Ionic Bonds and Some MainGroup Chemistry - PowerPoint PPT Presentation

1 / 31
About This Presentation
Title:

Ionic Bonds and Some MainGroup Chemistry

Description:

Main group elements tend to lose the same # of electrons as their group number ... energy required by 1 mole of gaseous atoms for 1 mole of electrons to be ejected. ... – PowerPoint PPT presentation

Number of Views:161
Avg rating:3.0/5.0
Slides: 32
Provided by: faithya
Category:

less

Transcript and Presenter's Notes

Title: Ionic Bonds and Some MainGroup Chemistry


1
Chapter 6
  • Ionic Bonds and Some Main-Group Chemistry

2
Ions and Their Electron Configurations
  • Chapter 2
  • Metals lose electrons to form cations
  • Main group elements tend to lose the same of
    electrons as their group number
  • Nonmetals when combined with metals gain
    electrons to form anions
  • The number gained 8 group
  • WHY???????

3
Ions and Their Electron Configurations
  • Main Group Elements - the number of electrons
    gained or lost the number of electrons
    necessary to obtain the nearest noble gas or
    pseudo-noble gas configuration (filled
    d-orbital).
  • Main group metal the electrons lost often
    of valence electrons
  • Nonmetal the electrons gained of
    electrons necessary to achieve 8 in the valence
    shell
  • Na, Ne, Na O, Ne, O2-
  • K, Ar, K Cl, Ar, Cl-
  • Ga, Ga3 Sn, Sn4

4
Ions and Their Electron Configurations
  • Transition element ions formed by
  • 1st losing their valence electrons
  • 2nd losing d-orbital electrons to obtain the
    charge
  • Fe2 Fe3 Co2 Co4
  • Ag Zn2

5
Problem
  • Select the correct set of quantum numbers (n, l,
    ml, ms) for the first electron removed in the
    formation of a cation for strontium, Sr. 
  • A.  5, 1 , 0, -½
  • B.  5, 1, 0, ½
  • C.  5, 0, 1, ½
  • D.  5, 1, 1, ½
  • E.  5, 0, 0, -½

6
Ionic Radii
  • Effect of charge on ionic radii evaluated using
    atomic size and Zeff
  • Atomic size increases with increasing energy
    levels
  • Zeff
  • Cation more protons than electrons stronger
    attraction
  • Anion less protons than electrons weaker
    attraction
  • Cation lt Neutral atom lt anion

7
Ionic Radii
8
Ionization Energy
  • Ionization Energy (Ei) the energy required by 1
    mole of gaseous atoms for 1 mole of electrons to
    be ejected.
  • Na EI Na e-
  • Energy necessary to make a cation
  • More energy required for smaller atoms

9
Ionization Energy
10
Ionization Energy Trend
  • Increases across a period held tighter
  • Decreases down a group larger (n)

11
Higher Ionization Energies
  • Ionization energy not limited to a single
    electron
  • 2nd electron removed requires even more energy
  • Removal of first leads to more protons than
    electrons
  • To break into a noble gas configuration requires
    a lot of energy because of their stability

12
Problem
  • Which one of the following equations correctly
    represents the process relating to the ionization
    energy of X? 
  • A.  X(s) ? X(g) e-
  • B.  X2(g) ? X(g) X-(g)
  • C.  X(g) e- ? X-(g)
  • D.  X-(g) ? X(g) e-
  • E.  X(g) ? X(g) e-

13
Problem
  • Which of the following elements has the smallest
    first ionization energy? 
  • A.  Rb
  • B.  Mg
  • C.  I
  • D.  As
  • E.  F

14
Problem
  • Which of the following elements has the largest
    second ionization energy (IE2)? 
  • A.  Li
  • B.  B
  • C.  O
  • D.  F
  • E.  Na

15
Electron Affinity
  • Electron Affinity (Eea) - Describes the energy
    associated with the absorption of 1 mole of
    electrons by 1 mole of gaseous atoms
  • Cl e- Cl-
  • Can be positive or negative
  • Positive energy had to be added to force the
    atom to absorb the electron (non-favored)
  • Negative energy was given off when the electron
    was added to the atom (favored)

16
Electron Affinity
17
Electron Affinity
  • Trend
  • Eea becomes more negative across a period
  • Eea becomes more positive down a group
  • Larger atoms dont care as much

18
Problem
  • Which one of the following equations correctly
    represents the process involved in the electron
    affinity of X? 
  • A.  X(g) ? X(g) e-
  • B.  X(g) ? X(aq)
  • C.  X(g) e- ? X(g)
  • D.  X(g) e- ? X-(g)
  • E.  X(g) Y-(g) ? XY(s)

19
Problem
  • Select the element with the most negative
    electron affinity (i.e., accepts an electron most
    readily). 
  • A.  H
  • B.  Li
  • C.  C
  • D.  F
  • E.  Ne

20
Ionic Bonds and the Formation of Ionic Solids
  • Ionic bonds
  • Form when an element with a small Ei value comes
    in contact with an element with a negative Eea
    value.

21
Ionic Bonds and the Formation of Ionic Solids
  • The energetics of ionic reactions can be viewed
    on a BornHaber Cycle which shows how each step
    contributes to the overall reaction energy.
  • That energy is called the lattice energy (U) of
    the solid. By convention, the lattice energy
    refers to the breakup of the crystal into ions.

22
Ionic Bonds and the Formation of Ionic Solids
BornHaber Cycle for NaCl
23
Ionic Solids and the Formation of Ionic Compounds
BornHaber Cycle for MgCl2
24
Ionic Bonds and the Formation of Ionic Solids
  • Calculate the lattice energy (in kJ/mol) for the
    formation of CaH2 from its elements.
  • Calculate the overall energy change (in kJ/mol)
    for the formation of CaCl from its elements.
  • Calculate the overall energy change (in kJ/mol)
    for the formation of CaCl2 from its elements.
  • Which is more likely to form, CaCl or CaCl2?

25
Ionic Bonds and the Formation of Ionic Solids
  • Trends in Lattice Energy
  • Increases with increasing charge
  • Increases with decreasing ion size

26
The Octet Rule
  • General Conclusions
  • Group 1A form 1 by losing ns1 electron to obtain
    noble gas configuration
  • Group 2A form 2 by losing ns2 electrons to
    obtain noble gas configuration
  • Group 3A tend to form 3 by losing ns2np1
    electrons to obtain noble gas configuration
  • Group 7A gain 1 electron to form ns2np6 hence
    giving them a noble gas configuration
  • Group 8A neither gain nor lose electrons because
    of stability of configuration

27
The Octet Rule
  • Octet Rule main group elements tend to undergo
    reactions that leave them with 8 outer shell
    electrons
  • Why does the rule work?

28
The Octet Rule
  • Electrons of metals are most likely lost due to
    the fact that
  • core electrons are shielding them from the
    nucleus
  • Zeff is lower
  • Small ionization energies
  • Upon loss they obtain noble gas configuration

29
The Octet Rule
  • Nonmetals are most likely to gain electrons due
    to the fact that
  • no additional shielding occurs from the nucleus
    occurs due to core electrons
  • Zeff is higher
  • More negative electron affinities
  • Upon gain they obtain noble gas configuration

30
Optional Homework
  • Text 6.30, 6.36, 6.38, 6.40, 6.42, 6.44, 6.46,
    6.48, 6.58, 6.64, 6.66
  • Chapter 6 Homework

31
Required Homework
  • Assignment 6
Write a Comment
User Comments (0)
About PowerShow.com