra)
19Spherical mirror equation
20f 10 cm
i 12.5 cm
21o
r
x
y
i
magnification
22f 10 cm
i 12.5 cm
m - 0.25
23Limiting cases
f ? ? Flat mirror (infinite radius r) o ?
? Parallel incident rays
24Two types of images
Real image i gt 0 , so light rays pass through
image point (in front of mirror) Inverted Virtua
l image i lt 0 , so light rays do not pass through
image point (behind mirror) Upright