Differential Amplifiers and Integrated Circuit (IC) Amplifiers - PowerPoint PPT Presentation

About This Presentation
Title:

Differential Amplifiers and Integrated Circuit (IC) Amplifiers

Description:

Chapter 7 Differential Amplifiers and Integrated Circuit (IC) Amplifiers Chapter 7 Differential Amplifiers and Integrated Circuit (IC) Amplifiers Figure 7.46 Small ... – PowerPoint PPT presentation

Number of Views:138
Avg rating:3.0/5.0
Slides: 41
Provided by: dUmnEduh3
Learn more at: https://www.d.umn.edu
Category:

less

Transcript and Presenter's Notes

Title: Differential Amplifiers and Integrated Circuit (IC) Amplifiers


1
Chapter 7
  • Differential Amplifiers and Integrated Circuit
    (IC) Amplifiers

2
Discrete and Integrated Circuits
A discrete circuit is constructed of components
that are manufactured separately. Later, these
components are connected together, by conductors
like wires, in a circuit board or a printed
circuit board (PCB). On the other hand, in an
integrated circuit, the components and their
inter-connections are manufactured concurrently
by a sequence of processing steps. The types of
components that are available and their practical
values depend heavily on the approach taken for
implementation. (for example, the capacitors in
discrete circuits can be in the range of 1pF to
1F, but only 1pF to 100pF in ICs. Also, inductors
are almost impractical in ICs. But in ICs,
matching of components is much easier) See table
7.1 in page 412 for detail. Applications of
discrete circuits will persist especially for
some special circuits that are to be mass
produced, but today the bulk of electronic
systems are based on ICs. Processing steps in
manufacturing ICs incur cost and failures and are
usually different for different technologies. BJT
technology are used more for high-quality analog
circuits, while MOS are more for general analog
circuits and digital circuits. Today,
semiconductor industry can manufacture both BJT
and MOS on the same chip, called BiCMOS
technology.
3
DC biasing for Integrated Circuits
Different from biasing of discrete circuits,
resistors and capacitors are expensive in terms
of cost and chip area, are therefore avoided
whenever possible. For amplifier circuits, the
BJT transistors operate in active region. The
following circuits show how matched transistors,
when combined with a few resistors, can act as
current sources that are useful in biasing IC
amplifiers. Collector of Q1 is connected to its
base. Thus , and
Q1 is in the active region. If is larger
than 0.2V, Q2 is also in the active region.
See page 415-416, it can be shown that
Figure 7.1 The current mirror.
4
DC biasing for Integrated Circuits II
To a first-order approximation, the base current
of Q2 is independent of the output voltage
, therefore the output characteristics is almost
identical to one of the collector characteristic
curves for Q2. An important specification of a
current source is the range of output voltage for
which the output current is approximately
constant, which is called compliance range.
Another important specification of a current
source is its dynamic output resistance, which is
the ratio of the incremental voltage divided by
the incremental output current (ideally it should
be infinite). In small-signal equivalent
circuit, the current source is replaced by its
dynamic resistance.
Figure 7.1 The current mirror.
5
Biasing an Emitter Follower
An example of how the current mirror can help
establish the bias point of an IC amplifier is
shown below. The current source is formed by R,
Q1 and Q2, while Q3 is an emitter follower
amplifying the input signal and delivering it to
the load. Often, we can simplify the circuit
diagram as in Figure7.2(b).
Note (1) the amplifier is direct-coupled
compared to AC-coupling in discrete
amplifiers (2) Output voltage is -0.7V for input
voltage of zero. In this case, the circuit
displays a DC offset, which is not desirable.
This problem can be solved or reduced by the
circuit shown in the next slide.
Figure 7.2 Emitter follower with bias current
source.
6
Biasing an Emitter Follower reducing offset
A simple way to reduce offset for this follower
is to cascade a second stage consisting of a pnp
emitter follower as shown in the figure below.
Note that in discrete circuits, offset is not an
issue as a coupling capacitor is used.
Figure 7.3 The offset voltage can be reduced by
cascading a complementary (pnp) emitter follower.
7
Effects of transistor area on current mirror
Doubling the area of a transistor is the same as
connecting two of the original transistors in
parallel, as shown in the Figure 7.4. The output
current of a current mirror for which the
relative junction areas of the transistors are A1
and A2 is given by Study example 7.1 in page
418.
Figure 7.4 Doubling the junction area of a BJT
is equivalent to connecting two of the original
BJTs in parallel.
Figure 7.5 Current mirror for Examples 7.1.
Figure 7.9 Collector characteristic of Q2,
illustrating the Early voltage.
8
Figure 7.7 Output characteristic for the
current mirror of Figure 7.5.
Figure 7.8 Dynamic output resistance of the
current mirror of Figure 7.5.
9
The Wilson current source
An improved circuit, called Wilson current
source, with higher output impedance that the
previous current mirror is shown in the Figure.
For the Wilson current source, the following
holds A1, A3 are the relative junction areas
of the Q1 and Q3 respectively. (see page 421)
Figure 7.10 The Wilson current source, which
has a high output resistance.
10
The Widlar current source
When the desired current is small, the Widlar
current source may be a better alternative, as
shown in the Figure. For Widlar current source,
the following holds (see page 422) See
example 7.3 in page 423.
Figure 7.11 The Widlar current source, which is
useful for small currents.
11
The combined current sources
In an Integrated Circuit amplifier, several
current sources use the same reference current,
as shown below. The current through R1 is the
reference current for all four current sources.
Q1, Q2 forms a current mirror, and Q1, Q3 forms a
Widlar source. Notice the pnp current source by
Q4, Q5 and Q6.
Figure 7.12 Typical biasing circuit for a
bipolar IC.
12
IC biasing with MOSFET
The BJT current sources have counterparts
constructed with MOSFET. The shown MOSFET current
mirror is very similar to the BJT current
mirror. In typically cases, the MOSFET M1
operates in saturation region, as drain-to-gate
voltage is zero. Assuming the transistors are
identical and that the output voltage is large
enough so that M2 is in saturation as well. The
current By using devices with different W/L
ratios, circuits having output current equal to a
predetermined constant times reference current
can be designed.
Figure 7.15 NMOS current mirror.
13
IC biasing with MOSFET
An improved current source is shown below, which
has higher output resistance than the simple
current mirror. The output current is related to
the reference current by the equation below as
well (assuming the transistors operating in
saturation region) The reference current I1
may be approximated by
Figure 7.16 NMOS Wilson current source.
14
Emitter-coupled differential pair
The emitter-coupled differential pair is a very
important circuit that is used many bipolar
analog integrate circuits. The circuit is shown
in the figure and the two transistors are assumed
identical. The current source IEE is typically
implemented as a current source circuit discussed
before (eg. Current mirror, wilson current
source). The input voltages vi1 and vi2 can be
considered to be composed of a differential
signal vid and a common mode signal vicm defined
below Differential output voltage is defined as

Figure 7.22 Basic BJT differentiial amplifier.
15
Emitter-coupled differential pair II
First, consider the two input signal vi1 and vi2
are equal. Then the differential input voltage
vid is 0 and we have a pure common-mode input
signal. In this case, the current IEE splits
equally between the Q1 and Q2, therefore
vod0. In other words, the circuit does not
respond to the common-mode component of the input.
Figure 7.23a Basic BJT differential amplifier
with waveforms.
16
Emitter-coupled differential pair III
For a pure differential input (when vicm0), it
can be shown the a non-zero differential output
voltage vod is resulted, as a differential input
signal steers IEE twoard one side or the
other. In summary, the circuits rejects
common-mode input and responds to the
differential input. In amplifiers, a small
differential input signal is amplified to a
differential output signal.
Figure 7.23b Basic BJT differential amplifier
with waveforms.
17
Emitter-coupled differential pair pnp version
Figure 7.24 pnp emitter-coupled pair.
18
Signal transfer characteristics I
See page 437 for derivation of the collector
current for the emitter-coupled differential
pair. The following collector current versus
differential input voltage can be
obtained. Note that in the plot, when vid0,
ic1ic2. For vidgt5VT, the current is steered
almost entirely through Q1 and similarly when
vidlt-5VT, the current is entirely through Q2.
Figure 7.25 Collector currents versus
differential input voltage.
19
Signal transfer characteristics II
Using the previous equation of
, one can find A plot of this
transfer characteristics is shown in the
following figure. The curvature Shows that the
differential amplifier can distort a signal if
the amplitude is too large. For input voltage
less VT, the characteristics is quite straight
giving linear gain.
Figure 7.26 Voltage transfer characteristic of
the BJT differential amplifier.
20
Emitter degeneration
Sometimes it is advantageous to add emitter
generation resistor REF to the circuit, as shown
in the Figure. There resistors have the
disadvantage of reducing the differential voltage
gain of the circuit. However, two reasons for
this is to increase input impedance and to reduce
distortion due to the nonlinearity of the
BJTs. The right figure shows the transfer
characteristic of the differential amplifier
(REF40VT/IEE).
Figure 7.27 Differential amplifier with emitter
degeneration resistors.
Figure 7.28 Voltage transfer characteristic with
emitter degeneration resistors. REF
40(VT/IEE).
21
Balanced versus single-ended outputs
The output of a differential amplifier can be
balanced, in which case the output voltages from
both collectors are connected to the inputs of
another differential amplifier. On the other
hand, the output can be taken from one collector,
in which case we say the output is single-ended.
If a single-ended output is desired, there is no
need for a resistor in the collector of the other
resistor. (resistor at collector of Q1 omitted as
shown).
Figure 7.29 Either a balanced or single-ended
output is available\break from the differential
amplifier.
22
The current mirror as a load
The following figure shows a variation of the
emitter-coupled pair in which the collector
resistors are replaced by a current mirror. This
circuit is particularly favored in ICs, as
transistors are much cheaper than resistors. A
simple analysis by assuming large so that
base currents of Q3 and Q4 are neglected, results
in the equation as follows For
is approximately proportional to vid. Notice
furthermore that the common-mode input component
does not affect the output current.
Figure 7.30 Emitter-coupled pair with
current-mirror load.
23
Small-signal analysis of the Emitter-coupled
differential pairc
Using small-signal analysis, we can derive
expressions for voltage gain, input impedance and
output impedance of the emitter-coupled
differential pair. The small-signal equivalent
circuit for the differential pair is shown below
by replacing the transistors by their
small-signal models.
Note that power supply has been shorted to GND in
small-signal circuit. Also note that the IEE
current source is replaced by a resistance REB in
the small-signal circuit, as practical current
sources has a finite output impedance.
Figure 7.33 Small-signal equivalent circuit for
the differential amplifier of Figure 7.27. (REB
is the output impedance of the current source
IEE.)
24
Small-signal analysis differential input
First, we analyze the circuit for a pure
differential input signal. Therefore the input
voltage are vi1-vi2vid/2. The analysis can be
simplified by observing that the equivalent
circuit is symmetrical. Due to this symmetry and
opposite polarity of the independent sources, the
voltage at point J is zero. The circuit behavior
would not change by shorting point J to Ground.
We can then consider only the left-hand side
circuit as shown in the Figure. We need to
analyze only this half circuit as the right half
is the same except different polarity.
Figure 7.34 Half-circuit for a differential
input signal.
25
Small-signal analysis differential input II
The half circuit, we then find out the gain and
input impedance Notice that we have defined Rid
as the ratio of the entire differential voltage
vid to the input current. Thus, Rid is the input
impedance between the input terminals of the
complete circuit. The voltage gain is For
output impedance, we have
Figure 7.34 Half-circuit for a differential
input signal.
26
Small-signal analysis common-mode input
When the input voltage are vi1vi2vicm, the
equivalent circuit is depicted in the figure. We
have shown the output impedance of the current
source as the parallel combination of two
resistors. The equivalent circuit is symmetrical
with respect to the dashed line including the
polarities of the signal sources. Therefore, we
conclude that current iJ must be zero. As such,
we can open the connection and consider only left
or right hand half circuit.
Figure 7.35 Small-signal equivalent circuit with
a pure common-mode input signal.
27
Small-signal analysis common-mode input
From the half circuit, we can then compute the
gain, input impedance and output
impedance. Note that we have defined the
common-mode input impedance to be the voltage
divided by the total current the source must
deliver to both terminals. The gain from a
single-ended load to common-mode input is As
vo1vo2vocm. For output impedance, we have
Figure 7.36 Half-circuit for a pure common-mode
input signal.
28
Small-signal analysis CMRR
In amplifier circuits, it is often desirable to
reject common-mode signal while amplifying the
differential signal. A measure of how well the
amplifier rejects the common-mode signal relative
to the differential signal is the common-mode
rejection ratio (CMRR). By definition, the CMRR
is ratio of the gain for the differential signal
to the gain for common-mode signal. From results
of previous results, the CMRR for the
single-ended output and balanced output can be
defined respectively as follows It can be
seen that CMRR is nearly independent of . To
increase CMRR, it is desired to select a larger
value for REB and a small REF.
29
Amplifier design how to increase input impedance?
Figure 7.38 Addition of emitter followers to
increase input impedance.
30
An design example for high CMRR
Figure 7.40 Differential amplifier of
Example7.4 using the Wilson current source.
Figure 7.39 First attempt in Example 7.4.
31
Figure 7.42a Waveforms for the differential
amplifier of Example 7.4.
32
The source-coupled differential pair
Using MOSFET, we can construct an source-coupled
differential pair, which is a counterpart of the
emitter-coupled differential pair using BJTs. The
main advantage of using MOSFET for a differential
pair compared to BJTs is the nearly infinite
input impedance, while the disadvantage is lower
gain magnitude.
Figure 7.43 Source-coupled differential
amplifier.
33
The source-coupled differential pair II
Assuming the two MOSFETs are the same. The
analysis of the source-coupled differential pair
proceeds in the same way as the emitter-coupled
differential pair for both common-mode signal and
differential input signal. The transfer
characteristics for drain current Id1 and Id2 are
shown in the figure.
Figure 7.45 Differential output voltage versus
normalized input voltage.
Figure 7.44 Drain currents versus normalized
input voltage.
34
The source-coupled differential pair III
The small-signal equivalent circuit fir the
source coupled differential pair is shown in the
figure. The power supply is replaced by a short
circuit and the resistance RSB represents the
output impedance of the bias current source. The
circuit can be analyzed for differential and
common-mode input signal in almost the same way
as the emitter-coupled differential pair
discussed before. Refer to results in Table 7.3
in page 462.
Figure 7.46 Small-signal equivalent circuit for
the source-coupled amplifier of Figure
7.43. (Note RSB is the output resistance of the
bias current source I.)
35
An example of IC amplifier MOS
The advantage of the amplifier is that it can be
fabricated on the same chip as CMOS logic
circuits. The PMOS M8, M1 and M2 form a dual
current mirror that supplies bias currents to the
amplifier stages. The resistor Rset is selected
to yield the desired reference current. The
input stage consists of transistors M3 and M4,
which forms a source-coupled differential pair.
Note that Q-point currents on M3 and M4 are
approximately equal to Iset. Transistors M5 and
M6 form a current mirror load for the input
stage. Transistor M7 is a common-source
amplifier and M2 acts like a active load.
Figure 7.49 CMOS op amp.
36
An example of IC amplifier II MOS
The small-signal equivalent circuit for the
output stage is shown below. Note that the in
the model we treated the Ccomp as a open circuit
and included the drain-source small-signal
resistance rd. Transistor M2 forms the output
device of the a current mirror and its
gate-to-source voltage is pure DC with no signal
component. In other words, the small signal
vgs20, therefore the current source id2gm2vgs2
is zero as well. Then we obtain
Figure 7.50 Small-signal equivalent circuit for
the output stage consisting of M7 and M2.
37
An example of IC amplifier III MOS
Next, we need to analyze the source-coupled pair
to find its differential voltage gain. The
small-signal equivalent circuit is shown below.
Note that source terminals of M3 and M4 are
connected to ground as the circuit is
symmetrical. Assuming the current on the
small-signal rd resistors are small compared to
the current source, we can derive the following
(refer to page 467-468)
Figure 7.50 Small-signal equivalent circuit for
the output stage consisting of M7 and M2.
38
Figure 7.53 Open-loop gain versus frequency for
the CMOS op amp.
39
An example of IC amplifier BJT
Q1, Q2 form a differential amplifier balanced
outputs, Q3, Q4 form a differential amplifier
with single-ended outputs, Q5 is a pnp emitter
amplifier an emitter resistance R6, Q6 is an
emitter follower, and finally Q7, Q8, Q9 form a
double current mirror.
Figure 7.55 A BJT op amp.
40
Equivalent circuit for the first stage of Figure
7.55.
Figure 7.56 REB represents the output impedance
of current sink Q8. Ri is the
differential input impedance of the second stage.
Write a Comment
User Comments (0)
About PowerShow.com