MoBoard Program

1
This program has been developed to assist those
who need help in maneuvering boards. It is NOT
DESIGNED TO TEACH but to show graphical
representations of solutions to moboard problems.
The examples are taken from a Maneuvering board
WORKBOOK. You will need some moboard paper and
your plotting instruments. Use the mouse to
navigate through this program. Some slides will
direct you to use the ltspace bargt to see the
answers. Once you are ready to proceed, please
press ltspace bargt to continue.
2
Choose from the following available examples by
using the mouse and placing the arrow over the
respective category.
Tracking Problem
True Wind
Search Turn
Wheeling Problem
Target Angle
Change of Station
Change of Station With Avoiding Course
Pretest
ADDITIONAL PROBLEMS
View sample maneuvers
Screen Kilo
Exit Program
3
5-21-1WB Problem 1. At time 1703, CIC reports a
surface contact bearing 320 degrees true (T) at
27,000 yards. Your ship is on course 270T at 15
knots. At 1718, the same contact bears 310T at
24,000 yards. Solve for
Click on the following to see respective answers.
A. Course and Speed of Contact
B. Bearing at Closest Point of Approach (CPA)
C. Range at CPA
D. Time of CPA
E. Relative Bearing at M1
RETURN TO THE MAIN MENU
F. Target Angle (TA) at CPA
4
1. Remember to go from M1 to M2 and parallel this
vector to the tip of your ER vector.
2. Next, measure the distance between M1 and M2.
Take this value and mark it on your nomogram.
Mark off 15 minutes and determine your relative
speed (SRM). Plot your RM vector and then your EM
vector.
1 A.
320T
M1 _at_ 1703
310T
M2 _at_ 1718
27,000 yds
24,000 yds
15 kts
SRM 11 kts
E
R
270T
M
Contacts speed is 20.25 kts
238T
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problem
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plotted.
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the problem plotted.
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the problem plotted.
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the problem plotted.
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the problem plotted.
5
1 B.
Remember draw your Relative Motion Line from M1
to M2 and parallel it to the center of your
moboard and this is your DRM. Add or subtract 90
towards your Relative Motion Line to mark off
your CPA. CPA Bearing is 281.1T.
M1 _at_ 1703
M2 _at_ 1718
281.1T
CPA
E
R
90
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problem
Press ltSpace Bargt once to see how the CPA is
plotted.
191.1T
6
1 C.
Remember draw your DRM from M1 to M2 and parallel
it to the center of your moboard. Add 90 towards
your DRM to mark off your CPA.
M1 _at_ 1703
M2 _at_ 1718
281.1T
Range 21,100 yds
E
R
CPA

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problem
Press the ltSpace Bargt to see the CPA range
plotted.
191.1T
7
1 D.
To calculate the time of CPA, use the M1 to CPA
distance and your SRM to calculate the CPA time.
Using 17,100 yds and 11kts, you should get 47.6
min.
M1 _at_ 1703
M2 _at_ 1718
M1 to CPA 17,100 yds
CPA
CPA time is at 1750.6
281.1T
SRM 11 kts
E
R

M
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problem
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CPA plotted.
191.1T
8
1 E.
O5OR
TB RB SH
320T
M1 _at_ 1703
O4OR
320T RB 270T
O3OR
RB 320 - 270
O2OR
RB 050R
O1OR
270T
OOOR
E
R

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how the RB is calculated.
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problem
9
1 F.
M1 _at_ 1703
TA TB 180 - TC
M2 _at_ 1718
TA 281.1T 180 - 238T
TA 461.1 - 238
CPA
281.1T
TA 223.1 R
E
R
Contacts speed is 20.25 kts

M
238T
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how TA is calculated.
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problem
191.1T
10
5-21-1WB Problem 2. The formation is on course
045T at 12 kts. Your ship in on station 090R
from the guide at 9,000 yds. You are ordered to
station 180T from the guide at 8,000 yds. Solve
for
Click on the following to see respective answers.
A. Course to be on station in 7 minutes
D. Taking into account the effects of
deceleration, you would slow to 12 kts when
the guide bears?
B. Speed of Relative Motion to be on station in
7 min
C. Stationing speed required to be on station in
7 min
RETURN TO THE MAIN MENU
11
2 A B.
1. Calculate TB TB RB SH TB 090 045 TB
135T
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
3. Next, measure distance from M1 to M2. This
represents your relative distance (MRM).
4. Now plot 6,500 yds and 7 min on your
nomogram. You should get 27.7 kts as your
relative speed (SRM).
045T
27.7 kts
R
275.2T
M
E
12 kts
M1 _at_ 9000 yds
M2 _at_ 8000 yds
135T
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problem
MRM 6,500 yds
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first.
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180T
12
2 C.
For determining your stationing speed, measure
your EM vector.
045T
R
M
E
12 kts
18 kts
M1 _at_ 9000 yds
M2 _at_ 8000 yds
135T
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problem
180T
13
2 D.
357.7T
1. To calculate Surge Bearing, you subtract your
base speed of 12 kts from your stationing speed
of 18 kts. Multiply 6 by 35 yds. You should get
210 yds.
045T
R
2. Next, measure 210 yds from your M2 in the
direction of M1.
M
E
12 kts
3. Once you plot this point, be sure to read
what the bearing is TO THE GUIDE.
18 kts
M1 _at_ 9000 yds
M2 _at_ 8000 yds
135T
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problem
210 yds
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180T
14
5-21-2-WB Problem 5. Your ship is on course
220T at 12 knots. The anemometer indicates
that the relative wind is from 060R at 22 knots.
The CO desires the relative wind to be 30
degrees off the port bow at 25 knots in
preparation for flight operations. Solve for
Click on the following to see respective answers.
A. True wind direction and velocity
D. Course required (high speed solution)
B. Course required (low speed solution)
E. Speed required (low speed solution)
C. Speed required (high speed solution)
RETURN TO THE MAIN MENU
15
5 A.
312.5T
19 knots
Relative wind 060R or Apparent Wind at 280T _at_
22 knots
220T _at_ 12 knots
Remember to go from Ship to Wind
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problem
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16
Remember to use the 19 knots of True wind
speed to mark off your Low speed solution
353.9T
5 B.
312.5T
Remember to go from DOT 1 to DOT 2
DOT 2
CO desires relative wind to be 30 degrees off the
port bow at 25 knots
19 kts
stbd
DOT 1
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problem
port
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17
Remember to use the 19 knots of True wind
speed to mark off your High speed solution
5 C.
312.5T
Remember to go from DOT 1 to DOT 2
35.7 kts
CO desires relative wind to be 30 degrees off the
port bow at 25 knots
DOT 1
DOT 2
stbd
19 kts
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problem
port
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18
Remember to use the 19 knots of True wind speed
to mark off your High speed solution
5 D.
312.5T
Remember to go from DOT 1 to DOT 2
091T
CO desires relative wind to be 30 degrees off the
port bow at 25 knots
DOT 1
DOT 2
stbd
19 kts
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problem
port
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19
Remember to use the 19 knots of True wind speed
to mark off your Low speed solution
5 E.
312.5T
Remember to go from DOT 1 to DOT 2
DOT 2
CO desires relative wind to be 30 degrees off the
port bow at 25 knots
7.4 kts
19 kts
stbd
DOT 1
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problem
port
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20
5-21-1WB Problem 3. Your ship is in station
5100 of a circular formation with an axis of
100T. The guide is in station zero. Formation
course is 135T at 12 kts. Your ship is ordered
to station 5280. The Captain desires to pass
astern of the guide and no closer than 2000
yards. Use 25 kts for stationing speed and solve
for
Click on the following to see respective answers.
A. Course for the first leg of the maneuver
B. Bearing to the guide at the start of the
second leg.
C. Course for the second leg of the maneuver.
D. Time to complete the maneuver
RETURN TO THE MAIN MENU
21
3 A.
015T
Plot your EM vector using 25 kts of stationing
speed by intercepting your RM vector that has
been paralleled to the ER vector.
Plot a 2000 yds circle around the guide.
Draw your tangent so that you pass astern of the
guide.
M
Station 5280 Bears 280R at 5000 yds
25 kts
E
12 kts
Formation Axis
100T
R
135T
Station 5100 Bears 100R at 5000 yds
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22
3 B.
To plot the bearing to the guide at the start of
the second leg, draw the other tangent line. The
intersection of the two tangent will mark the
point where you need to turn.
Station 5280 Bears 280R at 5000 yds
E
12 kts
Remember to go from the intersection of the two
tangents TO THE GUIDE.
R
113.3T
Station 5100 Bears 100R at 5000 yds
135T
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problem
23
3 C.
Parallel the second tangent to the tip of the ER
vector.
Since you are told to use 25 kts for stationing
speed, plot this and intercept your RM vector.
Station 5280 Bears 280R at 5000 yds
25 kts
072T
M
E
12 kts
R
113.3T
Station 5100 Bears 100R at 5000 yds
135T
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problem
24
3 D.
015T
Use both SRMs that you plotted earlier, and the
respective MRMs and input these values into your
nomogram. Combine these times for overall answer.
5500 yds
SRM 33 kts
072T
M
E
12 kts
SRM 22kts
5400 yds
R
5.0 min 7.5 min 12.5 min
135T
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problem
25
5-21-2WB Problem 3. Five Destroyers are in a
line abreast to port, 2000 yard spacing, on
course 090T at 22 kts. The guide is the ship
in station three. Your ship is in station two.
The formation is ordered to conduct a wheel to
course 000T and decrease speed to 10 knots. Use
25 kts for stationing speed. Solve for
Click on the following to see respective answers.
A. Bearing to the guide when on station after
wheeling
C. Course to station
D. Time to Station
E. Based on the effects of decel, you would slow
to the guides speed when the guide bears ____?
B. Range to the guide when on station after
wheeling
RETURN TO THE MAIN MENU
26
3 A B.
000T
You must shift the entire formation so that the
new guide is in the center.
Upon execution of signal, the inside pivot ship
becomes the guide.
5
4
10 kts
270T
090T
22 kts
3
Bearing TO the guide AFTER wheeling is 270T at
6000 yds
2
6000 yds
1
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problem
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27
3 C.
000T
028.5T
Remember to go from M1 to M2 and parallel to ER
vector.
Next, use the 25 kts to intercept the RM vector
M
R
10 kts
M2
E
M1
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problem
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28
3 D.
000T
028.5T
Remember to measure your MRM from M1 to M2 and
your SRM from your RM vector. Plot these on your
nomogram and you should get
M
SRM
R
10 kts
M2
E
MRM
15 min
M1
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problem
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29
3 E.
000T
Next, plot from this point back TO the guide to
get the true bearing. You should get 273T.
To calculate the Surge Bearing, subtract 10kts
from 25kts. Multiply 15kts by 35yds and you get
525yds. Measure this back from your M2 towards
your M1 and plot this point.
M
R
273T
25 kts
10 kts
M2
E
M1
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problem
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30
5-21-2WB Problem 4. Six destroyers are in a
line abreast to starboard on course 155T at 12
kts and are 2000 yds apart. Your ship is the
guide and is in station three. The formation is
ordered to conduct a search turn to course 065T
and increase speed to 25 kts. Based on this
information solve for
Click on the following to see respective answers.
A. Bearing and range to the guide upon execution
of the maneuver.
D. Relative speed upon execution of the maneuver.
E. Based on Advance and Transfer, you come to
base course when guide bears__?
B. Bearing and range to the guide upon
completion of the maneuver.
RETURN TO THE MAIN MENU
C. Time to complete the maneuver.
31
4 A.
Remember when the search turn is executed, the
wing ship furthest away from the direction of the
turn becomes the guide. Shift the formation
accordingly so that the ship furthest from the
turn immediately turns to the new base course and
speed.
We are here.
1
2
065T
6000 yds
3
4
1
5
2
6
3
The bearing and range TO the guide UPON execution
is 245T at 6000 yds.
4
12 kts
5
6
245T
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155T
32
4 B.
335T
We are here.
065T
25 kts
12 kts
6
25 kts
5
4
3
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problem
2
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155T
1
33
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how each ship maneuvers.
065T
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problem
155T
34
4 C D.
Remember to use your SRM and MRM to find the time.
065T
M1
Time is 7.2 min and SRM is 35.3 kts
25 kts
SRM
MRM
25 kts
M2
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problem
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155T
35
4 E.
326T
To find Turn Bearing, subtract 065 from 155T.
Divide 90by 10 and you get 9. Plot this amount
back from your M2. Remember to take bearing TO
the Guide.
065T
M1
25 kts
MRM
25 kts
M2
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problem
146T
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155T
36
Click on the respective buttons to see any
additional CHANGE OF STATION problems on pages
5-23-10 WB.
22
23
24
25
RETURN TO MAIN THE MENU
37
5-23-10WB 22. The formation is on course 085T
at 10 kts. The guide bears 190T from your ship
9000 yds. You are ordered to take station dead
astern of the guide at 4500 yds. Use 25 kts for
stationing speed. Based on this information,
solve for
Click on the following to see respective answers.
A. Course to Station
D. Taking into account the effect of
deceleration, you slow to formation speed when
the guide bears__?
B. Speed of Relative Motion (SRM) for the
maneuver
C. Time to complete the maneuver
RETURN TO THE MAIN MENU
38
010T
22 A B.
M1 _at_ 9000 yds
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
3. Next, measure 25 kts and intercept your RM
vector
4. Next, measure your RM vector.
1. To take station dead astern is 180R.
085T
R
10 kts
M2 _at_ 4500 yds
E
265T
Stat Spd 25 kts
30 kts
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problem
M
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195T
39
010T
22 A B.
M1 _at_ 9000 yds
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
3. Next, measure 25 kts and intercept your RM
vector
4. Next, measure your RM vector.
1. To take station dead astern is 180R.
085T
R
10 kts
M2 _at_ 4500 yds
E
265T
Stat Spd 25 kts
30 kts
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problem
M
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195T
40
010T
22 C.
M1 _at_ 9000 yds
11000 yds
MRM
085T
R
10 kts
Using your MRM of 11000 yds and your SRM of 30
kts, you should get 10.9 minutes to complete this
maneuver.
E
M2 _at_ 4500 yds
SRM
265T
30 kts
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problem
M
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195T
41
010T
22 D.
M1
1. To calculate Surge Bearing, you subtract your
base speed of 10 kts (ER) from your stationing
speed of 25kts (EM). Multiply 15 by 35 yds. You
should get 525 yds.
085T
10 kts
R
3. Once you plot this point, be sure to read
what the bearing is TO THE GUIDE.
090.6T
E
525 yds
2. Next, measure 525 yds from your M2 in the
direction of M1.
M2
265T
25 kts
30 kts
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problem
M
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195T
42
5-23-10WB 23. Your ship is on station 140T
from the guide at 6000 yds. Formation course is
060T at 12 kts. Your are ordered to take
station dead astern of the guide at 3000 yds.
The Captain desires course 325T to station.
Solve for
Click on the following to see respective answers.
A. Stationing speed required
C. Time to complete the maneuver
D. Turn Bearing
B. Speed of Relative Motion (SRM) for the maneuver
RETURN TO THE MAIN MENU
43
23 A.
1. To take station dead astern is 180R.
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
3. Next, CO wants you to use 325T to maneuver
to station.
4. Next, measure your EM vector.
325T
M
060T
R
Stat Spd is 20 kts
12 kts
E
M2 _at_ 3000 yds
240T
M1 _at_ 6000 yds
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problem
140T
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44
23 B.
325T
M
24.3 kts
Measure your RM vector to get your SRM
060T
R
Stat Spd is 20 kts
12 kts
E
M2 _at_ 3000 yds
240T
M1 _at_ 6000 yds
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problem
140T
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45
23 C.
325T
M
24.3 kts
Measure your RM vector to get your SRM.
Next, use your SRM and MRM to calculate the time.
060T
SRM
R
Stat Spd is 20 kts
12 kts
E
Time to complete maneuver 8.7 min
M2 _at_ 3000 yds
MRM
240T
M1 _at_ 6000 yds
7200 yds
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problem
140T
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46
23 D.
325T
M
050.5T
060T
R
12 kts
1. To calculate Turn Bearing, you subtract your
base course of 060 (ER) from your stat crs of
325 (EM).
2. You should get 95 which you divide by 10.
Take 9.5 and measure from your M2 going back
towards M1.
E
3. After plotting this point, remember to read
the bearing TO THE GUIDE.
M2 _at_ 3000 yds
MRM
9.5
240T
M1 _at_ 6000 yds
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problem
140T
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47
5-23-10WB 24. A surface contact is on course
230T at 15 kts and presently bears 125T at
12000 yds from your ship. You are ordered to
take station bearing 040T at 8000 yds from the
contact. Based on the information, solve for
Click on the following to see respective answers.
A. Speed of Relative Motion (SRM) to be
on station in 15 min.
D. Taking into account the effects of advance
transfer (turn bearing), you would come to the
contacts course when the contact bears__?
B. Course to station required to be on station in
15 min
RETURN TO THE MAIN MENU
C. Stationing speed required to be on station
48
24 A B.
1. Remember, you need to plot your ship on the
reciprocal bearing from the guide.
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
3. Next, use the 15 min and your MRM to
calculate the relative speed.
040T
305T
M2 _at_ 8000 yds
M1 _at_ 12000 yds
MRM
4. Next, mark off the relative speed along your
SRM.
E
R
15 kts
SRM
M
121.5T
Relative Speed is 21.5 kts
230T
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49
24 C.
Measure your EM vector to see what your
stationing speed is.
040T
305T
M2 _at_ 8000 yds
M1 _at_ 12000 yds
MRM
Stationing Speed is 21.5 kts
E
R
15 kts
SRM
M
Relative Speed is 30 kts
121.5T
230T
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problem
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50
24 D.
2.. Take 10.95 and measure from your M2 going
back towards M1.
040T
M1 _at_ 12000 yds
305T
M2 _at_ 8000 yds
11
Take the difference between your stationing
course and the course you will eventually come to
and divide by 10.
230 - 121.5 109.5 109.5/10 10.95 or 11
E
15 kts
R
M
121.5T
230T
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problem
209T
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51
5-23-10WB 25. The guide of the formation bears
050T from your ship at 16000 yds. Formation
course is 270T at 20 kts. You are ordered to
take station on the port beam of the guide at
9000 yds. Use 30 kts for stationing speed.
Solve for
Click on the following to see respective answers.
A. Course to station
D. Based on the effect of deceleration, you would
slow down to formation speed when the guide
bears___?
B. Speed of Relative Motion (SRM) for
the maneuver
C. Time to complete the maneuver
RETURN TO THE MAIN MENU
52
25 A B.
050T
3. Next, use the 30 kts of stationing speed and
intercept your RM to determine what course to
steer.
4. Measure your SRM from your RM vector.
2. Remember to connect from M1 to M2 and
parallel to your ER vector.
SRM is 49.8 kts
080.2T
270T
M
30 kts
20 kts
E
R
1. To take station off the port beam is 270R
M1 _at_ 16000 yds
MRM
M2 _at_ 9000 yds
230T
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53
25 C.
050T
1. Use your SRM and MRM to get the time.
49.8 kts
Time is 7.5 min
080.2T
SRM
270T
M
30 kts
20 kts
E
R
M1 _at_ 16000 yds
MRM
M2 _at_ 9000 yds
12100 yds
230T
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54
002.6T
25 D.
1. To calculate Surge Bearing, subtract your
base speed of 20 kts (ER) from your stationing
speed of 30kts (EM). Multiply 10 by 35 yds. You
should get 350 yds.
050T
3. Once you plot this point, be sure to read
what the bearing is TO THE GUIDE.
080.2T
270T
M
30 kts
20 kts
E
R
2. Next, measure 350 yds from your M2 in the
direction of M1.
M1 _at_ 16000 yds
MRM
M2 _at_ 9000 yds
230T
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55
Click on the respective buttons to see any
additional WHEELING LINE ABREAST problems on
page 5-23-23WB.
61
62
RETURN TO MAIN THE MENU
56
5-23-23WB 61 A. Five destroyers are in a Line
Abreast to starboard with 2000 yd spacing on
course 120T at 15 kts. The ship in station
three is the guide. Your ship is the the ship in
station one. The formation has been ordered to
wheel to course 210T and increase speed to 20
kts. Use 25 kts for stationing speed. Solve for
Click on the following to see respective answers.
A. Bearing TO the guide when on station after
wheeling
B. Range TO the guide when on station after
wheeling
C. Course to station at 25 kts
D. Time to station
E. Accounting for deceleration, you would slow to
the guides speed when it bears___?
RETURN TO THE MAIN MENU
57
61 A.
1
1. When the formation wheels to 210T, the inside
pivot ship 5 becomes the guide. Shift the
formation so that 5 is in the center.
2
300T
1
3
2
4
3
5
5
4
4
3
2
5
1
120T
210T
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58
61 B.
300T
8000 yds
5
4
3
2
1
120T
210T
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59
61 C.
1
M1
2
3
Remember to connect M1 to M2 and parallel to your
ER vector.
4
5
5
E
Mark off 25 kts as your EM vector
4
3
20 kts
2
1
M2
120T
R
25 kts
210T
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199.5T
M
60
61 D.
1
M1
2
Use your SRM and MRM to get the time.
3
4
5
MRM
5
E
Time is 52 min
4
3
20 kts
2
1
M2
120T
R
25 kts
210T
SRM
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199.5T
M
61
61 E.
1
To calculate Surge Bearing, subtract 20 from 25
kts. Multiply 5 kts by 35 yds and get 175 yds.
M1
2
298.8T
3
4
Plot this point from M2 back towards M1
5
5
E
Now measure the bearing TO the guide.
4
3
20 kts
2
1
M2
120T
R
25 kts
210T
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199.5T
M
62
5-23-23WB 62. Five fast frigates are in a Line
Abreast to starboard, with 2000 yd spacing, on
course 120T at 15 kts. The ship in station three
is the guide. Your ship is in station four. The
formation has been ordered to wheel to course
030T and increases speed to 20 kts. Use 25 kts
for stationing speed. Based on this solve for
Click on the following to see respective answers.
A. Bearing TO the guide when on station after
wheeling
D. Time to station
E. Taking into account the effects of
deceleration, you would slow to the guides
speed when it bears__?
B. Range TO the guide when on station
after wheeling
RETURN TO THE MAIN MENU
C. Course to station
63
62 A.
030T
300T
When the signal is executed, the guide shifts to
the inside pivot ship.
After you shift the guide, plot your new base
course and speed.
Next, plot what the formation will be after
wheeling.
Measure the bearing TO the guide
120T
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64
62 B.
030T
6000 yds
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problem
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65
62 C.
030T
040.5T
Remember plot your MRM from M1 to M2
R
M
Next parallel to the ER vector and then measure
your 25 kts as your EM vector
25 kts
E
M2
120T
M1
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66
62 D.
030T
040.5T
SRM
Use your MRM SRM to calculate the time.
R
M
25 kts
Time is 38.5 min
E
MRM
M2
120T
M1
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67
62 E.
030T
To calculate the turn bearing, subtract your
stationing course from the base course. Divide
10.5T by 10 and you should get 1.5T. Plot this
back from M2 towards M1.
040.5T
301.5T
R
M
25 kts
E
M2
120T
M1
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68
Click on the respective buttons to see additional
problems in the following areas
Avoiding Course
True and Desired Wind
Change of Station
Search Turn
Wheeling
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69
Please choose one of the following buttons to see
the maneuver displayed.
Column to a Diamond formation executed
Corpen from Line Abreast
Turn from Line Abreast
Corpen From a Column
Turn from a Column
Search Turn Executed
Turn from a Diamond
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70
Press ltSpace Bargt to see a column formation go to
a diamond formation.
2
2D
1
2
3
4
1
4
D
3D
3
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71
Press ltspace bargt to see the search turn begin
Note that this Line Abreast to PORT will end up a
Line Abreast to STBD
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72
Press ltspace bargt to see a CORPEN begin
Note that your relative bearing to the guide
remains the same.
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73
Press ltspace bargt to see a TURN begin
Note that your TRUE bearing to the guide remains
the same.
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74
Press ltspace bargt to see a CORPEN begin
Note that your relative bearing to the guide
remains the same.
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75
Press ltspace bargt to see a TURN begin
Note that your TRUE bearing to the guide remains
the same.
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76
Press ltspace bargt to see a TURN begin
Note that your TRUE bearing to the guide remains
the same.
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77
The following problems are located on 5-23-37WB.
Click on the respective buttons to see
additional AVOIDING COURSE problems.
101
102
103
104
105
Return to Main Page
78
5-23-37WB 101. At 0935 you detect a contact
bearing 150T at 18000 yds. The contacts
course and speed is 240T at 17 kts. The Captain
orders you to alter course to pass astern of the
contact, approaching no closer than 6000 yds. You
are presently on course 200T at 25 kts. Based on
this information solve for
Click on the following to see respective answers.
A. Course to steer to accomplish the maneuver
B. Time of CPA
Return to Main Page
79
101 A.
330T _at_ 18000 yds
M1
Remember to draw your 6000 yd arc astern of the
contact.
Next, draw the tangent from M1 to the arc and
parallel to the contacts course.
17 kts
Next, use 25 kts and intercept your RM vector.
25 kts
240T
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171T
80
101 B.
330T _at_ 18000 yds
Use your MRM and SRM to figure out your time to
CPA.
M1
MRM
Time is 20.5 min
CPA
17 kts
25 kts
240T
SRM
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171T
81
5-23-37WB 102. You are on course 310T at 20
kts. At time 0900 you detect a contact bearing
358, 18000 yds. At 0909, the contact bears
004T, 13700 yds. Based on this information
solve for
Click on the following to see respective answers.
A. Contacts Bearing Drift
B. Will the contact pass ahead or astern of you?
C. If you slow to 5 kts at time 0909, what will
be th enew CPA range?
Return to Main Page
82
102 A B.
358T
004T
M1
310T
M2
20 kts
Going from M1 to M2, the contact will have a
RIGHT bearing drift and pass ASTERN of us.
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83
102 C.
358T
004T
M1
MRM
310T
To solve for the new CPA, first determine the
contacts course and speed.
M2
R
20 kts
Using your MRM and 9 min, you should get a SRM of
15 kts.
15 kts
E
M
261T
Mark off 15 kts from the ER vector to form your
RM vector.
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84
102 C.
Now that you have determined the contacts
course, use this with your new speed of 5 kts and
redraw the your RM vector.
M1
310T
M2
9500 yds
Once you redraw your ER vector, parallel this
back to your M2. This will be your relative
motion line.
R
5 KTS
E
M
261T
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85
5-23-37WB 103. You are on course 040T at 24
kts. At time 1322, contact bears 034T at 24000
yds. At time 1325, the contact bears 035T 20000
yds. Based on this information, solve for
Click on the following to see respective answers.
A. Contacts Crs Spd
B. CPA Time
C. If you were to alter course immediately,
which course would you steer to open the CPA to
6000 yds? Maneuver IAW Rules of the Road
Return to Main Page
86
103 A.
034T
035T
040T
M1 _at_ 24000 yds
Once you connect M1 to M2, parallel this to your
ER vector.
M2 _at_ 20000 yds
R
24 kts
Using your MRM and 3 min, you should get a SRM
around 41kts.
E
16 kts
41 kts
Next, measure your EM vector to get contacts
course and speed.
M
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193T
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87
103 B.
M2 _at_ 20000 yds
M1 _at_ 24000 yds
Using your SRM of 41 kts and your MRM of 24000
yds, you should get a time of
MRM of 24000 yds
R
20.5 minutes
E
CPA
SRM of 41 kts
120T
M
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88
103 C.
1. If you alter course when the contact is at M2
IAW Rules of the Road, you must alter course to
stbd. First, draw your 6000 yd circle.
2. Next, draw the tangent so that you maneuver
for a PORT to PORT passage.
3. Next, parallel this back to the ER vector and
draw in the direction of the CPA to the M2.
4. Using the same speed of 24 kts, intercept the
RM vector. This will become your EM vector.
M2 _at_ 20000 yds
M
CPA
24 kts
078T
E
16 kts
R
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193T
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89
5-23-37WB 104. You are on course 330T at 15
kts. At 0915, a contact bears 320T at 15000 yds.
The contact is on course 130T at 18 kts. The
Captain orders you to alter course to avoid the
contact by 14000 yds. The Captain wants you to
alter course when the contacts range is 14000
yds. Based on this information solve for
Click on the following to see respective answers.
Course to avoid contact by 4000 yds
Return to Main Page
90
104 A.
011T
330T
320T
15000 yds
M1
14000 yds
15 kts
R
15 kts
E
18 kts
M
2. Since we are ordered to maneuver when the
contact bears 14000 yds, draw the tangent to the
4000 yd circle.
4. Next, plot your 15 kts to intercept the new
RM vector.
1. First determine where the contact will be at
14000 yds. Do this by using your RM vector and
paralleling it to the M1.
3. Next, parallel this back to the old EM vector
as shown.
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91
5-23-37WB 105. You are on course 235T at 16
kts. At 1700, a contact bears 269T at 10 nm. At
1710, the contact bears 266T at 14000 yds. When
the contact bears 260T, you are to change
course, passing astern to avoid the contact by
4000 yds. Based on the information solve for
Click on the following to see respective answers.
A. Contacts course speed
C. Time of CPA
B. Your avoiding course
D. Bearing of contact at CPA
E. Range of contact when you changed course
Return to Main Page
92
105 A.
2. With you MRM and 10 min, you should get an SRM
of 18 kts.
1. Connect M1 to M2 and parallel to the ER vector.
16 kts
E
269T
MRM
M1
M2
12 kts
R
266T
235T
M
SRM of 18 kts
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156T
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93
105 B.
3. Next, parallel this to the old EM vector and
intercept your speed of 16 kts to determine your
avoiding course.
1. Plot along your relative motion line where the
contact will be when it bears 260T as noted
below.
2. Next plot the 4000 yd circle and draw the
tangent as shown below.
E
16 kts
R
M2
12 kts
260T
252T
M
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156T
94
105 C.
Using your SRM and the MRM shown below, you
should get a time of
1730
E
16 kts
R
M2
CPA
12 kts
260T
252T
M
MRM
SRM
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156T
95
105 D.
E
16 kts
R
M2
CPA
12 kts
260T
252T
M
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198T
156T
96
105 E.
At M2, you change course to 252T.
9000 yds
E
R
M2
12 kts
260T
252T
M
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156T
97
Click on the respective buttons to see any
additional SEARCH TURN problems located on
5-23-27WB.
71
72
Return to Main Page
98
5-23-27WB 71. Five destroyers are in a Line
Abreast to Port, with 2000 yd spacing, on course
120T _at_10 kts. The ship in station three is the
guide. Your ship is in station two. The
formation is ordered to conduct a Search Turn to
230T and increase speed to 20 kts. Solve for
Click on the following to see respective answers.
A. Bearing and range to the guide upon execution
of the maneuver.
D. Relative speed upon execution of the maneuver.
E. Based on Advance and Transfer, you come to
base course when guide bears__?
B. Bearing and range to the guide upon
completion of the maneuver.
RETURN TO THE MAIN MENU
C. Time to complete the maneuver.
99
71 A.
030T
Remember when the search turn is executed, the
wing ship furthest away from the direction of the
turn becomes the guide. Shift the formation
accordingly so that the ship furthest from the
turn immediately turns to the new base course and
speed.
6000 yds
120T
230T
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100
71 B.
320T
1. Since, you are in a Line Abreast to PORT upon
execution of the Search Turn, you will end up in
a Line Abreast to STBD upon completion of the
maneuver.
6000 yds
120T
230T
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101
71 C D.
1. Measuring your SRM and MRM shown below, you
can calculate the time for the maneuver.
6.2 min
E
20 kts
20 kts
M
SRM of 32.6 kts
R
120T
MRM
230T
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problem
102
71 E.
1. To figure out the turn bearing, subtract 120
from 230 and you should get 110. Divide this
number by 10 and you should get 11. Go back this
amount from the M2 in the direction of M1.
Remember to read the bearing TO the guide.
331T
E
M
R
120T
M2
MRM
230T
M1
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103
5-23-23WB 72. Six destroyers are in a Line
Abreast to STBD, 1500 yds apart on course 315T
at 15 kts. The guide is in station one. Your ship
is in station 5. The formation is ordered to
conduct a Search Turn to 090T and increase speed
to 20 kts. Solve for
Click on the following to see respective answers.
A. Bearing and range to the guide upon execution
of the maneuver.
D. Relative speed upon execution of the maneuver.
E. Based on Advance and Transfer, you come to
base course when guide bears__?
B. Bearing and range to the guide upon
completion of the maneuver.
RETURN TO THE MAIN MENU
C. Time to complete the maneuver.
104
72 A.
315T
Remember when the search turn is executed, the
wing ship furthest away from the direction of the
turn becomes the guide. Shift the formation
accordingly so that the ship furthest from the
turn immediately turns to the new base course and
speed.
15 kts
20 kts
090T
225T
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105
72 B.
315T
1. Since, you are in a Line Abreast to STBD upon
execution of the Search Turn, you will end up in
a Line Abreast to PORT upon completion of the
maneuver.
15 kts
20 kts
090T
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180T
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106
72 C D.
315T
MRM
20 kts
1. To calculate the time to complete the
maneuver, remember to use the SRM and the MRM as
shown.
SRM
20 kts
090T
SRM is 37 kts
Time is 3.78 minutes
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180T
107
72 E.
315T
M2
MRM
M1
20 kts
1. To calculate the turn bearing, remember to
subtract your maneuvering course from the course
you will steady on. In our case, 090 - 315 360
135. Next divide by 10 and you get 13.5.
Remember to plot back from your M2.
20 kts
090T
193.5T
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problem
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180T
108
Click on the respective buttons to see any
additional TRUE DESIRED WIND problems on page
5-23-36WB.
91
92
Return to Main Page
109
5-23-24WB 91. Your ship is on course 195T at 10
kts.The apparent wind is from 045T at 10 kts.
The Captain desires the relative wind to be 30
to PORT at 30 kts. Solve for
Click on the following to see respective answers.
A. True wind direction and velocity
B. Course required (low speed solution)
C. Speed required (high speed solution)
RETURN TO THE MAIN MENU
110
91 A.
030T
045T
1. Remember to plot from SHIP to WIND to get the
true wind speed and direction.
Apparent Wind
10 kts
10 kts
19.5 Kts
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195T
111
91 B C.
030T
2. Measure course for the low speed solution.
1. Knowing that the True Wind is from 030T at
19.5 kts, plot 30 to PORT at 30 kts and mark off
19.5 kts as shown below.
3. Measure the speed required for the high speed
solution.
080.4T
DOT 2
19.5 kts
DOT 1
19.5 kts
37.75 kts
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problem
port
DOT 2
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stbd
112
5-23-34WB 92. Your ship is on course 042T at 17
kts.The anemometer indicates that the relative
wind is from 058R at 25 kts. The Captain desires
the relative wind to be 30 to PORT at 25 kts.
Solve for
Click on the following to see respective answers.
A. True wind direction and velocity
B. Course required (high speed solution)
C. Speed required (low speed solution)
RETURN TO THE MAIN MENU
113
92 A.
195T
1. Remember to plot from SHIP to WIND to get the
true wind speed and direction.
21.25 Kts
17 kts
25 kts
Relative Wind is at 058R or at 100T
141.5T
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114
92 B C.
1. Knowing that the True Wind is from 141.5T at
21.25 kts, plot 30 to PORT at 25 kts and mark
off 21.25 kts as shown below.
2. Measure course for the high speed solution.
3. Measure the speed required for the low speed
solution.
port
DOT 2
stbd
DOT 1
21.25 kts
286T
21.25 kts
4.25 kts
DOT 2
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141.5T
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115
Please choose from the following problems taken
from the PRETEST on pages 5-23-3 through 5WB
1
2
3
4
5
6
7
8
9
10
Return to Main Menu
116
5-23-3WB 1. Your ship is on course 300T, speed
10 kts. At 0815 CIC reports a surface contact
bearing 005T at range of 15000 yds. At 0815 the
contact bears 350T, range 10000 yds. Based on
this information, solve for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. Course and speed on the contact.
D. Time at closest point of approach (CPA).
B. Bearing at closest point of approach (CPA).
E. Relative Bearing (RB) at M1.
F. Target angle(TA) at Closest Point of
approach (CPA).
C. Range at closest point of approach (CPA).
Return to MAIN MENU
117
1 A.
005T
350T
M1 _at_ 0805
MRM
300T
Remember, draw your MRM between M1 and M2 in the
direction of M2.
M2 _at_ 0815
R
Next, parallel this to your ER vector.
10 kts
Determine your SRM using your MRM and a time of
10 min and mark it off which becomes the RM
vector.
E
SRM
M
20.5 kts
240T
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118
1 B C.
005T
350T
M1 _at_ 0805
MRM
300.5T
M2 _at_ 0815
To determine the CPA bearing, you must determine
your DRM. Do this by paralleling your MRM vector
to the center of the moboard.
CPA
6500 yds
Next, add or subtract 90 degrees to your DRM in
the direction of your MRM vector and draw a line
to intercept your MRM vector. This intersection
is your CPA.
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210.5T
119
1 D.
005T
350T
M1 _at_ 0805
MRM
300.5T
M2 _at_ 0815
Using your SRM from part A, measure the distance
from M1 to CPA and you should be able to
determine the time to reach CPA.
CPA
Time of CPA is 0828
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problem
210T
120
1 E.
065R
005T
M1
000R
Remember your formula for calculating RB. Note
the formula below.
300T
TB RB SH RB TB - SH RB 005 - 300 360 RB
065R
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121
1 F.
M1
MRM
300.5T
M2
Using the formula for Target Angle (TA), you
should get ... TA TB 180 - TC TA 300.5
180 - 240
CPA
TA 240.5R
240T
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problem
122
5-23-3WB 2. Five destroyers are in a Line
Abreast to stbd, 2000 yds apart on course 270T
at 18 kts. The ship in station one is the guide.
The formation is ordered to conduct a Search Turn
to course 170T at a speed of 25 kts. Your ship
is in station three. Solve for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. Bearing TO the guide when in new station.
D. Relative speed upon execution of Search Turn.
B. Range TO the guide when in new station.
E. Based on the effects of advance transfer
(turn bearing), you would come the guides
course when the guide bears?
C. Time to station.
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123
2 A B.
080T
18 kts
270T
4000 yds
25 kts
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170T
124
2 C D.
Remember to that all ships will increase speed to
25 knots upon execution of Search Turn.
Next, measure your SRM
Using your SRM and MRM, you should be able
calculate the time which is
4.1 minutes
25 kts
MRM
SRM
25 kts
SRM is 38.25 kts
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125
2 E.
Remember to calculate the Turn Bearing, subtract
your maneuvering course (270) from your base
course (170). Take this number and divide by 10.
In this case, you should take (270-170)/10
10.
070T
Plot this amount along your MRM vector and go
from M2 back towards M1. Read the bearing back TO
the guide.
270T
M2
M1
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170T
126
5-23-3WB 3. A surface contact bears 260T, range
10000 yds from your ship. The contact is on
course 020T speed 12 kts. You are ordered to
take station 8000 yds bearing 145R from the
contact. Based on this information, solve for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. Speed of relative motion (SRM) required to be
on station in 10 minutes.
C. Stationing speed required for question A.
D. Taking into account the effects of
deceleration, you would slow to 12 kts when the
guide bears?
B. Course required for question A listed above.
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127
3 A.
020T
Using your MRM and a time of 10 min, you should
get an SRM of
R
080T _at_ 10000 yds
M1
12 kts
37 kts
E
MRM
260T
TB RB SH TB 145R 020T TB 165T
M2
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165 _at_ 8000 yds
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128
3 B C.
020T
Once you mark of your SRM of 37 kts, plot your EM
vector. You can determine your stationing course
and speed from here.
R
080T _at_ 10000 yds
M1
12 kts
SRM of 37 kts
E
MRM
26 KTS
M
228T
M2
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165 _at_ 8000 yds
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129
3 D.
020T
341.8T
To calculate your Surge Bearing, subtract your
stationing speed of 26 kts from your base speed
of 12 kts. Take 14 kts and multiply by 35 yds.
Take this distance and plot the back from M2
towards M1.
R
080T _at_ 10000 yds
M1
12 kts
E
MRM
26 KTS
M
228T
M2
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165 _at_ 8000 yds
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130
5-23-3WB 4. A surface contact bearing 175T,
range 8000 yds is on course 090T, speed 16 kts.
You are ordered to take station bearing 140T,
range 8000 yds from the contact. The Captain
desires to maneuver to station passing no closer
than 2000 yds astern of the contact. Use 25 kts
for stationing speed. Based on this info, solve
for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. Course for the first leg of the maneuver.
C. Course for the second leg of the maneuver.
D. Time to complete the maneuver?
B. Bearing TO the contact at the start of the
second leg.
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131
4 A.
355T
Draw your 2000 yd circle around the contact.
Next, draw your tangent from M1 to the circle
astern of the contact and parallel this to the ER
vector.
M1 _at_ 8000 yds
Plot your 25 kts of stationing speed and
intercept your RM vector.
2000 yd circle
E
R
090T
16 kts
25 kts
M2 _at_ 8000 yds
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140T
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150T
175T
132
4 B.
355T
M1 _at_ 8000 yds
067T
To determine the point when to maneuver for the
second leg, draw your other tangent from M2 to
the circle. The interception of both MRMs. This
is the point when you should maneuver for the
second leg.
2000 yd circle
E
R
090T
16 kts
M2 _at_ 8000 yds
140T
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175T
133
4 C.
355T
M1 _at_ 8000 yds
Parallel your MRM to the ER vector. Again, using
25 kts stationing speed intercept your RM vector.
This will be the course of the second leg.
E
R
16 kts
090T
104T
MRM
M2 _at_ 8000 yds
140T
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175T
134
4 D.
M1 _at_ 8000 yds
Using your MRMs and respective SRMs, you should
be able to determine the time to complete the
maneuver.
MRM
16 kts
E
R
090T
SRM
Total Time of 38.2 minutes
SRM
M2 _at_ 8000 yds
MRM
140T
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135
5-23-4WB 5. Your ship is on course 100T, speed
10 kts. The anemometer indicates that the
relative wind is from 320 relative speed 21
kts. The Captain desires the relative wind to be
from 25 off the port bow at 30 kts. Based on
this information, solve for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. True wind direction and velocity.
C. Speed required (LOW speed solution).
B. Course required (HIGH speed solution).
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136
5 A.
034T
060T
21 kts
Apparent wind is 320R or Relative Wind is at
060T
15 kts
10 kts
100T
Remember to go from SHIP TO WIND when determining
the True Wind Course and Speed.
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137
True Wind is from 034T
5 B C.
Plot from DOT1 to DOT2 and parallel to the
center. This becomes your low speed solution.
With the true wind coming from 034T, plot your
DOT1 at 25 off the port bow at 25 kts. Using
your magnitude of the True Wind of 15 kts, mark
from DOT1 to your DOT2s as shown.
Plot from DOT1 to DOT2 and measure your speed
from the center. This becomes your high speed
solution.
091.2T
15 kts
DOT 1
DOT 2
35.5 kts
port
DOT 2
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stbd
138
5-23-4WB 6. Your ship is on course 260T, speed
10 kts. The anemometer indicates that the
relative wind is from 050 relative speed 20
kts. The Captain desires the relative wind to be
from 25 off the starboard bow at 30 kts. Based
on this information, solve for
PRESS RESPECTIVE BUTTON TO SEE ANSWERS.
A. True wind direction and velocity.
C. Speed required (LOW speed solution).
B. Course required (HIGH speed solution).
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139
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