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Aqueous Solutions

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species molar concentration of dissolved species involved in the ... Dissociation of water. 2H2O H3O OH- H2O H OH- Lecture 12. Slide 3. Aqueous Solutions ... – PowerPoint PPT presentation

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Title: Aqueous Solutions


1
  • Aqueous Solutions
  • Chemical equilibrium - law of mass action
  • For the general equation aA bB zZ
    xX
  • species molar concentration of dissolved
    species involved in the reaction
  • partial pressure of a gas in atmospheres of
    gaseous reactants
  • 1 if the species is a pure liquid, pure
    solid or solvent for a dilute solution
  • At equilibrium, the rate of the forward reaction
    rate of reverse reaction
  • The position of the equilibrium is independent of
    how it is established
  • Example for the equilibrium 1A 1B

2
  • Aqueous Solutions
  • Chemical Equilibrium - Le Châteliers Principle
  • When a stress is imposed on a system at
    equilibrium the system will respond in such a
    way as to relieve the stress.
  • Addition of a reactant
  • Change in pressure or volume of a gas
  • Change in temperature
  • Types of equilibria
  • Dissociation of water
  • 2H2O H3O OH-
  • H2O H OH-

3
  • Aqueous Solutions
  • Types of equilibria
  • Dissociation of water
  • Example pure water
  • 2H2O H3O OH-
  • H3O OH-
  • Example An aqueous solution 0.100 M NaOH
  • 2H2O H3O OH-
  • H3O
    OH-0.100-H3O
  • Kw H3OOH- H3O(0.100-H3O)
  • if H3O ltlt 0.100
  • H3O x 0.100 1.00x10-14
  • H3O 1.00x10-13
  • OH- 0.100 1.00x10-13 0.100

4
  • Aqueous Solutions
  • Types of equilibria
  • Brønsted-Lowry acids and bases
  • An acid is a substance that donates H to a
    proton acceptor
  • A base is a H acceptor from a proton donor
  • Conjugate acid - base pairs
  • acid1 base1 acid2 base2
  • base2 is the conjugate base of acid1
  • Example
  • acid1 base1 acid2 base2
  • H2O NH3 NH4 OH-

conjugate pair
conjugate pair
OH- is the conj. Base of the acid H2O and NH4 is
the conj. acid of the base NH3 H2O is the conj.
Acid of the base OH- and NH3 is the conj. base of
NH4
5
  • Aqueous Solutions
  • Types of equilibria
  • Brønsted-Lowry acids and bases
  • Example
  • acid1 base1 acid2 base2
  • HAc H2O H3O Ac-
  • Ac- is the conj. base of Hac and H3O is the
    conj. acid of H2O
  • H2O is the conj. base of H3O and HAc is the
    conj acid of Ac-
  • Note H2O was an acid in the previous example
  • Water is amphiprotic.
  • Other amphiprotic substances
  • HCO3- H2O H2CO3 OH-
  • HCO3- H2O CO32- H3O-

6
Aqueous Solutions Relationship between Ka and Kb
for conjugate a acid - base pair HAc H2O
H3O Ac- Ac- H2O HAc OH-
2H2O H3O OH- KwH3OOH-
The same result is obtained for a weak base in
water
7
Aqueous Solutions Amine bases
8
  • Aqueous Solutions
  • Calculate the H in an aqueous solution of a
    weak acid or base
  • Example what is H in a 1.00 M NH4Cl solution
  • NH4 H2O NH3 H3O
  • Assume the 2nd equilibrium is suppressed
  • by the 1st equilibrium
  • NH3H3O

2H2O H3O OH-
KwH3OOH-
9
  • Aqueous Solutions
  • Calculation of H for a solution of a weak acid
    or base often leads to a quadratic equation as
    in previous problem
  • The assumption that H ltlt CHA simplifies the
    algebra and arithmetic
  • An error in the calculated H results
  • See the table and figure showing errors in
    calculated H as a function of Ka and CHA in
    FAC7
  • Sometimes the problem requires solution to a
    complex equation in one unknown
  • ax3 bx1/2 c 0
  • Use the method of successive approximations - or
    Mathcad

10
  • Aqueous Solutions
  • Types of equilibria
  • Slightly soluble inorganic solids
  • Assume dissolved solid is 100 dissociated into
    ions
  • PbI2(s) Pb2(aq) 2I-(aq)

1
Stoichiometry demands I- 2Pb2 at
equilibrium Find the solubility of PbI2 in
concentration terms, how many moles PbI2
dissolves in 1 L of solution - find the C of
PbI2 in moles per liter of solution Solubility
S Pb2 since I- 2Pb2 at
equilibrium Pb2I-2 Pb2(2Pb2)2
7.1x10-9 4Pb23 7.1x10-9 Pb2 1.2x10-3
S
11
  • Aqueous Solutions
  • Types of equilibria - slightly soluble inorganic
    solids
  • Common ion effect - dissolve a solid in a
    solution containing one of the ions common to
    the solid
  • Example What is the solubility of PbI2 in a
    solution that is 0.100 M in KI?

PbI2(s) Pb2(aq) 2I-(aq) Ksp
Pb2I-2 7.1 x 10-9 S Pb2 I- 0.100
2Pb2 Pb2(0.100 2Pb2)2 7.1 x
10-9 assume 2Pb2 ltlt 0.100 Pb2(0.0100) 7.1
x 10-9 Pb2 7.1 x 10-7 S Check assumption
2 x Pb2 1.42 x 10-6 ltlt 0.100
12
  • Aqueous Solutions
  • Types of equilibria
  • Complex ion formation
  • Ag 2NH3 Ag(NH3)2
  • Fe3 SCN- FeSCN2
  • Oxidation - reduction equilibria
  • 5Fe2 MnO4- 8H 5Fe3 Mn2 4H2O
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