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Hydrologic Cycle

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While estimates vary, 70-75% of the Earth is covered by water. Facts ... Q = vA = kiA ... Q = vA = KiA. Where: Q = the rate of flow, v = discharge velocity, ... – PowerPoint PPT presentation

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Title: Hydrologic Cycle


1
Hydrologic Cycle
Source US Geological Survey, http//ga.water.usgs
.gov/edu/watercycleinfiltration.html
2
Facts and Figures
  • While estimates vary, 70-75 of the Earth is
    covered by water

3
Facts and Figures
  • 97.2 Saline water in oceans
  • 2.14 Ice caps and glaciers
  • 0.61 Groundwater
  • 0.009 Surface water (lakes, etc.)
  • 0.005 Soil moisture (vadose zone)
  • 0.001 Atmosphere

4
Facts and Figures
  • 98 of the available water is groundwater
  • In the North Carolina, and in the U.S.A., about
    50 of the drinking water is derived from
    groundwater

5
Subsurface Characteristics
Source US Geological Survey, http//ga.water.usgs
.gov/edu/watercycleinfiltration.html
6
Aquifer Characteristics
Source US Geological Survey, http//ga.water.usgs
.gov/edu/watercycleinfiltration.html
7
Basic Definitions
Porosity Vv/VT Void Ratio Vv/Vs Degree of
Saturation Vw/VV Moisture Content Mw/Ms
8
Q K (h1-h2)/l A K i A Q V A V K i
Source LaGrega et al. 2001, Hazardous Waste
Management, 2nd Edition, McGraw Hill
9
Saturated Zone
  • Darcys Law
  • Q vA kiA
  • Where Q the rate of flow, v velocity, k a
    constant known as Darcy's coefficient of
    permeability,
  • i hydraulic gradient, and A cross-sectional
    area for which flow can pass through. The
    equation can be rewritten as
  • v ki Q/A
  • Flow Velocity and Seepage Velocity If the
    hydraulic gradient, i, is unity, then the
    velocity, v, is equal to k. Also, v is called
    approach velocity or superficial velocity. The
    average effective velocity, vs, also known as
    seepage velocity of flow through the soil can be
    computed as
  • vs v/n
  • Where vs seepage velocity and n porosity

10
Source LaGrega et al. 2001, Hazardous Waste
Management, 2nd Edition, McGraw Hill
FIGURE 4-12 Flow lines and equipotentials.
11
4-4.
The groundwater contours are spaced at intervals
of about 50 m.
12
EXAMPLE 4-7. FLOW NET FOR A WATER TABLE AQUIFER.
13
FIGURE 4-13 Flow net for steady-state flow
through a homogeneous embankment.
14
Hydraulic Conductivity Measurement
  • Laboratory
  • Constant and Variable Head tests
  • Rigid wall vs. flexible wall tests
  • Consolidometers
  • Field
  • Groundwater
  • Pump tests-one well vs. time, several wells vs.
    distance
  • Slug tests
  • Compacted or Surface Soils
  • Lysimeters
  • Infiltrometers

15
Constant and Falling Head MethodsSee class
notes
16
Triaxial-Flexible Wall System
17
Saturated Zone
  • Darcys Law
  • Q vA KiA
  • Where
  • Q the rate of flow,
  • v discharge velocity,
  • K a constant known as Darcy's coefficient of
    permeability or hydraulic conductivity
  • i hydraulic gradient, and
  • A cross-sectional area for which flow can pass
    through. The equation can be rewritten as
  • v Ki Q/A

18
Constant Head Setup
Q K (h1-h2)/l A K i A Q V A v K i
Source LaGrega et al. 2001, Hazardous Waste
Management, 2nd Edition, McGraw Hill
19
Seepage Velocity
  • Seepage Velocity, vs v/n
  • Where
  • vs seepage velocity and
  • n porosity

20
Pipe Flow Example
21
Seepage Velocity Example
  • Given K 70 ft/day ( 2.5 x 10-2 cm/s)
  • n0.45
  • How long for a conservative tracer to travel from
    MW-1 to MW-2?

22
Seepage Velocity Example
  • How long for the center of mass of a conservative
    tracer to travel from MW-1 to MW-2?

MW-2
MW-1
166
180
23
Seepage Velocity Example
  • Vs Ki / n v / n distance / time
  • Distance is the actual flow path, not straight
    line distance

Right angle
24
Seepage Velocity Example
  • Assume measured distance along flow path is 6,
    or 600 feet in the field
  • i?H/L 180-166 / 600 14 / 600 0.023
  • Vs Ki / n (70 ft/day)(0.023) / 0.45 3.58
    ft/day
  • Vs distance / time Time distance / Vs
  • Time 600 ft / 3.58 ft/day 167.7 days

25
Determining Groundwater Direction and Hydraulic
Gradient
  • Simple three well system
  • Process
  • Identify groundwater elevation at three
    locations, in triangular fashion
  • Draw a line between the highest and lowest
    elevation
  • Identify point on the newly drawn line that
    corresponds to the elevation of the intermediate
    well

26
Determining Groundwater Direction and Hydraulic
Gradient
A
Well GW Elevation A 78.75 B 78.20 C 77.27
469 feet
B
533 feet
368 feet
C
Scale 1 100
27
Determining Groundwater Direction and Hydraulic
Gradient
A
GW Elev. 78.20
x
B
533 feet
Connecting point B to the point on the line AC
where the distance x is located creates an
equipotential line
C
Scale 1 100
28
Determining Groundwater Direction and Hydraulic
Gradient
Direction is computed as normal to equipotential
line If drawing is scaled, then distance can be
measured from equipotential line to Point C Lets
say that distance was measured at 200 feet Then
the hydraulic gradient, i?h/L(78.20-77.27) /
200 i0.0047
A
GW Elev. 78.20
B
C
Scale 1 100
29
Slug Test
Step 1 Identify monitoring well
Step 1 Insert slug (or bail out water)
Step 3 Record change in water versus time
30
Slug test Data
Assume Well screen (R) and well casing (r)
radius 2 in. 0.17 ft Assume length of well
(Le) screen 10 ft Hvorslev (1951) Method
31
Plot data
32
Plot semi-log
33
Use Equation
34
Chemical transport
  • Transport in coarse soils advection
  • Transport in fine-grained soils diffusion
  • Molecular diffusion
  • Net transport of molecules in a liquid or gas as
    a result of intermolecular collisions rather than
    turbulence or bulk transport, i.e., convection or
    mixing does not control it
  • Rate of diffusion controlled by nature of
    diffusing substance and properties of medium

35
Chemical TransportDiffusion in Soils
  • Reduced cross-sectional area (solids)
  • Tortuosity (Le/L)
  • Influence of electrical force fields
  • Retardation as a result of chemical reactions in
    fluid and media
  • Biodegradation (organics)
  • Effective Diffusion Coefficient
  • D ?aD0
  • ?a 0.01 to 0.5, accounts for porosity and
    tortuosity
  • Values for D0 typically on the order of 10-5
    cm2/s (in water)

36
Ficks First and Second Laws
  • First Law, JD D (?C/ ?L)A
  • Steady state conditions

100 Solute Concentration
Contaminant Free Flush
?L
?C
Concentration
Distance from source
37
Ficks First and Second Laws
  • Second Law
  • Unsteady state conditions

100 Solute Concentration
Contaminant Free Flush
?L
?C
Concentration
t1
t2
t3
Distance from source
38
Unsteady Diffusion Mass Transport
39
Sample Problem-Diffusion
Backfill Material
Ground Surface
Direction of Contaminant Plume
Clean Soil
C Co
C 0
Bedrock
40
Sample Problem Diffusion
  • Determine the time required for 25 of the source
    concentration to reach the other side of the
    slurry wall
  • Given
  • D 5 x 10-10 m2/s
  • x 90 cm

41
Sample Problem Diffusion
  • C/C0 0.25
  • erfc(B) 0.25
  • From table, B ? 0.80

42
Organization
  • Contaminant Barriers
  • Diffusion
  • Advection/Dispersion
  • Retardation/Distribution Coefficients

43
Advection-Dispersion
  • Dispersion includes the effects of molecular
    diffusion as well as velocity-induced mixing

44
Advection-Dispersion
Ogata and Banks (1961)
Short Form
C(x ? ?, t) 0
C(0, t) Co
C(x, 0) 0
45
Advection-Dispersion
  • Transport in compacted clay dominated by
    diffusion

46
Organization
  • Contaminant Barriers
  • Chemical Compatibility
  • Diffusion
  • Advection/Dispersion
  • Retardation/Distribution Coefficients

47
Advection-Dispersion
  • Include a new term
  • R Retardation coefficient
  • Mass transport across liners

48
Advection Dispersion
  • Retardation coefficient
  • Increase dry density or distribution coefficient
    to improve attenuation

49
Advection Dispersion
50
Advection-Dispersion
Ogata and Banks (1961)
Short Form
C(x ? ?, t) 0
C(0, t) Co
C(x, 0) 0
51
Laboratory Measurements
52
Traditional and Low-Cost Additives
53
Contaminant Transport
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