Title: Dealing With Uncertainty
1CHAPTER 10
2RISK
- Risk and uncertainty are similar
- Both present the problem of not knowing what
future conditions will be - Risk offers estimates of probabilities for
possible outcomes - Uncertainty does not provide estimates of
probabilities for possible outcomes - This book treats them as interchangeable
3Four Major Sources Of Uncertainty
- Possible inaccuracy of cash-flow estimates used
in the study - How much source information is available
- How dependable is the source information
- Type of business relative to the future health of
the economy - Some businesses will typically be more at risk
when there is a general decline in the economy - Type of physical plant and equipment involved
- Some equipment have more definite lives and MV
than the others (general lathe machine vs. mining
equipment) - Length of study period
- The longer the study period, the greater the
level of uncertainty of a capital investment
4Sensitivity Analysis
- Sensitivity The degree to which a measure of
merit (I.e., PW, IRR, etc) will change as a
result of changes in one or more of the study
factor values - Sensitivity Analysis Techniques
- Breakeven Analysis
- Sensitivity Graph (spiderplot)
- Combination of factors
5Breakeven Analysis
- Useful for choosing among alternatives when costs
or revenues are highly sensitive to a single
factor that is hard to estimate (e.g., operating
hours per year, useful life, etc.) - General Procedure
- Write an expression of equivalent worth for each
alternative in terms of the common factor. - Equate the equivalent worths and solve for the
value of the common factor. This value is the
breakeven point (B.E.P.). - Estimate whether the actual factor value will be
higher or lower than the B.E.P. and then choose
the appropriate alternative.
6Breakeven Problem Involving Two Alternatives
- Indifference between alternatives (EWA f1(y)
EWB f2(y) - EWA EWB f1(y) f2(y) Solve for y
- Economic acceptability of engineering project
- EWp f(z) 0
- The value of z is the value at which we would
be indifferent between accepting or rejecting the
project
7Example
- Suppose that there are two alternative electric
motors that provide 100 hp output. An Alpha motor
can be purchased for 12,500 and has an
efficiency of 74, an estimated life of 10 years,
and estimated maintenance cost of 500 per year.
A Beta motor will cost 16,000 and has an
efficiency of 92, a life of 10 years, and annual
maintenance costs of 250. Annual taxes and
insurance costs on either motor will be 1-1/2 of
the investment. If the minimum attractive rate of
return is 15, how many hours per year would the
motors have to be operated at full load for the
annual costs to be equal? Assume that salvage
values for both motors are negligible and that
electricity costs 0.05 per kilowatt-hour.
8Formulation
- Decision Criterion Minimize Equivalent Uniform
Annual Cost (AC) - AC CR Operating cost Taxes Ins.
Maintenance - Alpha Beta
- Purchase Price 12,500 16,000
- Maintenance Cost/yr 500 250
- Annual Taxes Insurance 12,500(0.015)
16,000(0.015) - Efficiency 74 92
- Useful Life (yrs) 10 10
- Note Electrical Efficiency power output , and
1 hp 0.746 kW - At breakeven, ACa ACb
- 2,490 5.04X 500 187 3,190 4.05X
250 240 - or 3,177 5.04X 3,680 4.05X. Solving for
X, we find X 508 hrs/year
9Sensitivity Graph (Spiderplot)
- Makes explicit the impact of uncertainty in the
estimates of each factor of concern on the
economic measure of merit - Annual revenue and expenses
- Rate of return
- Market (or salvage) value
- Equipment Life
- Capacity utilization
10Example
- A machine for which most likely cash flow
estimates are given in the following list is
being considered for immediate installation.
Because of the new technology built into this
machine, it is desired to investigate its PW over
a range of 40 in - (a) initial investment, (b) annual net cash flow,
(c) salvage value, and (d) useful life - Based on these estimates, how much can the
initial investment increase without making the
machine an unattractive venture? - Draw a diagram that summarizes the sensitivity of
present worth to changes in each separate
parameter when the MARR 10 per year
11Example Solution
- PW(10) -11,500 3,000(PA,10,6)
1,000(PF,10,6) 2,130 - a) When the Initial Investment varies by p
- PW(1 p /100)(-11,500) 3,000(PA,10,6)
1,000(PF,10,6) - b) When Net Annual Cash Flow varies by a
- PW -11,500(1 a /100)(3,000)(PA,
10,6)1,000(PF,10,6) - c) When Salvage Value varies by s
- PW -11,5003,000(PA,10,6)(1 s /100
)(1,000)(PF,10,6) - d) When the Useful Life varies by n
- PW -11,5003,000PA,10,6(1 n /100 )
- 1,000PF,10,6(1 n /100)
12Sensitivity Graph (Spiderplot) Of Four Factors
PW (10)
7000
6000
Capital Investment
5000
Annual Net Cash Flow, A
2130
Useful Life, N
4000
3000
Market Value, MV
2000
- Deviation Changes in Factor Estimate
- Deviation
- Changes in
- Factor
- Estimate
1000
0
10 20 30 40
- 40 -30 -20 -10
-1000
-2000
-3000
-4000
13Revelations Of Spiderplot
- Shows the sensitivity of the present worth to
percent deviation changes in each factors best
estimate - Other factors are assumed to remain at their best
estimate values - The relative degree of sensitivity of the present
worth to each factor is indicated by the slope of
the curves (the steeper the slope of a curve
the more sensitive the present worth is to the
factor) - In this example
- Present worth is insensitive to MV
- Present worth is sensitive to I, A, and N
14Measuring Sensitivity By A Combination Of Factors
- Develop a sensitivity graph for the project
- Use sensitivity graph to select most sensitive
project factors. - Analyze combined effects of these factors on
projects economic measure of merit -
15Example - Continued
- Which parameter is most sensitive to change?
- PW(10) 0 when Initial Investment increases
18.5 - PW(10) 0 when Net Annual CF decreases 16.3
- PW(10) 0 when Salvage Value decreases 378
- Note requires a negative Salvage Value
- PW(10) 0 when Useful Life decreases 21.7
16Optimistic - Pessimistic Estimates
- Exploring sensitivity by estimating one or more
factors in a favorable direction and in an
unfavorable direction to investigate the effect
on study results. - Optimistic - 95th percentile (desirable)
- Pessimistic - 5th percentile (undesirable)
- Not only do we examine the Equivalent Worth (EW)
for all three estimation conditions, we examine
the EW for all combinations of estimated outcomes
for the key factors being estimated.
17Problem 10-18 (page 455)
- Suppose for an engineering project the
optimistic, most likely, and pessimistic
estimates are as shown below - Optimistic Most Likely Pessimistic
- Capital Investment -80,000 -95,000 -120,000
- Useful Life 12 years 10 years 6 years
- Market Value 30,000 20,000 0
- Net Annual CF 35,000 30,000 20,000
- MARR 12/yr 12/yr 12/yr
- a) What is the AW for each of the three
estimation conditions? - b) It is thought the most critical elements are
useful life and net annual cash flow. Develop a
table showing the AW for all combinations of
estimates for these two factors, assuming that
all other factors remain at their most likely
values.
18Problem 10-18 Set up
- AW(12)
- Set up a table to illustrate summary results
- Useful Life
- Net Annual O ML P
- Cash Flow (12 yrs) (10 yrs) (6 yrs)
- O 35,000
- ML 30,000
- P 20,000
19Dealing with Uncertainty
- Uncertainty causes factors to become random
variable in engineering economy analysis - Risk-Adjusted MARR
- A widely used industrial practice for including
some consideration of uncertainty is to increase
the MARR - Reduction of useful life
- By dropping from consideration those revenues
(savings) and expenses that may occur after a
reduced study period, heavy emphasis is placed on
rapid recovery of capital in early years of a
projects life - This method is closely related to the discounted
payback technique and suffers from most of the
same deficiencies