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Payload Thermal Issues

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All payload components can function properly only within particular temperature ranges ... Q = k A ((T1-T2)/L) for a rod of area A and length L ... – PowerPoint PPT presentation

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Title: Payload Thermal Issues


1
Payload Thermal Issues Calculations
  • Ballooning Unit, Lecture 3

2
Thermal Requirements
  • All payload components can function properly only
    within particular temperature ranges
  • Operating temperature range (narrowest)
  • In this temperature range the component will
    perform to within specified parameters
  • Non-Operation temperature range (wider)
  • Component will not perform within specs, but will
    do so when returned to operating temperature
    range
  • Survival temperature range (widest)
  • If this range is exceeded component will never
    return to proper operation
  • Thermal requirements constitute specifying these
    ranges for all components

3
Thermal Control Plan
  • Systems and procedures for satisfying the thermal
    requirements
  • Show that thermal system (i.e. heaters,
    insulation, surface treatment) is sufficient to
    avoid excursions beyond survival temperature
    range
  • Show critical components remain mostly in the
    operating temperature range
  • Specify mitigation procedures if temperature
    moves to non-operating range (e.g. turn on
    heaters)

4
Determining Temperature Ranges
  • Start with OEM (original equipment manufacturer)
    datasheet on product
  • Datasheets usually specify only operating
    temperature range
  • Definition of operating may vary from
    manufacturer to manufacturer for similar
    components
  • Look for information on how operating parameters
    change as a function of temperature
  • Your operating requirement may be more stringent
    than the manufacturer
  • Find similar products and verify that temperature
    ranges are similar
  • Search for papers reporting results from
    performance testing of product
  • Call manufacturer and request specific information

5
Survival Temperature Range
  • Survival temperature range will be the most
    difficult to quantify
  • Range limits may be due to different effects
  • Softening or loss of temper
  • Differential coefficients of expansion can lead
    to excessive shear
  • Contact manufacturer and ask for their
    measurements or opinion
  • Estimate from ranges reports for similar products
  • Measure using thermal chamber

6
Heat Transfer
  • The payload will gain or lose heat energy through
    three fundamental heat transfer mechanisms
  • Convection is the process by which heat is
    transferred by the mass movement of molecules
    (i.e. generally a fluid of some sort) from one
    place to another.
  • Conduction is the process by which heat is
    transferred by the collision of hot fast moving
    molecules with cold slow moving molecules,
    speeding (heating) these slow molecules up.
  • Radiation is the process by which heat is
    transferred by the emission and absorption of
    electromagnetic waves.

7
Convection
  • Requires a temperature difference and a working
    fluid to transfer energy
  • Qconv h A ( T1 T2 )
  • The temperature of the surface is T1 and the
    temperature of the fluid is T2 in Ko
  • The surface area exposed to convection is given
    by A in m2
  • The coefficient h depends on the properties of
    the fluid.
  • 5 to 6 W/(m2 Ko ) for normal pressure calm
    winds
  • 0.4 W/(m2 Ko ) or so for low pressure
  • In the space environment, where air pressure is
    at a minimum, convection heat transfer is not
    very important.

8
Conduction
  • Requires a temperature gradient (dT/dx) and some
    kind of material to convey the energy
  • Qcond k A ( dT / dx )
  • The surface area exposed to conduction is given
    by A in m2
  • The coefficient k is the thermal conductivity of
    the material.
  • 0.01 W/(m2 Ko ) for styrofoam
  • 0.04 W/(m2 Ko ) for rock wool, cork, fiberglass
  • 205 W/(m2 Ko ) for aluminium
  • Need to integrate the gradient over the geometry
    of the conductor.
  • Q k A ((T1-T2)/L) for a rod of area A and
    length L
  • Q 4? k r (r x) ((T1-T2)/x) for a spherical
    shell of radius r and thickness x

9
Radiation
  • Requires a temperature difference between two
    bodies, but no matter is needed to transfer the
    heat
  • Qrad ? ? A ( T14 T24 )
  • The Stefan-Boltzmann constant, ?, value is 5.67 x
    10-8 W/m2 K4
  • The surface area involved in radiative heat
    transfer is given by A in m2
  • The coefficient ? is the emissivity of the
    material.
  • Varies from 0 to 1
  • Equal to the aborptivity ( ? )at the same
    wavelength
  • A good emitter is also a good absorper
  • A good reflector is a bad emitter
  • In the space environment, radiation will be the
    dominant heat transfer mechanism between the
    payload environment

10
Emissivity Absorptivity 1
  • Kirchoffs Law of Thermal Radiation At thermal
    equilibrium, the emissivity of a body (or
    surface) equals its absorptivity
  • A material with high reflectivity (e.g. silver)
    would have a low absorptivity AND a low
    emissivity
  • Vacuum bottles are silver coated to stop
    radiative emission
  • Survival space blankets use the same principle
  • Kirchoffs Law requires an integral over all
    wavelengths
  • Thus, some materials are described as having
    different absorptivity and emissivity value.

11
Emissivity Absorptivity 2
  • Manufacturers define absorption and emission
    parameters over specific (different) wavelength
    ranges
  • Solar Absorptance ( ?s ) absorptivity for 0.3 to
    2.5 micron wavelengths
  • Normal Emittance ( ?n ) emissivity for 5 to 50
    micron wavelengths
  • The Sun, Earth and deep space are all at
    different temperatures and, therefore, emit power
    over different wavelengths
  • A blackbody at the Suns temperature (6,000 Ko)
    would emit between about 0.3 and 3 microns and at
    the Earths temperature (290 Ko) would emit
    between about 3 and 50 microns
  • For space we want to absorb little of the Suns
    power and transfer much of the payload heat to
    deep space.
  • Want a material with low ?s and high ?n .
  • Sherwin Williams white paint has ?s of 0.35 and
    ?n of 0.85

12
Steady State Solution
  • In a steady state all heat flows are constant and
    nothing changes in the system
  • Sum of all heat generators is equal to the sum of
    all heat losses ( Qin Qout )
  • Example flow of heat through a payload box wall
  • Assume vacuum so no convection
  • Input heat ( Qin ) generated by electronics flows
    through wall by conduction and is then radiated
    to space.
  • Qcond Qin or kA ( T1 T2 ) / L Qin (1)
  • Qrad Qin or ??A (T24 Ts4 ) Qin (2)
  • Use eq. 2 to determine T2 and then use eq. 1 to
    determine T1
  • But real systems are never this simple

13
Balloon Environment is Complex
  • Multiple heat sources
  • Direct solar input (Qsun), Sun reflection
    (Qalbedo), IR from Earth (QIR), Experiment power
    (Qpower)
  • Multiple heat sinks
  • Radiation to space (Qr,space), Radiation to Earth
    (Qr,Earth), Convection to atmosphere (Qc)
  • Equation must be solved by iteration to get the
    external temperature
  • Then conduct heat through insulation to get
    internal temperature

QsunQalbedoQIRQpower Qr,spaceQr,EarthQc
14
Solar Input Is Very Important
  • Nominal Solar Constant value is 1370 W / m2
  • Varies 2 over year due to Earth orbit
    eccentricity
  • Much larger variation due to solar inclination
    angle
  • Depends upon latitude, time of year time of day
  • Albedo is reflection of sun from Earth surface or
    clouds
  • Fraction of solar input depending on surface
    conditions under payload

ATIC-02 data showing effects of daily variation
of sun input
15
Other Important Parameters
  • IR radiation from the Earth is absorbed by the
    payload
  • Flux in range 160 to 260 W/m2, over wavelength
    range 5 to 50 microns, depending on surface
    conditions
  • Radiation is absorbed in proportion of Normal
    Emittance ( ?n )
  • Heat is lost via radiation to Earth and deep
    space
  • Earth temperature is 290 Ko and deep space is 4
    Ko
  • There is also convective heat loss to the
    residual atmosphere
  • Atmosphere temperature 260 Ko
  • For a 8 cm radius, white painted sphere at
    100,000 feet above Palestine, TX on 5/21 at 7 am
    local time with 1 W interior power
  • Qsun 9.5 W, Qalbedo 3.7 W, QIR 1.6 W
  • Qr,Earth 0.1 W, Qr,Space 15.3 W, Qconv
    0.4 W

16
Application for BalloonSat
  • Can probably neglect heat loss due to convection
    and radiation to Earth
  • Simplifies the equation you need to solve
  • Need to determine if the solar inclination angle
    will be important for your payload geometry
  • e.g. a sphere will absorb about the same solar
    radiation regardless of time of day and latitude
  • Spend some time convincing yourself that you know
    values for your payload surface ?s and ?n and
    your insulation k.
  • Biggest problem will be to estimate albedo and
    Earth IR input
  • Use extremes for albedo and IR to bracket your
    temperature range

17
References
  • HyperPhysics web based physics concepts,
    calculators and examples by Carl R. Nave,
    Department of Physics Astronomy, Georgia State
    University
  • Home page at http//hyperphysics.phy-astr.gsu.edu/
    hbase/hph.htmlhph
  • Thermodynamics at http//hyperphysics.phy-astr.gsu
    .edu/hbase/heacon.htmlheacon
  • Heat Transfer at http//hyperphysics.phy-astr.gsu.
    edu/hbase/thermo/heatra.htmlc1
  • Vacuum Flask at http//hyperphysics.phy-astr.gsu.e
    du/hbase/thermo/vacfla.htmlc1
  • Thermal Conductivity Table at http//hyperphysics.
    phy-astr.gsu.edu/hbase/tables/thrcn.htmlc1
  • Table of Solar Absorptance and Normal Emmittance
    for various materials by Dr. Andrew Marsh and
    Caroline Raines of Square One research and the
    Welsh School of Architecture at Cardiff
    University.
  • http//www.squ1.com/index.php?http//www.squ1.com/
    materials/abs-emmit.html
  • Sun, Moon Altitude, Azimuth table generator from
    the U.S. Naval Observatory
  • http//aa.usno.navy.mil/data/docs/AltAz.html
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