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Bernoulli

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Title: Bernoulli


1
Bernoulli
  • Bernoulli population is a population in which
    each element is one of two possibilities. The two
    possibilities are usually designed as success and
    failure.
  • The probability of success is p which means that
    the probability of failure
  • is 1-p.
  • A Bernoulli trial is observing one element in a
    Bernoulli population.

2
Example
  • Ex1. The toss of a coin results in a Bernoulli
    population.
  • Ex2. The homes in Dallas either heat with gas or
    not. Choices to heat with gas or not is a
    Bernoulli population.
  • Ex3. In a local election, the voters either
    favor a candidate for mayor or do not. The
    choices of voters result in a Bernoulli
    population.

3
Binomial experiment
  • A Binomial experiment is an experiment that
    consists of n repeated independent Bernoulli
    trials in which the probability of success on
    each trial is ? and the probability of failure
    on each trial is 1- ? .

4
Criteria for a Binomial Setting
  • 1.consists of n Bernoulli trials (each trial
    yields either S or F.
  • 2.For each trial, P(S) ? ,and P(F)1- ? .
  • 3.The trials are independent.
  • Ex1. The toss of a coin 3 times

5
binomial random variable.
  • The random variable x, which gives the number of
    success in the n trials of Bernoulli experiment,
    is called a binomial random variable. The sample
    space of x is
  • Sx 0, 1, 2, , n.
  • Ex1. The number of head after tossing a coin 10
    times.
  • The binomial random variable is a discrete random
    variable.

6
Question Are the following random variables
binomial random variable?
  • The number of getting head after flipping a coin
    10 times.
  • 40 of all airline pilot are over 40 years of
    age. The number of pilots who are over 40 out of
    15 randomly chosen pilots.
  • Suppose a salesperson makes sales to 20 of her
    customers, the number of customers until her
    first sale.
  • A room contains 6 women and four men, Three
    people are selected to form a committee. The
    number of women on the committee.

7
  • Suppose a couple plans to have 3 children. The
    chance they have a boy is 0.2. The gender of one
    child is independent of the gender of another
    child.
    Let X be the number of boys they have.

8
  • If the chance a child is a boy is 0.2, whats the
    chance a child is a girl?
  • How many gender sequences (i.e. BBB, BBG, BGG,
    etc) are possible?

9
We want to fill in the probability distributionn
below
P(X 0) P(all three are girls) P(GGG)
(0.8)3
P(X 3) P(all three are boys) P(BBB) (0.2)3
10
  • P(X 1)
  • P(only one boy)
  • P(GGB) P(GBG) P(BGG)
  • (0.8)2(0.2) (0.8)2(0.2)
  • (0.8)2(0.2)
  • 3 (0.8)2(0.2)

11
  • Similarly, P(X2) equals 3(0.2)2(0.8). Now we
  • can complete the probability distribution of X.

12
Binomial distribution
Probability of k successes out of n trials is
given by
where
13
  • Ex 50 of homes in Dallas are heated with gas.
    Let Y of homes out of 6 that are heated with
    gas.
  • The sample space of the value of y is
  • Sy 0, 1, 2, 3, 4, 5, 6
  • It is a Binomial random variable. What is the
    distribution of Y?

14
Solution
  • When n is very large, computing the probabilities
    becomes very tedious. In fact, We can use
    computer or binomial table to find out the
    probabilities for certain values of n, k and ? .
  • Look at table B.1 on Appendix B.

15
How the two parameters (n, ?) affect binomial
distribution?
  • Fix n, ? is more close to .5, the distribution
    is more near to a bell curve. If ? is more
    close to 0, the distribution is more skewed to
    the right. If ? is more close to 1, the
    distribution is more skewed to the left.

16
Fix n, let ? change
17
Fix ? , let n change
  • When the success probability ? on each trial is
    fixed and n is lager, the distribution is more
    close to a bell curve

18
Fix ? , let n change
19
mean and standard deviation
  • For binomial distribution
  • Meanµ n ?
  • Variances 2 n? (1- ? )
  • Standard deviation s

20
Example 4.25(page 274)
  • Suppose that the probability of successfully
    rehabilitating a convicted criminal in a penal
    institution is .4. Let r represent the number
    successfully rehabilitated out of a random sample
    of ten convicted criminal, find out the mean and
    the standard deviation of the variable r.

21
Example 4.13
  • 30 of homes in Dallas are heated with gas. Let
    Y of homes out of 6 that are heated with gas.
  • What is the probability of Y

22
  • 0 0.117649
  • 1 0.302526
  • 2 0.324135
  • P(Y

23
Probability of event in the Binomial case
  • Calculate the unknown probability of random
    variable y with n4 and ?.2
  • P(y2)
  • P(y
  • P(y2)
  • P(y3)
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