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Equation of a Straight Line

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Collinear Points ... BC have different gradients(m1 m2) so they are not collinear. P,Q,R,S do not share a common point although m1= m2 so they are not collinear. ... – PowerPoint PPT presentation

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Title: Equation of a Straight Line


1
Unit 1
  • Equation of a Straight Line

2
Revision from S4
(x2 , y2)
  • The gradient of a straight line is calculated
    using the formula-
  • The gradient can also be calculated using -

y2 - y1
(x1. y1)
x2-x1
o
?
a
3
Finding a gradient
  • Horizontal lines have zero gradient.
  • Vertical lines have undefined gradient.
  • Parallel lines have equal gradients.

Find the gradients of the lines connecting the
following points- a) (2 , 7) and (5 , 9) b) (3
, -4) and (-1 , 2) c) (1 , 4) and (3 , 4) d)
(5 , 4) and 5 , -2)
m 2/3
m -2/3
m 0
m is undefined
4
Collinear Points
C
B
  • A,B,C share a common point but AB and BC have
    different gradients(m1?m2) so they are not
    collinear.
  • P,Q,R,S do not share a common point although m1
    m2 so they are not collinear.
  • M,N,O have a common point and m1m2 so the y are
    collinear.

A
Q
S
P
R
O
N
M
5
Perpendicular Lines
  • If 2 lines are perpendicular then the product of
    their gradients will be -1 i.e. m1m2 - 1
  • Write down the gradient of the line perpendicular
    to the line with gradient -

m -3/2
m 5/4
m -1/2
m 1/4
6
Finding a Midpoint
  • To calculate the midpoint of a line you can use
    the formula -

x2,y2
x1,y1
M
7
Altitude
  • The perpendicular bisector of a line meets it at
    right angles and cuts it in two.
  • The altitude of a triangle is a line from one of
    its vertices that is perpendicular to the
    opposite side.

8
Median
  • The median of a triangle is a line from a vertice
    that cuts the opposite side in two.

9
Equation of line through (a,b) with gradient m.
(x,y)
m
y -b
(a,b)
x - a
10
Last Slide
  • Please complete the worksheet
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