Title: EE 434 Lecture 19
1EE 434Lecture 19
- Model Extension
- Small signal model extension
- Small signal analysis
2Quiz 13
Assume the MOS transistor in this circuit was
designed in a 0.6u process with device parameters
µCOX100µA/V2 and VT1V. With the square-law
model of the device introduced in class, it can
be shown that the small-signal gain for this
circuit is
where gm is the transconductance gain of the
transistor. Assume a reverse-engineering team is
trying to determine what the dimensions are of
the device and can not open the package to see
the device. They did, however, measure the
small signal voltage gain and it was -4 and they
measured the quiescent VGS and it was 3V. What
is W/L for the transistor?
3And the number is .
4And the number is .
5Quiz 13
Assume the MOS transistor in this circuit was
designed in a 0.6u process with device parameters
µCOX100µA/V2 and VT1V. With the square-law
model of the device introduced in class, it can
be shown that the small-signal gain for this
circuit is
where gm is the transconductance gain of the
transistor. Assume a reverse-engineering team is
trying to determine what the dimensions are of
the device and can not open the package to see
the device. They did, however, measure the
small signal voltage gain and it was -4 and they
measured the quiescent VGS and it was 3V. What
is W/L for the transistor?
Solution
6Quiz 13
Assume the MOS transistor in this circuit was
designed in a 0.6u process with device parameters
µCOX100µA/V2 and VT1V. With the square-law
model of the device introduced in class, it can
be shown that the small-signal gain for this
circuit is
where gm is the transconductance gain of the
transistor. Assume a reverse-engineering team is
trying to determine what the dimensions are of
the device and can not open the package to see
the device. They did, however, measure the
small signal voltage gain and it was -4 and they
measured the quiescent VGS and it was 3V. What
is W/L for the transistor?
Solution
7Quiz 13
Assume the MOS transistor in this circuit was
designed in a 0.6u process with device parameters
µCOX100µA/V2 and VT1V. With the square-law
model of the device introduced in class, it can
be shown that the small-signal gain for this
circuit is
where gm is the transconductance gain of the
transistor. Assume a reverse-engineering team is
trying to determine what the dimensions are of
the device and can not open the package to see
the device. They did, however, measure the
small signal voltage gain and it was -4 and they
measured the quiescent VGS and it was 3V. What
is W/L for the transistor?
Solution
8Review from Last Time
Small signal model for MOS transistor was
developed
9Review from Last Time
Model Extension to Account for Slope of ID-VDS
Characteristics
Introduces a discontinuity between triode and
saturation regions Does not exist in real
devices Multiply by 1?VDS in triode
region as well in simulators
Issue of how gm varies with IDQ discussed and
apparent delima identified
10How does gm vary with IDQ?
Review from Last Time
Varies with the square root of IDQ
Varies linearly with IDQ
Doesnt vary with IDQ
11Graphical Interpretation of MOS Model
12Graphical Interpretation of MOS Model
13Further Model Extensions
Existing model does not depend upon the bulk
voltage !
Observe that changing the bulk voltage will
change the electric field in the channel region !
E
14Further Model Extensions
Existing model does not depend upon the bulk
voltage !
Observe that changing the bulk voltage will
change the electric field in the channel region !
E
Changing the bulk voltage will change the
thickness of the inversion layer
Changing the bulk voltage will change the
threshold voltage of the device
15Typical Effects of Bulk on Threshold Voltage for
n-channel Device
Bulk-Diffusion Generally Reverse Biased (VBSlt 0
or at least less than 0.3V) for n-channel
Shift in threshold voltage with bulk voltage can
be substantial Often VBS0
16Typical Effects of Bulk on Threshold Voltage for
p-channel Device
Bulk-Diffusion Generally Reverse Biased (VBS gt 0
or at least greater than -0.3V) for n-channel
Same functional form as for n-channel devices but
VT0 is now negative and the magnitude of VT still
increases with the magnitude of the reverse bias
17Model Extension Summary
Model Parameters µ,COX,VT0,f,?,?
Design Parameters W,L but only one degree
of freedom W/L
18Small-Signal Model Extension
19(No Transcript)
20Small Signal Model Summary
21Small Signal Model Observation
Consider
3 alternate equivalent expressions for gm
If µCOX100µA/V2 , ?.01V-1, ? 0.4V0.5,
VEBQ1V, W/L1, VBSQ0V
In this example
This relationship is common
In many circuits, VBS0 as well
22Small Signal Model Summary
Large Signal Model
Small Signal Model
where
23How does gm vary with IDQ?
Varies with the square root of IDQ
Varies linearly with IDQ
Doesnt vary with IDQ
24How does gm vary with IDQ?
All of the above are true but with qualification
gm is a function of more than one variable (IDQ)
and how it varies depends upon how the remaining
variables are constrained
25Small Signal Model Summary
An equivalent circuit
This contains absolutely no more information than
the previous model
26Small Signal Model Summary
More convenient representation
27Small Signal Model Summary
Simplification that is often adequate
28Small Signal Model Summary
Even further simplification that is often adequate
29Small Signal Model Summary
Alternate equivalent representations for gm
from
30Small-Signal Circuit Analysis
- Obtain dc equivalent circuit by replacing all
elements with large-signal (dc) equivalent
circuits - Obtain dc operating points (Q-point)
- Obtain ac equivalent circuit by replacing all
elements with small-signal equivalent circuits - Analyze linear small-signal equivalent circuit
31Dc and small-signal equivalent elements
32Dc and small-signal equivalent elements
33End of Lecture 19
34Small signal analysis example
uCOX100uA/V2 VT.75V ?.01V-1 VDD8V VSS
-1.25V W16u L1u R115K
35Small signal analysis example
Must solve 5 simultaneous equations to obtain VOUT
But one of these equations is nonlinear making
the solution very tedious
36Small signal analysis example
37Small signal analysis example
Q-point
Consider VIN very small
38Small signal analysis example
Consider VIN0,Vm,-Vm
Define VEBVGS-VT when VIN0 Thus VEB-VSS-VT
39Small signal analysis example
40Small signal analysis example
This is termed the quiescent output voltage
41Small signal analysis example
5V
Q-point
42Small signal analysis example
If VM0.1V
43Small signal analysis example
VIN-VM
3.68
5.0
6.08
VINVM
Note signal swing is not symmetric
44Small signal analysis example
Parametric expression for apparent gain
Note Apparent gain is independent of VM
45Small signal analysis example
Very simple expression for apparent gain
Derivation of apparent gain very tedious
Apparent gain gives minimal insight into design
strategies
Near the Q-point, all well-behaved circuits
operate linearly
Can this linear operation be exploited to
simplify the analysis?
46Small signal analysis example
Circuit Schematic
Linearized Small Signal Circuit
47Small signal analysis example
Linearized Small Signal Circuits
48Small signal analysis example
Linearized Small Signal Circuits
Still need IDQ and VEB
Small signal analysis much simpler (because
linear)
49Small signal analysis example
Linearized Small Signal Circuits
This is identical to the numerical value obtained
for the apparent gain !
50Small signal analysis example
How does small signal gain compare to apparent
gain for this circuit?
For this circuit the apparent gain and the actual
gain are identical
This is not true in general but they will be
close provided VM is reasonably small and they
become equal in the limit as VM approaches 0