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CSE 144 Project

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KL: any pair of unlocked components valid FM: only allow moves fulfilling area constraints ... Unlocked components. Always choose component in the highest ... – PowerPoint PPT presentation

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Title: CSE 144 Project


1
CSE 144 Project
2
Overall Goal of the Project
  • Implement a physical design tool for a two-row
    standard cell design

0
5
3
1
2
4
3
Problems to be resolved
  • Positions of components
  • Which row to place each component Partitioning
  • The relative position of components in each row
    Placement
  • Interconnect between components Routing

4
What to optimize?
  • In partitioning minimize the number of
    interconnects between partitions (rows)
  • In placement minimize the overall horizontal
    length of interconnects
  • In routing fulfill the geometrical constraints
    --- wires in the same directions should not
    overlap

5
Input Specification
  • Matrix form circuit model
  • First line the number of components, N
  • The following N lines the output-input
    connections between components
  • A non-zero entry Aij denotes a connection between
    components i and j
  • The value of Aij denotes the pin number of i
  • Last line the size of each components

6
Output Specification
Partitioning Placement
  • Routing
  • Position of pins connected by each net
  • Leftmost and rightmost boundaries of each nets
  • Channel track occupied by each net

7
Part 1 Partitioning
  • Goal minimize the number of interconnects
    crossing the two rows
  • Constraints partition size should stay within a
    tolerance window
  • The tolerance bound is the size of the largest
    component
  • floor(V/2 - Cmax) lt A lt ceiling( V/2
    Cmax)

8
Fundamental Ideas
  • The flow of FM algorithm is the same as KL
    algorithm
  • Two differences
  • KL component swap per tentative move FM one
    component per tentative move
  • KL any pair of unlocked components valid FM
    only allow moves fulfilling area constraints

9
Algorithm
  • Initial partitioning (subject to area
    constraints)
  • Gain calculation (same equations as in KL)
  • Move and lock the component with highest gain,
    which satisfies area constraints (one component
    per tentative move). Update gains.
  • Repeat moving until no one can be moved
  • Make permanent all the movements up to and
    including the move giving the highest
    accumulative gain
  • Unlock all components and repeat until no
    improvement can be obtained

10
How to improve efficiency?
  • Gain updating technique
  • Locked components neednt be updated
  • Components unconnected to the ones being moved
    neednt be updated
  • Use efficient data structure
  • Three data structure candidates provided

11
Data Structure 1 Linked List
Gain stamps
Unlocked components
Gmax
Current max gain
3
Comp 5
Comp 0
NIL
2
Comp 1
Comp 3
NIL
1
0
Comp 4
NIL
-1
  • Always choose component in the highest linked
    list for tentative move
  • Gain updating corresponds to changing the
    position of components in the linked lists

-2
-3
-Gmax
12
Data Structure 2 Gain Matrix
Components
c4
c0
c2
c3
c5
c1
1
1
3
  • Always choose component in the highest row that
    contains 1-entries
  • Gain updating corresponds to changing the
    positions of 1-entries in the gain matrix

1
1
2
1
Gain value
1
0
1
-1
-2
-3
13
Data Structure 3 Gain Array
Components
c1
c2
c3
c4
c5
c0
3
2
-1
2
0
3
Gain
  • Gain updating corresponds to changing the values
    of the gain array elements

14
Implementation Requirement
  • Analyze the suggested data structures in terms of
  • Primarily computational efficiency
  • Secondarily space efficiency
  • Implement the most efficient one you think
  • Provide a detailed description of your analysis
    in your turn-in
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