Title: Industrial Ventilation vs. IAQ
1Industrial Ventilation vs. IAQ
Heating Ventilation Air Conditioning
2Industrial Ventilation vs. IAQ
24
3Industrial Ventilation vs. IAQ
4Industrial Ventilation vs. IAQ
5Routes of Entry
- Inhalation
- Ingestion
- Absorption
- Injection
6Control Options
- Process change
- Substitution
- Isolation
- Ventilation
- Administrative control
- Personal protective equipment
7Problem Characterization
AIRFLOW
EMISSION SOURCE
BURTON 2-1
8Burton Ex. 2-1
- GROUP EXERCISE
- Study the figure on page 2-4 and discuss
potential control measures that you might use to
correct the problem.
BURTON 2-4
9THE BEHAVIOR OF AIR
10The Atmosphere
- Reaches 50 miles into space.
- Pressure 14.7 pounds per square inch.
11Composition of Air
12Pressure Measurement
Vacuum
Atmospheric Pressure 14.7 psia
13Pressure Measurement
14.7 psia 407in. Water
14.7 psia 29.92 in. Mercury (Hg.)
14How Do We Make Air Move ?
15Pressure
- Differences in air pressure cause movement.
16Pressure Differential Causes Movement
FLOW
LOW
HIGH
FAN
BURTON 3-6
17Negative Pressure Less Than Atmospheric
18Positive Pressure Greater Than Atmospheric
19Pressure Relationships
20Pressure Terms
- Static Pressure
- Velocity Pressure
- Total Pressure
21Static Pressure
Flow
SP
Static pressure (SP) is exerted in all directions.
22Velocity Pressure
Flow
SP
VP
Velocity Pressure (VP) is kinetic (moving
pressure) resulting from air flow.
23Total Pressure
Flow
SP
VP
TP
Total pressure (TP) is the algebraic sum of the
VP and SP.
24Pressure Upstream and Downstream of the Fan
- TP SP VP
- Up-stream - -
- Down-stream
BURTON 3-8
25What is use of the term Velocity Pressure ?
- Determine the air flow.
- To design the system.
- V 4005(VP)1/2
26What is use of the term Static Pressure ?
- Accelerate the air.
- Overcome resistance to friction.
27Static Pressure and Velocity Pressure are
Mutually Convertible
When air is accelerated, the static pressure is
converted to velocity pressure.
When air is decelerated, the velocity pressure
can be transformed back into static pressure.
28Conservation of Mass
- Mass in Mass out.
- Air speeds up when the duct area is smaller.
Q VA Q Cubic Feet Per Minute V Velocity A
Area
29Dilution Ventilation
- YES
- non-hazardous
- gas, vapor, respirable particle
- uniform time emission
- emissions not close to people
- moderate climate
- NO
- toxic material
- large particulate
- emission varies widely over time
- large, point source emissions
- people in vicinity
- severe climate
- irritation or complaints
BURTON 4-1
30Volume Vapor Flow Rate
BURTON 4-3
31Estimating Dilution Air Volume
BURTON 4-5
32Poor Dilution
33Good Dilution
34Example 4-1
- What is q, the volume flow rate of vapor
formed, if 0.5 gallons of toluene are evaporated
uniformly over an 8-hr. shift? What volume flow
rate Qd is required for dilution to 10 ppm, if
Kmixing 2 ? (Assume STP d 1.0) - What is the average face velocity of air in a
room 10ft. 8ft. 40ft for these conditions?
BURTON 4-6
35Strategy Ex. 4-2
- Step 1 Calculate the volume flow rate of the
vapor - emitted q.
- q (387 lbs. evaporated)/ (MW
t d) - Notelbs. Evaporated
gal. 8.31 SG - Step 2. Calculate the dilution air volume flow
rate - Qd.
- Qd q 106 K mixing
-
Ca (ppm) - Step 3 Calculate the face velocity.
- V face Qd/A
- Step 4 Calculate the air changes/ hour.
- N (Qd 60)/Vr
36Purge and Buildup
- Purge and buildup - predict contaminant buildup
or purge rate. - Steady state -equilibrium maintained.
BURTON 4-9
37Example 4-5
- An automobile garage was severely contaminated
with carbon monoxide. -
- How long will it take to purge the garage?
BURTON 4-11
38Chapter 11 - Makeup Air Balance
- Exhausted air must be replaced.
- Negative pressure without makeup air.
BURTON 11-1
39Make up Air
- Fresh air supplied into the breathing zone of the
associate.
40Overcoming Negative Static Pressure
- Changes in static pressure involving radial
(squirrel cage) fans cause a small change in the
volumetric flow rate.
- Changes in static pressure involving axial
(propeller) fans cause a large change in the
volumetric flow rate.
BURTON 11-2
41Good Makeup Air
INDUSTRIAL VENTILATION 2-4
42Bad Makeup Air
INDUSTRIAL VENTILATION 2-4
43Reentrainment
BURTON 11-9
44Reentrainment
BURTON 11-9
45Avoiding Reentrainment10-50-3000 RULE
BURTON 14-5
46Recirculation of Exhaust Air
- Good for non-toxic particulate control.
- Can recover 40-60 of heat energy.
BURTON 12-1
47Types of Ventilation Systems
BURTON 5-1
48Why Choose Local Ventilation?
- No other controls
- Containment
- Employee in vicinity
- Emissions vary with time
- Sources large and few
- Fixed source
- Codes
BURTON 5-2
49Exercise 5-3
- Form your group and try exercise 5-3. Compare
the operation to the parameters listed below - No other controls available
- Hazardous contaminant
- Employee in immediate vicinity
- Emissions vary with time
- Emission sources large and few
- Fixed emission source
- Codes standards
BURTON 5-3
50Components of a Local Exhaust System
BURTON 5-4
51Static Pressure Review
BURTON 5-5
52 Energy Conservation
BURTON 5-6
53Basic Air Flow Equations
- Q V A
- TP SP VP
- V 4005(VP/d)0.5
BURTON 5-7
54Static Pressure Loss
- Static Pressure Loss Kloss VP d
BURTON 5-8
55Elbow Loss
- Air moving through elbows spends static
pressure because of - directional change
- friction
- shock losses
- turbulent mixing
- air bunching up
- SP(loss) K(elbow ) VP d
BURTON 5-9
56Elbow Loss Ex. 5-8
- What is the elbow loss factor K(elbow) where
the elbow radius of curvature is R/D 2.0 in a
smooth transition elbow.
BURTON 5-9
57Elbow Loss Exercise 5-9
- What is the actual loss in inches of water of
air flowing through a 60-degree, 3-piece elbow at
V 3440 fpm? R/D 1.5, STP, d1.
BURTON 5-10
58Elbow Loss Exercise 5-9
- SPloss K VP d
- Use Chart 13, Appendix pg. 25 for information on
a 90-degree 3- piece elbow with R/D 1.5 - Let K (angle/90) K 90
- VP (V/4005)2
59Friction Loss as a Function of Duct Length
- Friction Loss K VP L R d
- K is a value taken from Chart 5,
- appendix page 9
- VP is duct velocity pressure, in w.g.
- L is the length of the duct in feet
- d is the density correction factor
- R is roughness correction factor
BURTON 5-11
60Exercise 5-10
- What is the friction loss for a length of
galvanized duct with the following parameters? D
8in., Q 1000scfm, L 43 ft. R 1. -
61Tee Losses
BURTON 5-11
62Tee Losses Ex. 5-12
- What is the estimated static pressure loss in
inches of water for a branch entry of 30 degrees
where the branch entry velocity is 4500 fpm?
BURTON 5-12
63Converting Static Pressure To Velocity Pressure
- At the hood, all of the available static
pressure is converted to velocity pressure and
hood entry loss. - ?SPh ? VP he
-
BURTON 6-2
64Measuring Hood Static Pressure
- Measure hood static pressure 4-6 duct
diameters downstream from the hood.
4-6 D
BURTON 6-2
65Hood Entry Losses
- The hood entry loss is the sum total of all
losses from the hood face to the point of
measurement in the duct. - SP(loss) K VP d
- he K VP d
-
BURTON 6-2
66Example 6-1
- What is the hood static pressure when the duct
velocity pressure is VP 1.10 in. w.g. and the
hood entry loss is - he 1.00 in w.g.
- ?SPh ? VP he
- ?SPh ? 1.10 1.00
- -2.10 in w.g.
BURTON 6-3
67Vena Contracta
- The greatest loss normally occurs at the
entrance to the duct, due to the vena contracta
formed in the throat of the duct.
BURTON 6-3
68Hood Efficiency
- A hoods efficiency can be described by the
ratio of actual to ideal flow. This ratio is
called the Coefficient of Entry, Ce. -
- Ce Q(actual)/Q(ideal)
BURTON 6-4
69Hood Static Pressure and Entry Losses Example 6-5
- The average velocity in a duct serving a hood
is V 2000 fpm. The loss factor for the hood
has been obtained from the manufacturer as Khood
2.2. What are the he and SPh? (Assume STP,
d 1) -
BURTON 6-5
70Hand Grinding Table Example 6-6
- Assume that a special hand grinding table
hood has been built and the following data have
been measured - SPh -2.50 in w.g., V 4000fpm, and the
duct diameter is 18 in. (Assume STP, d1) -
BURTON 6-6
71Types of Hoods
- Receiving
- Capturing
- Enclosing
BURTON 6-10
72Hood Types
73Hood Types
74Hood Types
75Hood Types
76Grinding Wheel Hood Example Example 6-9
- Determine the volume flow rate, transport
velocity, duct diameter, loss factor K, Ce, he,
and SPh, for a grinding wheel hood, wheel
diameter 13in. (low surface speed), straight
take off sto, STP) -
BURTON 6-12
77EXERCISE 6-10USEFUL FORMULAS
- Q V A
- V 4005(VP)1/2
- VP (V/4005)2
- he K VP
- ?SPh ? VP he
BURTON 6-12 AND 6-13
78Exercise 6-10a
- Where appropriate, determine the volume flow
rate, transport velocity, duct diameter, loss
factor K, Ce, he, and SPh for a grinding wheel
hood with a wheel diameter of 14 in. (low surface
speed, tapered takeoff tto. Note the picture
in the book is for a buffing hood.
BURTON 6-12
79Exercise 6-10a Strategy
- 1. Use Chart 11C, appendix pg. 18 to find Q,
Vtrans., K, and Ce. - 2. Use Chart 5A in appendix pg. 9 to find the
diameter of the pipe needed and its area. - 3. Calculate Vactual Q/A
- 4. VP (Vactual/4005)2
- 5. he K VP
- 6. ?SPh ? VP he
80Exercise 6-10b
- Where appropriate, determine the volume flow
rate, transport velocity, duct diameter, loss
factor K, Ce, he, and SPh for a hand grinding
table 10 feet long by 2 feet wide.
BURTON 6-13
81Exercise 6-10b Strategy
- 1. Use Chart 11C, appendix pg. 18 to find Q,
Vtrans., K, and Ce. - 2. Use Chart 5A in appendix pg. 9 to find the
diameter of the pipe needed and its area. - 3. Calculate Vactual Q/A
- 4. VP (Vactual/4005)2
- 5. he K VP
- 6. ?SPh ? VP he
82Exercise 6-10c
- Where appropriate, determine the volume flow
rate, transport velocity, duct diameter, loss
factor K, Ce, he, and SPh for a band saw used to
cut wood that has a blade width of 1 inch.
BURTON 6-13
83Exercise 6-10c Strategy
- 1. Use Chart 11E, appendix pg. 20 to find Q,
Vtrans., K, and Ce. - 2. Use Chart 5A in appendix pg. 9 to find the
diameter of the pipe needed and its area. - 3. Calculate Vactual Q/A
- 4. VP (Vactual/4005)2
- 5. he K VP
- 6. ?SPh ? VP he
84Exercise 6-10d
- Where appropriate, determine the volume flow
rate, transport velocity, duct diameter, loss
factor K, Ce, he, and SPh for a bell-mouthed hood
used for welding. X10 in., Vc 100 fpm, Vtrans
3000 fpm.
BURTON 6-13
85Exercise 6-10d Strategy
- 1. Use Chart 11A, appendix pg. 16 to find Q, K,
and Ce. - 2. Use Chart 5A in appendix pg. 9 to find the
diameter of the pipe needed and its area. - 3. Calculate Vactual Q/A
- 4. VP (Vactual/4005)2
- 5. he K VP
- 6. ?SPh ? VP he
86Exercise 6-10e
- Where appropriate, determine the volume flow
rate, transport velocity, duct diameter, loss
factor K, Ce, he, and SPh for a canopy hood used
for a hot-liquid open surfaced tank. P 16 ft.,
X 3 ft., Vcontrol 125 fpm, Vtrans 2000fpm.
BURTON 6-13
87Exercise 6-10e Strategy
- 1. Use Chart 11B, appendix pg. 17 to find Q, K,
and Ce. - 2. Use Chart 5A in appendix pg. 9 to find the
diameter of the pipe needed and its area. - 3. Calculate Vactual Q/A
- 4. VP (Vactual/4005)2
- 5. he K VP
- 6. ?SPh ? VP he
88Factors Influencing Hood Performance
- Competition
- Mixing
- Work practices
BURTON 6-17
89Canopy Hoods
- Use only for hot processes with rising air.
- Estimate initial and terminal velocities of
rising air stream. - The volume of air exhausted from the hood must
exceed the volume of air arriving at the hood
face. - Warm rising air expands as it rises. Make the
cross-sectional area of the hood face 125 larger
than the plume of hot air. - Avoid canopy hoods if an employee must work over
the source.
BURTON 6-19
90Chapter 7Selection and Design of Ductwork
BURTON 7-1
91Exercise 7-2
- Standard air (d1) moves through an 8 in.
galvanized duct system at 4000 fpm. Estimate VP,
find the loss factors K from the Charts, and then
estimate static pressure loss for each component
in each branch. (Note treat the branch entry as
two 45-degree entries and use the ACGIH value for
K on Chart 14.)
BURTON 7-4
92Exercise 7-2a, Flanged Hood
BURTON 7-4
93Exercise 7-2b, Plain Duct Hood
BURTON 7-4
94Exercise 7-2c, Elbow, 3-piece
BURTON 7-4
95Exercise 7-2d, Elbow, 5-piece
BURTON 7-4
96Exercise7-2e, Elbow, 4-piece
BURTON 7-4
97Exercise 7-2f, Branch Entry
BURTON 7-4
98Exercise 7-2g, 50 ft. of Duct
BURTON 7-4
99RoughnessExample 7-1
- Standard air is flowing in 40 feet of a 24 in.
concrete pipe at the 4000 fpm. What is the
correction factor, R? The loss factor K? -
BURTON 7-5
100Duct Shapes
- Use round duct whenever possible, it resists
collapsing, provides better aerosol transport
conditions, and may be less expensive.
BURTON 7-6
101Pressure Diagrams
BURTON 7-11
102Chapter 8 Fan Selection and Operation
- AXIAL FANS
- propeller fans
- CENTRIFUGAL FANS
- radial fans
- forward inclined
- backward inclined
BURTON 8-2
103Fan Total Pressure
- The fan total pressure (FTP) represents all
energy requirements for moving air through the
ventilation system. - The fan total pressure is often referred to
as the fan total static pressure drop. - FTP TP outlet - TP inlet
- FTP SPout - VP out - SPin - VP in
- FTP SPout - SPin
BURTON 8-3
104Exercise 8-1
- Find the Fan Total Pressure given that the
SPin -5.0 in w.g, SPout 0.40 in w.g. - VPin VPout 1.0 in. w.g.
- FTP SPout - SPin
- 0.40 - (-5.0) 5.4 in w.g.
BURTON 8-3
105Exercise 8-2Fan Static Pressure
- The fan static pressure out of the fan is
defined as the fan total pressure minus the
average velocity pressure out of the fan. - FSP Fan TP - VPout
BURTON 8-4
106SOP and Fan Curves
- To develop a system curve, the fan should be
turned at different rpms and the flow and the
absolute values of the static pressures at the
fan are plotted.
BURTON 8-5
107Developing Fan Curves
BURTON 8-6
108SOP on Steep Part of Curve
BURTON 8-7
109Example 8-1
- Choose an appropriate fan for a system
operating point of Q 10,000 scfm and FTP 1.5
in. w.g. -
BURTON 8-8
110Exercise 8-3
- Find a fan and appropriate rpm for a fan
exhausting 15,000 cfm at a fan TP 2.0 in. w.g.
BURTON 8-8
111Exercise8-4
- Find a suitable fan and the appropriate rpm
for a ventilation system exhausting 480 cfm at a
fan TP 13.8 in. w.g.
BURTON 8-8
112Commercial Fan Curves
BURTON 8-9
113Commercial Fan Curves
BURTON 8-10
114Commercial Fan Curves
BURTON 8-11
115System Effect Losses
BURTON 8-12
116Six-and-Three Rule
BURTON 8-13
117Air Horsepower
- Air horsepower refers to the minimum amount
of power to move a volume of air against the fan
total pressure. It represents the power to get
the air through the duct system. - ahp ( FTP Q d)/6356
BURTON 8-14
118Brake Horsepower
- Brake horsepower refers to the actual power
required to operate the fan so that it fulfills
the job of moving the specified cfm against the
FTP. It takes into account fan inefficiencies,
i.e. losses in the fan. - bhp ahp/ME
BURTON 8-15
119Shaft Horsepower
- Shaft horsepower is bhp plus any power
required for drive losses, bearing losses, and
pulley losses between the fan and the shaft of
the motor. - shp bhp Kdl
-
BURTON 8-15
120Rated Horsepower
- Rated horsepower is the nameplate horsepower on
the motor.
BURTON 8-15
121Example 8-4
- What is the required power for the system and
what rated power motor would you use? - FTP 5.0 in. w.g. ,
- Q 12000 scfm
- ME 0.60, Kdl 1.10, d 1,
- f 6356
BURTON 8-16
122Exercise 8-7
- Estimate the ahp, bhp, shp, and the rated
power motor you would choose for the following
system. - Fan TP 10.0 in. w.g.,
- Q 5000 scfm
- Kdl 1.15, STP(d1),
- f 6356, ME 0.65
BURTON 8-17
123Fan Laws
BURTON 8-19
124Local Exhaust Ventilation Design
BURTON 9-1
125Plenum Design
BURTON 9-3
126BALANCING
- Balancing during the design phase means
adjusting losses in duct runs leading to a
junction that the predicted loss in each run is
essentially equal.
BURTON 9-4
127Example 9-2
- Design an local exhaust system based on the
criteria listed in the example.
BURTON 9-5
128 129Example 9-3
- Design a local exhaust system based upon the
criteria listed on this page.
BURTON 9-11
130(No Transcript)