Title: Next Semester we will begin with the study of chemical reactions
1- Next Semester we will begin with the study of
chemical reactions - In order to study chemical reactions we need to
be able to - write chemical formulas for compounds involved
in reactions - Name chemical compounds involved in chemical
reactions -
2- Metals with more than one charge
- Formula Stock name Classical name Formula
Stock name Classical name - Cu1 Copper (I) ion Cuprous ion
Hg22 Mercury (I) ion Mercurous
ion - Cu2 Copper (II) ion Cupric ion
Hg2 Mercury (II) ion Mercuric
ion - Fe2 Iron (II) ion Ferrous ion
Pb2 Lead (II) ion Plumbous
ion - Fe3 Iron (III) ion Ferric ion
Pb4 Lead (IV) ion
Plumbic ion - Sn2 Tin (II) ion Stannous ion
Cr2 Chromium (II) ion
Chromous ion - Sn4 Tin (IV) ion Stannic ion
Cr3 Chromium (III) ion Chromic
ion - Co2 Cobalt (II) ion Cobaltous ion
Mn2 Manganese (II) ion Manganous
ion - Co3 Cobalt (III) ion Cobaltic ion
Mn3 Manganese (III) ion Manganic
ion
3- Chapter 7 Chemical Names and Formulas
- Elements Symbols and the Diatomic 7
- 1. You probably know the chemical symbols for
many elements (ex Sodium ____, Mercury ____,
Silver ____, Gold ______ etc). - 2. There are 7 elements that exist in nature as
___________ (two atoms together). They are
called the diatomic 7. List them below - (Note The charge of these diatomic elements is
0) - 4. Many elements exist in a combined state with
other elements to make what is called a compound. - Binary Ionic Compounds (pg. 222-223) Compounds
composed of ___ elements. These elements will be
a ____________ and _______________. (No prefixes
for ionic compounds) - 1. Compounds of a metal and non-metal are
commonly called __________ compounds. - 2. When ionic compounds form the metal will
___________ electrons to form a __ ion - ( __________) and the non-metal will _________
electrons to form a __ ion (____________). - 3. The chemical formula for an ionic compound
will have the __________ written first followed
by the __________. The metal will be given its
elemental name and the non-metal will have a
modification of its elements name so that it
includes an _________ ending. - Ex Chemical Formula NaCl
Name - Chemical Formula LiBr
Name - Chemical Formula CaCl2
Name - To write the chemical formula for an ionic
compound, the positive and negative charges must
be ___________. In order to determine if the
charges are equal, you must look at the oxidation
number of each element present in the compound
(recall the oxidation number for elements in
group 1A is ___, for elements in group 6A is ___
etc.) - In order to balance the charge, ______________
will be written below the chemical symbols.
Na
Hg
Au
Ag
diatoms
I2
Br2
F2
O2
Cl2
N2
H2
2
metal
non-metal
ionic
lose
gain
anion
-
cation
metal
non-metal
-ide
sodium
chloride
lithium
bromide
calcium
chloride
equal
1
-2
subscripts
4- Ionic Compounds Containing Transition Metals
(Use Roman Numerals) - Stock Names
- Many transition metals have more than one charge
as ions in compounds (exceptions Ag always has a
___ charge as an ion and Cd and Zn always have a
______charge as an ion.) - Note We are not saying that metals always have
a charge. In an uncombined state as an element
they have no charge, but when they combine with
non-metals to form compounds they will have a
charge.
Ex Write the chemical formula for sodium
bromide
-1
1
Na
Br
Charges are balanced, erase oxidation s
Ex Write the chemical formula for potassium
oxide
1
-2
K
O
2
Ex Write the chemical formula for barium
fluoride
2
-1
Ba
F
2
Ex Write the chemical formula for calcium
phosphide
2
-3
Ca
P
3
2
2
1
5- 2. When writing the name of an ionic compound
with a transition metal it is important to
indicate the _____________ of the transition
metal. The charge will be indicated as a
______________ numeral after the transition
metal. - Ex Write the name of CuCl Write the name of
CuCl2 - Classical Name (-ous or ic ending on transition
metal) - 1. Often the stock system is not used and the
_____________ names are given to ionic compounds
containing transition metals with more than one
charge. - 2. Here, the ion of a particular transition
metal with the lower charge will have an
_________ ending and the ion with the higher
charge will have an _____ ending. - 3. Your naming sheet has the charges and
classical names for different transition metal
ions.
charge
roman
copper chloride
copper chloride
( )
( )
II
I
classical
-ous
-ic
Write the chemical formula for Iron (II) Oxide
Write the chemical formula for Ferric Sulfide
-2
2
3
-2
Fe
S
O
Fe
2
3
Write the chemical formula for Mercury (I) Oxide
and Mercury (II) Oxide
2
-2
2
-2
Hg2
Hg
O
O
6- Write the chemical formula for Plumbous Chloride
- Name the compound SnCl4 using the classical and
stock names.
2
-1
Cl
Pb
2
Stock Name
tin chloride
( )
IV
Classical Name
stannic chloride
7- Homework
- 1. Write the names for the following binary ionic
compounds - (For transition metal compounds use the Stock and
Classical Names when applicable) - a. KCl b. NaI c. K2O d. CuS
e. Li2S f. Na3N g. AgI h. FeO
i. ZnO - 2. Write the chemical formula for the following
binary ionic compounds - a. Lithium Oxide b. Tin(IV) Sulfide
c. Hydrogen Chloride d. Silver Chloride - e. Manganese (II) Nitride f. Mercury (I) Oxide
g. Mercury (II) Bromide h. Cadmium
Sulfide
sulfide
lithium
a. potassium
chloride
e.
1.
i. zinc oxide
iodide
b. sodium
f.
sodium nitride
g. silver iodide
oxide
potassium
c.
sulfide
stock
copper
( )
II
d.
h.
stock
iron (II) oxide
sulfide
classical
cupric
ferrous oxide
classical
a. Li2O
2.
e. Mn3N2
b. SnS2
h. CdS
f. Hg2O
c. HCl
g. HgBr2
d. AgCl
8- Chemical Names and Formulas II
- Ionic Compounds containing polyatomic ions (pg.
225-227) - The same rules apply to ionic compounds
containing polyatomic ions as did for binary
ionic compounds (___ prefixes) except there will
be no ide endings added. Here, write the name
of the metal first (use stock (roman numeral) and
classical name if necessary), then write the name
of the polyatomic ion (most polyatomic ions end
in ite or ate ending except hydroxide (
), peroxide ( ) and cyanide (
)). - Examples
- 1. Write the Chemical Formula for the following
- 2. Write the chemical name for the following
(include classical and stock names)
no
O2-2
OH-
CN-
a. Sodium Phosphate
b. hydrogen peroxide
c. ferrous hypochlorite
d. ammonium sulfate
-1
-2
Fe
2
-3
H
1
O2
ClO
PO4
( )
1
Na
1
SO4
-2
( )
NH4
2
3
2
2
e. calcium carbonate
f. copper (II) nitrate
-2
Ca
2
2
CO3
Cu
NO3
-1
( )
2
a. Fe2(SO4)3
b. Na2CrO4
c. Cr2(C4H4O6)3
stock
stock
chromium ( )
tartrate
III
sulfate
sodium
iron ( )
III
chromate
classical
chromic tartrate
ferric sulfate
classical
f. (Hg2)3(PO4)2
d. Mn(OH)2
e. NH4HCO3
stock
stock
ammonium hydrogen carbonate
ammonium bicarbonate
phosphate
mercury ( )
I
manganese (II) hydroxide
mercurous phosphate
classical
manganous hydroxide
classical
9- Naming Covalent (molecular) compounds (pg.
227-229) - Covalent compounds are compounds composed of
non-metals (or metalloid/non-metal). - For these compounds prefixes will be used to
indicate the numbers of that element present
(exceptions ________ will not be used on the
first element shown like CO is carbon monoxide).
- The last element will be given an _________
ending. - Prefixes
- mono-1 di-2 tri- 3 tetra- 4 penta- 5
hexa- 6 hepta- 7 octa- 8 nona- 9
deca- 10 - Examples
- 1. Name the following
- a. NO b. NO2 c. N2O d. P4O7
-
- 2. Write the chemical formula for the following
- a. dinitrogen pentoxide b. boron trifluoride c.
carbon tetrachloride - Summary
- When the first element of a compound is a metal
then it is ionic. Dont use prefixes (if it is a
transition metal give the classical and stock
name labeled properly (no s or c)).
mono-
-ide
dinitrogen monoxide
nitrogen monoxide
nitrogen dioxide
tetraphosphorus heptoxide
CCl4
N2O5
BF3
10- Naming Inorganic Acids (pg. 230-231)
- Acids are named for the Latin word acidus which
means _______ or tart. Acids taste sour and
substances that are bases are ________. The
Arrhenius theory of acids state that acids
release ____ when dissolved in water and bases
release _____ when dissolved in water. - Rules for Naming Acids
- General Chemical formula for acids HX (aq)- the
(aq) means the substance is dissolved in
________. Dissolving an acid in water results in
the releasing of an ____ ion. - 1. When the X anion ends in ______ use _______
stem ___ acid. - Examples
- HCl (aq) HBr(aq) HCN(aq)
- HCl (g) hydrosulfuric acid
- 2. When the X anion ends in _______ use stem
_____ acid. - Examples
- HClO4 (aq) HNO3 (aq) H3PO4 (aq)
- carbonic acid acetic acid
sour
bitter
H
OH-
water
H
-ide
-ic
hydro-
hydrochloric acid
hydrobromic acid
hydrocyanic acid
hydrogen monochloride
1
-2
(aq)
S
H
2
-ate
-ic
perchloric acid
nitric acid
phosphoric acid
-2
1
-1
1
(aq)
C2H3O2
H
CO3
H
(aq)
2
11- 3. When the X anion ends in ____ use stem _____
acid. - Examples
- H2SO3 (aq) HClO (aq)
- phosphorous acid chlorous acid
- Summary
- 1. If the first element of the compound is a
metal (or ammonium ion) then it is ionic (NO
PREFIXES!). - -if the metal has more than 1 charge use
classical and stock names - 2. If the first element of the compound is a
metalloid or non-metal (other than hydrogen) then
it is - covalent (USE PREFIXES!)
- 3. If the first element of the compound is H and
there is an (aq) symbol, then it is an acid. - if anion ends in ide use hydro stem ic acid
-ous
-ite
sulfurous acid
hypochlorous acid
-1
1
1
-3
(aq)
(aq)
H
PO3
H
ClO2
3
12- Properties of Ionic and Covalent Compounds,
Metals pg. 193-196 - Ionic compounds
- a. Tend to be ________________ at room
temperature due to the strong electrostatic
attractions between the oppositely charged ions.
Solids have a definite shape and volume (fig. 6
pg 9). - b. The ions are in fixed positions relative to
each other. If an ionic compound is struck, like
charged ions a forced close to each other and the
structure will _______________ (see fig. 17 pg.
193). - c. When heated to the molten state (or
dissolved in water), the ions are free to move
and will conduct ________________. - d. The simplest particle that retains the
properties of an ionic compound is called a
_____________ unit. - e. An ionic compound composed of metallic
cations and an anion from some acid are called
_______. - Metals
- a. Tend to be solids at room temperature.
Metallic bonding consists of metallic cations
being surrounded by a sea of freely floating
______________ electrons (see fig. 18 pg. 195).
The result of the freely floating electrons (free
to move cation to cation) is the unique
properties of malleability, ductility,
conductivity of electricity and heat as well as
the ability to reflect light well (have a
luster). - b. The simplest particle that retains the
properties of a metal is an ____________ (just
like most elements except for the diatomic 7
which are composed of molecules). - Covalent compounds
- Have a ________ range of boiling and melting
points due to a broad range in strength of
intermolecular forces. The result is that some
covalent compounds being solids, some being
liquids (have a definite volume but assume the
shape of the container) and some being gases
(assume the volume and shape of the container). - b. The simplest particle that retains the
properties of a sample of covalent compound is a
____________. - c. Covalent compounds are brittle as solids and
do not conduct electricity in the solid or molten
state (they are ____________________). Variable
solubility in water (depends upon the polarity of
the molecule).
solids
shatter
electricity
formula
salts
valence
atom
broad
molecule
insulators
13- Percentage Composition (pg. 242-244)
- Percentage composition is a statement that
relates the ________ of one element in a compound
to the sum of all the masses of all the elements
within the compound. - This may be determined in a couple of ways
- 1. Percentage composition from experimental data
- A chemist determines that there is 1.58 g of
Copper present in 1.98 g of a compound that
contains Copper and Sulfur. Determine the
percentage composition of Sulfur and Copper in
the compound. - Cu g Cu 100
- g cmp
- Cu 1.58 g 100
- 1.98 g
- Cu 79.8
- 2. Percentage composition from Chemical Formula
- Is the compound shown in sample 1a. Copper (I)
Sulfide or Copper (II) Sulfide?
mass
S 100 - Cu
S 100 79.798
S 20.2
Cu2S
Cu2S
CuS
Cu in Cu2S
Cu in CuS
Cu g Cu 100 g CuS
Cu g Cu 100 g Cu2S
Cu 63.546 g/mol 100 63.546 g/mol
32.06 g/mol
Cu 2(63.546 g/mol) 100 2(63.546
g/mol) 32.06 g/mol
Cu 66.47
Cu 79.86
14- Empirical Formula (pg. 245-247)
- Empirical Formula is the simplest ratio of atoms
present in a molecule - The empirical formula for C6H6 is _________
- 2. Empirical Formulas may be determined from
composition data. Here you must determine the
simplest whole number ratio of _________ for each
element. - Determine the empirical formula for a compound
that contains 0.900 g Ca and 1.60 g Cl.
CH
moles
moles Ca
0.900 g Ca
mol Ca 40.08 g Ca
0.022455 mol Ca
__________________ 0.022455 mol
1.00
mol Cl 35.453 g Cl
moles Cl 1.60 g Cl
0.045130 mol Cl
__________________ 0.022455 mol
2.01
To obtain the simplest ratio of moles, divide by
the smaller value
If values are within 0.1, round to the nearest
whole number
CaCl2
15- Determine the empirical formula for a compound
that contains 40.0 C, 6.71 H and 53.3 O.
When 's are given merely assume that you have
______ g of the compound.
100
mol C 12.011 g C
40.0 g C
moles C
3.3302 mol C
__________________ 3.3302 mol
1.00
mol H 1.008 g H
6.71 g H
moles H
6.6567 mol H
__________________ 3.3302 mol
2.00
CH2O
53.3 g O
mol O 15.999 g O
moles O
3.3315 mol O
__________________ 3.3302 mol
1.00
Determine the empirical formula for a compound
that contains 25.9 Nitrogen and 74.1 Oxygen.
This example will show what to do when the mole
ratio is not a whole number.
mol N 14.007 g N
moles N
25.9 g N
1.8491 mol N
_______________ 1.8491 mol
x 2
2
1.00
N2O5
moles O
74.1 g O
mol O 15.999 g O
4.6315 mol O
_______________ 1.8491 mol
x 2
5
2.50
Not within 0.1, multiply each by a so that each
will be a whole
16- Molecular Formulas from Empirical Formulas-this
is the true chemical formula of a compound and
can be determined from the ____________ formula
and the ___________________ of the compound.
Practice problem N 248
empirical
molar mass
Step 1 Determine the of empirical formula
units that fit within the molecule
This is obtained from the quotient of molar mass
of compound and the molar mass of the empirical
formula
283.89 g/mol________ 2(30.974 g/mol)
5(15.999 g/mol)
283.89 g/mol________ 141.943 g/mol
2.00
Step 2 Multiply each subscript of the empircal
formula by the calculated above.
Empirical formulaP2O5
P4O10
Pg. 246-247 sample problem L, M are good for
more practice on empirical formulas
17- pg. 246,7
- L. mole Na 32.38 g Na . mol Na 1.4079 mol Na
1.99 (2) - 22.999 g Na 0.70640 mol
- mole S 22.65 g S . mol S 0.70640
mol S 1.00 (1) - 32.064 g S 0.70640 mol
- mole O 44.99 g O . mol O 2.8121 mol O
3.98 (4) - 15.999 g O 0.70640 mol
- Na2SO4
- M. mol P 4.433 g P . mol P 0.14312 mol P
1.00 (2) 2 - 30.974 g P
0.14312 mol -
- mol O 5.717 g O . mol O 0.35733 mol O
2.50 (2) 5 - 15.999 g O 0.14312 mol
- P2O5