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Real Networkers don

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11011110 00100001 00000100 00000000 is a Class C network ... Class A: 8 network bits, 24 host bits, starts 0... 00101100 01111011 10101100 01111011 ... – PowerPoint PPT presentation

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Title: Real Networkers don


1
Real Networkers dont use Decimal! Part 1.
  • Binary Interpreting IP Addresses
  • October 19, 2004

2
Understanding Binary
  • Computers, networks and network addressing
    schemes use the binary number system.
  • Number systems are based on powers of the base
    number.
  • Binary is based on powers of 2.
  • The powers of 2 table is a powerful tool for
    network designers.

3
Counting in Binary
  • 0
  • 1
  • 10
  • 11
  • 100
  • 101
  • 110
  • 111
  • 1000
  • 1001
  • 1010
  • 1011
  • 1100
  • 1101
  • 1110
  • 1111

4
Powers of 2
2POWER Example 23 8 decimal 1000
binary Notice 3 zeros.
5
Powers of 2, continued
32 0s
6
Conversion from Binary to Decimal
  • Decimal value is determined by the total value of
    bits.
  • Each bit position value is some power of 2

7
Conversion sample 1
  • 1101101101
  • Add the value of each bit position containing a
    one.
  • 512 256 64 32 8 4 1 877

8
Conversion sample 2
  • 11011011011101101101
  • Add the value of each bit position containing a
    one.
  • 524288 262144 65536 32768 8192 4096
    1024 512 256 64 32 8 4 1 898,925

9
Key Points of IP addressing
  • 32 bits addressing allows 4,294,967,295 possible
    addresses.
  • Not feasible to keep track of 4.3 trillion routes
    to individual hosts.
  • Separating the address into Network Bits and Host
    bits allows a single network address to summarize
    information for many hosts. 001011000111101110101
    10001111011

Network Bits
Host bits
10
Identifying networks
  • A network address represents a way to connect to
    many hosts.
  • One Class A network address connects 16,777,215
    hosts
  • One Class C network connects 255 hosts.
  • Network addresses are identified by setting the
    host bits to 0 in an IP Address.
  • 11011110 00100001 00000100 00000000 is a Class C
    network
  • 11011110 00100001 00000100 00100100 is a host on
    that network

11
Three types of IP addresses
  • Network Address Host bits all 0s
  • Broadcast Address Host bits all 1s
  • Host Address at least one 0 one 1
  • 11011110 00100001 00000100 00000000 is a network
    address.
  • 11011110 00100001 00000100 11111111 is the
    broadcast address for that network.
  • 11011110 00100001 00000100 00100100 is a host
    address on that network.

All 0s
All 1s
12
Address Ranges
  • 32 bits on every device
  • 10101100 01111011 10101100 01111011
  • Class A 8 network bits, 24 host bits, starts
    0
  • 00101100 01111011 10101100 01111011
  • Class B 16 network bits, 16 host bits, starts
    10
  • 10101100 01111011 10101100 01111011
  • Class C 24 network bits, 8 host bits, starts
    110
  • 11001100 01111011 10101100 01111011

Does this address identify a host or a network?
13
Address Ranges
  • Class D Multicast, starts 1110
  • 11100110 01111011 10101100 01111011
  • 224.0.0.5 and 224.0.0.6 are used by OSPF
  • Class E Reserved, starts 1111
  • 11110100 01111011 10101100 01111011
  • Classes D E are not important in CCNA1.

14
Address Ranges in Decimal
15
Special Address Ranges
16
Notation Scheme
  • IP 32 bit binary number for all addresses.
  • 10101100011110111010110001111011
  • Reading and writing 32 bits of binary is too
    hard!
  • Converting all 32 bits to Decimal is too tedious
  • Break 32 bits into 4 groups of 8 bits called
    octets
  • Dotted Decimal notation converts octets to
    decimal
  • A notation scheme is merely a way of representing
    the bits in an address, it is for convenience
    networking is based on the bits not the notation!

17
Sample Address in bits
  • Without breaking it down into octets
  • 10101100011110110010110001111000
  • 2,893,753,464 too hard to do correctly

18
Sample Address, dotted decimal
  • Same address using octets
  • 10101100.01111011.00101100.01111000
  • easy to add up each octet
  • 128 32 8 4 ? 64 32 16 8 2 1
    ? 32 8 4 ? 64 32 16 8
  • 172.123.44.120 in dotted decimal notation

19
Sample Address Network Host Bits
  • Begins 10 so it is a Class B address with the
    first 16 bits representing the network.
  • 10101100.01111011.00101100.01111000
  • 172.123.44.120 in dotted decimal.
  • This is the 00101100.01111000 host on the
    10101100.01111011 network.

20
Subnetting begins!
  • In A, B, C networks, boundary between network
    and host bits always on an octet boundary.
  • 10101100.01111011.00101100.01111000
  • Subnetting some host bits are converted to
    subnet bits.
  • 10101100.01111011.00101100.01111000
  • 172.123.44.120
  • One octet may have both subnet host bits.

21
How many subnets?
  • 10101100 01111011 00100000 00000000 has three
    subnet bits.
  • Represents just one subnet.
  • When 3 bits are used for subnetting, how many
    possible subnets may be created? Lets list them.
  • 8 subnets

22
Possible subnets in Binary
  • 3 bits are borrowed in a Class B network
  • SN 0 10101100 01111011 000 00000 00000000
  • SN 1 10101100 01111011 001 00000 00000000
  • SN 2 10101100 01111011 010 00000 00000000
  • SN 3 10101100 01111011 011 00000 00000000
  • SN 4 10101100 01111011 100 00000 00000000
  • SN 5 10101100 01111011 101 00000 00000000
  • SN 6 10101100 01111011 110 00000 00000000
  • SN 7 10101100 01111011 111 00000 00000000

23
Possible subnets in Dotted Decimal
  • 3 bits are borrowed from a class B network
  • SN 0 172.123.0.0
  • SN 1 172.123.32.0
  • SN 2 172.123.64.0
  • SN 3 172.123.96.0
  • SN 4 172.123.128.0
  • SN 5 172.123.160.0
  • SN 6 172.123.192.0
  • SN 7 172.123.224.0

24
Some Addresses on a Subnet
  • 10101100 01111011 00100000 00000001
    (172.123.32.1) and
  • 10101100 01111011 00100010 00000000
    (172.123.34.0) are both hosts on the
  • 10101100 01111011 00100000 00000000 (172.123.32.0
    ) network.

What address type is 10101100 01111011 01100010
00000000 (172.123.98.0) ?
25
The Formula!
  • 3 bits can provide for 8 possible subnets, 4 bits
    can provide for 16 possible subnets.
  • What is the rule?
  • of Possible Subnets 2Number of subnet bits

26
Why a mask is necessary
  • A 32 bit address may be interpreted many ways.
  • 10101100 01111011 00101100 01111000
  • 172.123.44.120/16 (no subnet)
  • 10101100 01111011 00101100 01111000
  • 172.123.44.120/19 (subnetted using 3 bits)
  • 10101100 01111011 00101100 01111000
  • 172.123.44.120/21 (subnetted using 5 bits)
  • IP address is meaningless without a mask!

27
Masking
  • Subnet mask every network bit is 1 and every
    host bit is 0.
  • Binary Address 10101100.01111011.00101100.0111100
    0
  • Binary Mask 11111111.11111111.00000000.00000000
  • Dotted Decimal Address 172.123.44.120
  • Dotted Decimal Mask 255.255.0.0
  • This is the default mask of a class B network.

28
Masking a 3 bit Subnet
  • Network, Subnet, Host Bits
  • Binary Address 10101100 01111011 00101100
    01111000
  • Binary Mask 11111111.11111111.11100000.00000000
  • Prefix
  • 11111111.11111111.111
  • count 1s 19
  • Dotted Decimal Address 172.123.44.120
  • Dotted Decimal Mask 255.255.224.0
  • Prefix /19

The mask does not distinguish between network and
subnetwork bits!
29
Masking a 4 bit Subnet
  • Network, Subnet, Host Bits
  • Binary Address 10101100 01111011 00101100
    01111000
  • Binary Mask 11111111.11111111.11110000.00000000
  • Dotted Decimal Address 172.123.44.120
  • Dotted Decimal Mask 255.255.240.0
    Prefix /_ _
  • Only 9 possible mask values
  • 0, 128, 192, 224, 240, 248, 252, 254 and 255

30
How many subnet bits?
  • A mask has only network and host bits.
  • The number of subnet bits must be calculated.
  • Number of subnet bits
  • Number of actual mask network bits
  • Number of default (class) mask network bits

31
Example Subnet bits calculation.
  • Address 172.123.44.120 10101100 01111011
    00101100 01111000
  • Mask 255.255.240.0 or /20 11111111.11111111.11110
    000.00000000
  • Address begins 10 so it is a Class B address
    which has a /16 default mask.
  • 20 mask bits 16 default mask bits
  • 4 subnet bits

32
How a Mask works.
  • The IP address and the mask are ANDed to
    determine the network address.
  • 0 AND 0 0
  • 0 AND 1 0
  • 1 AND 0 0
  • 1 AND 1 1
  • The mask acts as a filter which keeps only the
    network bits, sets all others to 0.

33
Sample Mask Application
  • What is the network address of
  • Address 172.123.44.120 10101100 01111011
    00101100 01111000
  • Mask 255.255.240.0 or /20 11111111.11111111.1111
    0000.00000000
  • Apply the mask
  • 10101100 01111011 00101100 0111100011111111.1111
    1111.11110000.0000000010101100 01111011 00100000
    00000000
  • Network Address 172.123.32.0

AND
34
Determining the Broadcast Address for a network
  • Start with a network address and mask
  • 10101100 01111011 00100000 00000000
    (172.123.32.0)
  • 11111111.11111111.11110000.00000000
    (255.255.240.0)
  • Apply the mask network bits remain unchanged!
  • 10101100 01111011 0010
  • Set all host bits to 1s
  • 1111 11111111
  • Put them together and you have the broadcast
    address
  • 10101100 01111011 00101111 11111111
  • 172.23.47.255 is the broadcast address for the
    172.123.32.0 /20 network

35
Interpreting IP Addresses
  • To get the network address from a specific host
    address and mask.
  • Convert Address and Mask to binary
  • AND the Address and Mask to get the Network
    Address
  • Convert the Network Address to decimal

36
Determining a Broadcast address
  • To get the broadcast address from a specific
    network address and mask.
  • Convert Network Address and Mask to binary
  • Use the Mask to identify the network and host
    bits
  • Copy the network bits from the Network Address
    and make the remaining host bits all 1s.
  • Convert to dotted decimal.

37
HAPPY NETWORKING!
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